I am using namedquery for rest api using Spring JPA. The named query is implemented in my entity class:
#Entity
#Table(name="SPECIMEN_TB")
#NamedQueries({
#NamedQuery(name="SpecimenTb.findBySpecimenNo", query="select s from SpecimenTb s where s.specimenNo = :specimenNo"),
})
public class SpecimenTb implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy=GenerationType.SEQUENCE, generator="SPECIMEN_TB_ROWID_GENERATOR")
#Column(name="ROW_ID")
private long rowId;
#Column(name="SPECIMEN_NO", unique = true)
private String specimenNo;
My controller looks like this:
#RestController
public class RistoreController {
#Autowired
private RistoreService ristoreService;
#RequestMapping(
value = "/ristore/foundation/{specno}",
method = RequestMethod.GET,
produces = "application/json")
public ResponseEntity<SpecimenTb> getFmSpecimen(#PathVariable("specno") String specno) {
List<SpecimenTb> specimens = ristoreService.findBySpecimenNo(specno);
if (specimens == null) {
return new ResponseEntity<SpecimenTb>(HttpStatus.NOT_FOUND);
}
return new ResponseEntity<SpecimenTb>(specimens.get(0), HttpStatus.OK);
}
I have a service bean which calls JPA repository findBySpecimenNo method.
#Service
public class RistoreServiceBean implements RistoreService {
#Autowired
private SpecimenRepository specimenRepository;
#Override
public List<SpecimenTb> findAll() {
List<SpecimenTb> specimens = specimenRepository.findAll();
return specimens;
}
#Override
public List<SpecimenTb> findBySpecimenNo(String specimenNo) {
List<SpecimenTb> specimens = specimenRepository.findBySpecimenNo(specimenNo);
return specimens;
}
When I start the Spring Boot Application and type in the url "http://localhost:8080/ristore/foundation/SKM1", I got the following error:
java.lang.IllegalArgumentException: Parameter with that position [1] did not exist
What did I do wrong?
Looks like you can't use a named parameter with the #NamedQuery based on the docs I read. Have you tried with ?1 instead?
Reason that named parameter doesn't work is that you also have to add the annotation on the method parameter so Spring knows which parameter matches to what placeholder in the query.
Related
I connected my Spring-Boot-Application to a MongoDB. The application is nothing serious, just for getting into working with spring and MongoDB.
The problem it, that my id is a String and I get an Internal Server Error, when I pass the id of a database entry, in order to get it byId...
This is my domain class:
#Data
#NoArgsConstructor
#AllArgsConstructor
#Builder
#Document(collection = "songinfo")
public class SongInfo {
#Id
private String id;
private int songId;
private String songName;
private String description;
}
The Controller-Method:
#RequiredArgsConstructor
#RestController
#RequestMapping("/songsinfo")
public class SongsInfoController {
private final SongInfoService songInfoService;
#GetMapping(value = "/{id}", headers = "Accept=application/json", produces =
{MediaType.APPLICATION_JSON_VALUE})
public ResponseEntity<SongInfo> getSongInfoById(#PathVariable(value = "id") String id) {
SongInfo songInfo = songInfoService.getSongInfoById(id);
if (songInfo == null)
return new ResponseEntity<>(HttpStatus.NOT_FOUND);
return new ResponseEntity<>(songInfo, HttpStatus.OK);
}
The SongInfoServiceImpl:*
#Override
public SongInfo getSongInfoById(String id) {
return songInfoRepository.findById(id).orElseThrow(NotFoundException::new);
}
This is the SongsInfoRepository:
public interface SongInfoRepository extends MongoRepository<SongInfo, String> {
}
Getting all songinfos from the database is working fine:
But when is pass the id from one of these entries, I get this:
What is wrong here with my implementation?
You're throwing the exception in SongInfoServiceImpl which is not handled in your SongsInfoController Class.
Solution 1: Instead of throwing the exception return null.
SongInfoServiceImpl.java
#Override
public SongInfo getSongInfoById(String id) {
return songInfoRepository.findById(id).orElse(null);
}
Solution 2: Add try catch block
SongsInfoController.java
#RequiredArgsConstructor
#RestController
#RequestMapping("/songsinfo")
public class SongsInfoController {
private final SongInfoService songInfoService;
#GetMapping(value = "/{id}",
headers = "Accept=application/json",
produces = {MediaType.APPLICATION_JSON_VALUE}
)
public ResponseEntity<SongInfo> getSongInfoById(#PathVariable(value = "id") String id) {
SongInfo songInfo = null;
try {
songInfo = songInfoService.getSongInfoById(id);
} catch(Exception e) {
return new ResponseEntity<>(HttpStatus.NOT_FOUND);
}
return new ResponseEntity<>(songInfo, HttpStatus.OK);
}
}
I think you need to divide two problem.
