Random number with user defined range - swift

I am teaching myself Swift and am stuck with a Random function.
What I want to achieve: User is able to specify the min and max of the Range.
Code I have now for the button, where I believe I am declaring the text as an integer:
#IBAction func generateNumbers(sender: AnyObject) {
let minRange:Int? = Int(lowValue.text!)
let maxRange:Int? = Int(highValue.text!)
func randomNumber(range: Range<Int> = minRange...maxRange) -> Int {
let min = range.startIndex
let max = range.endIndex
return Int(arc4random_uniform(UInt32(max - min))) + min
}
}
Obviously minRange and maxRange aren't valid integers for the Range, I am just wondering where I'm going wrong.
Thanks in advance for any assistance.

You are almost there
The problem is that
let minRange:Int? = Int(lowValue.text!)
let maxRange:Int? = Int(highValue.text!)
are defined as optionals.
While here
func randomNumber(range: Range<Int> = minRange...maxRange) -> Int {
you need minsRange and maxRange to be non optional.
So you could use the guard let statement to safely perform the needed unwrappings
#IBAction func generateNumbers(sender: AnyObject) {
guard let
lowText = lowValue.text,
highText = highValue.text,
minRange = Int(lowText),
maxRange = Int(highText)
else {
print("Couldn't find valid integers inside lowValue and highValue UITextFields. So I'm giving up...")
return
}
func randomNumber(range: Range<Int> = minRange...maxRange) -> Int {
let min = range.startIndex
let max = range.endIndex
return Int(arc4random_uniform(UInt32(max - min))) + min
}
}
Invoking randomNumber
Of course don't forget to finally invoke your function randomNumber(1...10)
Update
#IBAction func generateNumbers(sender: AnyObject) {
guard let
lowText = lowValue.text,
highText = highValue.text,
minRange = Int(lowText),
maxRange = Int(highText)
else {
print("Couldn't find valid integers inside lowValue and highValue UITextFields. So I'm giving up...")
return
}
let result = Int(arc4random_uniform(UInt32(minRange - maxRange))) + minRange
}

As others have identified, your minRange and maxRange are Optionals. They need to be Int, not Int? in order to form the range.
Also, you should avoid using ! to unwrap the text fields, just in case they're nil.
If you have some reasonable defaults for minRange and maxRange (such as 1 and 10), you could use the nil coalescing operator to unwrap your text fields and replace the values with defaults if the text fields can't be converted to an Int:
#IBAction func generateNumbers(sender: AnyObject) {
let minRange = Int(lowValue.text ?? "") ?? 1
let maxRange = Int(highValue.text ?? "") ?? 10
func randomNumber(range: Range<Int>) -> Int {
let min = range.startIndex
let max = range.endIndex
return Int(arc4random_uniform(UInt32(max - min))) + min
}
// test
let results = randomNumber(minRange...maxRange)
self.field1.text = String(results)
}
Note: The compiler is not happy with using the values minRange and maxRange to set the default value for range, so I added them to the call of randomNumber.
There is another potential gotcha here as well. You can't form a range if minRange is larger than maxRange, so you should check for that as well:
var minRange = Int(lowValue.text ?? "") ?? 1
var maxRange = Int(highValue.text ?? "") ?? 10
if minRange > maxRange {
// Swap 'em
(minRange, maxRange) = (maxRange, minRange)
}
Why even torture yourself in creating the range anyway? Since randomNumber is declared inside of generateNumbers you can just use minRange and maxRange:
#IBAction func generateNumbers(sender: AnyObject) {
var minRange = Int(lowValue.text ?? "") ?? 1
var maxRange = Int(highValue.text ?? "") ?? 10
if minRange > maxRange {
// Swap 'em
(minRange, maxRange) = (maxRange, minRange)
}
func randomNumber() -> Int {
return Int(arc4random_uniform(UInt32(maxRange - minRange))) + minRange
}
//test
let results = randomNumber()
self.field1.text = String(results)
}

Related

Why does xcode not allow me to explicitly declare type when changing string type to integer (Swift) [duplicate]

The application basically calculates acceleration by inputting Initial and final velocity and time and then use a formula to calculate acceleration. However, since the values in the text boxes are string, I am unable to convert them to integers.
#IBOutlet var txtBox1 : UITextField
#IBOutlet var txtBox2 : UITextField
#IBOutlet var txtBox3 : UITextField
#IBOutlet var lblAnswer : UILabel
#IBAction func btn1(sender : AnyObject) {
let answer1 = "The acceleration is"
var answer2 = txtBox1
var answer3 = txtBox2
var answer4 = txtBox3
Updated answer for Swift 2.0+:
toInt() method gives an error, as it was removed from String in Swift 2.x. Instead, the Int type now has an initializer that accepts a String:
let a: Int? = Int(firstTextField.text)
let b: Int? = Int(secondTextField.text)
Basic Idea, note that this only works in Swift 1.x (check out ParaSara's answer to see how it works in Swift 2.x):
// toInt returns optional that's why we used a:Int?
let a:Int? = firstText.text.toInt() // firstText is UITextField
let b:Int? = secondText.text.toInt() // secondText is UITextField
// check a and b before unwrapping using !
if a && b {
var ans = a! + b!
answerLabel.text = "Answer is \(ans)" // answerLabel ie UILabel
} else {
answerLabel.text = "Input values are not numeric"
}
Update for Swift 4
...
let a:Int? = Int(firstText.text) // firstText is UITextField
let b:Int? = Int(secondText.text) // secondText is UITextField
...
myString.toInt() - convert the string value into int .
