Launching Ionic app routing - ionic-framework

Question

Found this solution to lounching app via plugin
.run(['$state', '$window',
function($state, $window) {
$window.addEventListener('LaunchUrl', function(event) {
// gets page name from url
var page =/.*:[/]{2}([^?]*)[?]?(.*)/.exec(event.detail.url)[1];
// redirects to page specified in url
$state.go('tab.'+ page, {});
});
}]);
function handleOpenURL(url) {
setTimeout( function() {
var event = new CustomEvent('LaunchUrl', {detail: {'url': url}});
window.dispatchEvent(event);
}, 0);}
This solution works great if use simply state name, ex. myapp://posts
.state('app.posts', {
url: "/posts",
views: {
'menuContent': {
templateUrl: "templates/posts.html",
controller: 'PostsCtrl'
}
}})
open app/posts.
But I need open state like this
.state('app.post', {
url: "/posts/:postId",
views: {
'menuContent': {
templateUrl: "templates/post.html",
controller: 'PostCtrl'
}
}})
with link myapp://post/2525.
Can somebody help with this? Thank you!

Answer 1

Solved myself )))
.run(['$state', '$window',
function($state, $window) {
$window.addEventListener('LaunchUrl', function(event) {
// gets page name from url
var page =/.*:[/]{2}([^?]*)[?]?[/]{1}([^?]*)[?]?/.exec(event.detail.url)[1];
var id =/.*:[/]{2}([^?]*)[?]?[/]{1}([^?]*)[?]?/.exec(event.detail.url)[2];
// redirects to page specified in url
// alert ("id:" +id);
$state.go('app.'+ page, {'postId': + id});
});
}]);