I have these classes:
#Entity
public class Customer {
#Id long id;
String name;
#OneToMany List<Customer> related;
}
and I'm using this JPQL query:
select c from Customer c where c.name = 'ACME'
or exists( select 1 from c.related r where r.name = 'ACME' )
How can I write the same query with the Criteria API? I need to use exists with a subquery, like the JPQL, but I don't know how to create a subquery from a collection attribute in the Criteria API.
Something like this would give EXISTS (subquery)
Subquery<Long> sq = cq.subquery(Long.class);
Root<Customer> customerSub = sq.correlate(customer);
Join<Customer,Customer> related = customerSub.join(Customer_.related);
... extra config of subquery
Predicate existsCustomer = cb.exists(sq);
where cq is the CriteriaQuery, and cb is CriteriaBuilder. This comes from an example in the JPA 2.1 spec p323 Example 4
Related
I have this SQL query for MariaDB.
select #ref:=id as id, unique_id, reference_id
from mytable
join (select #ref:=id from mytable WHERE unique_id = 55544)tmp
where reference_id=#ref
https://www.db-fiddle.com/f/jKJodfVfvw65aMaVDyFySd/0
How this query can be implemented in HQL query? I would like to use it in JPA?
(Answer largely re-written after comments below)
JPA doesn't have built-in support for hierarchical queries. The main option is a native query.
E.g. with this entity class:
#Entity
public class MyTable {
#Id
#GeneratedValue
private int id;
private int uniqueId;
#ManyToOne
private MyTable reference;
// ... getters and setters ...
}
The following is an example of a native hierachical SQL query (actually against MySQL, just in case):
Query query = entityManager.createNativeQuery(
"select #ref\\:=id as id, unique_id, reference_id\r\n" +
"from my_table\r\n" +
"join (select #ref\\:=?)tmp\r\n" +
"where reference_id=#ref",
MyTable.class);
query.setParameter(1, 1);
query.getResultList();
This was chasing down a chain of references successfully.
(Other alternatives)
There probably aren't too many other options that can do this as a single query. If scalability is less of a concern, adding a back reference would be a simple way to navigate the model:
#OneToMany(mappedBy = "reference")
private Set<MyTable> backReferences;
Those would then be straightforward to recursively navigate. Clearly the relation defaults to lazy loading, so would add little overhead until used.
With #df778899's MyTable in spring-data it could look like:
#Repository
public interface MyRepository extends ...
#Query("select #ref:=id as id, unique_id, reference_id "+
"from mytable join (select #ref:=id from mytable WHERE unique_id = :pUid) tmp "+
"where reference_id=#ref", //just copy paste the query, use :pUid instead of constant...
nativeQuery = true) // and this!
List<MyTable> myCustomHirachicalQuery(#Param("pUid") Integer uid/*String/Long/...*/);
...
I want to find only the username field in my Registration collection
I am using the following query
db.Registration.find( {"username":"abcd"}, {username:1, _id:0} )
How will I write this query in hibernate?
If your entity looks like this:
#Entity
class Registration {
#Id
String id;
String username:
}
This should work:
String query = "FROM Registration r WHERE r.username = :username ORDER by r.username ASC, r.id DESC"
List<Registration> results = entityManager.createQuery( query )
.setParameter("username", "abcd")
.getResultList()
or
Registration results = entityManager.createQuery( query )
.setParameter("username", "abcd")
.getSingleResult()
You can also use native queries but I will let you to the documentation: https://docs.jboss.org/hibernate/ogm/5.4/reference/en-US/html_single/#ogm-mongodb-queries-native
You'll need to annotate the (none PK) columns you want to retrieve in the Entity with:
#Column(name = "username")
I use JPA 2.0 criteria builder. I need get data from one table and sort them by column from other. This tables have relations OneToMany:
class Club{
#OneToMany(mappedBy = "club")
private List<Address> addresses;
...
}
class Address{
#JoinColumn(name = "club_id", referencedColumnName = "id")
#ManyToOne(fetch = FetchType.LAZY)
private Club club;
#Column(name = "type")
private Long type;
#Column(name = "full_address")
private String full_address;
...
}
May be several address of some type but I need only one row of this specific address.
I write native queries with subquery, but it's has problem because subquery doesn't use in order clause and in select clause in JPA 2.0.
select c.full_name from club c
ORDER BY (select a.full_address from address a WHERE c.id= a.club_id and a.type=1 LIMIT 1)
select c.full_name, (select a.full_address from address a WHERE a.type=1 AND c.id=a.club_id LIMIT 1) as full_address FROM club c
ORDER BY fullAddress;
How I can replace native order by clause on JPA equivalent?
