So I have three queries. I'm trying to combine them all into one query. Here they are with their outputs:
Query 1:
SELECT distinct on (name) name, count(distinct board_id)
FROM tablea
INNER JOIN table_b on tablea.id = table_b.id
GROUP BY name
ORDER BY name ASC
Output:
A | 15
B | 26
C | 24
D | 11
E | 31
F | 32
G | 16
Query 2:
SELECT distinct on (name) name, count(board_id) as total
FROM tablea
INNER JOIN table_b on tablea.id = table_b.id
GROUP BY 1, board_id
ORDER BY name, total DESC
Output:
A | 435
B | 246
C | 611
D | 121
E | 436
F | 723
G | 293
Finally, the last query:
SELECT distinct on (name) name, count(board_id) as total
FROM tablea
INNER JOIN table_b on tablea.id = table_b.id
GROUP BY 1
ORDER BY name, total DESC
Output:
A | 14667
B | 65123
C | 87426
D | 55198
E | 80612
F | 31485
G | 43392
Is it possible to format it to be like this:
A | 15 | 435 | 14667
B | 26 | 246 | 65123
C | 24 | 611 | 87426
D | 11 | 121 | 55198
E | 31 | 436 | 80612
F | 32 | 723 | 31485
G | 16 | 293 | 43392
EDIT:
With #Clodoaldo Neto 's help, I combined the first and the third queries with this:
SELECT name, count(distinct board_id), count(board_id) as total
FROM tablea
INNER JOIN table_b on tablea.id = table_b.id
GROUP BY 1
ORDER BY description ASC
The only thing preventing me from combining the second query with this new one is the GROUP BY clause needing board_id to be in it. Any thoughts from here?
This is hard to get right without test data. But here is my try:
with s as (
select name, grouping(name, board_id) as grp,
count(distinct board_id) as dist_total,
count(*) as name_total,
count(*) as name_board_total
from
tablea
inner join
table_b on tablea.id = table_b.id
group by grouping sets ((name), (name, board_id))
)
select name, dist_total, name_total, name_board_total
from
(
select name, dist_total, name_total
from s
where grp = 1
) r
inner join
(
select name, max(name_board_total) as name_board_total
from s
where grp = 0
group by name
) q using (name)
order by name
https://www.postgresql.org/docs/current/static/queries-table-expressions.html#QUERIES-GROUPING-SETS
Related
To get 2 rows from each group I can use ROW_NUMBER() with condition <= 2 at last but my question is what If I want to get different limits on each group e.g 3 rows for section_id 1, 1 rows for 2 and 1 rows for 3?
Given the following table:
db=# SELECT * FROM xxx;
id | section_id | name
----+------------+------
1 | 1 | A
2 | 1 | B
3 | 1 | C
4 | 1 | D
5 | 2 | E
6 | 2 | F
7 | 3 | G
8 | 2 | H
(8 rows)
I get the first 2 rows (ordered by name) for each section_id, i.e. a result similar to:
id | section_id | name
----+------------+------
1 | 1 | A
2 | 1 | B
5 | 2 | E
6 | 2 | F
7 | 3 | G
(5 rows)
Current Query:
SELECT
*
FROM (
SELECT
ROW_NUMBER() OVER (PARTITION BY section_id ORDER BY name) AS r,
t.*
FROM
xxx t) x
WHERE
x.r <= 2;
Create a table to contain the section limits, then join. The big advantage being that as new sections are required or limits change maintenance is reduced to a single table update and comes at very little cost. See example.
select s.section_id, s.name
from (select section_id, name
, row_number() over (partition by section_id order by name) rn
from sections
) s
left join section_limits sl on (sl.section_id = s.section_id)
where
s.rn <= coalesce(sl.limit_to,2);
Just fix up your where clause:
with numbered as (
select row_number() over (partition by section_id
order by name) as r,
t.*
from xxx t
)
select *
from numbered
where (section_id = 1 and r <= 3)
or (section_id = 2 and r <= 1)
or (section_id = 3 and r <= 1);
I want to select the records that have a unique column combination in postgresql, however it doesn't seem to work with distinct as distinct only removes duplicates.
