I have a number of files that look like this:
imgDATA_subj001_log000_sess001_at.img
imgDATA_subj001_log000_sess001_cn.img
imgDATA_subj001_log000_sess001_cx.img
imgDATA_subj001_log000_sess002_at.img
imgDATA_subj001_log000_sess002_cn.img
imgDATA_subj001_log000_sess002_cx.img
imgDATA_subj002_log000_sess001_at.img
...
I want to rename a specific numeric part of the file name after subj . For instance, subj001, subj002, subj003, etc. would be renamed to subj014, subj027,subj65, etc. but preserve the rest of the file name. I have the list of new names but not sure how to look for old names and match with the new names then do the renaming. I tried using loops and fileparts but I don't know how to isolate the subj*** component. I could do move but that would be very inefficient. Can anyone help?
If you know the portions of the filename that you want to replace specifically, ie you know that subj001 = subj014 then what you should do is use a dir command to get the list of files in the existing directory.
This will give you a list of the files,
f=dir(imgData*.img)
for somecounter=1:length(f)
filename=f(somecounter).name
newname=strrep(filename,'subj001','subj014')
movefile(filename,newname)
end
Obviously you'll want to setup an array of each of the individual names to match up and iterate through that.
Related
I have a list of files in a adls container which contain date in the name as given below:
TestFile-Name-20221120. csv
TestFile-Name-20221119. csv
TestFile-Name-20221118. csv
and i want to copy files which contain today date only like TestFile-Name-20221120. csv on today and so on.
I've used get metedata activity to get list of files and then for each to iterate over each file and then used set variable to extract name from the file like 20221120 but not sure how to proceed further.
We have something similar running. We check an SFTP folder for the existanc e of files, using the Get Metadata activity. In our case, there can be folders or files. We only want to process files, and very specific ones for that matter (I.e. we have 1 pipeline per filename we can process, as the different filenames would contain different columns/datatypes etc).
Our pipeline looks like this:
Within our Get Metadata component, we basically just filter for the name of the object we want, and we only want files ending in .zip, meaning we added a Filename filter:
:
In your case, the first part would be 'TestFile-Name-', and the second part would be *.csv'.
We then have a For Each loop set up, to process anything (the child items) we retrieved in the Get Metadata step. Within the For Each we defined an If Condition to only process files, and not folders.
In our cases, we use the following expression:
#equals(item().type, 'File')
In your case, you could use something like:
#endsWith(item().name, concat(<variable containing your date>, '.csv'))
Assuming all the file names start with TestFile-Name-,
and you want to copy the data of file with todays date,
use get metadata activity to check if the file exists and the file name can be dynamic like
#concat('TestFile-Name-',utcnow(),'.csv')
Note: you need to fromat utcnow as per the needed format
and if file exists, then proceed for copy else ignore
I plan to list all the file names of a current folder (include subfolder) and put them and their path into an array. I can use s=dir to put the names and path of all the files in the current folder, I can also use "dir **/." to show the files in the current folder and subfolders.
But when I use "s=dir **/.", Matlab gives me error and I am not able to proceed. Is there anyone can help me on this？
The reason why I want to do this is to compare two folders which may contain plenty of duplicate files. I want to use file name as the indicator and to find out the new adding or removed files, so that I can update the log excel we have.
Thank you for your help.
To list only the files and not the directories try
file_names = dir('**/');
file_names = file_names(~[file_names.isdir]);
file_names = {file_names.name}
You were really close, you can just run:
s = dir('**\');
And that should get you what you need
I use this code to see existed files in a specific folder from FTP :
ftp_client = ftp('IP','Username','Password');
aa = dir(ftp_client,'First_folder/Second_folder');
I can see file names with these codes :
aa(1,1).name
aa(2,1).name
aa(3,1).name
How can I see all files names in a cell aray in this specific folder? Is there any command for it?
How can I count number of existed files in this folder?
How can I count number of existed files in this folder with a specific format?
Thanks.
A simple way is to collect the values into the cell array by using curly brackets: filenames = {aa.name};
The simplest method would be length(aa); or length(filenames);
A couple ways. You can either refine your dir call, aa = dir(ftp_client,'First_folder/Second_folder/*.jpeg') for example, or use your own filter (regexp is one option) on your filenames to return the indices of what you want.
As a general aside, if you're utilizing this program on different operating systems, I would recommend utilizing fullfile (or filesep at the very least) to build your full pathnames to ensure the right separator is used. Though I didn't do it in my example above...
I want to create a script i Matlab where all the individual objects are linked to a variable.
It would look like this:
M1 = xlsread('BonBon.xls');
M2 = xlsread('Bornfyn.xls');
Thing is i have about 300 .xls files i have to assign.
Is there a way of telling Matlab to get all the individual files in a specific folder (/subfolder) and assign them to a name? (Mx)
I have tried to use dir function but i cannot solve how i should define the folders.
Getting all file names at a given folder name
thereby i have tried http://www.mathworks.com/matlabcentral/newsreader/view_thread/273916
But that is even more complicated to figure out how i should costumize that script. (besides adding .xls to the list of filetypes).
Sincerely
I have several .csv files with similar filenames except a numeric month (i.e. 03_data.csv, 04_data.csv, 05_data.csv, etc.) that I'd like to read into R.
I have two questions:
Is there a function in R similar to
MATLAB's varname and assignin that
will let me create/declare a variable name
within a function or loop that will allow me to
read the respective .csv file - i.e.
03_data.csv into 03_data data.frame,
etc.? I want to write a quick loop to
do this because the filenames are
similar.
As an alternative, is it better to
create one dataframe with the first
file and then append the rest using a
for loop? How would I do that?
You could look at this related question. You can create the file names easily with a paste command:
file.names <- paste(sprintf("%02d",1:10), "_data.csv", sep="")
Once you have your file names (whether by creating them or by reading them from the directory as in the other question), you can import them quickly with an lapply:
import.list <- lapply(file.names, read.csv)
Lastly, to combine the list into one dataframe, the easiest approach is to use the reshape function below:
library(reshape)
data <- merge_recurse(import.list)
It is also very easy to read the content of a directory including use of regular expressions to skip focus on certain names only, e.g.
filestoread <- list.files(someDir, pattern="\\.csv$", full.names=TRUE)
returns all (fully-formed, including full path) files in the given directory someDir that end on ".csv". You can get fancier with better regular expressions which are documented in many places.
Once you have your list of files, it is straightforward to read them all using apply or lapply or a loop.