I have two collections users and clients. I want to use join between this two collections. Use hasMany relations. My eloquent query as follows
$user_list = User::with('clientMaster')
->where('client_status', '=', 1)
->get()
->toArray()
User Model
public function clientMaster()
{
return $this->hasMany('App\Client', '_id', 'client_name');
}
Now, when I print $user_list output as below. This output comes from users collection
(
[0] => Array
(
[_id] => 5788bbe97ffbe04a467634e1
[name] => Abc Pqr
[email] => abc.pqr#xyz.in
[client_id] => 57876dcdc83aa906e81371f4
[client_master] => Array
(
)
)
)
Now I want use join between client and user for fetcing client name on behalf of client._id = users.client_id. I don't know how to use join in laravel eloquent. Please suggest me.
Related
I'm trying to get all accounts that do not have an associated document.
This is what I have in mind:
$parameters = array(
'session' => $this->getSessionId(),
'module_name' => 'Accounts',
'query' => "accounts.id NOT IN (SELECT DISTINCT account_id FROM documents_accounts)",
);
but of course it doesn't work. I get an "Access denied" error (40).
Ideally I'd like to filter even further by querying for accounts that do not have an attached document of a given type. For example:
getAccountsWithout('contracts');
getAccountsWithout('quote1');
...
It could be that your are not correctly authenticating with the REST API. Or that your are not correctly provide what the method call needs.
If that is not the issue. One solution is to create a customer version the service/v4_1. So that you can add your own custom call.
This can be achieved by copying the v4_1 directory giving it a name like v4_1_1.
Rename the following:
SugarWebServiceImplv4_1.php to SugarWebServiceImplv4_1_1.php
SugarWebServiceUtilv4_1.php to SugarWebServiceImplv4_1_1.php
Change the class signatures to this:
SugarWebServiceImplv4_1:
class SugarWebServiceImplv4_1_1 extends SugarWebServiceImplv4_1
SugarWebServiceImplv4_1:
class SugarWebServiceUtilv4_1_1 extends SugarWebServiceUtilv4_1
Change the require/include paths in:
registry.php rest.php
soap.php
SugarWebServiceImplv4_1_1.php
SugarWebServiceImplv4_1_1.php
so that they now point to the 4_1_1 directory.
Implement a method in SugarWebServiceImplv4_1_1.php.
function get_without_documents($session, $module_name = 'accounts', $start = 1, $offset = 20) {
$output_list = array();
$db = DBManagerFactory::getInstance();
// just for example
$sql_query = "SELECT a.id FROM accounts a WHERE a.id NOT IN (SELECT DISTINCT account_id FROM documents_accounts)";
$result = $db->limitQuery($sql_query, $start, $offset,false);
while(($row = $db->fetchByAssoc($result)) != null){
$output_list[] = $row['id'];
}
return array(
'result_count'=> count($output_list),
'next_offset' => $offset + $start,
'entry_list' => $output_list,
);
}
Finally register the method and it the types in registry.php and the reference the url so that it uses v4_1_1.
Data stored in collection as below
[field_1] => Array
(
[fields] => Array
(
[0] => MongoInt64 Object
(
[value] => 1233
)
[1] => MongoInt64 Object
(
[value] => 1234
)
)
)
I need to search 1234 in field.
I used below code in php to search
$param = array('field_1.fields.$' => 1234);
But this is not working
You need to use the $in query criteria, to find elements within an array
$cursor = $collection->find(array("field_1.fields" => array('$in' => array("1234"))));
This will find all items that have 1234 within "fields"
$in doc: https://docs.mongodb.org/v3.0/reference/operator/query/in/
hi i have aproblem in my code, I want generate a list of user but this have a group and need just a group of user.
the error say:
Error: SQLSTATE[42P01]: Undefined table: 7 ERROR: missing FROM-clause entry for table "Grupo"
this is my code:
public function add()
{
$this->loadModel('SoyaProveedor');
$this->loadModel('Soya');
$this->set('oleaginosas', $this->Soya->find('list', array(
'fields'=> array('id','username'),
'conditions' => array('Grupo.categoria' => 'Soya' , 'Grupo.subcategoria' => 'Productor de Oleaginosas')
)));
if ($this->request->is('post')) {
$this->request->data['SoyaProveedor']['nombre'] = strtoupper($this->request->data['SoyaProveedor']['nombre']);
$this->request->data['SoyaProveedor']['codigo'] = strtoupper($this->request->data['SoyaProveedor']['codigo']);
if ($this->SoyaProveedor->save($this->request->data)) {
$this->Session->setFlash(__('La Información fue Guardada.'));
return $this->redirect(array('action' => 'index'));
}
}
}
the sql query of the cake generate it:
SQL Query: SELECT "Soya"."id" AS "Soya__id", "Soya"."username" AS
"Soya__username" FROM "public"."users" AS "Soya" WHERE
"Grupo"."categoria" = 'Soya' AND "Grupo"."subcategoria" = 'Productor
de Oleaginosas'
You need the grupos table to be joined in the query, your query in the question has no joins. There are a number of simple solutions.
