MongoDB aggregate nested array correctly - mongodb

Question

OK I am very new to Mongo, and I am already stuck.
Db has the following structure (much simplified for sure):
{
{
"_id" : ObjectId("57fdfbc12dc30a46507044ec"),
"keyterms" : [
{
"score" : "2",
"value" : "AA",
},
{
"score" : "2",
"value" : "AA",
},
{
"score" : "4",
"value" : "BB",
},
{
"score" : "3",
"value" : "CC",
}
]
},
{
"_id" : ObjectId("57fdfbc12dc30a46507044ef"),
"keyterms" : [
...
There are some Objects. Each Object have an array "keywords". Each of this Arrays Entries, which have score and value. There are some duplicates though (not really, since in the real db the keywords entries have much more fields, but concerning value and score they are duplicates).
Now I need a query, which
selects one object by id
groups its keyterms in by value
and counts the dublicates
sorts them by score
So I want to have something like that as result
// for Object 57fdfbc12dc30a46507044ec
"keyterms"; [
{
"score" : "4",
"value" : "BB",
"count" : 1
},
{
"score" : "3",
"value" : "CC",
"count" : 1
}
{
"score" : "2",
"value" : "AA",
"count" : 2
}
]
In SQL I would have written something like this
select
score, value, count(*) as count
from
all_keywords_table_or_some_join
group by
value
order by
score
But, sadly enough, it's not SQL.
In Mongo I managed to write this:
db.getCollection('tests').aggregate([
{$match: {'_id': ObjectId('57fdfbc12dc30a46507044ec')}},
{$unwind: "$keyterms"},
{$sort: {"keyterms.score": -1}},
{$group: {
'_id': "$_id",
'keyterms': {$push: "$keyterms"}
}},
{$project: {
'keyterms.score': 1,
'keyterms.value': 1
}}
])
But there is something missing: the grouping of the the keywords by their value. I can not get rid of the feeling, that this is the wrong approach at all. How can I select the keywords array and continue with that, and use an aggregate function inly on this - that would be easy.
BTW I read this
(Mongo aggregate nested array)
but I can't figure it out for my example unfortunately...

Answer 1

You'd want an aggregation pipeline where after you $unwind the array, you group the flattened documents by the array's value and score keys, aggregate the counts using the $sum accumulator operator and retain the main document's _id with the $first operator.
The preceding pipeline should then group the documents from the previous pipeline by the _id key so as to preserve the original schema and recreate the keyterms array using the $push operator.
The following demonstration attempts to explain the above aggregation operation:
db.tests.aggregate([
{ "$match": { "_id": ObjectId("57fdfbc12dc30a46507044ec") } },
{ "$unwind": "$keyterms" },
{
"$group": {
"_id": {
"value": "$keyterms.value",
"score": "$keyterms.score"
},
"doc_id": { "$first": "$_id" },
"count": { "$sum": 1 }
}
},
{ "$sort": {"_id.score": -1 } },
{
"$group": {
"_id": "$doc_id",
"keyterms": {
"$push": {
"value": "$_id.value",
"score": "$_id.score",
"count": "$count"
}
}
}
}
])
Sample Output
{
"_id" : ObjectId("57fdfbc12dc30a46507044ec"),
"keyterms" : [
{
"value" : "BB",
"score" : "4",
"count" : 1
},
{
"value" : "CC",
"score" : "3",
"count" : 1
},
{
"value" : "AA",
"score" : "2",
"count" : 2
}
]
}
Demo

Answer 2

Meanwhile, I solved it myself:
aggregate([
{$match: {'_id': ObjectId('57fdfbc12dc30a46507044ec')}},
{$unwind: "$keyterms"},
{$sort: {"keyterms.score": -1}},
{$group: {
'_id': "$keyterms.value",
'keyterms': {$push: "$keyterms"},
'escore': {$first: "$keyterms.score"},
'evalue': {$first: "$keyterms.value"}
}},
{$limit: 15},
{$project: {
"score": "$escore",
"value": "$evalue",
"count": {$size: "$keyterms"}
}}
])