Swift 3.x
If you have an integer hiding inside a string, you can convertby using the integer's constructor, like this:
let myInt = Int(textField.text)
As with other data types (Float and Double) you can also convert by using NSString:
let myString = "556"
let myInt = (myString as NSString).integerValue
You can use NSNumberFormatter().numberFromString(yourNumberString). It's great because it returns an an optional that you can then test with if let to determine if the conversion was successful.
eg.
var myString = "\(10)"
if let myNumber = NSNumberFormatter().numberFromString(myString) {
var myInt = myNumber.integerValue
// do what you need to do with myInt
} else {
// what ever error code you need to write
}
Swift 5
var myString = "\(10)"
if let myNumber = NumberFormatter().number(from: myString) {
var myInt = myNumber.intValue
// do what you need to do with myInt
} else {
// what ever error code you need to write
}
edit/update: Xcode 11.4 • Swift 5.2
Please check the comments through the code
IntegerField.swift file contents:
import UIKit
class IntegerField: UITextField {
// returns the textfield contents, removes non digit characters and converts the result to an integer value
var value: Int { string.digits.integer ?? 0 }
var maxValue: Int = 999_999_999
private var lastValue: Int = 0
override func willMove(toSuperview newSuperview: UIView?) {
// adds a target to the textfield to monitor when the text changes
addTarget(self, action: #selector(editingChanged), for: .editingChanged)
// sets the keyboard type to digits only
keyboardType = .numberPad
// set the text alignment to right
textAlignment = .right
// sends an editingChanged action to force the textfield to be updated
sendActions(for: .editingChanged)
}
// deletes the last digit of the text field
override func deleteBackward() {
// note that the field text property default value is an empty string so force unwrap its value is safe
// note also that collection remove at requires a non empty collection which is true as well in this case so no need to check if the collection is not empty.
text!.remove(at: text!.index(before: text!.endIndex))
// sends an editingChanged action to force the textfield to be updated
sendActions(for: .editingChanged)
}
#objc func editingChanged() {
guard value <= maxValue else {
text = Formatter.decimal.string(for: lastValue)
return
}
// This will format the textfield respecting the user device locale and settings
text = Formatter.decimal.string(for: value)
print("Value:", value)
lastValue = value
}
}
You would need to add those extensions to your project as well:
Extensions UITextField.swift file contents:
import UIKit
extension UITextField {
var string: String { text ?? "" }
}
Extensions Formatter.swift file contents:
import Foundation
extension Formatter {
static let decimal = NumberFormatter(numberStyle: .decimal)
}
Extensions NumberFormatter.swift file contents:
import Foundation
extension NumberFormatter {
convenience init(numberStyle: Style) {
self.init()
self.numberStyle = numberStyle
}
}
Extensions StringProtocol.swift file contents:
extension StringProtocol where Self: RangeReplaceableCollection {
var digits: Self { filter(\.isWholeNumber) }
var integer: Int? { Int(self) }
}
Sample project
swift 4.0
let stringNumber = "123"
let number = Int(stringNumber) //here number is of type "Int?"
//using Forced Unwrapping
if number != nil {
//string is converted to Int
}
you could also use Optional Binding other than forced binding.
eg:
if let number = Int(stringNumber) {
// number is of type Int
}
In Swift 4.2 and Xcode 10.1
let string = "789"
if let intValue = Int(string) {
print(intValue)
}
let integerValue = 789
let stringValue = String(integerValue)
OR
let stringValue = "\(integerValue)"
print(stringValue)
//Xcode 8.1 and swift 3.0
We can also handle it by Optional Binding, Simply
let occur = "10"
if let occ = Int(occur) {
print("By optional binding :", occ*2) // 20
}
Swift 3
The simplest and more secure way is:
#IBOutlet var textFieldA : UITextField
#IBOutlet var textFieldB : UITextField
#IBOutlet var answerLabel : UILabel
#IBAction func calculate(sender : AnyObject) {
if let intValueA = Int(textFieldA),
let intValueB = Int(textFieldB) {
let result = intValueA + intValueB
answerLabel.text = "The acceleration is \(result)"
}
else {
answerLabel.text = "The value \(intValueA) and/or \(intValueB) are not a valid integer value"
}
}
Avoid invalid values setting keyboard type to number pad:
textFieldA.keyboardType = .numberPad
textFieldB.keyboardType = .numberPad
In Swift 4:
extension String {
var numberValue:NSNumber? {
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
return formatter.number(from: self)
}
}
let someFloat = "12".numberValue
Useful for String to Int and other type
extension String {
//Converts String to Int
public func toInt() -> Int? {
if let num = NumberFormatter().number(from: self) {
return num.intValue
} else {
return nil
}
}
//Converts String to Double
public func toDouble() -> Double? {
if let num = NumberFormatter().number(from: self) {
return num.doubleValue
} else {
return nil
}
}
/// EZSE: Converts String to Float
public func toFloat() -> Float? {
if let num = NumberFormatter().number(from: self) {
return num.floatValue
} else {
return nil
}
}
//Converts String to Bool
public func toBool() -> Bool? {
return (self as NSString).boolValue
}
}
Use it like :
"123".toInt() // 123
i have made a simple program, where you have 2 txt field you take input form the user and add them to make it simpler to understand please find the code below.
