scala slick or and query - scala

Question

my question may sound very banal but I still didn't resolve it.
I have the Products Table implemented like
class ProductsTable(tag: Tag) extends Table[Product](tag, "PRODUCTS") {
def id = column[Int]("PRODUCT_ID", O.PrimaryKey, O.AutoInc)
def title = column[String]("NAME")
def description = column[String]("DESCRIPTION")
def style = column[String]("STYLE")
def price = column[Int]("PRICE")
def category_id = column[Int]("CATEGORY_ID")
def size_id = column[Int]("SIZE_ID")
def brand_id = column[Int]("BRAND_ID")
def * = (id.?, title, description, style, price, category_id, size_id, brand_id) <>(Product.tupled, Product.unapply _)
}
and its representation in
val Products = TableQuery[ProductsTable]
How can I implement query equivalent to SQl query:
select * from products where( category_id = 1 or category_id = 2 or category_id = 3 ) and (price between min and max)

Answer 1

Try something like this:
val query = Products filter { p => (p.category_id inSet List(1,2,3)) && p.price > min && p.price < max }
val result = db.run(query.result)
You can use println(query.result.statements) to see what query looks like.
EDIT:
Answer for additional question. You can make a function for your query that accepts optional min and max values:
def getProductsQuery(maybeMin: Option[Int] = None, maybeMax: Option[Int] = None) = {
val initialQuery = val query = Products filter { p => (p.category_id inSet List(1,2,3)) }
val queryWithMin = maybeMin match {
case Some(min) => initialQuery filter { _.price > min }
case None => initialQuery
}
val queryWithMax = maybeMax match {
case Some(max) => queryWithMin filter { _.price < max }
case None => queryWithMin
}
queryWithMax
}
And then you could do any of these:
val q1 = getProductsQuery() // without min or max
val q2 = getProductsQuery(maybeMin = Option(3)) // only min
val q3 = getProductsQuery(maybeMax = Option(10)) // only max
val q4 = getProductsQuery(maybeMin = Option(3), maybeMax = Option(10)) // both
and run any of these as needed...