How to run protractor with different config file in sequence? - protractor

Question

I have different configuration file for protractor, and I would like to create a gulp task which run protractor for each config file in sequence.
Here is my actual code:
gulp.src('conf/protractor.conf.*.js')
.pipe($.debug())
.pipe($.foreach(function(stream, file){
var configFileName = path.join('conf/', path.basename(file.path));
console.log(configFileName);
gulp.src(path.join(conf.paths.e2e, '/**/*.js'))
.pipe($.protractor.protractor({
configFile: configFileName,
args: args
}))
.on('error', function (err) {
// Make sure failed tests cause gulp to exit non-zero
console.log('Error catch by gulp');
throw err;
})
.on('end', function () {
// Close browser sync server
browserSync.exit();
done();
return stream;
});
}));
it run protractor only with the first configuration file and then stop, even if the different conf file were listed by foreach.
Does anyone has an idea of what I am missing?
Thanks

Answer 1

I found a workaround: instead of trying to use gulp only to do what I want to do, I created a little shell script.
Now, my gulp task take protractor config file path from command line argument like that:
var argv = require('minimist')(process.argv.slice(2));
if (!argv.conf || typeof argv.conf !== 'string' ) throw new Error('protractor configuration file path required');
function runProtractor (done) {
gulp.src(path.join(conf.paths.e2e, '/**/*.js'))
.pipe($.protractor.protractor({
configFile: argv.conf
}))
.on('error', function (err) {
// Make sure failed tests cause gulp to exit non-zero
throw err;
})
.on('end', function () {
// Close browser sync server
browserSync.exit();
done();
});
}
gulp.task('protractor', ['protractor:src']);
gulp.task('protractor:src', ['serve:e2e', 'webdriver-update'], runProtractor);
And I use a shell script to parse my folder and call gulp protractor for each configuration file:
#!/usr/bin/env bash
for filename in conf/protractor.conf.*.js; do
gulp protractor --conf=$filename
done
It works like a charm.