#IBOutlet weak var result: UILabel!
#IBOutlet weak var one: UITextField!
#IBOutlet weak var two: UITextField!
#IBAction func add(sender: AnyObject) {
let count = Int(one.text!)
let cal = Int(two.text!)
let sum = count! + cal!
result.text = "Sum is \(sum)"
}
hope this helps.
Swift 3.0
Try this, you don't need to check for any condition I have done everything just use this function. Send anything string, number, float, double ,etc,. you get a number as a value or 0 if it is unable to convert your value
Function:
func getNumber(number: Any?) -> NSNumber {
guard let statusNumber:NSNumber = number as? NSNumber else
{
guard let statString:String = number as? String else
{
return 0
}
if let myInteger = Int(statString)
{
return NSNumber(value:myInteger)
}
else{
return 0
}
}
return statusNumber
}
Usage:
Add the above function in code and to convert use
let myNumber = getNumber(number: myString)
if the myString has a number or string it returns the number else it returns 0
Example 1:
let number:String = "9834"
print("printing number \(getNumber(number: number))")
Output: printing number 9834
Example 2:
let number:Double = 9834
print("printing number \(getNumber(number: number))")
Output: printing number 9834
Example 3:
let number = 9834
print("printing number \(getNumber(number: number))")
Output: printing number 9834
About int() and Swift 2.x: if you get a nil value after conversion check if you try to convert a string with a big number (for example: 1073741824), in this case try:
let bytesInternet : Int64 = Int64(bytesInternetString)!
Latest swift3 this code is simply to convert string to int
let myString = "556"
let myInt = Int(myString)
Because a string might contain non-numerical characters you should use a guard to protect the operation. Example:
guard let labelInt:Int = Int(labelString) else {
return
}
useLabelInt()
I recently got the same issue. Below solution is work for me:
let strValue = "123"
let result = (strValue as NSString).integerValue
Swift5 float or int string to int:
extension String {
func convertStringToInt() -> Int {
return Int(Double(self) ?? 0.0)
}
}
let doubleStr = "4.2"
// print 4
print(doubleStr.convertStringToInt())
let intStr = "4"
// print 4
print(intStr.convertStringToInt())
Use this:
// get the values from text boxes
let a:Double = firstText.text.bridgeToObjectiveC().doubleValue
let b:Double = secondText.text.bridgeToObjectiveC().doubleValue
// we checking against 0.0, because above function return 0.0 if it gets failed to convert
if (a != 0.0) && (b != 0.0) {
var ans = a + b
answerLabel.text = "Answer is \(ans)"
} else {
answerLabel.text = "Input values are not numberic"
}
OR
Make your UITextField KeyboardType as DecimalTab from your XIB or storyboard, and remove any if condition for doing any calculation, ie.
var ans = a + b
answerLabel.text = "Answer is \(ans)"
Because keyboard type is DecimalPad there is no chance to enter other 0-9 or .
Hope this help !!
// To convert user input (i.e string) to int for calculation.I did this , and it works.
let num:Int? = Int(firstTextField.text!);
let sum:Int = num!-2
print(sum);
This works for me
var a:Int? = Int(userInput.text!)
for Swift3.x
extension String {
func toInt(defaultValue: Int) -> Int {
if let n = Int(self.trimmingCharacters(in: CharacterSet.whitespacesAndNewlines)) {
return n
} else {
return defaultValue
}
}
}
Swift 4, Swift 5
There are different cases to convert from something to something data type, it depends the input.
If the input data type is Any, we have to use as before convert to actual data type, then convert to data type what we want. For example:
func justGetDummyString() -> Any {
return "2000"
}
let dummyString: String = (justGetDummyString() as? String) ?? "" // output = "2000"
let dummyInt: Int = Int(dummyString) ?? 0 // output = 2000
for Alternative solution. You can use extension a native type. You can test with playground.
extension String {
func add(a: Int) -> Int? {
if let b = Int(self) {
return b + a
}
else {
return nil
}
}
}
"2".add(1)
My solution is to have a general extension for string to int conversion.
extension String {
// default: it is a number suitable for your project if the string is not an integer
func toInt(default: Int) -> Int {
if let result = Int(self) {
return result
}
else {
return default
}
}
}
#IBAction func calculateAclr(_ sender: Any) {
if let addition = addition(arrayString: [txtBox1.text, txtBox2.text, txtBox3.text]) {
print("Answer = \(addition)")
lblAnswer.text = "\(addition)"
}
}
func addition(arrayString: [Any?]) -> Int? {
var answer:Int?
for arrayElement in arrayString {
if let stringValue = arrayElement, let intValue = Int(stringValue) {
answer = (answer ?? 0) + intValue
}
}
return answer
}
Question : string "4.0000" can not be convert into integer using Int("4.000")?
