I got file called numbers.txt which is basically line with 5 numbers:
they look like this:
1 2 3 4 5
What I'm trying to achieve is I want to read those numbers from the line (which already works), then in each iteration I want to add +1 to every number which was read from that file and print them on screen with print, so the final result should look like:
1 2 3 4 5
2 3 4 5 6
3 4 5 6 7
4 5 6 7 8
5 6 7 8 9
.
#!/usr/bin/perl
use strict;
use warnings;
open("handle", 'numbers.txt') or die('unable to open numbers file\n');
$/ = ' ';
OUT: for my $line (<handle>) {
for (my $a = 0; $a < 5; $a++) {
chomp $line;
$line += 1;
print "$line ";
next OUT;
}
}
close("handle");
Haven't done looping in perl for a while now and would be great if someone could provide working example.
Also, it would be great if you could provide more than one working example, just to be future proof ;)
Thanks
You can try this on for size.
#!/usr/bin/perl
use strict;
use warnings;
open("handle", 'numbers.txt') or die('unable to open numbers file\n');
for my $line (<handle>) {
chomp $line;
for my $number (split /\s+/, $line) {
for (my $a = $number; $a < $number+5; $a++) {
print "$a ";
}
print "\n";
}
}
close("handle");
You can dispense with $/=' ' and instead let the outer loop iterate on lines of the file.
For each line you want to iterate for each number which is separated by white space, thus the split /\s+/, $line which gives you a list of numbers for the inner loop.
For your output $a starts at the number read from the file.
This will do what you're after:
use strict;
use warnings;
while(<DATA>) {
chomp;
print "$_\n";
my #split = split;
my $count = 0;
for (1..4){
$count++;
foreach (#split){
my $num = $_ + $count;
print "$num ";
}
print "\n";
}
}
__DATA__
1 2 3 4 5
Here no need to use nested loop it's always program make slower.
#!/usr/bin/perl
use strict;
use warnings;
my #num = split(" ",(<DATA>)[0]);
foreach my $inc (0..$#num)
{
print map{$inc+$_," "}#num; # Add one by one in array element
print "\n";
}
__DATA__
1 2 3 4 5
Update Added another method, this one in line with the posted approach.
Increment each number in the string, changing the string in place. Repeat that. Below are two ways to do that. Yet another method reads individual numbers and prints following integer sequences.
(1) With regular expressions. It also fits in one-liner
echo "1 2 3 4 5" | perl -e '$v = <>; for (1..5) { print $v; $v =~ s/(\d+)/$1+1/eg; }'
This prints the desired output. But better put it in a script
use warnings;
use strict;
my $file = 'numbers.txt';
open my $fh, '<', $file or die "can't open $file: $!";
while (my $line = <$fh>) {
# Add chomp($line) if needed for some other processing.
for (1..5) {
print $line;
$line =~ s/(\d+)/$1+1/eg;
}
}
The /e modifier is crucial for this. It makes the replacement side of the regex be evaluated as code instead of as a double-quoted string. So you can actually execute code there and here we add to the captured number, $1+1, for each matched number as /g moves down the string. This changes the string so the next iteration of the for (1..5) increments those, etc. I match multiple digits, \d+, which isn't necessary in your example but makes far more sense in general.
(2) Via split + map + join, also repeatedly changing the line in place
while (my $line = <$fh>) {
for (1..5) {
print $line;
$line = join ' ', map { $_+1 } split '\s+', $line;
}
}
The split gets the list of numbers from $line and feeds it to map, which increments each, feeding its output list to join. The joined string is assigned back to $line, and this is repeated. I split by \s+ to allow multiple white space but this makes it very 'relaxed' in what input format it accepts, see perlrecharclass. If you know it's one space please change that to ' '.
(3) Take a number at a time and print the integer sequence starting from it.
open my $fh, '<', $file or die "can't open $file: $!";
local $/ = ' ';
while (my $num = <$fh>) {
print "$_ " for $num..$num+4;
print "\n";
}
The magical 4 can be coded by pre-processing the whole line to find the sequence length, say by
my $len = () = $line =~ /(\d+)/g;
or by split-ing into an array and taking its scalar, then using $len-1.
Additional comments.
