I'm using CASE expression to display "NamaAyah" or "NamaIbu" or "NamaWali", and if all of them is empty, the default value will display "ORTU-'NomorPokok' ".
But the default value not displayed, it just displays symbol "-" in my table. I think the value in ELSE statement not executed.
Postgre Version : PostgreSQL 9.4.15
This is my code
SELECT
"MahasiswaID" AS "PERSONID","NomorPokok" AS "KODE",
UPPER(CASE
WHEN "NamaAyah" <> '' THEN "NamaAyah"
WHEN "NamaIbu" <> '' THEN "NamaIbu"
WHEN "NamaWali" <> '' THEN "NamaWali"
ELSE 'ORTU'||'-'||"NomorPokok"
END) AS "NAMALENGKAP"
FROM "MasterMahasiswa" ORDER BY "KODE"
and this is the result
The expression you have can simpler be:
ELSE 'ORTU-'||"NomorPokok"
Apart from that, the only reasonable explanation for what you display is that there are literal - in one or more of your columns "NamaAyah", "NamaIbu" and "NamaWali". Did you check that?
I want to convert the result of a division to a character string in DB2.
My result when I do '0.24'||'%' is '.24%'
I don't understand how to get exactly the output '0.24%'
hi try Something like this
case when myval<1 and myval>0 then '0' || cast(myval as char(15))
when myval>-1 and myval<0 then '-0' || cast(abs(myval) as char(15))
else cast(myval as char(15)) end myvaltochar
try this
to_char( yourzone
repeat('0', length(trim(int(abs(yourzone))))) || '.'||
repeat('0', length(trim(
INTEGER(SUBSTR(CHAR(-123.36),LOCATE(',',CHAR(yourzone))+1)))))
)
SELECT VARCHAR_FORMAT(24.0/100,'0.00')||'%' ...
If you are dividing integer types, you'll have to cast them as DOUBLE() otherwise the result will be 0
My assumption was that it would return a true if that value was numeric (within the isnumeric range) but FALSE if the ISNULL returns 'blah'. Seems like my assumption was off...
I'm using the it in the following way
case when ISNULL(ISNUMERIC(c.npinumber), 'blah') = 1
then c.NPiNUmber
else 'not valid: ' + c.NpiNumber
end as npi
Building on Dhruvesh's answer,
case
when ISNUMERIC(c.npinumber) = 1 then c.NPiNUmber
else 'not valid: ' + c.NpiNumber
end as npi
Will produce NULL anytime NpiNumber is NULL. The reason is that NULL + any string will still return NULL. The solution is to simply use the COALESCE function
case
when ISNUMERIC(c.npinumber) = 1 then c.NPiNUmber
else 'not valid: ' + COALESCE(c.NpiNumber, 'NULL VALUE')
end as npi
select ISNUMERIC(ISNULL(NULL, 'blah')),
ISNUMERIC(ISNULL(1234, 'blah')),
ISNUMERIC(ISNULL('ab', 'blah'))
Returns 0, 1, 0 - so your logic is correct.
When SQL's not behaving I like to simplify my query. Try running the query without your case statement first. If the results look right, then add additional logic.
What collation is your database? It's always a good idea to keep your column names properly cased (I'm looking at that all-lowercase column name over there...).
You don't require ISNULL. ISNUMERIC will return 1 if it's numberic or 0 if it's NULL or non-numeric.
case
when ISNUMERIC(c.NpiNumber) = 1 then c.NPiNUmber
else 'not valid: ' + c.NpiNumber
end as npi
Also as Euric Mentioned you may want to look at your all-lowercase column name.
I was trying to make a function to work in db2:
CREATE FUNCTION TO_DATE8(DATE_STRING numeric(8,0))
RETURNS DATE
LANGUAGE SQL
IF DATE_STRING > 0 THEN
// ERROR ->
RETURN DATE ( TO_DATE ( SUBSTR ( DATE_STRING , 1 , 8 ) , 'YYYYMMDD' ) )
ELSE
RETURN DATE ( TO_DATE ( '00000000' , 'YYYYMMDD' ) )
END IF
END
ERROR: DATE IS NOT VALID
What to do?
The form of the procedure required seems to be like this (at least on the iSeries version):
CREATE FUNCTION TO_DATE8(DATE_STRING numeric(8,0))
RETURNS DATE
LANGUAGE SQL
BEGIN
RETURN(CASE WHEN DATE_STRING > 0 THEN DATE(SUBSTR(DATE_STRING, 1, 4) || '-' ||
SUBSTR(DATE_STRING, 5, 2) || '-' ||
SUBSTR(DATE_STRING, 7, 2))
ELSE DATE('0001-01-01')
END);
END
However:
Your procedure is misnamed (reading from a date-8, not to it).
Your DATE_STRING is not a string (or even a char), it's numeric. Please rename it to something that does not include the datatype (dateToConvert works)
You seem to want to return something that is not a valid date (all 0s). I'm returning *loval here, although it's possible it should actually be null.