Answer : Int() check string is integer or not if yes then give you integer and otherwise nil. but Float or Double can convert any number string to respective Float or Double without giving nil. Example if you have "45" integer string but using Float("45") gives you 45.0 float value or using Double("4567") gives you 45.0.
Solution : NSString(string: "45.000").integerValue or Int(Float("45.000")!)! to get correct result.
An Int in Swift contains an initializer that accepts a String. It returns an optional Int? as the conversion can fail if the string contains not a number.
By using an if let statement you can validate whether the conversion succeeded.
So your code become something like this:
#IBOutlet var txtBox1 : UITextField
#IBOutlet var txtBox2 : UITextField
#IBOutlet var txtBox3 : UITextField
#IBOutlet var lblAnswer : UILabel
#IBAction func btn1(sender : AnyObject) {
let answer1 = "The acceleration is"
var answer2 = txtBox1
var answer3 = txtBox2
var answer4 = txtBox3
if let intAnswer = Int(txtBox1.text) {
// Correctly converted
}
}
Swift 5.0 and Above
Working
In case if you are splitting the String it creates two substrings and not two Strings . This below method will check for Any and convert it t0 NSNumber its easy to convert a NSNumber to Int, Float what ever data type you need.
Actual Code
//Convert Any To Number Object Removing Optional Key Word.
public func getNumber(number: Any) -> NSNumber{
guard let statusNumber:NSNumber = number as? NSNumber else {
guard let statString:String = number as? String else {
guard let statSubStr : Substring = number as? Substring else {
return 0
}
if let myInteger = Int(statSubStr) {
return NSNumber(value:myInteger)
}
else{
return 0
}
}
if let myInteger = Int(statString) {
return NSNumber(value:myInteger)
}
else if let myFloat = Float(statString) {
return NSNumber(value:myFloat)
}else {
return 0
}
}
return statusNumber }
Usage
if let hourVal = getNumber(number: hourStr) as? Int {
}
Passing String to check and convert to Double
Double(getNumber(number: dict["OUT"] ?? 0)
As of swift 3, I have to force my #%#! string & int with a "!" otherwise it just doesn't work.
For example:
let prefs = UserDefaults.standard
var counter: String!
counter = prefs.string(forKey:"counter")
print("counter: \(counter!)")
var counterInt = Int(counter!)
counterInt = counterInt! + 1
print("counterInt: \(counterInt!)")
OUTPUT:
counter: 1
counterInt: 2

UITextField check if user typed in numeric [duplicate]

The application basically calculates acceleration by inputting Initial and final velocity and time and then use a formula to calculate acceleration. However, since the values in the text boxes are string, I am unable to convert them to integers.
#IBOutlet var txtBox1 : UITextField
#IBOutlet var txtBox2 : UITextField
#IBOutlet var txtBox3 : UITextField
#IBOutlet var lblAnswer : UILabel
#IBAction func btn1(sender : AnyObject) {
let answer1 = "The acceleration is"
var answer2 = txtBox1
var answer3 = txtBox2
var answer4 = txtBox3
Updated answer for Swift 2.0+:
toInt() method gives an error, as it was removed from String in Swift 2.x. Instead, the Int type now has an initializer that accepts a String:
let a: Int? = Int(firstTextField.text)
let b: Int? = Int(secondTextField.text)
Basic Idea, note that this only works in Swift 1.x (check out ParaSara's answer to see how it works in Swift 2.x):
// toInt returns optional that's why we used a:Int?
let a:Int? = firstText.text.toInt() // firstText is UITextField
let b:Int? = secondText.text.toInt() // secondText is UITextField
// check a and b before unwrapping using !
if a && b {
var ans = a! + b!
answerLabel.text = "Answer is \(ans)" // answerLabel ie UILabel
} else {
answerLabel.text = "Input values are not numeric"
}
Update for Swift 4
...
let a:Int? = Int(firstText.text) // firstText is UITextField
let b:Int? = Int(secondText.text) // secondText is UITextField
...
myString.toInt() - convert the string value into int .
Swift 3.x
If you have an integer hiding inside a string, you can convertby using the integer's constructor, like this:
let myInt = Int(textField.text)
As with other data types (Float and Double) you can also convert by using NSString:
let myString = "556"
let myInt = (myString as NSString).integerValue
You can use NSNumberFormatter().numberFromString(yourNumberString). It's great because it returns an an optional that you can then test with if let to determine if the conversion was successful.
eg.
