Run command line in PowerShell - powershell

Question

I know there are lots of posts regarding this, but nothing worked for me.
I am trying to run this command line in PowerShell:
C:/Program Files (x86)/ClamWin/bin/clamd.exe --install
I have this in PowerShell:
&"C:/Program Files (x86)/ClamWin/bin/clamd.exe --install"
But all this does is execute clamd.exe, ignoring the --install parameter
How can I get the full command line to run?

Answer 1

Josef Z's comment on the question provides the solution:
& "C:/Program Files (x86)/ClamWin/bin/clamd.exe" --install # double-quoted exe path
or, given that the executable path is a literal (contains no variable references or subexpressions), using a verbatim (single-quoted) string ('...'):
& 'C:/Program Files (x86)/ClamWin/bin/clamd.exe' --install # single-quoted exe path
As for why your own solution attempt failed: The call operator, &, expects only a command name/path as an argument, not a full command line.
Invoke-Expression accepts an entire command line, but that complicates things further and can be a security risk.
As for why this is the solution:
The need for quoting stands to reason: you need to tell PowerShell that C:/Program Files (x86)/ClamWin/bin/clamd.exe is a single token (path), despite containing embedded spaces.
&, the so-called call operator, is needed, because PowerShell has two fundamental parsing modes:
argument mode, which works like a traditional shell, where the first token is a command name, with subsequent tokens representing the arguments, which only require quoting if they contain shell metacharacters (chars. with special meaning to PowerShell, such as spaces to separate tokens);
that is why --install need not, but can be quoted (PowerShell will simply remove the quotes for you before passing the argument to the target executable.)
expression mode, which works like expressions in programming languages.
PowerShell decides based on a statement's first token what parsing mode to apply:
If the first token is a quoted string - which we need here due to the embedded spaces in the executable path - or a variable reference (e.g., $var ...), PowerShell parses in expression mode by default.
A quoted string or a variable reference as an expression would simply output the string / variable value.
However, given that we want to execute the executable whose path is stored in a quoted string, we need to force argument mode, which is what the & operator ensures.
Generally, it's important to understand that PowerShell performs nontrivial pre-processing of the command line before the target executable is invoked, so what the command line looks like in PowerShell code is generally not directly what the target executable sees.
If you reference a PowerShell variable on the command line and that variable contains embedded spaces, PowerShell will implicitly enclose the variable's value in double quotes before passing it on - this is discussed in this answer to the linked question.
PowerShell's metacharacters differ from that of cmd.exe and are more numerous (notably, , has special meaning in PowerShell (array constructor), but not cmd.exe - see this answer).
To simplify reuse of existing, cmd.exe-based command lines, PowerShell v3 introduced the special stop-parsing symbol, --%, which turns off PowerShell's normal parsing of the remainder of the command line and only interpolates cmd.exe-style environment-variable references (e.g., %USERNAME%).