I would like to use spark SQL in an Intellij IDEA SBT project.
Even though I have imported the library the code does not seem to import it.
Spark Core seems to be working however.
You can't create a DataFrame from a scala List[A]. You need first to create an RDD[A], and then transform that to a DataFrame. You also need an SQLContext:
val conf = new SparkConf()
.setMaster("local[*]")
.setAppName("test")
val sc = new SparkContext(conf)
val sqlContext = new SQLContext(sc)
import sqlContext.implicits._
val test = sc.parallelize(List(1,2,3,4)).toDF
For reference this is how the Spark 2.0 boilerplate with spark sql should look like:
import org.apache.spark.sql.SparkSession
object Test {
def main(args: Array[String]) {
val spark = SparkSession.builder()
.master("local")
.appName("some name")
.getOrCreate()
import spark.sqlContext.implicits._
}
}
Related
I followed the solutions in here, however, I am still getting the "cannot resolve symbol SQLContext" error. ".implicits._" cannot be resolved either. What would be the reason for it?
Spark/Scala versions I use:
Scala 2.12.13
Spark 3.0.1 (without bundled Hadoop)
Here is my related code part:
import org.apache.log4j.LogManager
import org.apache.spark.{SparkConf, SparkContext}
object Count {
def main(args: Array[String]) {
...
...
val sc = new SparkContext(conf)
val sqlContext = new SQLContext(sc)
import sqlContext.implicits._
}}
You didn't import SQLContext at all:
import org.apache.spark.sql.SQLContext
You should probably not use SQLContext anymore in the first place though:
As of Spark 2.0, this is replaced by SparkSession. However, we are keeping the class here for backward compatibility.
https://spark.apache.org/docs/latest/api/scala/org/apache/spark/sql/SQLContext.html
See how to use a SparkSession from SparkContext at How to create SparkSession from existing SparkContext and then import sparkSession.implicits._.
I am new to Spark and I would like to read a CSV-file to a Dataframe.
Spark 1.3.0 / Scala 2.3.0
This is what I have so far:
# Start Scala with CSV Package Module
spark-shell --packages com.databricks:spark-csv_2.10:1.3.0
# Import Spark Classes
import org.apache.spark.SparkContext
import org.apache.spark.SparkConf
import org.apache.spark.sql.SQLContext
import sqlCtx ._
# Create SparkConf
val conf = new SparkConf().setAppName("local").setMaster("master")
val sc = new SparkContext(conf)
# Create SQLContext
val sqlCtx = new SQLContext(sc)
# Create SparkSession and use it for all purposes:
val session = SparkSession.builder().appName("local").master("master").getOrCreate()
# Read CSV-File and turn it into Dataframe.
val df_fc = sqlContext.read.format("com.databricks.spark.csv").option("header", "true").load("/home/Desktop/test.csv")
However at SparkSession.builder() it gives the following error:
^
How can I fix this error?
SparkSession is available in spark 2. No need to create sparkcontext in spark version 2. sparksession itself provides the gateway to all .
Try below as you are using version 1.x:
val df_fc = sqlCtx.read.format("com.databricks.spark.csv").option("header", "true").load("/home/Desktop/test.csv")
I have tried to write a transform method from DataFrame to DataFrame.
And I also want to test it by scalatest.
As you know, in Spark 2.x with Scala API, you can create SparkSession object as follows:
import org.apache.spark.sql.SparkSession
val spark = SparkSession.bulider
.config("spark.master", "local[2]")
.getOrCreate()
This code works fine with unit tests.
But, when I run this code with spark-submit, the cluster options did not work.
For example,
spark-submit --master yarn --deploy-mode client --num-executors 10 ...
does not create any executors.
I have found that the spark-submit arguments are applied when I remove config("master", "local[2]") part of the above code.
But, without master setting the unit test code did not work.
I tried to split spark (SparkSession) object generation part to test and main.
But there is so many code blocks needs spark, for example import spark.implicit,_ and spark.createDataFrame(rdd, schema).
Is there any best practice to write a code to create spark object both to test and to run spark-submit?
One way is to create a trait which provides the SparkContext/SparkSession, and use that in your test cases, like so:
trait SparkTestContext {
private val master = "local[*]"
private val appName = "testing"
System.setProperty("hadoop.home.dir", "c:\\winutils\\")
private val conf: SparkConf = new SparkConf()
.setMaster(master)
.setAppName(appName)
.set("spark.driver.allowMultipleContexts", "false")
.set("spark.ui.enabled", "false")
val ss: SparkSession = SparkSession.builder().config(conf).enableHiveSupport().getOrCreate()
val sc: SparkContext = ss.sparkContext
val sqlContext: SQLContext = ss.sqlContext
}
And your test class header then looks like this for example:
class TestWithSparkTest extends BaseSpec with SparkTestContext with Matchers{
I made a version where Spark will close correctly after tests.
import org.apache.spark.sql.{SQLContext, SparkSession}
import org.apache.spark.{SparkConf, SparkContext}
import org.scalatest.{BeforeAndAfterAll, FunSuite, Matchers}
trait SparkTest extends FunSuite with BeforeAndAfterAll with Matchers {
var ss: SparkSession = _
var sc: SparkContext = _
var sqlContext: SQLContext = _
override def beforeAll(): Unit = {
val master = "local[*]"
val appName = "MyApp"
val conf: SparkConf = new SparkConf()
.setMaster(master)
.setAppName(appName)
.set("spark.driver.allowMultipleContexts", "false")
.set("spark.ui.enabled", "false")
ss = SparkSession.builder().config(conf).getOrCreate()
sc = ss.sparkContext
sqlContext = ss.sqlContext
super.beforeAll()
}
override def afterAll(): Unit = {
sc.stop()
super.afterAll()
}
}
The spark-submit command with parameter --master yarn is setting yarn master.