Check id parameter SongsInfoController
Inside controller check your parameter is valid through log or sysout
Check getSongInfoById method in SongInfoServiceImpl
Simply getSongInfoById(8752); is get error?
I want to add comment but my reputation is under 50.
If you comment above two solution check result, then I will add additional answer.
So I'm new to Spring and I'm basically trying to make a REST service for the first time. Some of the data I'd like to return is some data from a properties file.
This is my configuration bean:
#Configuration
#PropertySource("classpath:client.properties")
public class PropertyConfig {
#Bean
public static PropertySourcesPlaceholderConfigurer
propertySourcesPlaceholderConfigurer() {
return new PropertySourcesPlaceholderConfigurer();
}
}
This is the class containing the info I want to return from the API. When I hover over the values, I can see that the property is being injected.
public class ProviderInfo {
#Value("${op.iss}") private String issuer;
#Value("${op.jwks_uri}") private String jwksURI;
#Value("${op.authz_uri}") private String authzURI;
#Value("${op.token_uri}") private String tokenURI;
#Value("${op.userinfo_uri}") private String userInfoURI;
// Getter methods
}
And this is the RestController
#RestController
public class ProviderInfoController {
#RequestMapping(value = "/provider-info", method = RequestMethod.GET)
public ProviderInfo providerInfo() {
return new ProviderInfo();
}
}
When I navigate to that endpoint, everything is null:
{"issuer":null,"jwksURI":null,"authzURI":null,"tokenURI":null,"userInfoURI":null}
Can anybody see what I'm doing wrong? Or if there is a better way to accomplish this in general?
Thanks!
The processing of the #Value annotations is done by Spring, so you need to get the ProviderInfo instance from Spring for the values to actually be set.
#RestController
public class ProviderInfoController {
#Autowired
private ProviderInfo providerInfo;
#RequestMapping(value = "/provider-info", method = RequestMethod.GET)
public ProviderInfo providerInfo() {
return providerInfo;
}
}
This also requires that Spring picks up and processes the ProviderInfo class.
Also, you need to add the ProviderInfo class to the Spring Bean life cycle using either #Component or #Service as follows:
#Component
public class ProviderInfo {
#Value("${op.iss}") private String issuer;
#Value("${op.jwks_uri}") private String jwksURI;
#Value("${op.authz_uri}") private String authzURI;
#Value("${op.token_uri}") private String tokenURI;
#Value("${op.userinfo_uri}") private String userInfoURI;
// Getter methods
}
Only then, you can use #Autowired inside ProviderInfoController class.
I have following relationship:
#Entity class Shop {
#OneToMany(mappedBy = "shop", fetch = LAZY)
private List<Employee> employees = new LinkedList<>();
}
and
#Entity class Employee {
#ManyToOne
private Shop shop;
}
I've declared Spring Data repository like this:
public interface ShopRepository extends JpaRepository<Shop, Long> {}
Calling ShopRepository#findOne(id) method forces fetching of the List<Employee> employees which is LAZY relationship.
I have service which uses Shop repository:
#Service
#Transactional(readOnly = true)
public class ShopService {
private final ShopRepository shopRepository;
#Autowired
public ShopService(ShopRepository shopRepository) {
this.shopRepository = shopRepository;
}
public Shop find(Long id) {
return shopRepository.findOne(id);
}
}
The service method is called within another controller method:
#RequestMapping(value = "api/schedule/{shopId:[0-9]+}/{date:\\d{4}-\\d{2}-\\d{2}}", method = RequestMethod.GET)
#ResponseBody
public Schedule getSchedule(#PathVariable Long shopId,
#PathVariable #DateTimeFormat(pattern = "yyyy-MM-dd") LocalDate date) {
Schedule schedule = scheduleService.findSchedule(shopId, date);
if(schedule != null)
return schedule;
else {
Shop shop = shopService.find(shopId);
Schedule empty = new Schedule(shop, date);
return empty;
}
}
How to get rid of fetching employees relationship?
I found solution.
Actually I used #JsonManagedReference/#JsonBackRefernce on my entity to prevent cycling while marshaling to JSON. It causes fetching LAZY loading data.
To avoid this you should add Hibernate4Module to MappingJackson2HttpMessageConverter.
