I would like to draw curves with two variables like f(x,y)=0 for example:
x^2+y^2-2ax+2by+c=0 (a,b,c are constants and x,y are variables)
Of course in the case above, it is a circle so I could write the equation above in the form of circle and calculate its center and radius. Then I can plot it out.
But next time if it is not a circle（for example there are 'xy' terms or there are 'x^3,y^3' terms）, is there any way to plot it out in the x-y plane too?
I know how to draw f(x,y) in 3D plot using meshgrid, But I would like to draw f(x,y)=0 in 2D forms
Suggestion 1:
fcontour
You would use it like this:
f = #(x,y) x.^2 + y.^2
fcontour(f,[xmin xmax ymin ymax])
This was introduced in R2016a.
Suggestion 2:
you may have to determine the x- and y-values for each equation and then plot those.
You could use anonymous functions to automate this. The good thing here is that you can create a cell array of anonymous functions and loop through those.
% // Generate the x and y values
x=-2*pi:0.01:2*pi;
y=-2*pi:0.01:2*pi;
Create anonymous functions that will hold your equation. It is up to you to design these as you see fit. This particular anonymous function that I did creates a matrix where the first column hold the x values and the second hold the y-values. You will probably have different x- and y- values for each function.
a=#(x,y) ([cos(x);sin(y)].');
a1 = #(x,y) ([cos(x).^2;sin(x).^2].');
Put them in an cell array
t{1} = a;
t{2} = a1;
Then you can loop through your anonymous functions
for n=1:length(t)
f = t{n};
subplot(2,1,n)
plot(f(y,x),'LineWidth',5);
end
you can have a look at the scatterplot function: http://uk.mathworks.com/help/matlab/ref/scatter.html
[edit] or just use plot(x,y) [/edit]
Related
I need to plot a parabola and ellipse. However the ellipse is giving me trouble. Can anyone help? The equations are: y = -5*x^2 + 2 and (x^2/16) + (y^2/2) = 4
I've tried this code but obviously I feel like like it isn't right.
x = linspace(-5, 5);
y1 = (x.^2/16) + (y.^2/2) - 1;
y2 = -5*x.^2 +2;
figure(1)
plot(x, y1)
hold on
plot(x, y2)
hold off
Firstly, you did not define a range variable x. Secondly, the ellipse won't pass the vertical line test and can't be plotted like a regular function f(x). Thirdly, your equation y1 = (x.^2/16) + (y.^2/2) - 1; is non-sensical because you have y on each side.
You could correct your method by defining a range variable x1 and x2 that each have appropriate ranges for the functions your plotting. What I mean by this is that you probably don't want the same range for each function, because the ellipse is undefined over most of the range that the parabola is defined. To plot the ellipse using f(x) you could observe that there are + and - values that are identical, using this fact you could plot your ellipse by two functions one to represent the top half and one to represent the bottom half, each of these would pass the vertical line test.
OR
You could utilize ezplot and have a nice time with it because it makes your life easier. Here is a solution.
ezplot('x^2/16+y^2/2-4'); axis equal; hold on
ezplot('-5*x^2+2-y')
There are multiple ways to plot an ellipse, e.g. you could also use a parametric representation of the equation.
In your approach though, when plotting functions using plot(x,y) command, you need to express your dependent variable (y) through independent variable (x). You defined the range for x, which is what you substitute into your equations in order to find y's. While for the parabola, the dependency of y from x is obvious, you forgot to derive such a relationship for the ellipse. In this case it will be +-sqrt((1 - x^2/16)*2). So in your approach, you'll have to take into account both negative and positive y's for the same value of x. Also there's discrepancy in your written equation for the ellipse (=4) and the one in Matlab code (=1).
x = linspace(-5, 5);
y1 = sqrt((1 - x.^2/16)*2);
y2 = -5*x.^2 +2;
figure(1)
plot(x, real(y1), 'r', x, -real(y1), 'r')
hold on
plot(x, y2)
hold off
Since the ellipse has real y's not on the whole x domain, if you want to plot only real parts, specify real(y1) or abs(y1) (even though Matlab does it for you, too). You can also dismiss complex numbers for certain x when computing y1, but you'll need a for-loop for that.