Define recursive.
Recursive is a very coarse control of what joins and queries are executed, by default find('list') has a recursive value of -1.
-1 means no joins, which is why there is no join in the resultant query. Setting it to a value of 0 adds a join to the main query for all hasOne and belongsTo associations.
Be wary of using/relying on recursive as it's very easy to generate queries with joins you don't need - and/or triggering many subsequent queries for related data (if set to a value larger than 0).
However this find call:
$data = $this->Soya->find('list', array(
'fields'=> array('Soya.id','Soya.username'),
'recursive' => 0, // added
'conditions' => array(
'Grupo.categoria' => 'Soya' ,
'Grupo.subcategoria' => 'Productor de Oleaginosas'
)
));
Should result in this query (If the Soya model has a belongsTo association to Grupo):
SELECT
"Soya"."id" AS "Soya__id",
"Soya"."username" AS "Soya__username"
FROM
"public"."users" as "Soya"
LEFT JOIN
"public"."Grupos" as "Grupo" on ("Soya"."grupo_id" = "Grupo"."id")
...
Possibly more joins
...
WHERE
"Grupo"."categoria" = 'Soya'
AND
"Grupo"."subcategoria" = 'Productor de Oleaginosas'
Or Use containable
The containable behavior allows better control of what queries are executed. Given the info in the question to use it that means:
<?php
class Soya extends AppModel {
// Assumed from information in the question
public $useTable = 'users';
public $belongsTo = array('Grupo');
// added
public $actsAs = array('Containable');
}
Will permit you to do the following in your controller:
$data = $this->Soya->find('list', array(
'fields'=> array('Soya.id','Soya.username'),
'contain' => array('Grupo'), // added
'conditions' => array(
'Grupo.categoria' => 'Soya' ,
'Grupo.subcategoria' => 'Productor de Oleaginosas'
)
));
Which will generate the following query (exactly one join):
SELECT
"Soya"."id" AS "Soya__id",
"Soya"."username" AS "Soya__username"
FROM
"public"."users" as "Soya"
LEFT JOIN
"public"."Grupos" as "Grupo" on ("Soya"."grupo_id" = "Grupo"."id")
WHERE
"Grupo"."categoria" = 'Soya'
AND
"Grupo"."subcategoria" = 'Productor de Oleaginosas'
Link your models together using associations: CakePHP Associations
Alternatively you can use custom sql-statemens using join e.g.:
$db = $this->getDataSource();
$result = $db->fetchAll(
"SELECT Soya.id AS Soya__id, Soya.username AS Soya__username FROM public.users AS Soya
join Grupo on Grupo.id = Soya.groupo_id
WHERE Grupo.categoria = ? AND Grupo.subcategoria = ?",
array('Soya', 'Productor de Oleaginosas')
);
$this->set('oleaginosas', $result);
I've got a problem. I'm trying to left join two tables with Zend Framework using $select object. Unfortunatly my tables has common field 'name' and when I'm joining one with the other the results I get is that name field from table overwrites the name field from the other.
My code is something like that:
$select->joinLeft ( array ('users' => 'users' ), $this->_name . '.employee_id = users.user_id', array ('*' ) );
How I can join tables and avoid this issue?
Use table aliases as you would in any normal sql query!
With Zend_Db aliases are written like this:
$select = $db->select()
->from(array('p' => 'products'),
array('product_id', 'product_name'))
->join(array('l' => 'line_items'),
'p.product_id = l.product_id',
array() ); // empty list of columns
The non-zend query would look like this:
SELECT p.product_id, p.product_name
FROM products AS p
JOIN line_items AS l ON p.product_id = l.product_id;
I guess it's bit late but to get all fields from two tables you must alias all the fields
$select = $db->select()
->from(array('u' => 'users'),
array('u.id'=>'u.id','u.employee_id'=>'u.employee_id','u.name'=>'u.name'))
->joinLeft(array('e' => 'employees'),
'e.id = u.employee_id',
array('e.id'=>'e.id','e.name'=>'e.name') );
And your array would look like:
array(
0=>array(
'u.id'=>'1',
'u.employee_id'=>'1',
'u.name'=>'John Doe',
'e.id'=>'1',
'e.name'=>'Worker'
),
1=>array(
...
));
I'm testing Zen_DB and Zend_DB_Table and I'm facing a problem:
Let's say I've got two tables
table A(id, title)
table B(id, title)
If I write something like
$db = $this->getDbTable()->getAdapter();
$query = "SELECT A.*, B.* FROM A INNER JOIN B on A.id = B.id"
$stmt = $db->query($query);
$rows = $stmt->fetchAll();
each resulting row is like ['id' => value, 'title' => value]
Question: How can the fetched rows be like ['A.id' => value, 'A.title' => value', 'B.id' => value, 'B.title' => value'] ?
Important: I don't want to modify the database schema
Your question was answered by this question