Order by two columns with different priority - Postgres - postgresql

Question

I want to be able to order users by two columns:
Number of followers they have
Number of the same following users that I am following - for similarity
Here's my query for now
SELECT COUNT(fSimilar.id) as similar_follow, COUNT(fCount.id) as followers_count, users.name FROM users
LEFT JOIN follows fSimilar ON fSimilar.user_id = users.id
AND fSimilar.following_id IN (
SELECT following_id FROM follows WHERE user_id = 1 // 1 is my user id
)
LEFT JOIN follows fCount ON fCount.following_id = users.id
WHERE users.name LIKE 'test%'
GROUP BY users.name
ORDER BY followers_count * 0.3 + similar_follow * 0.7 DESC
This selects people that follow the same people as me and also considers their popularity (amount of followers). This is similar to Instagram search.
I prioritise similar_follow by 70% or 0.7, and followers_count by 30%. However followers_count * 0.3 doesn't provide ordering integrity. For example some users have 1 - 10 million followers, this causes followers_count to be too large and similar_follow becomes too small to have any impact on ordering.
I have considered doing followers_count/500 where 500 is the average number of followers. However this still doesn't play well for ordering.
I need a way to equalise followers_count and similar_follow, so multiplication by percentages (0.3 and 0.7) makes a difference for both values.
I also looked at https://medium.com/hacking-and-gonzo/how-reddit-ranking-algorithms-work-ef111e33d0d9#.wuz8j0f4w which describes Wilson score interval but I am not sure if this is the right solution in my case, as I deal with 2 values (I might be wrong).
Thank you.

Answer 1

I usually use LOG() when normalizing data that has a large range. Also, to reiterate #Abelisto, your attempt to weight each column doesn't work in your implementation. Adding the 2 together should work.
for example:
...
ORDER BY LOG(followers_count) * 0.3 + LOG(similar_follow) * 0.7 DESC

Answer 2

What about multiplying by exponents (ie. similar_follow ^ 3.0 and followers_count ^ 1.5)?
Reference: https://www.postgresql.org/docs/9.1/static/functions-math.html

Answer 3

Thanks #ForRealHomie, I implemented a query that works. I'm still opened for other
suggestions :)
SELECT
users.id, users.name,
fSimilar.count + fPopular.count as followCount
FROM users
LEFT JOIN usernames ON usernames.user_id=users.id
LEFT JOIN (
SELECT LOG(COUNT(user_id) + 1) * 0.7 as count, user_id
FROM follows
WHERE username_id IN (SELECT username_id FROM follows WHERE user_id=1)
GROUP BY user_id
) fSimilar ON fSimilar.user_id = users.id
LEFT JOIN (SELECT LOG(COUNT(username_id) + 1) * 0.3 as count, username_id
FROM follows
GROUP BY username_id
) fPopular ON fPopular.username_id = usernames.id
WHERE users.id IN (2, 3 ,4)
ORDER BY followCount DESC
NB: LOG(COUNT(...) + 1), + 1 is needed in order to accept 0 values that are generated by COUNT, because LOG doesn't accept 0 so + 1 fixes the issue :)