In order to make things simpler, you can check the function fimplicit, ezplot is not recommended according to Matlab's documentation. Or if you want to plot the ellipse in a parametric way, fplot will work, too.
Another (more classic) approach for parametric plotting is given here already, then you don't need any other functions than what you already use. I think it is the simplest and most elegant way to plot an ellipse.
You will not be able to generate points for the ellipse using a function f(x) from a Cartesian linspace range. Instead, you can still use linspace but for the angle in a polar notation, from 0 to 2*pi. You should also be able to easily adjust radius and offset on both axis on the cos and sin expressions.
x = linspace(-5, 5);
y2 = -5*x.^2 +2;
figure(1)
clf;
plot(x, y2)
hold on
a = linspace(0,2*pi);
x2 = 4*cos(a);
y2 = sqrt(2)*sin(a);
plot(x2, y2)
xlim([-5,5]);
ylim([-5,5]);
hold off
MATLAB's surf command allows you to pass it optional X and Y data that specify non-cartesian x-y components. (they essentially change the basis vectors). I desire to pass similar arguments to a function that will draw a line.
How do I plot a line using a non-cartesian coordinate system?
My apologies if my terminology is a little off. This still might technically be a cartesian space but it wouldn't be square in the sense that one unit in the x-direction is orthogonal to one unit in the y-direction. If you can correct my terminology, I would really appreciate it!
EDIT:
Below better demonstrates what I mean:
The commands:
datA=1:10;
datB=1:10;
X=cosd(8*datA)'*datB;
Y=datA'*log10(datB*3);
Z=ones(size(datA'))*cosd(datB);
XX=X./(1+Z);
YY=Y./(1+Z);
surf(XX,YY,eye(10)); view([0 0 1])
produces the following graph:
Here, the X and Y dimensions are not orthogonal nor equi-spaced. One unit in x could correspond to 5 cm in the x direction but the next one unit in x could correspond to 2 cm in the x direction + 1 cm in the y direction. I desire to replicate this functionality but drawing a line instead of a surf For instance, I'm looking for a function where:
straightLine=[(1:10)' (1:10)'];
my_line(XX,YY,straightLine(:,1),straightLine(:,2))
would produce a line that traced the red squares on the surf graph.
I'm still not certain of what your input data are about, and what you want to plot. However, from how you want to plot it, I can help.
When you call
surf(XX,YY,eye(10)); view([0 0 1]);
and want to get only the "red parts", i.e. the maxima of the function, you are essentially selecting a subset of the XX, YY matrices using the diagonal matrix as indicator. So you could select those points manually, and use plot to plot them as a line:
Xplot = diag(XX);
Yplot = diag(YY);
plot(Xplot,Yplot,'r.-');
The call to diag(XX) will take the diagonal elements of the matrix XX, which is exactly where you'll get the red patches when you use surf with the z data according to eye().
Result:
Also, if you're just trying to do what your example states, then there's no need to use matrices just to take out the diagonal eventually. Here's the same result, using elementwise operations on your input vectors:
datA = 1:10;
datB = 1:10;
X2 = cosd(8*datA).*datB;
Y2 = datA.*log10(datB*3);
Z2 = cosd(datB);
XX2 = X2./(1+Z2);
YY2 = Y2./(1+Z2);
plot(Xplot,Yplot,'rs-',XX2,YY2,'bo--','linewidth',2,'markersize',10);
legend('original','vector')
Result:
Matlab has many built-in function to assist you.
In 2D the easiest way to do this is polar that allows you to make a graph using theta and rho vectors:
theta = linspace(0,2*pi,100);
r = sin(2*theta);
figure(1)
polar(theta, r), grid on
So, you would get this.
