Can't display PSObject - powershell

Question

I'm trying to display some data my script generates in a PSObject, so I can then export to a CSV, but the only object that shows is whichever one I add to the array first.
$pass=#("1","2","3")
$fail=#("4")
$obj=#()
$pass | % {
$obj+=New-Object PSObject -Property #{Pass=$_}
}
$fail | % {
$obj+=New-Object PSObject -Property #{Fail=$_}
}
$obj
I've also tried this, but I get a blank line showing in the table where the value isn't in that column, which I don't want:
$pass=#("1","2","3")
$fail=#("4")
$obj=#()
$pass | % {
$obj+=New-Object PSObject -Property #{Pass=$_;Fail=""}
}
$fail | % {
$obj+=New-Object PSObject -Property #{Pass="";Fail=$_}
}
$obj
My desired result:
Pass Fail
---- ----
1 4
2
3
I am using Powershell V2.

Answer 1

Another answer is right - you're using objects wrong. That being said, here's a function to help you use them wrong!
Function New-BadObjectfromArray($array1,$array2,$array1name,$array2name){
if ($array1.count -ge $array2.count){$iteratorCount = $array1.count}
else {$iteratorCount = $array2.count}
$obj = #()
$iteration=0
while ($iteration -le $iteratorCount){
New-Object PSObject -Property #{
$array1name=$array1[$iteration]
$array2name=$array2[$iteration]
}
$iteration += 1
}
$obj
}
$pass=#("1","2","3")
$fail=#("4")
New-BadObjectfromArray -array1 $fail -array2 $pass -array1name "Fail" -array2name "Pass"

Answer 2

As you figured out yourself, PowerShell only outputs the properties of the first item in your array. Its not designed to print the ouput you are expecting in the way you are using it.
As a workaround, you could use a for loop to "build" your desired output:
$pass=#("1","2","3")
$fail=#("4")
$obj=#()
for ($i = 0; $i -lt $pass.Count; $i++)
{
if ($fail.Count -gt $i)
{
$currentFail = $fail[$i]
}
else
{
$currentFail = ""
}
$obj+=New-Object PSObject -Property #{Fail=$currentFail;Pass=$pass[$i];}
}
$obj | select Pass, Fail
Output:
Pass Fail
---- ----
1 4
2
3