Validate year with current year using Lombok - spring-data-jpa

In my application, I have a field name 'year' contains only year(2016, 2015 .....). But I have to validate this 'year' field, this field should contain current year.
I check all the Lombok validation annotations, but I did not find any annotation help to me. How can I achieve this?

I think there aren't lombok validation constraint annotations. If there are I didn't know.
I assume your field is a Integer. So, I suggest you next solutions:
Solution 1 - java bean validation constraint Annotations
You could add a method which start by 'is'like next and add java validation constraint #assertTrue
private int year;
#AssertTrue
public boolean isCurrentYear(){
return LocalDate.now().getYear() == year;
}
Solution 2 - Programmatically
Create a method to protect your constructor, setter or both checking if the year integer is the current year:
private int year;
//Constructor
public YourClass(int year){
checkCurrentYear(year);
this.year = year;
}
//Setter
public void setYear(int year){
checkCurrentYear(year);
this.year= year;
}
public void checkCurrentYear(int year){
if(!isCurrentYear()) // or (LocalDate.now().getYear() != year)
throw new IllegalArgumentException("Year must be the current");
}
Solution 3 - Implement your Spring Validator
Implement spring validator interface and use it when you want:
public class YourClass implements Validator {
public boolean supports(Class clazz) {
return YourClass.class.equals(clazz);
}
public void validate(Object obj, Errors e) {
YourClass p = (YourClass) obj;
if (LocalDate.now().getYear() != p.getYear()) {
e.rejectValue("year", "notcurrentyear");
}
}
}

Related

Openpojo businessException when reference to other pojo

I'm trying to test pojo classess using openpojo but i have the same error like there. I don't understand that solution so I'll ask again. What should I do to proper using #BusinessKey.
My classes:
public class Person {
#BusinessKey
private Integer id;
...getters/setters
#Override
public boolean equals(Object obj) {
return BusinessIdentity.areEqual(this, obj);
}
#Override
public int hashCode() {
return BusinessIdentity.getHashCode(this);
}
}
public class Employee {
#BusinessKey
private Integer id;
private Person person;
...getters/setters
#Override
public boolean equals(Object obj) {
return BusinessIdentity.areEqual(this, obj);
}
#Override
public int hashCode() {
return BusinessIdentity.getHashCode(this);
}
}
The #BusinessKey annotation is designed to be thrown on your business keys, not your generated database ids.
So to annotate the fields, you have ask the business, what makes a person a person? how can two "Person" objects be determined to be the same? This should be done in the context of the business and how it identifies what makes a person a person.
In the example above, for Employee I am guessing you can't have a valid Employee object without it being linked to a person, so the #BusinessKey needs to be on person (plus other important fields).
Hope this helps.