I recommend the three-argument open, open my $fh, '<', $file
When you check a call print the error, die "Your message: $!", to see the reason for failure. If you decide to quit, if ($bad) { die "Got $bad" }, then you may not need $!. But when an external call fails you don't know the reason so you need the suitable error variable, most often $!.
Your program has a number of problems. Here is what's stopping it working
You are setting the record separator to a single space. Your input file contains "1 2 3 4 5\n", so the while loop will iterate five times setting $line to "1 ", "2 ", "3 ", "4 ", "5\n"
Your for loop is set up to iterate five times. It does chomp $line which removes the space after the number, then increments $line and prints it. Then you jump out of the for loop, having executed it only once, with next OUT. This results in each value in the file being incremented by one and printed, so you get 2 3 4 5 6
Removing the unnecessary next OUT, produces something closer
2 3 4 5 6 3 4 5 6 7 4 5 6 7 8 5 6 7 8 9 6 7 8 9 10
There are now five numbers being printed for each number in the input file
Adding print "\n" after the for loop help separate the lines
2 3 4 5 6
3 4 5 6 7
4 5 6 7 8
5 6 7 8 9
6 7 8 9 10
Now we need to print the number before it is incremented instead of afterwards. If we swap $line += 1 and print "$line " we get this
1 2 3 4 5
2 3 4 5 6
3 4 5 6 7
4 5 6 7 8
5
6 7 8 9
What is happening here is that the 5 is still followed be a newline, which now appears in the output. The chomp won't remove this because it removes the value of $/ from the end of a string. You've set that to a space, so it will remove only spaces. The fix is to replace chomp with a substitution s/\s+//g which removes *all whitespace from the string. You also need to do that only once so I've put it outside the for loop at the top
Now we get this
1 2 3 4 5
2 3 4 5 6
3 4 5 6 7
4 5 6 7 8
5 6 7 8 9
And this is your code as it ended up
use strict;
use warnings;
open( "handle", 'numbers.txt' ) or die('unable to open numbers file\n');
$/ = ' ';
for my $line (<handle>) {
$line =~ s/\s+//g;
for ( my $a = 0; $a < 5; $a++ ) {
print "$line ";
$line += 1;
}
print "\n";
}
close("handle");
There are a few other best practices that could improve your program
Use use warnings 'all'
Use lexical file handles, and the three-parameter form of open
Use local if you are changing Perl's built-in variables
Put $! into your die string so that you know why the open failed
Avoid the C-style for loop, and iterate over a list instead
Making these fixes as well looks like this. The output is identical to the above
use strict;
use warnings 'all';
open my $fh, '<', 'numbers.txt'
or die qq{Unable to open "numbers.txt" for input: $!};
local $/ = ' ';
for my $line ( <$fh> ) {
$line =~ s/\s+//g;
for my $a ( 0 .. 4 ) {
print "$line ";
++$line;
}
print "\n";
}
Related
I have a Perl script:
$i=0;
while ( ($num = <STDIN>) =~ /\S/ ) {
push #lines, $num; $i++;
print ("$num"x"$i")."\n";
}
It prints this:
3
3
4
4
4
5
5
5
5
But I want it to print this:
3
3
4
4 4
5
5 5 5
How can I prevent Perl from printing a new line after every print?
I have tried this method, as you can see in the code snippet:
$num x $i
You probably need chomp($num); which will remove your input newline at the end of $num.
my $i=0;
while ( (my $num = <STDIN>) =~ /\S/ ) {
chomp($num);
$i++;
print "$num " x $i, "\n"
}
Or you could just:
print "$& " x ++$i, "\n" while <STDIN>=~/\d+/;
(Also, when asking code questions you should strip down your example to only contain what is relevant. Your push #lines, $num can only contribute to confuse potential answerers)
I am trying to take user input such as 4 2 1 4 and store that into an array. Then loop through the array looking for duplicates to store into a hash table.
#!/usr/bin/perl -w
print "Enter numbers into hash table :";
my #num = <STDIN>;
my %hash;
foreach $x (#num){
my $count =1;
foreach $y(#num){
if($x == $y){
my $count++;
$hash{'$x'} = $count;
}
}
}
map{print "$_\t$hash{$_}\n"}keys %hash;
I expect the result to be:
1 1
2 1
4 2
The actual result, I just continue to enter digits, after I hit enter the program continues to ask for more input. I hit CTRL D and nothing happens.