var myString = "\(10)"
if let myNumber = NSNumberFormatter().numberFromString(myString) {
var myInt = myNumber.integerValue
// do what you need to do with myInt
} else {
// what ever error code you need to write
}
Swift 5
var myString = "\(10)"
if let myNumber = NumberFormatter().number(from: myString) {
var myInt = myNumber.intValue
// do what you need to do with myInt
} else {
// what ever error code you need to write
}
edit/update: Xcode 11.4 • Swift 5.2
Please check the comments through the code
IntegerField.swift file contents:
import UIKit
class IntegerField: UITextField {
// returns the textfield contents, removes non digit characters and converts the result to an integer value
var value: Int { string.digits.integer ?? 0 }
var maxValue: Int = 999_999_999
private var lastValue: Int = 0
override func willMove(toSuperview newSuperview: UIView?) {
// adds a target to the textfield to monitor when the text changes
addTarget(self, action: #selector(editingChanged), for: .editingChanged)
// sets the keyboard type to digits only
keyboardType = .numberPad
// set the text alignment to right
textAlignment = .right
// sends an editingChanged action to force the textfield to be updated
sendActions(for: .editingChanged)
}
// deletes the last digit of the text field
override func deleteBackward() {
// note that the field text property default value is an empty string so force unwrap its value is safe
// note also that collection remove at requires a non empty collection which is true as well in this case so no need to check if the collection is not empty.
text!.remove(at: text!.index(before: text!.endIndex))
// sends an editingChanged action to force the textfield to be updated
sendActions(for: .editingChanged)
}
#objc func editingChanged() {
guard value <= maxValue else {
text = Formatter.decimal.string(for: lastValue)
return
}
// This will format the textfield respecting the user device locale and settings
text = Formatter.decimal.string(for: value)
print("Value:", value)
lastValue = value
}
}
You would need to add those extensions to your project as well:
Extensions UITextField.swift file contents:
import UIKit
extension UITextField {
var string: String { text ?? "" }
}
Extensions Formatter.swift file contents:
import Foundation
extension Formatter {
static let decimal = NumberFormatter(numberStyle: .decimal)
}
Extensions NumberFormatter.swift file contents:
import Foundation
extension NumberFormatter {
convenience init(numberStyle: Style) {
self.init()
self.numberStyle = numberStyle
}
}
Extensions StringProtocol.swift file contents:
extension StringProtocol where Self: RangeReplaceableCollection {
var digits: Self { filter(\.isWholeNumber) }
var integer: Int? { Int(self) }
}
Sample project
swift 4.0
let stringNumber = "123"
let number = Int(stringNumber) //here number is of type "Int?"
//using Forced Unwrapping
if number != nil {
//string is converted to Int
}
you could also use Optional Binding other than forced binding.
eg:
if let number = Int(stringNumber) {
// number is of type Int
}
In Swift 4.2 and Xcode 10.1
let string = "789"
if let intValue = Int(string) {
print(intValue)
}
let integerValue = 789
let stringValue = String(integerValue)
OR
let stringValue = "\(integerValue)"
print(stringValue)
//Xcode 8.1 and swift 3.0
We can also handle it by Optional Binding, Simply
let occur = "10"
if let occ = Int(occur) {
print("By optional binding :", occ*2) // 20
}
Swift 3
The simplest and more secure way is:
#IBOutlet var textFieldA : UITextField
#IBOutlet var textFieldB : UITextField
#IBOutlet var answerLabel : UILabel
#IBAction func calculate(sender : AnyObject) {
if let intValueA = Int(textFieldA),
let intValueB = Int(textFieldB) {
let result = intValueA + intValueB
answerLabel.text = "The acceleration is \(result)"
}
else {
answerLabel.text = "The value \(intValueA) and/or \(intValueB) are not a valid integer value"
}
}
Avoid invalid values setting keyboard type to number pad:
textFieldA.keyboardType = .numberPad
textFieldB.keyboardType = .numberPad
In Swift 4:
extension String {
var numberValue:NSNumber? {
let formatter = NumberFormatter()
formatter.numberStyle = .decimal
return formatter.number(from: self)
}
}
let someFloat = "12".numberValue
Useful for String to Int and other type
extension String {
//Converts String to Int
public func toInt() -> Int? {
if let num = NumberFormatter().number(from: self) {
return num.intValue
} else {
return nil
}
}
//Converts String to Double
public func toDouble() -> Double? {
if let num = NumberFormatter().number(from: self) {
return num.doubleValue
} else {
return nil
}
}
/// EZSE: Converts String to Float
public func toFloat() -> Float? {
if let num = NumberFormatter().number(from: self) {
return num.floatValue
} else {
return nil
}
}
//Converts String to Bool
public func toBool() -> Bool? {
return (self as NSString).boolValue
}
}
Use it like :
"123".toInt() // 123
i have made a simple program, where you have 2 txt field you take input form the user and add them to make it simpler to understand please find the code below.
#IBOutlet weak var result: UILabel!
#IBOutlet weak var one: UITextField!
#IBOutlet weak var two: UITextField!
#IBAction func add(sender: AnyObject) {
let count = Int(one.text!)
let cal = Int(two.text!)
let sum = count! + cal!
result.text = "Sum is \(sum)"
}
hope this helps.
