I have a number of text files with data, and want to read a specific part of each file (time information), which is always located at the end of the first row of each file. Here's an example:
%termo2, 30-Jan-2016 12:27:20
I.e. I would like to get "12:27:20".
I've tried using textscan, which I have used before for similar problems. I figured there are 3 columns of this row, with single white space as delimiter.
I first tried to specify these as strings (%s):
fid = fopen(fname);
time = textscan(fid,'%s %s %s');
I also tried to specify the date and time using datetime format:
time = textscan(fid,'%s %{dd-MMM-yyyy}D %{HH:mm:ss}D')
Both of these just produce a blank cell. (I've also tried a number of variations, such as defining the delimiter as ' ', with the same result)
Thanks for any help!
Here's the entire file (not sure pasting here is the right way to do this - i'm new to both matlab and stackoverflow..):
%termo2, 30-Jan-2016 12:27:20
%
%102
%
%stimkod stimtyp
% 1 Next:Pain
% 2 Next:Brush
% vaskod text
% 1 Obeh -> Beh
% 2 Inte alls intensiv -> Mycket intensiv
% stimnr starttid stimkod vaskod VASstart VASmark VAS
1 78.470 2 1 96.470 100.708 6.912
1 78.470 2 2 96.470 104.739 2.763
2 138.822 1 2 156.821 162.619 7.615
2 138.822 1 1 156.821 166.659 2.496
3 199.117 2 2 217.116 222.978 2.897
3 199.117 2 1 217.116 224.795 5.773
4 258.612 2 1 276.612 280.419 5.395
4 258.612 2 2 276.612 284.145 4.622
5 320.068 1 1 338.068 340.689 4.396
5 320.068 1 2 338.068 346.090 2.722
6 377.348 1 2 395.347 398.809 6.336
6 377.348 1 1 395.347 404.465 3.391
7 443.707 2 1 461.707 464.840 6.604
7 443.707 2 2 461.707 473.703 3.652
8 503.122 1 2 521.122 526.009 4.285
8 503.122 1 1 521.122 529.808 3.646
9 568.546 2 2 586.546 586.546 5.000
9 568.546 2 1 586.546 595.496 6.412
10 629.953 2 1 647.953 650.304 7.034
10 629.953 2 2 647.953 655.600 6.615
11 694.305 1 1 712.305 714.416 4.669
11 694.305 1 2 712.305 721.079 2.478
12 751.537 2 2 769.537 773.511 7.307
12 751.537 2 1 769.537 777.423 8.225
13 813.944 1 2 831.944 834.958 7.731
13 813.944 1 1 831.944 839.255 1.363
14 872.448 2 1 890.448 893.829 6.813
14 872.448 2 2 890.448 899.439 2.600
15 939.880 1 2 957.880 963.811 4.332
15 939.880 1 1 957.880 966.603 2.786
16 998.328 2 1 1016.327 1020.707 5.837
16 998.328 2 2 1016.327 1025.275 2.664
17 1062.911 1 2 1080.910 1082.967 2.792
17 1062.911 1 1 1080.910 1088.674 4.094
18 1125.182 1 1 1143.182 1144.379 0.619
18 1125.182 1 2 1143.182 1151.786 8.992
If you're not reading in the entire file, you could just read the first line using fgetl, split on the strings (using regexp) and then grab the last element.
parts = regexp(fgetl(fid), '\s+', 'split');
last = parts{end};
That being said, there doesn't seem to be anything wrong with the way you're using textscan if your file is actually how you say. You could alternately do something like:
parts = textscan(fid, '%s', 3);
last = parts{end}
Update
Also, be sure to rewind the file pointer using frewind before trying to parse the file to ensure that it starts at the top of the file.
frewind(fid)
Related
I need to import a txt file into Matlab which has this format
text text text
1 0 1 2 3
4 5 6 7
2 10 11 15 18
15 1 18 3
The first column is separated with the second one by a tab delimiter, while the rest of the data are separated by a space.
I tried to import it using this:
g = importdata('file.txt',delimiterIn,headerlinesIn);
delimiterIn = ' ';
headerlinesIn = 1;
but then the extracted table is like this:
text text text
1 0 1 2 3
4 5 6 7 nan
2 10 11 15 18
15 1 18 3 nan
What I want is a table that maintains the format, with the first column of g.data on its own and then all the others.
I want an output matrix like
1 0 1 2 3
4 5 6 7
2 10 11 15 18
15 1 18 3
Then if I need to extract data represented by 2 in the first column, I can put it into another matrix with the values
10 11 15 18
15 1 18 3
each number inside a cell of a matrix
How can I do it?