There are a great many problems with your code and I don't have time to explore them all
I hope it helps to offer you a working solution
#!/usr/bin/perl
use strict;
use warnings 'all';
my %counts;
print "Enter numbers into counts table: ";
++$counts{$_} for split ' ', <STDIN>;
print "$_\t$counts{$_}\n" for keys %counts;
output
E:\Perl\source>count.pl
Enter numbers into counts table: 4 2 1 4
1 1
2 1
4 2
Probably it is possible to do more nicely, but i would do this as:
use strict;
use warnings;
use Data::Dumper;
my $numbers;
print "Enter numbers and finish with CTRL-D\n";
while(my $line = <STDIN>) {
$numbers->{$_}++ for ( $line =~ m/(\b\d+\b)/g );
}
print Dumper $numbers;
I want to join the first to 16th word and 17th to 31st, etc in an array with space to one line but do not know why the code does not work. Hope to get help here.Thanks
my #file = <FILE>;
for ( $i=0; $i<=$#file; $i+=16 ){
my $string = join ( " ", #file[$i..$i+15] );
print FILE1 "$string\n";
}
Below is part of my file.
1
2
3
...
What i wan to print is
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
17 18 19 20 21....
I wouldn't do it the way you've done it.
Instead I would:
open ( my $input, '<', "your_file_name" ) or die $!;
chomp ( my #file = <$input> );
print join (" ",splice (#file, 0, 15)),"\n" while #file;
Note - I've used a lexical file handle with a 3 argument open, because that's better style.
splice removes the first 16 elements from #file each iteration, and continues until #file is empty.
Your lines have newlines attached to them. Remove them with chomp. Then loop over the array, remove 16 items and print them.
my #file = <FILE>;
chomp #file;
while (#file) {
my #temp;
INNER: for ( 0 .. 15 ) {
push #temp, shift #file || last INNER; # not or
}
print join( q{ }, #temp ), "\n";
}
This is the long implementation of the splice solution Sobrique suggested in the comments. It's does the same thing, just way more verbose.
This is the old answer before the edit:
If you only want the first 16, this is way more effective.
my $string = join q{ }, map { <FILE>; chomp; $_ } 1 .. 16;
This reads 16 lines and chomp each of them, then joins.
You might also want to use lexical file handles $fh instead of the GLOB FILE.
open my $fh, '<', $path_to_file or die $!;
Suppose if you want to read it from file, don't store the whole file into an array. Instead loop through line by line. And check the line number with $. special variable.
use warnings;
use strict;
open my $fh,"<","input.txt";
my $line;
while (<$fh>)
{
chomp;
$line.= $_." ";
print "$line\n" and $line="" if($. % 16 == 0);
END{ print "$line\n";};
}
Or this also will work
use warnings;
use strict;
open my $wh,"<","input.txt";
my $line;
foreach (;;)
{
my $data = join " ",(map { my $m=<$wh> || ""; chomp($m); $m} (0..15));
last if ($data =~m/^\s+$/);
print $data,"\n";
}
Assuming that you have FILE and FILE1 descriptors open, try:
$.%16?s!\s+! !:1 and print FILE1 $_ while <FILE>;
I am trying to transpose an array.
I tried the following code...
#! /usr/bin/perl
use strict;
use warnings;
use autodie;
open my $fh, '<',"op.txt" || die "$!";
open my $wh , '>',"pwl.txt" || die "$!";
select ($wh);
while (my $line = <$fh>) {
my #rows = $line;
my #transposed;
for my $row (#rows) {
for my $column (0 .. $#{$row}) {
push(#{$transposed[$column]}, $row->[$column]);
}
}
for my $new_row (#transposed) {
for my $new_col (#{$new_row}) {
print $new_col, " ";
}
print "\n";
}
}
**********INPUT FILE******
1 2 3
4 5 6
7 8 9
********** EXPECTED OUTPUT FILE *******
1 4 7
2 5 8
3 6 9
******** GENERATED OUTPUT FILE *******
Currently couldn't able print anything. script shows the error
"can't use string ("1 4 7") as an array ref while "strict refs" in use
Reference:
used the following reference...