Thanks!
This native query also resolve problem and it can replace by JPA query
select c.full_name, min(a.full_address) FROM club c LEFT JOIN address a on c.id = a.club_id
where a.id is null or a.type=1 or not exists(SELECT 1 from address aSub WHERE aSub .club_id=c.id AND aSub.type=1)
GROUP BY c.id, c.full_name ORDER BY min(a.full_address);
JPA equivalent
CriteriaBuilder builder = em.getCriteriaBuilder();
CriteriaQuery<ClubItem> query = builder.createQuery(ClubItem.class);
Root<Club> root = query.from(Club.class);
Join<Club, Address> addressJoin = root.join(Club_.address, JoinType.LEFT);
query.select(builder.construct(ClubItem.class, root.get(Club_.id), root.get(Club_.fullName), builder.function("min", String.class, addressJoin.get(Address_.fullAddress))));
Subquery<Address> subquery = query.subquery(Address.class);
Root<Address> addressRoot = subquery.from(Address.class);
subquery.select(addressRoot);
subquery.where(
builder.and(
builder.equal(addressRoot.get(Address_.type), 1),
builder.equal(addressRoot.get(Address_.clubId), root.get(Club_.id))));
query.where(builder.or(builder.isNull(addressJoin), builder.equal(addressJoin.get(Address_.type), builder.literal(new Long(1))),
builder.not(builder.exists(subquery))));
query.groupBy(root.get(Club_.id), root.get(Club_.fullName))
Order order = builder.asc(builder.function("min", String.class, addressJoin.get(Address_.fullAddress)));
query.orderBy(order);
TypedQuery<ClubItem> contentQuery = em.createQuery(query);
It's not terribly elegant, but it gets the job done...
Make your "Club" class implement Comparable. Put the order-by logic into the Comparable. Then use Collections.sort(unsortedList) to get the list into sorted form. There's also a Collections.sort(unsortedList, Comparable) method which could be useful, especially if you are doing a bunch of similar methods that just vary on order-by.
I have a problem in JPQL cascade query with eclipselink2.5
please see code
Entity code
public class Category{
...
#JoinColumn(name = "parent_category", referencedColumnName = "id")
#ManyToOne(cascade = CascadeType.REFRESH, fetch = FetchType.EAGER,optional = true)
private Category parentCategory;
...
}
JPQL code
String jpql = "select o from Category o order by o.parentCategory.sort ASC";
problem
the problem is this JPQL return list does not include 'o' if 'o.parentCategory' is null.
please see this table http://i.stack.imgur.com/xsXvk.jpg
the return list only rows id is 2,3,4 .
because the column parent_category is null, I lost rows 1,5,6
the correct result should be return all rows
Looking forward to your help！
Using o.parentCategory.sort in the order by clause forces an inner join which filters nulls. If you want nulls included, you will need to use an explicit outer join in the query:
"select o from Category o outer join o.parentCategory parentCategory order by parentCategory.sort ASC"
I have the following QueryDSL query:
QCustomer customer = QCustomer.customer;
BooleanBuilder builder = new BooleanBuilder();
builder.or(customer.person.name.containsIgnoreCase(query));
builder.or(customer.company.name.containsIgnoreCase(query));
return builder;
And I expect to get results from Persons that contains the name = query and/or Companies that contains the query parameter. But I get nothing.
This is my Customer class mapping:
#OneToOne(orphanRemoval = false, optional = true, cascade = CascadeType.ALL)
private Company company;
#OneToOne(orphanRemoval = false, optional = true, cascade = CascadeType.ALL)
private Person person;
Did someone knows what I'm missing here?
I expect to get a query like this:
select o
from Customer
where o.person.name like '%:name%' or o.company.name like '%:name%'
This is the generated query:
select
count(customer0_.uid) as col_0_0_
from
Customer customer0_
cross join
Person person1_
cross join
Company company2_
where
customer0_.person_uid=person1_.uid
and customer0_.company_uid = company2_.uid
and (lower(person1_.name) like ? escape '!' or lower(company2_.name) like ? escape '!') limit ?
It uses a count because it's the first query that Spring Data use to paginate the result.
The query looks ok. Most probably you get wrong results because the implicit property based joins make the joins inner joins.
Using left joins you might get the results you need.
QPerson person = QPerson.person;
QCompany company = QCompany.company;
BooleanBuilder builder = new BooleanBuilder();
builder.or(person.name.containsIgnoreCase(str));
builder.or(company.name.containsIgnoreCase(str));
query.from(customer)
.leftJoin(customer.person, person)
.leftJoin(customer.company, company)
.where(builder);