why coloumn not updating using in pl/sql - oracle10g

i am trying to calculate the cgpa of a student from his term gpa.
and store the gpa value in gpa coloumn in the result table.
my code link:http://paste.ubuntu.com/21677789/.
finally it's showing the output:
hello term1
1307001 2 1 2
hello year2
hello term1
1307001 3 1 1.7
hello year3
hello roll1307001
hello term1
1307002 2 1 1.71315789473684210526315789473684210526
hello year2
hello term1
1307002 3 1 1.76315789473684210526315789473684210526
hello year3
hello roll1307002
PL/SQL procedure successfully completed.
and gpa value is not updated in result value..why value of tt showing too long ...help please..thanks in advance.

Related

Substring function to extract part of the string

data = {'desc': ['ADRIAN PETER - ANN 80020355787C - 11 Baillon Pass.pdf', 'AILEEN MARCUS - ANC 800E15432922 - 5 Mandarin Way.pdf',
'AJITH SINGH - ANN 80020837750 - 11 Berkeley Loop.pdf', 'ALEX MARTIN-CURTIS - ANC 80021710355 - 26 Dovedale St.pdf',
'Alice.Smith\Jodee - Karen - ANE 80020428377 - 58 Harrisdale Dr.pdf']}
df = pd.DataFrame(data, columns = ['desc'])
df
From the data frame, I want to create a new column called ID, and in that ID, I want to have only those values starting after ANN, ANC or ANE. So I am expecting a result as below.
ID
80020355787C
800E15432922
80020837750
80021710355
80020428377
I tried running the code below, but it did not get the desired result. Appreciate your help on this.
df['id'] = df['desc'].str.extract(r'\-([^|]+)\-')
You can use - AN[NCE] (800[0-9A-Z]+) -, where:
AN[NCE] matches literally AN followed by N or C or E;
800[0-9A-Z]+ matches literally 800 followed by one or more characters between 0 and 9 or between A and Z.
>>> df['desc'].str.extract(r'- AN[NCE] (800[0-9A-Z]+) -')
0
0 80020355787C
1 800E15432922
2 80020837750
3 80021710355
4 80020428377
If not all your ids start with "800", you can just remove it from the pattern.

read function name and args from a table row and iterate and execute it and store the output to a single table