Transpose in perl
however in this reference example, array input lines are declared manually where as i am trying to process a array which is in a text file
could anybody help me where i did mistake?
Many Thanks
You did have to split input line as #dland suggested. But, there were a few other issues.
Here's the corrected code [please pardon the gratuitous style cleanup]:
#! /usr/bin/perl
use strict;
use warnings;
use autodie;
open my $fh, '<',"op.txt" || die "$!";
open my $wh , '>',"pwl.txt" || die "$!";
my #rows;
while (my $line = <$fh>) {
my #line = split(" ",$line);
push(#rows,\#line);
}
close($fh);
my #transposed;
for my $row (#rows) {
push(#transposed,[]);
}
my $rowidx = -1;
for my $rowptr (#rows) {
++$rowidx;
my $colidx = -1;
for my $rowval (#$rowptr) {
++$colidx;
###printf("R=%d C=%d\n",$rowidx,$colidx);
my $colptr = $transposed[$colidx];
$colptr->[$rowidx] = $rowval;
}
}
for my $new_row (#transposed) {
for my $new_col (#$new_row) {
print $wh $new_col, " ";
}
print $wh "\n";
}
close($wh);
Note: It's slightly harder to transpose a non-square matrix. The above code may need to be extended a bit for that.
You're trying to shove a scalar into an array:
my #row = $line;
I think what you really want is to split on spaces:
my #row = split / /, $line;
adding my #row =map [ split], $line to my initial code is helping to print the data to pwl.txt.
however its not printing side by side.. instead it is printing to new line.
I guess because of this Mr.Borodin didn't include matrix in side while loop!
1
2
3
4
5
6
7
8
9
Here's a simpler way of doing this. It assumes all the rows are of the same length, and that all the lines in the file contain data -- i.e. there are no blank lines
The name of the input file is expected as a parameter on the command line, and the output is sent to STDOUT so it can be redirected on the command line. For instance
perl transpose.pl op.txt > pwl.txt
use strict;
use warnings 'all';
my #matrix = map [ split ], <>;
print "#$_\n" for #matrix;
print "\n";
my #transpose;
for my $i ( 0 .. $#{ $matrix[0] } ) {
$transpose[$i] = [ map { $_->[$i] } #matrix ]
}
print "#$_\n" for #transpose;
print "\n";
output
1 2 3
4 5 6
7 8 9
1 4 7
2 5 8
3 6 9
I have been trying to find values that match between two columns (columns a and column b) of a large file and print the common values, plus the corresponding column d. I have been doing this by interating through hashes, however, because the file is so large, there is not enough memory to produce the output file. Is there any other way to do the same thing using less memory resources.
Any help is much appreciated.
The script I have written thus far is below:
#!usr/bin/perl
use warnings;
use strict;
open (FILE1, "<input.txt") || die "$!\n Couldn't open input.txt\n";
open (Output, ">output.txt")||die "Can't Open output.txt ";
my $hash1={};
my $hash2={};
while (<FILE1>) {
chomp (my $line=$_);
my ($a, $b, $c, $d) = split (/\t/, $line);
if ($a) {
$hash1->{$a}{info1} = "$d"; #original_ID-> YOB
}
if ($b) {
$hash2->{$b}{info2} = "$a"; #original_ID-> sire
}
foreach my $key (keys %$hash2) {
if (exists $hash1{$a}) {
$info1 = $hash1->{$a}->{info1};
print "$a\t$info1\n";
}
}
}
close FILE1;
close Output;
print "Done\n";
To clarify, the input file is a large pedigree file. An example is:
1 2 3 1977
2 4 5 1944
3 4 5 1950
4 5 6 1930
5 7 6 1928
An example of the output file is:
2 1944
4 1950
5 1928
Does the below work for you ?
#!/usr/local/bin/perl
use strict;
use warnings;
use DBM::Deep;
use List::MoreUtils qw(uniq);
my #seen;
my $db = DBM::Deep->new(
file => "foo.db",
autoflush => 1
);
while (<>) {
chomp;
my #fields = split /\s+/;
$$db{$fields[0]} = $fields[3];
push #seen, $fields[1];
}
for (uniq #seen) {
print $_ . " " . $$db{$_} . "\n" if exists $$db{$_};
}