Swift 3.0
Try this, you don't need to check for any condition I have done everything just use this function. Send anything string, number, float, double ,etc,. you get a number as a value or 0 if it is unable to convert your value
Function:
func getNumber(number: Any?) -> NSNumber {
guard let statusNumber:NSNumber = number as? NSNumber else
{
guard let statString:String = number as? String else
{
return 0
}
if let myInteger = Int(statString)
{
return NSNumber(value:myInteger)
}
else{
return 0
}
}
return statusNumber
}
Usage:
Add the above function in code and to convert use
let myNumber = getNumber(number: myString)
if the myString has a number or string it returns the number else it returns 0
Example 1:
let number:String = "9834"
print("printing number \(getNumber(number: number))")
Output: printing number 9834
Example 2:
let number:Double = 9834
print("printing number \(getNumber(number: number))")
Output: printing number 9834
Example 3:
let number = 9834
print("printing number \(getNumber(number: number))")
Output: printing number 9834
About int() and Swift 2.x: if you get a nil value after conversion check if you try to convert a string with a big number (for example: 1073741824), in this case try:
let bytesInternet : Int64 = Int64(bytesInternetString)!
Latest swift3 this code is simply to convert string to int
let myString = "556"
let myInt = Int(myString)
Because a string might contain non-numerical characters you should use a guard to protect the operation. Example:
guard let labelInt:Int = Int(labelString) else {
return
}
useLabelInt()
I recently got the same issue. Below solution is work for me:
let strValue = "123"
let result = (strValue as NSString).integerValue
Swift5 float or int string to int:
extension String {
func convertStringToInt() -> Int {
return Int(Double(self) ?? 0.0)
}
}
let doubleStr = "4.2"
// print 4
print(doubleStr.convertStringToInt())
let intStr = "4"
// print 4
print(intStr.convertStringToInt())
Use this:
// get the values from text boxes
let a:Double = firstText.text.bridgeToObjectiveC().doubleValue
let b:Double = secondText.text.bridgeToObjectiveC().doubleValue
// we checking against 0.0, because above function return 0.0 if it gets failed to convert
if (a != 0.0) && (b != 0.0) {
var ans = a + b
answerLabel.text = "Answer is \(ans)"
} else {
answerLabel.text = "Input values are not numberic"
}
OR
Make your UITextField KeyboardType as DecimalTab from your XIB or storyboard, and remove any if condition for doing any calculation, ie.
var ans = a + b
answerLabel.text = "Answer is \(ans)"
Because keyboard type is DecimalPad there is no chance to enter other 0-9 or .
Hope this help !!
// To convert user input (i.e string) to int for calculation.I did this , and it works.
let num:Int? = Int(firstTextField.text!);
let sum:Int = num!-2
print(sum);
This works for me
var a:Int? = Int(userInput.text!)
for Swift3.x
extension String {
func toInt(defaultValue: Int) -> Int {
if let n = Int(self.trimmingCharacters(in: CharacterSet.whitespacesAndNewlines)) {
return n
} else {
return defaultValue
}
}
}
Swift 4, Swift 5
There are different cases to convert from something to something data type, it depends the input.
If the input data type is Any, we have to use as before convert to actual data type, then convert to data type what we want. For example:
func justGetDummyString() -> Any {
return "2000"
}
let dummyString: String = (justGetDummyString() as? String) ?? "" // output = "2000"
let dummyInt: Int = Int(dummyString) ?? 0 // output = 2000
for Alternative solution. You can use extension a native type. You can test with playground.
extension String {
func add(a: Int) -> Int? {
if let b = Int(self) {
return b + a
}
else {
return nil
}
}
}
"2".add(1)
My solution is to have a general extension for string to int conversion.
extension String {
// default: it is a number suitable for your project if the string is not an integer
func toInt(default: Int) -> Int {
if let result = Int(self) {
return result
}
else {
return default
}
}
}
#IBAction func calculateAclr(_ sender: Any) {
if let addition = addition(arrayString: [txtBox1.text, txtBox2.text, txtBox3.text]) {
print("Answer = \(addition)")
lblAnswer.text = "\(addition)"
}
}
func addition(arrayString: [Any?]) -> Int? {
var answer:Int?
for arrayElement in arrayString {
if let stringValue = arrayElement, let intValue = Int(stringValue) {
answer = (answer ?? 0) + intValue
}
}
return answer
}
Question : string "4.0000" can not be convert into integer using Int("4.000")?
Answer : Int() check string is integer or not if yes then give you integer and otherwise nil. but Float or Double can convert any number string to respective Float or Double without giving nil. Example if you have "45" integer string but using Float("45") gives you 45.0 float value or using Double("4567") gives you 45.0.
Solution : NSString(string: "45.000").integerValue or Int(Float("45.000")!)! to get correct result.
An Int in Swift contains an initializer that accepts a String. It returns an optional Int? as the conversion can fail if the string contains not a number.
By using an if let statement you can validate whether the conversion succeeded.
So your code become something like this:
#IBOutlet var txtBox1 : UITextField
#IBOutlet var txtBox2 : UITextField
#IBOutlet var txtBox3 : UITextField
#IBOutlet var lblAnswer : UILabel
#IBAction func btn1(sender : AnyObject) {
let answer1 = "The acceleration is"
var answer2 = txtBox1
var answer3 = txtBox2
var answer4 = txtBox3
if let intAnswer = Int(txtBox1.text) {
// Correctly converted
}
}
Swift 5.0 and Above
Working
In case if you are splitting the String it creates two substrings and not two Strings . This below method will check for Any and convert it t0 NSNumber its easy to convert a NSNumber to Int, Float what ever data type you need.