There also is pol2cart function that would convert your data into x and y format:
[x,y] = pol2cart(theta,r);
figure(2)
plot(x, y), grid on
This would look slightly different
Then, if we extend this to 3D, you are only left with plot3. So, If you have data like:
theta = linspace(0,10*pi,500);
r = ones(size(theta));
z = linspace(-10,10,500);
you need to use pol2cart with 3 arguments to produce this:
[x,y,z] = pol2cart(theta,r,z);
figure(3)
plot3(x,y,z),grid on
Finally, if you have spherical data, you have sph2cart:
theta = linspace(0,2*pi,100);
phi = linspace(-pi/2,pi/2,100);
rho = sin(2*theta - phi);
[x,y,z] = sph2cart(theta, phi, rho);
figure(4)
plot3(x,y,z),grid on
view([-150 70])
That would look this way
I use the following example taken from the site that describes fit. Returns an
object. Is it possible to take the data that refer to the fitted surface?
load franke
sf = fit([x, y],z,'poly23')
plot(sf,[x,y],z)
Thanks!
Here is a way to do it; but there is probably a cleaner one:
After getting your sf object, you can access its methods like so:
MethodName(sf)
See here for the list of available methods
So let's say you wish to plot the surface using a handle for the plot:
hPlot = plot(sf)
Then you can fetch the XData, YData and ZData using the handles like so:
X = get(hPlot,'XData')
Y = get(hPlot,'YData')
Z = get(hPlot,'ZData')
Might be a it cumbersome but it works. Note that you can also fetch the coefficients of the fitted surface like so:
coeffvalues(sf)
and the formula used to generate it:
formula(sf)
Therefore you could generate X, Y data and create Z values using meshgrid for example and you could then modify the surface as you wish.
EDIT Here is how you could create your own surface using the coefficients and the formula. Here I create an anonymous function with two input arguments (x and y) and use it to generate z values to plot. From the data obtained using plot(sf) I used x = 1:0.01:0.01:1 and y = 500:500:3000 but you could obviously change them.
I entered the formula manually in the function handle but there has to be a better way; I'm a bit in a hurry so I did not looked further into that but you could extract every element of the formula and multiply it by the right coefficient to automatically generate the formula.
Here is the whole code:
clear
clc
close all
load franke
sf = fit([x, y],z,'poly23')
c = coeffvalues(sf)
F = formula(sf)
%// Generate x and y values.
[x,y] = meshgrid(500:100:3000,0.01:.01:1);
%// There should be a better approach than manually entering the data haha.
%// Maybe use eval or feval.
MyFun = #(x,y) (c(1) + c(2)*x + c(3)*y +c(4)*x.^2 + c(5)*x.*y + c(6)*y.^2 + c(7)*(x.^2).*y + c(8)*x.*y.^2 + c(9)*y.^3);
%// Generate z data to create a surface
z = (MyFun(x,y));
figure
subplot(1,2,1)
plot(sf)
title('Plot using sf','FontSize',18)
subplot(1,2,2)
surf(x,y,z)
title('Plot using MyFun','FontSize',18)
Output:
[I know this is many years later, but I thought I'd add this for future visitors looking for answers]
There is a much simpler way to do this - use feval, or the implicit shortcuts to it by calling the fittype object itself. It did take me a little digging to find this when I needed it, it isn't particularly obvious.
From the feval MATLAB documentation:
Standard feval syntax:
y = feval(cfun,x)
z = feval(sfun,[x,y])
z = feval(sfun,x,y)
y = feval(ffun,coeff1,coeff2,...,x)
z = feval(ffun,coeff1,coeff2,...,x,y)
You can use feval to evaluate fits, but the following simpler syntax is recommended to evaluate these objects, instead of calling feval directly. You can treat fit objects as functions and call feval indirectly using the following syntax:
y = cfun(x) % cfit objects;
z = sfun(x,y) % sfit objects
z = sfun([x, y]) % sfit objects
y = ffun(coef1,coef2,...,x) % curve fittype objects;
z = ffun(coef1,coef2,...,x,y) % surface fittype objects;
I have three functions in spherical coordinates that I want to plot. They are functions of r,theta,phi and I want to view them in the x-y,y-z,x-z planes. I've tried accomplishing this for literally 8 hours. Every method I've tried has been unsuccessful.