I didn't put in enough checks for a valid date - this will blow up really easily.
If at all possible, the database should be changed to contain actual dates, not a numeric value. Disk is (relative to programmer/architect headaches) cheap.
You may also find a calendar file helpful, if the 8-digit numeric was one of the included columns.
For the benifit of others, this can be done in one line rather than a function:
CASE WHEN MYDATE = 0 THEN NULL ELSE DATE(INSERT(INSERT(LEFT(CHAR(MYDATE),8),5,0,'-'),8,0,'-')) END
MYDATE was 8 packed in my case.
What's the best way to extract the first word of a string in sql server query?
SELECT CASE CHARINDEX(' ', #Foo, 1)
WHEN 0 THEN #Foo -- empty or single word
ELSE SUBSTRING(#Foo, 1, CHARINDEX(' ', #Foo, 1) - 1) -- multi-word
END
You could perhaps use this in a UDF:
CREATE FUNCTION [dbo].[FirstWord] (#value varchar(max))
RETURNS varchar(max)
AS
BEGIN
RETURN CASE CHARINDEX(' ', #value, 1)
WHEN 0 THEN #value
ELSE SUBSTRING(#value, 1, CHARINDEX(' ', #value, 1) - 1) END
END
GO -- test:
SELECT dbo.FirstWord(NULL)
SELECT dbo.FirstWord('')
SELECT dbo.FirstWord('abc')
SELECT dbo.FirstWord('abc def')
SELECT dbo.FirstWord('abc def ghi')
I wanted to do something like this without making a separate function, and came up with this simple one-line approach:
DECLARE #test NVARCHAR(255)
SET #test = 'First Second'
SELECT SUBSTRING(#test,1,(CHARINDEX(' ',#test + ' ')-1))
This would return the result "First"
It's short, just not as robust, as it assumes your string doesn't start with a space. It will handle one-word inputs, multi-word inputs, and empty string inputs.
Enhancement of Ben Brandt's answer to compensate even if the string starts with space by applying LTRIM(). Tried to edit his answer but rejected, so I am now posting it here separately.
DECLARE #test NVARCHAR(255)
SET #test = 'First Second'
SELECT SUBSTRING(LTRIM(#test),1,(CHARINDEX(' ',LTRIM(#test) + ' ')-1))
Adding the following before the RETURN statement would solve for the cases where a leading space was included in the field:
SET #Value = LTRIM(RTRIM(#Value))
Marc's answer got me most of the way to what I needed, but I had to go with patIndex rather than charIndex because sometimes characters other than spaces mark the ends of my data's words. Here I'm using '%[ /-]%' to look for space, slash, or dash.
Select race_id, race_description
, Case patIndex ('%[ /-]%', LTrim (race_description))
When 0 Then LTrim (race_description)
Else substring (LTrim (race_description), 1, patIndex ('%[ /-]%', LTrim (race_description)) - 1)
End race_abbreviation
from tbl_races
Results...
race_id race_description race_abbreviation
------- ------------------------- -----------------
1 White White
2 Black or African American Black
3 Hispanic/Latino Hispanic
Caveat: this is for a small data set (US federal race reporting categories); I don't know what would happen to performance when scaled up to huge numbers.
DECLARE #string NVARCHAR(50)
SET #string = 'CUT STRING'
SELECT LEFT(#string,(PATINDEX('% %',#string)))
Extract the first word from the indicated field:
SELECT SUBSTRING(field1, 1, CHARINDEX(' ', field1)) FROM table1;
Extract the second and successive words from the indicated field:
SELECT SUBSTRING(field1, CHARINDEX(' ', field1)+1, LEN (field1)-CHARINDEX(' ', field1)) FROM table1;
A slight tweak to the function returns the next word from a start point in the entry
CREATE FUNCTION [dbo].[GetWord]
(
#value varchar(max)
, #startLocation int
)
RETURNS varchar(max)
AS
BEGIN
SET #value = LTRIM(RTRIM(#Value))
SELECT #startLocation =
CASE
WHEN #startLocation > Len(#value) THEN LEN(#value)
ELSE #startLocation
END
SELECT #value =
CASE
WHEN #startLocation > 1
THEN LTRIM(RTRIM(RIGHT(#value, LEN(#value) - #startLocation)))
ELSE #value
END
RETURN CASE CHARINDEX(' ', #value, 1)
WHEN 0 THEN #value
ELSE SUBSTRING(#value, 1, CHARINDEX(' ', #value, 1) - 1)
END
END
GO
SELECT dbo.GetWord(NULL, 1)
SELECT dbo.GetWord('', 1)
SELECT dbo.GetWord('abc', 1)
SELECT dbo.GetWord('abc def', 4)
SELECT dbo.GetWord('abc def ghi', 20)
Try This:
Select race_id, race_description
, Case patIndex ('%[ /-]%', LTrim (race_description))
When 0 Then LTrim (race_description)
Else substring (LTrim (race_description), 1, patIndex ('%[ /-]%', LTrim (race_description)) - 1)
End race_abbreviation
from tbl_races