How to use hidden field to store data model in wicket

I have a entity, name Product.It have two property is unit (byte) and unitName(String). unit property is mapped on database. Ex: 0:Kg ; 1:g;.... I want when input a valid unit, unit property is stored; unless, it save to unitName
Product
public class Product implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "product_id")
private int productId;
#Column(name = "product_name")
private String productName;
#Column(name = "unit")
private Byte unit;
#Transient
private String unitName;
}
In unit text field, I use a UnitConvert
UnitConvert
public class UnitConverter implements IConverter<Byte> {
private static final long serialVersionUID = 4798262219257031818L;
public UnitConverter() {
}
#Override
public Byte convertToObject(String value, Locale locale) {
return Text.isEmpty(value) ? 0 : UtilCommon.getTaniCode(value);
}
#Override
public String convertToString(Byte value, Locale locale) {
return (value == null || value==0 ) ? "" : UtilCommon.getTaniName(value);
}
}
I only think about HiddenField to do that, but I don't know how to do that.
Someone know how to use or anything can help me. Thank you very much
So from what I understood you want to save the input of a Model to a different database property depending on certain checks before hand. You can do that in your Form.onSubmit() method.
A very simple implementation could look like this:
public ProductPanel(String id, final IModel<Object> productModel) {
super(id, productModel);
// we're putting the productModel into the constructor.
// Therefore it's guaranteed to be detached
// -> it's okay to have it with final modifier.
IModel<String> formModel = Model.of("");
Form<String> form = new Form<String>("form", formModel) {
#Override
protected void onSubmit() {
super.onSubmit();
String productName = getModelObject();
Object realProduct = productModel.getObject();
if (isAcceptableUnit(productName)) {
realProduct.setUnit(parseUnit(productName));
} else {
realProduct.setUnitName(productName);
}
layer.saveProduct();
}
};
add(form);
TextField<String> productName = new TextField<String>("textField", formModel);
form.add(productName);
}
private boolean isAcceptableUnit(String productName) {
// your logic to determine if it's okay to cast to byte here...
return true;
}
private byte parseUnit(String productName) {
// your logic to parse the String to byte here...
return 0;
}
Some additional comments since I'm uncertain if the code snippets you provided are just for simplicity or actually code pieces:
You should try to avoid declaring your db object Serializable. Should you use normal Model objects to save your DTOs wicket will actually serialize them and you won't be able to do anything with them (well with hibernate at least).
Database object should use LoadableDetachableModel and save the primary key to load the entity in the load() method of it.
This would enable you now to work directly on those objects by using CompoundPropertyModel etc (which has it's pros and cons which I will not explain in detail here).
Still in your case I would add an Model<String> to the form and let the server decide how the input should be handled and mapped to the actual domain object.

Disadvantages of interface objected programming

class Person{
private String name;
private int age;
private String gender;
//......
}
class Student extends Person{
private String id;
private String schoolBelongTo;
//......
}
public void showInfoOf(Person person){
System.out.println(person.getName());
//......
}
When using function "showInfoOf" ,if an object of Peron is used as the param,OK.However,if it is the type Student,I cannot get access to the field id and schoolBelongTo.
So I am confused ,how to ?
Actually, I want to know is this one of its(Interface oriented programming's or Supper class oriented programming's) disadvantages???
Two possible solutions:
You can programatically check the type in showInfoOf (Person), and use a cast to access & print the desired fields; or,
You can define a method on Person which will print/provide the desired info -- and either replace showPersonInfo() with that entirely, or call it into it. This is the more OO way.
Example:
abstract class Person {
private String name;
private int age;
private String gender;
public void printInfo() {
System.out.println( name);
}
}
class Student extends Person{
private String id;
private String schoolBelongTo;
#Override
public void printInfo() {
super.printInfo();
System.out.println( id);
System.out.println( schoolBelongTo);
}
}
public void showInfoOf (Person person){
person.printInfo();
}
In this example, all functionality has moved to Person.printInfo() and there is no real functionality remaining in showInfoOf (Person).
However in the real-world, you'd probably want move versatility in a Person.provideInfo() function -- perhaps returning a LinkedHashMap of fields & values (since unlabelled values on their own, are not great design).
The showInfoOf (Person) function could then handle formatting & printing the values to the specific requirement, leaving the Person.provideInfo() function general & multi-purpose.
in showInfoOf() you would have to check that person is of type Student, then cast it as a Student to get id or schoolBelongsTo