More info at this post: Avoid Jackson serialization on non fetched lazy objects
I have entities with joined inheritance:
Supporter
#Entity
#Inheritance(strategy=InheritanceType.JOINED)
#JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY, property = "supporterType")
#JsonSubTypes({
#JsonSubTypes.Type(value = PersonSupporterEntity.class, name = "PERSON"),
#JsonSubTypes.Type(value = CompanySupporterEntity.class, name = "COMPANY")
})
#DiscriminatorColumn(name="supporter_type")
#Table(name = "supporter")
public class SupporterEntity extends UpdatableEntity {
private long id;
private SupporterType supporterType;
private PartnerEntity partner;
...
}
PersonSupporter
#Entity
#DiscriminatorValue("PERSON")
#Table(name = "person_supporter")
public class PersonSupporterEntity extends SupporterEntity {
...
}
CompanySupporter
#Entity
#DiscriminatorValue("COMPANY")
#Table(name = "company_supporter")
public class CompanySupporterEntity extends SupporterEntity {
...
}
I have another entity which references SupporterEntity
#Entity
#Table(name = "contact")
public class ContactEntity extends UpdatableEntity {
private long id;
private SupporterEntity supporter;
...
#ManyToOne // same error with #OneToOne
#JoinColumn(name = "supporter_id", referencedColumnName = "id", nullable = false)
public SupporterEntity getSupporter() {
return supporter;
}
...
}
Repositories
#Transactional
#RepositoryRestResource(collectionResourceRel = "supporters", path = "supporters")
public interface SupporterEntityRepository extends JpaRepository<SupporterEntity, Long> {
#Transactional(readOnly = true)
#RestResource(path = "by-partner", rel = "by-partner")
public Page<SupporterEntity> findByPartnerName(#Param("name") String name, Pageable pageable);
}
#Transactional
#RepositoryRestResource(collectionResourceRel = "person_supporters", path = "person_supporters")
public interface PersonSupporterEntityRepository extends JpaRepository<PersonSupporterEntity, Long> {
}
#Transactional
#RepositoryRestResource(collectionResourceRel = "company_supporters", path = "company_supporters")
public interface CompanySupporterEntityRepository extends JpaRepository<CompanySupporterEntity, Long> {
}
#Transactional
#RepositoryRestResource(collectionResourceRel = "contacts", path = "contacts")
public interface ContactEntityRepository extends JpaRepository<ContactEntity, Long> {
#Transactional(readOnly = true)
#RestResource(path = "by-supporter", rel = "by-supporter")
public ContactEntity findBySupporterId(#Param("id") Long id);
}
I use Spring Boot, Spring Data REST, Spring Data JPA, Hibernate, Jackson. When I try to create a new ContactEntity with a post request like this:
{
"supporter":"/supporters/52",
"postcode":"1111",
"city":"Test City 1",
"address":"Test Address 1",
"email":"test1#email.com",
"newsletter":true
}
I get this exception:
Caused by: com.fasterxml.jackson.databind.JsonMappingException: Unexpected token (VALUE_STRING), expected FIELD_NAME: missing property 'supporterType' that is to contain type id (for class com.facer.domain.supporter.SupporterEntity)
at [Source: HttpInputOverHTTP#4321c221; line: 1, column: 2] (through reference chain: com.facer.domain.supporter.ContactEntity["supporter"])
at com.fasterxml.jackson.databind.JsonMappingException.from(JsonMappingException.java:148) ~[jackson-databind-2.4.4.jar:2.4.4]
After 2 days of debugging I found a way, but I kinda guessed it. So if I post it like this:
{
"supporter":{
"supporterType":"PERSON",
"id":"52"
},
"postcode":"1111",
"city":"Test City 1",
"address":"Test Address 1",
"email":"test1#email.com",
"newsletter":true
}
It works, but I don't know why. What's wrong with the other request? It works like that everywhere else when the referenced entity does not have inheritance.
Just another workaround using a RelProvider:
Do not use #JsonTypeInfo
Create a RelProvider for SupporterEntity sub-classes
#Component
#Order(Ordered.HIGHEST_PRECEDENCE)
public class SupporterEntityRelProvider implements RelProvider {
#Override
public String getCollectionResourceRelFor(final Class<?> type) {
return "supporters";
}
#Override
public String getItemResourceRelFor(final Class<?> type) {
return "supporter";
}
#Override
public boolean supports(final Class<?> delimiter) {
return org.apache.commons.lang3.ClassUtils.isAssignable(delimiter, SupporterEntity.class);
}
}
See also:
https://jira.spring.io/browse/DATAREST-344
http://docs.spring.io/spring-hateoas/docs/current/reference/html/#configuration.at-enable
It looks like a Jackson problem. To be specific, it's the following code in com.fasterxml.jackson.databind.deser.SettableBeanProperty:
if (_valueTypeDeserializer != null) {
return _valueDeserializer.deserializeWithType(jp, ctxt, _valueTypeDeserializer);
}
return _valueDeserializer.deserialize(jp, ctxt);
Without inheritance _valueDeserializer.deserialize would be called which in turn runs some Spring code to convert the URI to a Supporter.