And this will be conflict with your code master("x"), even using like master("yarn").
If you want to use import sparkSession.implicits._ like toDF ,toDS or other func,
you can just use a local sparkSession variable created like below:
val spark = SparkSession.builder().appName("YourName").getOrCreate()
without setting master("x") in spark-submit --master yarn, not in local machine.
I advice : do not use global sparkSession in your code. That may cause some errors or exceptions.
hope this helps you.
good luck!
How about defining an object in which a method creates a singleton instance of SparkSession, like MySparkSession.get(), and pass it as a paramter in each of your unit tests.
In your main method, you can create a separate SparkSession instance, which can have different configurations.
I have a Spark application which using Spark 2.0 new API with SparkSession.
I am building this application on top of the another application which is using SparkContext. I would like to pass SparkContext to my application and initialize SparkSession using existing SparkContext.
However I could not find a way how to do that. I found that SparkSession constructor with SparkContext is private so I can't initialize it in that way and builder does not offer any setSparkContext method. Do you think there exist some workaround?
Deriving the SparkSession object out of SparkContext or even SparkConf is easy. Just that you might find the API to be slightly convoluted. Here's an example (I'm using Spark 2.4 but this should work in the older 2.x releases as well):
// If you already have SparkContext stored in `sc`
val spark = SparkSession.builder.config(sc.getConf).getOrCreate()
// Another example which builds a SparkConf, SparkContext and SparkSession
val conf = new SparkConf().setAppName("spark-test").setMaster("local[2]")
val sc = new SparkContext(conf)
val spark = SparkSession.builder.config(sc.getConf).getOrCreate()
Hope that helps!
Like in the above example you cannot create because SparkSession's constructor is private
Instead you can create a SQLContext using the SparkContext, and later get the sparksession from the sqlcontext like this
val sqlContext=new SQLContext(sparkContext);
val spark=sqlContext.sparkSession
Hope this helps
Apparently there is no way how to initialize SparkSession from existing SparkContext.
public JavaSparkContext getSparkContext()
{
SparkConf conf = new SparkConf()
.setAppName("appName")
.setMaster("local[*]");
JavaSparkContext jsc = new JavaSparkContext(conf);
return jsc;
}
public SparkSession getSparkSession()
{
sparkSession= new SparkSession(getSparkContext().sc());
return sparkSession;
}
you can also try using builder
public SparkSession getSparkSession()
{
SparkConf conf = new SparkConf()
.setAppName("appName")
.setMaster("local");
SparkSession sparkSession = SparkSession
.builder()
.config(conf)
.getOrCreate();
return sparkSession;
}
val sparkSession = SparkSession.builder.config(sc.getConf).getOrCreate()
I am getting below exception if I do join in between two dataframes in spark (ver 1.5, scala 2.10).
Exception in thread "main" org.apache.spark.sql.AnalysisException: syntax error in attribute name: col1.;
at org.apache.spark.sql.catalyst.analysis.UnresolvedAttribute$.e$1(unresolved.scala:99)
at org.apache.spark.sql.catalyst.analysis.UnresolvedAttribute$.parseAttributeName(unresolved.scala:118)
at org.apache.spark.sql.catalyst.plans.logical.LogicalPlan.resolveQuoted(LogicalPlan.scala:182)
at org.apache.spark.sql.DataFrame.resolve(DataFrame.scala:158)
at org.apache.spark.sql.DataFrame.col(DataFrame.scala:653)
at com.nielsen.buy.integration.commons.Demo$.main(Demo.scala:62)
at com.nielsen.buy.integration.commons.Demo.main(Demo.scala)
Code works fine if column in dataframe does not contain any period . Please do help me out.
You can find the code that I am using.
import org.apache.spark.SparkConf
import org.apache.spark.SparkContext
import org.apache.spark.sql.SQLContext
import com.google.gson.Gson
import org.apache.spark.sql.types.StructType
import org.apache.spark.sql.types.StructField
import org.apache.spark.sql.types.StringType
import org.apache.spark.sql.Row
object Demo
{
lazy val sc: SparkContext = {
val conf = new SparkConf().setMaster("local")
.setAppName("demooo")
.set("spark.driver.allowMultipleContexts", "true")
new SparkContext(conf)
}
sc.setLogLevel("ERROR")
lazy val sqlcontext=new SQLContext(sc)
val data=List(Row("a","b"),Row("v","b"))
val dataRdd=sc.parallelize(data)
val schema = new StructType(Array(StructField("col.1",StringType,true),StructField("col2",StringType,true)))
val df1=sqlcontext.createDataFrame(dataRdd, schema)
val data2=List(Row("a","b"),Row("v","b"))
val dataRdd2=sc.parallelize(data2)
val schema2 = new StructType(Array(StructField("col3",StringType,true),StructField("col4",StringType,true)))
val df2=sqlcontext.createDataFrame(dataRdd2, schema2)
val val1="col.1"
val df3= df1.join(df2,df1.col(val1).equalTo(df2.col("col3")),"outer").show
}
In general, period is used to access members of a struct field.
The spark version you are using (1.5) is relatively old. Several such issues were fixed in later versions so if you upgrade it might just solve the issue.
That said, you can simply use withColumnRenamed to rename the column to something which does not have a period before the join.
So you basically do something like this:
val dfTmp = df1.withColumnRenamed(val1, "JOIN_COL")
val df3= dfTmp.join(df2,dfTmp.col("JOIN_COL").equalTo(df2.col("col3")),"outer").withColumnRenamed("JOIN_COL", val1)
df3.show
btw show returns a Unit so you probably meant df3 to be equal to the expression without it and do df3.show separately.