JPA composite PK is not working with 'finder' in play framework

I have a model called 'UserRoleHolder' like below.
#Entity
public class UserRoleHolder extends Model implements RoleHolder {
private static final long serialVersionUID = 1L;
#EmbeddedId
public UserRoleHolderPK userRoleHolderPK;
public List<UserPermission> permissions;
public List<UserRole> roles;
....
I made a composite PK called UserRoleHolderPK and it contains two foreign keys like below.
#Embeddable
public class UserRoleHolderPK {
#Basic
public Long userId;
#Basic
public Long projectId;
public UserRoleHolderPK(Long userId, Long projectId) {
this.userId = userId;
this.projectId = projectId;
}
public boolean equals(Object object) {
if (object instanceof UserRoleHolderPK) {
UserRoleHolderPK userRoleHolderPK = (UserRoleHolderPK) object;
return userId == userRoleHolderPK.userId && projectId == userRoleHolderPK.projectId;
} else {
return false;
}
}
public int hashCode() {
return (int) (userId + projectId);
}
}
userId and projectId are from other Models. (User.java and Project.java)
Then, in 'UserRoleHolder' class, I made a method called 'findRolesById' like below.
public static List<? extends Role> findRolesById(Long userId, Long projectId) {
return find
.where()
.eq("userRoleHolderPK", new UserRoleHolderPK(userId, projectId))
.findUnique().roles;
}
However, when I tried to run a test code like below, I encountered serious errors.
#Test
public void findRolesById() {
// Given
// When
#SuppressWarnings("unchecked")
List<UserRole> list = (List<UserRole>) UserRoleHolder.findRolesById(1l, 1l);
// Then
assertThat(list.get(0).name).isEqualTo("manager");
}
Errors are like,
'Syntax error in SQL statement "SELECT T0.USER_ID C0, T0.PROJECT_ID C1 FROM USER_ROLE_HOLDER T0 WHERE T0.NULL[*] = ? "; expected "identifier"; SQL statement: select t0.user_id c0, t0.project_id c1 from user_role_holder t0 where t0.null = ? [42001-158]
Bind values:[null]
Query was:
select t0.user_id c0, t0.project_id c1 from user_role_holder t0 where t0.null = ?
I think I missed some serious and basic stuff when I used JPA. Please, let me know what is the problem.
I think your problem is that you are trying to compare the Embeddedid object and not its fields, I don't think that the program will be smart enough as to know how to convert an user object comparison (the equals) to sql, so you might want to try something like this:
public static List<? extends Role> findRolesById(Long userId, Long projectId) {
return find
.where()
.eq("userRoleHolderPK.userId", userId)
.eq("userRoleHolderPK.projectId", projectId)
.findUnique().roles;
}

Wicket - DropDownChoice from Enum to Primitive

Im having some problem with DropDownChoice.
I have an Enum with a list of school title like:
public enum StudyTitle {
NONE(null,null),ELEMENTARY("1","Elementary"),COLLEGE("2","College");
private String code;
private String description;
private StudyTitle(String code, String description){
setCode(code);
setDescription(description);
}
[setter and getter]
}
Then I have a Pojo with a String proprerty call "studyTitleCode" where I want to put the code (ex 1 for elementary, 2 for college etc...).
When I create a DropDownChoice Wicket doesn't allow me to have a proprerty Model of type String if the DropDownChoice is of type StudyTitle.
Ex.
[building the listOfStudyTitle as ArrayList of Enums]
DropDownChoice<String> studyLevel = new DropDownChoice<String>("id",new PropertyModel<String>(myPojo,"studyTitleCode"),listOfStudyTitle,new ChoiceRenderer<StudyTitle>("description","code"));
Is there a Method to allow Wicket to link one property of the Enum to the Property of Model?
Thanks
The choice options for an AbstractSingleSelectChoice must match the type of the value model. The only related config option for the DropDownChoice that I'm aware of is the IChoiceRenderer which allows you to set how the enum value is rendered (vs the default call toString()).
One option would be, instead of using the enum instance itself for your choices model, give the enum a String property that can be used:
public enum TestEnum {
ONE ("ONE"),
TWO ("TWO"),
THREE ("THREE");
private String value;
TestEnum(String value) {
this.value = value;
}
public String getValue() {
return value;
}
public static List<String> getStringValues()
{
List<String> stringValues = new ArrayList<String>();
for (TestEnum test : values()) {
stringValues.add(test.getValue());
}
return stringValues;
}
}
#Override
protected void onInitialize() {
super.onInitialize();
IModel<String> myStringValueModel = new Model<String>();
add(new DropDownChoice<String>("id", myStringValueModel, TestEnum.getStringValues()));
}