A sollution might be:
fid = fopen('test.txt');
M = {[]};Midx=1;
l = fgetl(fid); %header
l = fgetl(fid);
while ~isnumeric(l)
idx = str2double(l(1));
if ~isnan(idx)
Midx=idx;
M{Midx}=[];
l = l(2:end);
end
val = cell2mat(textscan(l,'%f'))';
M{Midx}=[M{Midx};val];
l=fgetl(fid);
end
fclose(fid);
Maybe a bit too pragmatic, but this might help:
for i=1:size(A,1)
if isnan(A(i,end))==1
A(i,2:end) = A(i,1:4);
A(i,1) = NaN;
end
end
for i=1:size(A,1)
if A(i,1)==2
B = A(i:i+1,2:end);
end
end
I need some help please. I have an array, as shown below, 6 rows and 5 columns, none of the elements in any one row repeats. The elements are all single digit numbers.
I want to find out, per row, when a number, let's say 1 appears, I want to keep of how often the other numbers of the row appear. For example, 1 shows up 3 times in rows one, three and five. When 1 shows up, 2 shows up one time, 3 shows up two times, 4 shows up two times, 5 shows up one time, 6 shows up two times, 7 shows up one time, 8 shows up three times, and 9 shows up zero times. I want to keep a vector of this information that will look like, V = [3,1,2,2,1,2,1,3,0], by starting with a vector like N = [1,2,3,4,5,6,7,8,9]
ARRAY =
1 5 8 2 6
2 3 4 6 7
3 1 8 7 4
6 5 7 9 4
1 4 3 8 6
5 7 8 9 6
The code I have below does not give the feedback I am looking for, can someone help please? Thanks
for i=1:length(ARRAY)
for j=1:length(N)
ARRAY(i,:)==j
V(j) = sum(j)
end
end
Using indices that is in A creae a zero and one 6 * 9 matrix that [i,j] th element of it is 1 if i th row of A contains j.
Then multiply the zero and one matrix with its transpose to get desirable result:
A =[...
1 5 8 2 6
2 3 4 6 7
3 1 8 7 4
6 5 7 9 4
1 4 3 8 6
5 7 8 9 6]
% create a matrix with the size of A that each row contains the row number
rowidx = repmat((1 : size(A,1)).' , 1 , size(A , 2))
% z_o a zero and one 6 * 9 matrix that [i,j] th element of it is 1 if i th row of A contains j
z_o = full(sparse(rowidx , A, 1))
% matrix multiplication with its transpose to create desirable result. each column relates to number N
out = z_o.' * z_o
Result: each column relates to N
3 1 2 2 1 2 1 3 0
1 2 1 1 1 2 1 1 0
2 1 3 3 0 2 2 2 0
2 1 3 4 1 3 3 2 1
1 1 0 1 3 3 2 2 2
2 2 2 3 3 5 3 3 2
1 1 2 3 2 3 4 2 2
3 1 2 2 2 3 2 4 1
0 0 0 1 2 2 2 1 2
I don't understand how you are approaching the problem with your sample code but here is something that should work. This uses find, any and accumarray and in each iteration for the loop it will return a V corresponding to the ith element in N
for i=1:length(N)
rowIdx = find(any(A == N(i),2)); % Find all the rows contain N(j)
A_red = A(rowIdx,:); % Get only those rows
V = [accumarray(A_red(:),1)]'; % Count occurrences of the 9 numbers
V(end+1:9) = 0; % If some numbers don't exist place zeros on their counts
end
I have input files containing data in the following format.
65910/A
22 9 4 2
9 10 4 1
2 5 2 0
4 1 1 0
65910/T
14 7 0 4
8 4 0 2
1 2 0 0
1 1 1 1
.
.
.
I need to take the input where the first line is a combination of %d and %c with a / in between and the next four line as a 4x4 integer matrix. I need to perform some work on the matrix and then identify them with the header information.
How can I take this input format in MATLAB?
Since your file contains data that may be considered structured (or "formatted", if using MATLAB's terms), you can use the textscan function to read its contents. The main advantage of this function is that you don't need to specify how many times your "header+data" structure appears - the function just keeps going until it reaches the end of the file.
Given an input file with the following structure (let's call it q35853578.txt):
65910/A
22 9 4 2
9 10 4 1
2 5 2 0
4 1 1 0
65910/T
14 7 0 4
8 4 0 2
1 2 0 0
1 1 1 1
We can write something like this:
function [data,headers] = q35853578(filepath)
%// Default input
if nargin < 1
filepath = 'q35853578.txt';
end
%// Define constants
N_ROWS = 4;
VALS_PER_ROW = 4;
NEWLINE = '\r\n';
%// Read structured file contents
fid = fopen(filepath);
headers = textscan(fid,['%u/%c' repmat([NEWLINE repmat('%u',1,VALS_PER_ROW)],1,N_ROWS)]);
fclose(fid);
%// Parse contents and prepare outputs
data = cell2mat(reshape(cellfun(#(x)reshape(x,1,1,[]),headers(3:end),...
'UniformOutput',false),VALS_PER_ROW,N_ROWS).'); %'
headers = headers(1:2);
%// Output checking
if nargout < 2
warning('Not all outputs assigned, some outputs will not be returned!')
end
%// Debug
clear ans fid N_ROWS NEWLINE VALS_PER_ROW filepath
keyboard; %// For debugging, delete/comment when done.