How can I accomplish this phenomenally simple task?
F1 = (r.^2).*abs((1/(8*sqrt(pi))).*r.*exp(-r/2).*sin(theta).*cos(phi)).^2;
F2 = (r.^2).*abs((1/(8*sqrt(pi))).*r.*exp(-r/2).*sin(theta).*sin(phi)).^2;
F3 = (r.^2).*abs((1/(4*sqrt(2*pi))).*r.*exp(-r/2).*cos(theta)).^2;
As you can see, all three of the functions are F(r,theta,phi). That means that there are four dimensions: F,r,theta,phi.
If your functions cannot be expressed as r=f(theta,phi), maybe you can compute the value of f(theta,phi,r) over a grid and then plot an isosurface where your volume data equals your value twoPx.
I tried this small example from which you can expand but I do not know if the shape is correct because I do not know what to expect:
n=20;
rmax=5;
twoPx=0;
%%%%%%%%%%
[theta phi r]=ndgrid(linspace(0,2*pi,n),linspace(-pi/2,pi/2,n),linspace(0,rmax,n));
%%%%%%%%%%
value=(r.^2).*abs((1/(8*sqrt(pi))).*r.*exp(-r/2).*sin(theta).*cos(phi)).^2;
%%%%%%%%%%
[x y z]=sph2cart(theta,phi,r);
%%%%%%%%%%
p=patch(isosurface(x,y,z,value,twoPx));
%%%%%%%%%%
set(p,'FaceColor','b','EdgeColor','k','FaceAlpha',0.5);
daspect([1 1 1])
axis square;
grid on;
camlight;
view([0 0]);
A little explanation of what this snippet does:
define a spherical grid (ndgrid)
compute the value of your function on that grid
compute the cartesian grid corresponding to the spherical grid (sph2cart)
plot the isosurface where your volume equals twoPx (patch and isosurface)
Finally you may want to use the Matlab function view to specify which plane you want to look from.
I have a custom function which returns either 0 or 1 depending on two given inputs:
function val = myFunction(val1, val2)
% logic to determine if val=1 or val=0
end
How can I create a contour plot of the function over the x,y coordinates generated by the following meshgrid?
meshgrid(0:.5:3, 0:.5:3);
This plot will just simply display where the function is 0 or 1 on the contour map.
If your function myFunction is not designed to handle matrix inputs, then you can use the function ARRAYFUN to apply it to all the corresponding entries of x and y:
[x,y] = meshgrid(0:0.5:3); %# Create a mesh of x and y points
z = arrayfun(#myFunction,x,y); %# Compute z (same size as x and y)
Then you could use the function CONTOUR to generate a contour plot for the above data. Since your z data only has 2 different values, it would probably make sense for you to only plot one contour level (which would be at a value of 0.5, halfway between your two values). You might also want to instead use the function CONTOURF, which produces color-filled contours that will clearly show where the ones and zeroes are:
contourf(x,y,z,1); %# Plots 1 contour level, filling the area on either
%# side with different color
NOTE: Since you are plotting data that only has ones and zeroes, plotting contours may not be the best way to visualize it. I would instead use something like the function IMAGESC, like so:
imagesc(x(1,:),y(:,1),z);
Keep in mind the y-axis in this plot will be reversed relative to the plot generated by CONTOURF.
The following will do it:
function bincontour
clear; clc;
xrange = 0:.5:3;
yrange = 1:.5:5;
[xmesh, ymesh] = meshgrid(xrange, yrange);
z = arrayfun(#myFunction, xmesh, ymesh);
contourf(xrange, yrange, z, 5)
end
function val = myFunction(val1, val2)
val = rand() > 0.5;
end