Actual Code
//Convert Any To Number Object Removing Optional Key Word.
public func getNumber(number: Any) -> NSNumber{
guard let statusNumber:NSNumber = number as? NSNumber else {
guard let statString:String = number as? String else {
guard let statSubStr : Substring = number as? Substring else {
return 0
}
if let myInteger = Int(statSubStr) {
return NSNumber(value:myInteger)
}
else{
return 0
}
}
if let myInteger = Int(statString) {
return NSNumber(value:myInteger)
}
else if let myFloat = Float(statString) {
return NSNumber(value:myFloat)
}else {
return 0
}
}
return statusNumber }
Usage
if let hourVal = getNumber(number: hourStr) as? Int {
}
Passing String to check and convert to Double
Double(getNumber(number: dict["OUT"] ?? 0)
As of swift 3, I have to force my #%#! string & int with a "!" otherwise it just doesn't work.
For example:
let prefs = UserDefaults.standard
var counter: String!
counter = prefs.string(forKey:"counter")
print("counter: \(counter!)")
var counterInt = Int(counter!)
counterInt = counterInt! + 1
print("counterInt: \(counterInt!)")
OUTPUT:
counter: 1
counterInt: 2

Cannot assign value of type Double to type String

trying to assign label text to 2 each textField inputs
warning show up says cannot assign value of type Double to type string
any suggestions
#IBAction func percentage1button(_ sender: Any) {
let firstValue = Double(percentage1textField1.text!)
let secondValue = Double(percentage1textfield2.text!)
let outputValue = Double(firstValue! + secondValue!)
percentage1result.text = outputValue
}
I will also suggest you not to use force unwrap:
#IBAction func percentage1button(_ sender: Any) {
guard let val1 = Double(percentage1textField1.text ?? ""),
let val2 = Double(percentage1textfield2.text ?? "") else
{
return
}
let outputValue = val1 + val2
percentage1result.text = "\(outputValue)"
}

Label intValue not show for greater than (>) to work

I am new at Swift the code builds just fine but the greater than (>) dose not work. I'm trying to producing at a number in the "totalCoal" label, but never goes over the "coalPileHolding" Second label. I know that this code can be way better But i am trying to get the basic first. I also know that the timeDiffernt ">" dose not work also so somehow I am missing something. Thank you for your help
#IBOutlet weak var coalPileHoldingLabel: UILabel!
func loadBigCoalPile () {
var coalPileHolding = Int ()
if UserDefaults.standard.object(forKey: "coalPileResearch") == nil {
coalPileHolding = 0 } else {
coalPileHolding = UserDefaults.standard.object(forKey: "coalPileResearch") as! Int}
if coalPileHolding == 1 {
let coalPileHolding = 200
coalPileHoldingLabel.text = String(coalPileHolding) }
if coalPileHolding == 2 {
let coalPileHolding = 300
coalPileHoldingLabel.text = String(coalPileHolding) }
if coalPileHolding == 3 {
let coalPileHolding = 400
coalPileHoldingLabel.text = String(coalPileHolding) }
#objc func buttonIsInAction(){
}
#IBOutlet weak var coalRunButton: UIButton!
#IBAction func coalRunButton(_ sender: Any) {
func getMillisecondsNow() -> Int64{
let currentDate = Date()
return getMillisecondsFromDate(date: currentDate)
}
func getMillisecondsFromDate(date: Date) -> Int64{
var d : Int64 = 0
let interval = date.timeIntervalSince1970
d = Int64(interval * 1000)
return d
}
func getTimeDifferenceFromNowInMilliseconds(time: Int64) -> Int64{
let now = getMillisecondsNow()
let diff: Int64 = now - time
return diff
}
var terminationTime = Int64()
if UserDefaults.standard.object(forKey: "latestTerminationDate") == nil {
terminationTime = getMillisecondsNow()
UserDefaults.standard.set(terminationTime, forKey:"latestTerminationDate")
}
else {
terminationTime = UserDefaults.standard.object(forKey: "latestTerminationDate") as! Int64 }
let timeDiff = getTimeDifferenceFromNowInMilliseconds(time: terminationTime)
let timeDiffernt = Int(timeDiff)
let now = getMillisecondsNow()
UserDefaults.standard.set (now, forKey: "latestTerminationDate")
if timeDiffernt > 86400000 { _ = 86400000}
var methodOfCut = Int ()
var machineryButton = Int ()
var qualityOfWorkers = Int ()
if UserDefaults.standard.object(forKey: "methodOfCut") == nil {
methodOfCut = 0 } else {
methodOfCut = UserDefaults.standard.object(forKey: "methodOfCut") as! Int}
if UserDefaults.standard.object(forKey: "machineryButton") == nil {
machineryButton = 0 } else {
machineryButton = UserDefaults.standard.object(forKey: "machineryButton") as! Int}
if UserDefaults.standard.object(forKey: "qualityOfWorkers") == nil {
qualityOfWorkers = 0 } else {
qualityOfWorkers = UserDefaults.standard.object(forKey: "qualityOfWorkers") as! Int}
let coalMayham = (machineryButton) + (qualityOfWorkers) + (methodOfCut)
let (dailyCoalAccumulate) = ((timeDiffernt) * (coalMayham) + 1) / 10000