Example
ID A B
01 1 2
02 1 2
03 1 3
04 2 4
05 1 4
06 2 4
07 2 5
08 1 3
In this example row with ID 05 and 07 have unique combination AB, how can i get these records
SELECT ...
With NOT EXISTS:
select t.* from tablename t
where not exists (
select 1 from tablename
where id <> t.id and a = t.a and b = t.b
)
Or with COUNT() window function:
select t.id, t.a, t.b
from (
select *, count(id) over (partition by a, b) counter
from tablename
) t
where t.counter = 1
Or with aggregation:
select max(id) id, a, b
from tablename
group by a, b
having count(id) = 1
Or with a self LEFT join that excludes the matching rows:
select t.*
from tablename t left join tablename tt
on tt.id <> t.id and tt.a = t.a and tt.b = t.b
where tt.id is null
See the demo.
Results:
| id | a | b |
| --- | --- | --- |
| 05 | 1 | 4 |
| 07 | 2 | 5 |
I have a table persons that contains a column for parent_id, which refers to another row in the same table. Assume this is the logical hierarchy:
P1
P2 P3 P4
P5 P6 P7 P8 P9 P10
I have written a query that prints all parents of a given node, along with the height above the node, and it seems to work fine:
WITH
RECURSIVE ancestors AS (
SELECT id, parent_id
FROM persons
WHERE id = 8
UNION
SELECT p.id, p.parent_id
FROM persons p
INNER JOIN ancestors
ON
p.id = ancestors.parent_id
)
SELECT persons.id, persons.name,
ROW_NUMBER() over () as height
FROM ancestors
INNER JOIN persons
ON
ancestors.id = persons.id
WHERE
persons.id <> 8
Result:
id | name | height
-------+-------------+---------
3 | P3 | 1
1 | P1 | 2
(2 rows)
I now want to write a query that similarly prints all descendants, along with depth. Here's the query so far (same as above with id and parent_id swapped in the UNION join):
WITH
RECURSIVE descendants AS (
SELECT id, parent_id
FROM persons
WHERE id = 1
UNION
SELECT p.id, p.parent_id
FROM persons p
INNER JOIN descendants
ON
p.parent_id = descendants.id
)
SELECT persons.id, persons.name,
ROW_NUMBER() over () as depth
FROM descendants
INNER JOIN persons
ON
descendants.id = persons.id
WHERE
persons.id <> 1
This gives the following result:
id | name | depth
-------+-------------+---------
2 | P2 | 1
3 | P3 | 2
4 | P4 | 3
5 | P5 | 4
6 | P6 | 5
7 | P7 | 6
8 | P8 | 7
9 | P9 | 8
10 | P10 | 9
(9 rows)
Clearly, the depth is all wrong. ROW_NUMBER() isn't doing what I want. How do I go about this?
I've thought about using a counter within the recursive part of the query itself, which increments every time it is run, but I'm not sure if there's a way to achieve that.
Use an additional integer column with values incremented at each recursive step.
WITH RECURSIVE descendants AS (
SELECT id, parent_id, 0 AS depth
FROM persons
WHERE id = 1
UNION
SELECT p.id, p.parent_id, d.depth+ 1
FROM persons p
INNER JOIN descendants d
ON p.parent_id = d.id
)
SELECT p.id, p.name, depth
FROM descendants d
INNER JOIN persons p
ON d.id = p.id
WHERE p.id <> 1;
id | name | depth
----+------+-------
2 | P2 | 1
3 | P3 | 1
4 | P4 | 1
5 | P5 | 2
6 | P6 | 2
7 | P7 | 2
8 | P8 | 2
9 | P9 | 2
10 | P10 | 2
(9 rows)
Db<>fiddle.
