I would like a spreadsheet row to contain the date of today, but only on every other Thursday, changing at 9:30 am.
To give you an example:
Next thursday the 21.07.16 it shell contain "21.07.16".
Until in exactly 14 days on thursday the 4.08.16 it shell contain this date and than change to 4.08.16.
Also I would like this change to happen at 9:30 am.
I can not think of a way how to do this. Can you point me into a direction?
One has to set a starting datetime somewhere in the past, such as July 7, 2016, at 9:30am.
Then find the difference between the current and the starting datetime. Truncate this difference down to a multiple of 14, and add this value to the starting datetime.
The datetimes are represented in Sheets numerically as the number of days since December 30, 1899. In this system, 2016-07-07 9:30 is about 42558.4 So the formula would be
=42558.4 + 14*floor((now()-42558.4)/14)
The output should be formatted as a date.
A less cryptic version is
=value("2016-07-07 09:30") + 14*floor((now() - value("2016-07-07 09:30"))/14)
(value follows the local convention for parsing dates, but I hope the format I used will be understood universally.)
Related
I have downloaded a dataset called Real estate valuation data set from https://archive.ics.uci.edu/ml/datasets/Real+estate+valuation+data+set?source=post_page . But I am not able to understand in which format the transaction date is given. They have given some examples like 2013.250=2013 March, 2013.500=2013 June, etc.
I encountered this same problem and I figured that the months were represented as a fraction of a year. So, for instance, June is the 6th month of the year, hence it is 6/12 = 0.5; that's why we had June 2013 as 2013.500, etc.
I have the below columns
StartDate EndDate CountDay
01 May 20 05 May 20 ?
As you see, 01 May is Friday, so from 01-05 May if we count all days including weekend it will be 4 days.
What I want is on column "CountDay" it only counts the Workdays, not the weekend.
SO the expected result would be 2.
Anyone know how to do it using a formula in Google Sheets?
Do you consider Fridays as part of the weekend?
If yes, then you could also try the following formula:
=NETWORKDAYS.INTL(A10, B10,"0000111")
If not, please use this formula:
=NETWORKDAYS.INTL(A10, B10)
How the formulas work.
By using the function NETWORKDAYS.INTL we can "adjust" the weekend (non-working weekdays) to our liking.
In this case we account Fridays as our non-working weekdays by using as the 3rd parameter 0000111 instead of the default 0000011 where every 0 represents a working weekday and every 1 a non-working weekday.
(Very useful for people working part-time)
Someone who has part-time work on only Mondays, Wednesdays and Fridays and wants to calculate the working days Friday, 1 May 2020 - Tuesday, 30 June 2020 could adjust the formula to:
=NETWORKDAYS.INTL(A10, B10,"0101011")
As explained on the official Google help page for NETWORKDAYS.INTL
weekend – [ OPTIONAL – 1 by default ] – A number or string representing which days of the week are considered weekends.
String method: Weekends can be specified using seven 0s and 1s, where the first number in the set represents Monday and the last number is for Sunday. A zero means that the day is a work day, a 1 means that the day is a weekend. For example, “0000011” would mean Saturday and Sunday are weekends.
Number method: Instead of using the string method above, a single number can be used. 1 = Saturday/Sunday are weekends, 2 = Sunday/Monday and this pattern repeats until 7 = Friday/Saturday. 11 = Sunday is the only weekend day, 12 = Monday is the only weekend day and this pattern repeats until 17 = Saturday is the only weekend day.
I just found how to do it:
=if(weeknum(A10)<weeknum(B10),B10-A10-2*(weeknum(B10)-weeknum(A10)),B10-A10)
something like that
What date time format is this : 735715:37344280
<ExecDateTOD Friendly="Monday April 27, 2015 10:23:00am">735715:37344280</ExecDateTOD>
It's found in C:\Windows\Performance\WinSAT\DataStore\file_name.xml, and is the date time when the Windows Experience Index Assessment test was run.
Any idea how it's structured and can be edited? I need to change it to a previous years Date.
It seems that this format is called VariantTime, in MSDN the call to convert time is called VariantTimeToSystemTime. So it may be number of days, with decimal part after the :.
For the timestamp 735715:37344280
The first number (the one before the colon) is the number of days since the year 0:
735715 / 365 = 2015.66
The second number (the one after the colon) is the number of milliseconds that have passed within the current day.
37344280 / (1000*60*60) = 10.37 hours since start of day
So you can just subtract 365 days from the first number to obtain the previous year like this:
<ExecDateTOD Friendly="Monday April 27, 2014 10:23:00am">735350:37344280</ExecDateTOD>
Note that there were no leap years in either 2015 or 2014, so these year are exactly 365 days long.
Here is a link to a page with another <ExecDateTOD> tag where you can compare: http://www.scribd.com/doc/82935159/2012-01-30-16-00-49-986-Formal-assessment-Recent-WinSAT#scribd
I think that if you subtract 365 from that number, you'll be in previous year.
That number seems to be days since the year 0. The first part might be the number of days, taking into account leap years, etc). The second part the time coded in some way.
I have a variable called sentDate which stores the month and day from Nov 27th - Dec 6th.Each day has a number of sentiment ratings that it represents therefore I need to assign unique day codes to each day so I can perform...
allSents(dayCodes==1)
So far I have managed to assign day codes using...
[a,b,dayCodes]=unique(sentDate);
[d,e,allSents]=unique(sentiment);
However the day codes take the last digit on the date e.g 27th becomes 7, 28th becomes 8, etc. I need it so the day codes start from 1 and increase for each day until the 6th of December, therefore 1-11.
Any idea on how I may do this ?
have you tried the datenum function? then subtract off whatever offset to give the appropriate start day number.
For those who may have a similar problem, by specifying stable in as a parameter e.g
[a,b,dayCodes]=unique(sentDate,'stable');
Will specify the daycodes in the same order as in sentDate.
Is there a function in Haskell that will allow me to enter component of a date (like a string representation or day month year components) that I can get information from (like day of week, days in a month, etc.)?
I've looked online and it looks like there are a lot of custom libraries, but I'm hoping there's one in the standard prelude library of ghci 10.6.4 that's just not well documented?
Are Data.Time.Calendar and Data.Time.Format in the time library sufficient?
You can parse a string representation of a date and get the length of a month using gregorianMonthLength. Not sure about day of the week, though you could format the date as a string using a format that just displays the week day.
A quick Google search turns up this, which may be what you want. It lets you parse strings representing dates and extract information from them.
You can find the day of the week with mondayStartWeek or sundayStartWeek, depending on whether you think a week starts on Monday, or on Sunday. Both functions are in Data.Time.Calendar.OrdinalDate.
λ> snd $ mondayStartWeek $ fromGregorian 2017 10 3
2
In the above example, the return value is 2, which indicates the second day of the week. Since the function is called mondayStartWeek, Monday is the first day, so 2 corresponds to Tuesday. This is true of October 3, 2017.
A warning regarding week numbers
Both functions return a tuple, where the second element is the week day. As far as I can tell, that should be trustworthy.
The first element, however, is the week number of the year. Be careful with that, because the rules for week numbering are political. If I remember correctly, in USA, week 1 is the week that contains January 1. That's not the case in Denmark, where I live. Here, week 1 is the first week where Thursday falls in the new year. This can mean that December 31 can fall in week 1 of the next year. IIRC, this is the rule for many other European countries. Some years, the American and the European week numbers align, but some years, they don't.