var coalPileHolding2 = 0
if let coalPile = Int(coalPileLabel.text!) {
let totalCoal = (dailyCoalAccumulate) + coalPile
coalPileHolding2 = Int(coalPileHoldingLabel.text!) ?? 0
if totalCoal > coalPileHolding2 { coalPileHolding2 = totalCoal }
coalPileLabel.text = String(totalCoal)
UserDefaults.standard.set(totalCoal, forKey:"totalCoal")}
callOutLabel.text = String(dailyCoalAccumulate)}}
That mix of numeric types (Int32, Float, Int) is rather confusing. In general you want to use Int or Double. All other variants should only be used when absolutely necessary, for example if an API requires a different type. So lets assume that dailyCoalAccumulate is Int and switch everything else to Int too:
let coalPileHolding = 0
if let coalPile = Int(coalPileLabel.text!) {
let totalCoal = dailyCoalAccumulate + coalPile
let coalPileHolding = Int((coalPileHoldingLabel.text as! NSString).intValue)
if totalCoal > coalPileHolding {
let coalPileHolding = totalCoal
}
coalPileLabel.text = String(totalCoal)
UserDefaults.standard.set(totalCoal, forKey:"totalCoal")
}
callOutLabel.text = String(dailyCoalAccumulate)
Here the intValue API of NSString returns Int32 but I immediately convert it to a regular Int. But of course there is a better way to do this without having to bridge to the Objective-C NSString. If the string doesn't contain a number intValue simply returns zero. We can produce the same behavior when we use the Int initializer to convert the string and then replace the nil value with zero: Int(coalPileHoldingLabel.text!) ?? 0.
Then we have three different variables named coalPileHolding. Since they are defined in different scopes they can share the same name, but are still different variables. My guess is that you want to actually update the coalPileHolding variable. Otherwise the assignment in the inner if makes no sense - the compiler even warns about that.
So lets change coalPileHolding to var and update its value.
var coalPileHolding = 0
if let coalPile = Int(coalPileLabel.text!) {
let totalCoal = dailyCoalAccumulate + coalPile
coalPileHolding = Int(coalPileHoldingLabel.text!) ?? 0
if totalCoal > coalPileHolding {
coalPileHolding = totalCoal
}
coalPileLabel.text = String(totalCoal)
UserDefaults.standard.set(totalCoal, forKey:"totalCoal")
}
callOutLabel.text = String(dailyCoalAccumulate)

How to output result in UITextView in Swift 3?

I'm trying to output result in text field in Swift 3, but when the button is pressed nothing happens, doesn't even print in the console. It should be somewhere in the last 3 lines of code I guess. I can't figure out what I'm doing wrong, so your help is much appreciated! I'm also new to Swift, so it may be something obvious to you, but dead end for me.
And this is my code:
#IBAction func encrypt(sender: AnyObject?) {
let text = encryptText.text
let key = pkey.text
func encrypt(text: String) -> (text: String, key: [Int]) {
let text = text.lowercased()
let key = self.key(count: text.characters.count)
let map = self.map()
var output = String()
for (index, character) in text.characters.enumerated() {
if character == " " {
output.append(character)
}
else {
if let letterIndex = map.forward[String(character)] {
let keyIndex = key[index]
let outputIndex = (letterIndex + keyIndex + map.lastCharacterIndex) % map.lastCharacterIndex
if let outputCharacter = map.reversed[outputIndex] {
output.append(outputCharacter)
}
}
}
}
print(text)
outputText.text = output
return (text: output.uppercased(), key: key)
}
}
You have a function (encrypt) nested in another function (the #IBAction also called encrypt), but you are never calling the nested function. Try something like this:
#IBAction func encrypt(sender: AnyObject?) {
func encrypt(text: String) -> (text: String, key: [Int]) {
let text = text.lowercased()
let key = self.key(count: text.characters.count)
let map = self.map()
var output = String()
for (index, character) in text.characters.enumerated() {
if character == " " {
output.append(character)
}
else {
if let letterIndex = map.forward[String(character)] {
let keyIndex = key[index]
let outputIndex = (letterIndex + keyIndex + map.lastCharacterIndex) % map.lastCharacterIndex
if let outputCharacter = map.reversed[outputIndex] {
output.append(outputCharacter)
}
}
}
}
return (text: output.uppercased(), key: key)
}
let text = encryptText.text
let key = pkey.text
// call the encrypt function
let (resultText, resultKey) = encrypt(text: text)
// put the result in the text view
outputText.text = resultText
}
It's also a little difficult to determine exactly what you are doing because you declare so many variables with the same names (text, key, encrypt, etc). Choosing slight variations of those names can improve the readability of your code.