Powershell script to print file-path of every file in a folder - powershell

Question

I have 2 folders: 'Old' and 'New'. Most of the files from 'Old' have been copied to 'New'. However, the structure of the sub-folders in 'Old' and 'New" are different. So the file-path for a file in 'Old' is very different from its copy in 'New'.
I need to loop through each file in 'Old', search for that file in 'New', and write the old and new file-paths for each file to a text file.
I have been assigned to do this manually, but it will take a long time due to the number of files. So I want to write a script. I am new to Powershell and am having difficulty figuring out which cmdlets can help me with my task.
I will appreciate any kind of guidance. Thank you.

Answer 1

try Something like this
#list old files
$patholdfile="c:\temp"
$listoldfile=Get-ChildItem $patholdfile -File -Recurse | select Name, FullName
#list new files
$pathnewfile="c:\temp2"
$listnewfile=Get-ChildItem $pathnewfile -File -Recurse | select Name, FullName
#extract liste file old and name and search all file in newlist
$resultsearch=#()
foreach ($currentfile in $listoldfile)
{
$resultsearch+=New-Object psobject -Property #{
Name=$currentfile.Name
OldPath=$currentfile.FullName
#if you want the firt founded uncomment this and comment after
#NewPaths=($listnewfile | Where {$_.Name -eq $currentfile.Name} | select FullName -First 1).FullName
NewPaths=($listnewfile | Where {$_.Name -eq $currentfile.Name} | select FullName).FullName -join "~"
}
}
#export result in csv file
$resultsearch | select name, OldPath , NewPaths | export-csv -Path "c:\temp\result.txt" -NoTypeInformation