With inheritance _valueDeserializer.deserializeWithType is called and vanilla Jackson, of course, expects an object, not a URI.
If supporter was nullable you could first POST to /contacts and then PUT the supporter's URI to /contacts/xx/supporter. Unfortunately I am not aware of any other solution.
You should be able to workaround this by setting #JsonTypeInfo(use= JsonTypeInfo.Id.NONE) at the property/method level e.g.
Try with this:
#ManyToOne // same error with #OneToOne
#JoinColumn(name = "supporter_id", referencedColumnName = "id", nullable = false)
#JsonTypeInfo(use= JsonTypeInfo.Id.NONE)
public SupporterEntity getSupporter() {
return supporter;
}
I am using Spring Data MongodB 1.4.2.Release version. For Spring Data MongoDB, I have created the custom repository interface and implementation in one location and create custom query function getUsersName(Users users).
However I am still getting below exception:
Caused by: org.springframework.data.mapping.PropertyReferenceException:
No property get found for type Users! at org.springframework.data.mapping.PropertyPath. (PropertyPath.java:75) at
org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:327) at
org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:359) at
org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:359) at
org.springframework.data.mapping.PropertyPath.create(PropertyPath.java:307) at
org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:270) at
org.springframework.data.mapping.PropertyPath.from(PropertyPath.java:241) at
org.springframework.data.repository.query.parser.Part.(Part.java:76) at
org.springframework.data.repository.query.parser.PartTree$OrPart.(PartTree.java:201) at
org.springframework.data.repository.query.parser.PartTree$Predicate.buildTree(PartTree.java:291) at
org.springframework.data.repository.query.parser.PartTree$Predicate.(PartTree.java:271) at
org.springframework.data.repository.query.parser.PartTree.(PartTree.java:80) at
org.springframework.data.mongodb.repository.query.PartTreeMongoQuery.(PartTreeMongoQuery.java:47)
Below is my Spring Data MongoDB structure:
/* Users Domain Object */
#Document(collection = "users")
public class Users {
#Id
private ObjectId id;
#Field ("last_name")
private String last_name;
#Field ("first_name")
private String first_name;
public String getLast_name() {
return last_name;
}
public void setLast_name(String last_name) {
this.last_name = last_name;
}
public String getFirst_name() {
return first_name;
}
public void setFirst_name(String first_name) {
this.first_name = first_name;
}
}
/* UsersRepository.java main interface */
#Repository
public interface UsersRepository extends MongoRepository<Users,String>, UsersRepositoryCustom {
List findUsersById(String id);
}
/* UsersRepositoryCustom.java custom interface */
#Repository
public interface UsersRepositoryCustom {
List<Users> getUsersName(Users users);
}
/* UsersRepositoryImpl.java custom interface implementation */
#Component
public class UsersRepositoryImpl implements UsersRepositoryCustom {
#Autowired
MongoOperations mongoOperations;
#Override
public List<Users> getUsersName(Users users) {
return mongoOperations.find(
Query.query(Criteria.where("first_name").is(users.getFirst_name()).and("last_name").is(users.getLast_name())), Users.class);
}
/* Mongo Test function inside Spring JUnit Test class calling custom function with main UsersRepository interface */
#Autowired
private UsersRepository usersRepository;
#Test
public void getUsersName() {
Users users = new Users();
users.setFirst_name("James");`enter code here`
users.setLast_name("Oliver");
List<Users> usersDetails = usersRepository.getUsersName(users);
System.out.println("users List" + usersDetails.size());
Assert.assertTrue(usersDetails.size() > 0);
}
The query method declaration in your repository interface is invalid. As clearly stated in the reference documentation, query methods need to start with get…By, read_By, find…By or query…by.
With custom repositories, there shouldn't be a need for method naming conventions as Oliver stated. I have mine working with a method named updateMessageCount
Having said that, I can't see the problem with the code provided here.
I resolved this issue with the help of this post here, where I wasn't naming my Impl class correctly :
No property found for type error when try to create custom repository with Spring Data JPA