The resulting output is a 3d array of uint32 (the output class can be changed by adjusting the inputs to textscan, as permitted by formatSpec):
ans(:,:,1) =
22 9 4 2
9 10 4 1
2 5 2 0
4 1 1 0
ans(:,:,2) =
14 7 0 4
8 4 0 2
1 2 0 0
1 1 1 1
I want to do the following:
I create a matrix with all possible permutations from 1:n, for example
n=4;
L=perms(1:n)';
I get as output as expected a 4-by-24 matrix:
L =
Columns 1 through 13
4 4 4 4 4 4 3 3 3 3 3 3
3 3 2 2 1 1 4 4 2 2 1 1
2 1 3 1 2 3 2 1 4 1 2 4
1 2 1 3 3 2 1 2 1 4 4 2
Columns 14 through 24
2 2 2 2 2 1 1 1 1 1 1
3 4 4 1 1 3 3 2 2 4 4
1 3 1 4 3 2 4 3 4 2 3
4 1 3 3 4 4 2 4 3 3 2
Now I want to use this matrix for the indexes of a for loop:
Using the first column, I want to feed the input of my loop the following indexes: i=4 j=3,2,1. Then for i=3 j=2,1. Then for i=2 j=1. i=1 is empty
This could be done just for the first column like this:
for u=4:-1:1
for v=u-1:-1:1
But will not work for other columns so I need to do the same but with the entries of matrix L, something like (it doesn't work in MATLB) for column i=1:
u=L(1:4,1)
v=L(u:L(4,1) , 1) %// where u corresponds to L(1,1) then L(2,1) then L(3,1)
(for all the columns it would look like:
for i=1:length(L)
for u=L(4*(i-1)+1:4*i)
for v=.. ?
)
This doesn't work because MATLAB takes the values of the entries and when I write L(1,1):L(4,1) it doesn't mean return the entries from line one to line four but rather all the numbers with increment 1 from the value of L(1,1) to the value of L(4,1) (here empty).
Any ideas ? thank you very much in advance
I believe something like this will solve you problem.
for col = 1:size(L,2)
rowIdx = 1;
for j = [L(:,col)]'
for k = [L(rowIdx:end,col)]'
% Do your stuff here
end
rowIdx = rowIdx + 1;
end
end
Notice how I use the values from columns from L directly as loop index variable. In a for loop statement you can basically write any row vector and the index takes those values. For example
for i = [1, 7, 11, 14, 23]
disp(i); % prints 1,7,11,14,23
end
This is true for arrays of objects, cell arrays, basically any single row matrix.
You can do it like this:
for col = 1:size(L, 2)
for I = 1:n-1
for J = I:n
i = L(I,col);
j = L(J,col);
%// As an example just print out the loop variable values
disp(sprintf('Col:%d\ti:%d\tj:%d\r\n',col,i,j))
end
end
end
this is my code where it has a matrix where it adds each row with its col where
as example
sum of row 1 =4
sum of col 1= 10
my number will be 14
so far my code works correct where number calculates all rows with col and gives this display
number =
14 18 22 26
in my loop os where i went wrong it split it with a counter to show like
number 1 has 14
number 2 has 18
number 3 has 22
number 4 has 26
it works for the first one and goes to an infinite loop and even not displaying the rest of the numbers can you tell me how to work with this and where did i go wrong thank you
first loop result
matrix =
1 2 3 4
1 2 3 4
1 2 3 4
1 2 3 4
1 has 14 number
12 has 22 number
code
matrix=[1 2 3 4;1 2 3 4;1 2 3 4;1 2 3 4]
number= sum(matrix)+sum(matrix');
number
len= length(number);
x=1;
y=1;
number(1,y) ; %
while x<=len
fprintf('%x has %d number \n',x,number)
x+1;
y+1;
number
end
Desired output:
matrix =
1 2 3 4
1 2 3 4
1 2 3 4
1 2 3 4
number =
14 18 22 26
1 has 14
2 has 18
3 has 22
4 has 26
There are multiple errors in your loop:
y is unused, you can delete it.
numbers prints the full array each iteration, not what you want.
x+1 calculates x+1 but does nothing with the result. Use x=x+1; instead.
When using fprint, you are using a the full array number instead of the right number number(x) as an input argument.
matrix=[1 2 3 4;1 2 3 4;1 2 3 4;1 2 3 4]
number= sum(matrix)+sum(matrix');
number
len= length(number);
x=1;
while x<=len
fprintf('%x has %d number \n',x,number(x))
x=x+1;
end
matrix=[1 2 3 4;1 2 3 4;1 2 3 4;1 2 3 4]
number= sum(matrix)+sum(matrix');
number
len= length(number);
x=1;
while x<=len
fprintf('%x has %d number \n',x,number(x))
x=x+1;
end