i have only one table "tbl_test"
Which have table filed given below
tbl_test table
trx_id | proj_num | parent_num|
1 | 14 | 0 |
2 | 14 | 1 |
3 | 14 | 2 |
4 | 14 | 0 |
5 | 14 | 3 |
6 | 15 | 0 |
Result i want is : when trx_id value 5 is fetched
it's a parent child relationship. so,
trx_id -> parent_num
5 -> 3
3 -> 2
2 -> 1
That means output value:
3
2
1
Getting all parent chain
Query i used :
SELECT * FROM (
WITH RECURSIVE tree_data(project_num, task_num, parent_task_num) AS(
SELECT project_num, task_num, parent_task_num
FROM tb_task
WHERE project_num = 14 and task_num = 5
UNION ALL
SELECT child.project_num, child.task_num, child.parent_task_num
FROM tree_data parent Join tb_task child
ON parent.task_num = child.task_num AND parent.task_num = child.parent_task_num
)
SELECT project_num, task_num, parent_task_num
FROM tree_data
) AS tree_list ;
Can anybody help me ?
There's no need to do this with pl/pgsql. You can do it straight in SQL. Consider:
WITH RECURSIVE my_tree AS (
SELECT trx_id as id, parent_id as parent, trx_id::text as path, 1 as level
FROM tbl_test
WHERE trx_id = 5 -- start value
UNION ALL
SELECT t.trx_id, t.parent_id, p.path || ',' || t.trx_id::text, p.level + 1
FROM my_tree p
JOIN tbl_text t ON t.trx_id = p.parent
)
select * from my_tree;
If you are using PostgresSQL, try using a WITH clause:
WITH regional_sales AS (
SELECT region, SUM(amount) AS total_sales
FROM orders
GROUP BY region
), top_regions AS (
SELECT region
FROM regional_sales
WHERE total_sales > (SELECT SUM(total_sales)/10 FROM regional_sales)
)
SELECT region,
product,
SUM(quantity) AS product_units,
SUM(amount) AS product_sales
FROM orders
WHERE region IN (SELECT region FROM top_regions)
GROUP BY region, product;
I have a query:
select
a.kli,
b.term_desc,
count(distinct(a.adic)) as count,
a.partner_id
from
ad_delivery.sgmt_kli_adic a
join wand.wandterms b on a.kli = b.term_code
join wand.wandterms c on b.term_desc=c.term_desc
join dwh.sgmt_clients e on a.partner_id::varchar = e.partner_id
join dwh.schema_names f on e.partner_id::integer = f.partner_id::integer
where
a.partner_id::integer in (f.partner_id)
and c.class_code = 969
group by a.partner_id, b.term_desc, a.kli
order by partner_id, count desc;
which brings back counts for certain terms per partner_id. I want to be able to show the top 10 for each of the ~40 partner_id in order by the count desc
the query results look like
db=# SELECT * FROM xxx;
pid | term_desc | count
----+------------+------
4 | termdesc1 | 3434
4 | termdesc2 | 235
4 | termdesc3 | 367
4 | termdesc4 | 4533
5 | termdesc1 | 235
5 | termdesc2 | 567
5 | termdesc3 | 344
5 | termdesc4 | 56
(10k+ rows)
You could add a rank column and then filter the result by the rank :
select
a.kli,
b.term_desc,
count(distinct(a.adic)) as count,
a.partner_id,
RANK() OVER (PARTITION BY a.partner_id order by a.partner_id DESC) AS r
from
ad_delivery.sgmt_kli_adic a
join wand.wandterms b on a.kli = b.term_code
join wand.wandterms c on b.term_desc=c.term_desc
join dwh.sgmt_clients e on a.partner_id::varchar = e.partner_id
join dwh.schema_names f on e.partner_id::integer = f.partner_id::integer
where
a.partner_id::integer in (f.partner_id)
and c.class_code = 969
group by a.partner_id, b.term_desc, a.kli
HAVING r < 11
order by partner_id, count desc;
I have not tested the code, however the trick is ranking the each row of the GROUP BY and filter the resultset with the HAVING clause, keeping only item with a lower rank than 11 (you will get 10 item per group).