I have a data.csv which looks like below having a function name and a dictionary.
function,args
fun1,(`startDate`endDate`sym`rollPerct`expDateThreshold`expDateThresholdExpiry)!(.z.D-5;.z.D;`AAPL;0.8;10;1)
fun2,(`startDate`endDate`sym`rollPerct`expDateThreshold`expDateThresholdExpiry)!(.z.D-5;.z.D;`MSFT`ZAK;0.8;10;1)
fun3,(`startDate`endDate`sym`rollPerct`expDateThreshold`expDateThresholdExpiry)!(.z.D-5;.z.D;`NAFK;0.8;10;1)
And If I read the data
tab:("S*";enlist ",") 0:`$data.csv
Now, I want to iterate all rows from the table like below and call them and save all 3 results to a single table res
fun1 [(`startDate`endDate`sym`rollPerct`expDateThreshold`expDateThresholdExpiry)!(.z.D-5;.z.D;`AAPL;0.8;10;1)]
fun2 [(`startDate`endDate`sym`rollPerct`expDateThreshold`expDateThresholdExpiry)!(.z.D-5;.z.D;`MSFT`ZAK;0.8;10;1)]
fun3 [(`startDate`endDate`sym`rollPerct`expDateThreshold`expDateThresholdExpiry)!(.z.D-5;.z.D;`NAFK;0.8;10;1)]
Code snippet to iterate over f1[args], f2[args] and f3[args]. Combine all 3 results into a single table. I had used loop here, but there should be something better than loop here? let me know if any?
cnt:(count table); //get count of table
ino:0; //initialize out counter to 0
tab::flip (`date`sym`ric!(`date$();`symbol$();`symbol$())); //create a global table so it can hold iteration data
//perform iteration where f1[args],f2[args],f3[args]=tab
while[ino<cnt;
data:exec .[first function;args] from table where i=ino;
upsert[`tab;data];
ino:ino+1
]
//tab now has all the itration data of f1 f2 f3
tab
if your inputs are correctly ordered for all functions, the following simple example should work
q)f1:{x+y+z+2};f2:{x*y*z*22};f3:{x%y%z%42};
q)tab:([]func:`f1`f2`f3;args:`x`y`z!/:3 cut til 9)
q)tab
func args
-----------------
f1 `x`y`z!0 1 2
f2 `x`y`z!3 4 5
f3 `x`y`z!6 7 8
q)update res:func .'get'[args]from tab
func args res
---------------------------
f1 `x`y`z!0 1 2 5
f2 `x`y`z!3 4 5 1320
f3 `x`y`z!6 7 8 0.1632653
NB: if you're loaded args are strings, you'll want to parse these
for example - taking the above again
q)tab:update .Q.s1'[args]from tab
q)tab
func args
-------------------
f1 "`x`y`z!0 1 2"
f2 "`x`y`z!3 4 5"
f3 "`x`y`z!6 7 8"
q)meta tab
c | t f a
----| -----
func| s
args| C
q)tab:update'[reval;parse]'[args]from tab
q)tab
func args
-----------------
f1 `x`y`z!0 1 2
f2 `x`y`z!3 4 5
f3 `x`y`z!6 7 8
q)meta tab
c | t f a
----| -----
func| s
args|
q)update res:func .'get'[args]from tab
func args res
---------------------------
f1 `x`y`z!0 1 2 5
f2 `x`y`z!3 4 5 1320
f3 `x`y`z!6 7 8 0.1632653
reval in the above will try to stop anything dodgy being ran but i would avoid parsing code straight from files where possible

How to get a zoo object with a num and Date object in it?

I want to transform my excel (bank return & the date) in a zoo object, with the data in the zoo object being numeric & date. I used the following data:
Classes ‘tbl_df’, ‘tbl’ and 'data.frame': 1455 obs. of 2 variables:
$ date : POSIXct, format: "1925-01-02" "1925-01-03" "1925-01-05" "1925-01-06" ...
$ Deutsche Bank: num 0.181 0.191 0.191 0.184 0.186 ...
I used the following code:
db.xts <- na.omit(as.data.frame(db.kurs))
db.xts2 <- db.xts %>% mutate(date = as.Date(date, format = "%d.%m.%Y")) %>% mutate(`Deutsche Bank` = as.numeric(`Deutsche Bank`))
db.xts3 <- as.xts(db.xts2, db.kurs$date)
db.zoo <- as.zoo(db.xts3)
db.zoo <- db.zoo[, colnames(db.zoo) != "date"]
which leaves me with the following:
‘zoo’ series from 1925-01-02 to 1929-12-31
Data: chr [1:1455] "0.1807194" "0.1911455" "0.1911455" "0.1841948" "0.1859325" "0.1841948" "0.1807194" "0.1789817" ...
Index: POSIXct[1:1455], format: "1925-01-02" "1925-01-03" "1925-01-05" "1925-01-06" "1925-01-07" "1925-01-08" "1925-01-09" "1925-01-10" ...
If I try to run it without the as.xts command R deletes all the dates and uses an iteger from 1 to 1455.
Does anybody have an idea how to solve it?
Thanks for the help,
Nick

An issue with argument "sortv" of function seqIplot()

