Swift: Programmatically make UILabel bold without changing its size? - swift

Question

I have a UILabel created programmatically. I would like to make the text of the label bold without specifying font size. So far I have only found:
UIFont.boldSystemFont(ofSize: CGFloat)
This is what I have exactly:
let titleLabel = UILabel()
let fontSize: CGFloat = 26
titleLabel.font = UIFont.boldSystemFont(ofSize: titleLabelFontSize)
But this way I am also setting the size. I would like to avoid that. Is there a way?
If there is no way, what would be a good workaround in Swift?
Thank you!

Answer 1

Why not just:
titleLabel.font = UIFont.boldSystemFont(ofSize: titleLabel.font.pointSize)

Answer 2

To just make the Font bold without altering the font size you could create an extension like this (which is based off the answer here:
extension UIFont {
func withTraits(traits:UIFontDescriptorSymbolicTraits...) -> UIFont {
let descriptor = self.fontDescriptor()
.fontDescriptorWithSymbolicTraits(UIFontDescriptorSymbolicTraits(traits))
return UIFont(descriptor: descriptor, size: 0)
}
func bold() -> UIFont {
return withTraits(.TraitBold)
}
}
So that way you could use it like this:
let titleLabel = UILabel()
titleLabel.font = titleLabel.font.bold() //no need to include size!
Update for Swift 4 syntax:
extension UIFont {
func withTraits(traits:UIFontDescriptorSymbolicTraits...) -> UIFont {
let descriptor = self.fontDescriptor
.withSymbolicTraits(UIFontDescriptorSymbolicTraits(traits))
return UIFont(descriptor: descriptor!, size: 0)
}
func bold() -> UIFont {
return withTraits(traits: .traitBold)
}
}