I'm trying to plot individual sequences by means of function seqIplot() in TraMineR. These individual sequences represent work trajectories, completed by former school's graduates via a WEB questionnaire.
Using argument "sortv", I'd like to sort my sequences according to the order of the levels of one covariate, the year of graduation, named "PROMO".
"PROMO" is a factor variable contained in a data frame named "covariates.seq", gathering covariates together:
str(covariates.seq)
'data.frame': 733 obs. of 6 variables:
$ ID_SQ : Factor w/ 733 levels "1","2","3","5",..: 1 2 3 4 5 6
7 8 9 10 ...
$ SEXE : Factor w/ 2 levels "Féminin","Masculin": 1 1 1 1 2 1
1 2 2 1 ...
$ PROMO : Factor w/ 6 levels "1997","1998",..: 1 2 2 4 4 3 2 2
2 2 ...
$ DEPARTEMENT : Factor w/ 10 levels "BC","GCU","GE",..: 1 4 7 8 7 9
9 7 7 4 ...
$ NIVEAU_ADMISSION: Factor w/ 2 levels "En Premier Cycle",..: NA 1 1 1 1
1 NA 1 1 1 ...
$ FILIERE_SECTION : Factor w/ 4 levels "Cursus Classique",..: NA 4 2 NA
1 1 NA NA 4 3 ..
I'm also using "SEXE", the graduates' gender, as a grouping variable. To plot the individual sequences so, my command is as follows:
seqIplot(sequences, group = covariates.seq$SEXE,
sortv = covariates.seq$PROMO,
cex.axis = 0.7, cex.legend = 0.7)
I expected that, by using a process time axis (with the year of graduation as sequence-dependent origin), sorting the sequences according to the order of the levels of "PROMO" would give a plot with groups of sequences from the longest (for the older graduates) to the shortest (for the younger graduates).
But I've got an issue: in the output plot, the sequences don't appear to be correctly sorted according to the levels of "PROMO". Indeed, by using "sortv = covariates.seq$PROMO" as in the command above, the plot doesn't show groups of sequences from the longest to the shortest, as expected. It looks like the plot obtained without using the argument "sortv" (see Figures below).
Without using argument "sortv"
Using "sortv = covariates.seq$PROMO"
Note that I have 733 individual sequences in my object "sequences", created as follows:
labs <- c("En poste","Au chômage (d'au moins 6 mois)", "Autre situation
(d'au moins 6 mois)","En poursuite d'études (thèse ou hors
thèse)", "En reprise d'études / formation (d'au moins 6 mois)")
codes <- c("En poste", "Au chômage", "Autre situation", "En poursuite
d'études", "En reprise d'études / formation")
sequences <- seqdef(situations, alphabet = labs, states = codes, left =
NA, right = "DEL", missing = NA,
cnames = as.character(seq(0,7400/365,1/365)),
xtstep = 365)
The values of the covariates are sorted in the same order as the individual sequences. The covariate "PROMO" doesn't contain any missing value.
Something's going wrong, but what?
Thank you in advance for your help,
Best,
Arnaud.
Using a factor as sortv argument in seqIplot works fine as illustrated by the example below:
sdc <- c("aabbccdd","bbbccc","aaaddd","abcabcab")
sd <- seqdecomp(sdc, sep="")
seq <- seqdef(sd)
fac <- factor(c("2000","2001","2001","2000"))
par(mfrow=c(1,3))
seqIplot(seq, with.legend=FALSE)
seqIplot(seq, sortv=fac, with.legend=FALSE)
seqlegend(seq)

how do I select an atom using pymol?

I'm not sure if this is the right web page to ask...
I have a xyz file I have generated:
C 0 0 0
O 0 0 0.1
O 0 0 0.2
C 0 0 0.6
O 0 0 0.5
O 0 0 0.4
.
.
.
How can I select a specific atom in command line or measure the distance between two atoms (pymol)?
pymol select command is described in detail here:
http://www.pymolwiki.org/index.php/Property_Selectors
In your case, to select certain atom(s), you can use:
select C_atoms, name C # select all C atoms and name the selection C_atoms
select atom_4, id 4 # select the 4th atom in the file and name it atom_4
select idx_4, index 4 #
select rank_4, rank 4 #
as for the difference between rank, ID, index for atoms, see
http://www.mail-archive.com/pymol-users#lists.sourceforge.net/msg08503.html
I have sent an email to the pymol email-list. I need to find the ID of the atom/molecule I want (I'm sure there is a better way but I have used the gui interface) and then:
select id <num>
or
distance id<num>, id<num>
to measure distance