Find distinct tree hierarchy - tsql

I have DB with following tables and relations:
Trunk (1..n) Branch (1..n) Twig (0..n) Leaf
Branch, Twig and Leaf have similar columns.
For example Twig has columns:
id, branchID, name, description, key1, key2, key3
I don't care about name and description, but I care about key 1 - 3
My goal is to find distinct tree structure (or hierarchy) and get Trunk IDs that follow same tree configuration.
Same tree configuration means:
each Trunk has same number of Branches (1 - n)
Branches have same key values (but can have different name and description)
each Branch has same number of Twigs (1 -n)
Twigs have same key values (but can have different name and description)
each Twig has same number of Leafs (0 - n)
Leaf have same key values (but can have different name and description)
When I join all tables (Trunk, Branch, Twig and left join Leaf) and group them by relevant key values
I only get Trunks that share a specific Trunk-to-Leaf combination but they might differ in another branch (or miss it altogether)
Now I have 500 Trunks, while there might be only 8 different tree configurations.
My expected result would be: TrunkID - TreeConfiguration (1 - 8)

Related

Neo4J - How to merge nodes with the same attribute value (name) but different node labels

I currently have duplicate name values across different node labels and I want to merge them. The issue is that every question I've found online assumes that BOTH the attribute name and the labels are the same. The code I've executed to query the instances I'm referring to is:
MATCH (a)-[r:FEATURED_IN]->(b) WHERE a.name = b.name AND id(a) <> id(b)
So that means that 'a' is featured in 'b', obviously 'a' and 'b' refer to the different node labels but the values are the same. How can I perform a merge to ensure that the 'b' node is deleted and only the 'a' node is returned? I know I could do this manually but there are so many instances of this that I would like to find a quick fix.
Thanks in advance.
You can collect all names in the nodes and combine them. Then UNWIND (it is like a For loop) and return distinct name.
MATCH (a)-[r:SYN_OF]->(b) WHERE a.name = b.name AND id(a) <> id(b)
WITH collect(distinct a.name) + collect(distinct b.name) as names
UNWIND names as name
RETURN distinct name
Result:
╒═══════════╕
│"name" │
╞═══════════╡
│"Same Name"│
└───────────┘

Reference foreign keys using SSIS-Lookup

I am asking for help on the following topic. I am trying to create an ETL process with two Excel data sources (S1 ~300 rows and S2 ~7000 rows). S1 contains project information and employee details and S2 contains the amount of hours, which each employee worked in which project at a timestamp.
I want to insert the amount of hours, which each employee worked in each project at a timestamp, into the fact table by referencing to the existing primary keys in the dimension tables. If an entry is not present in the dimension tables already, i want to add a new entry first and use the newly generated id. The destination table structure looks as follows (Data Warehouse, Star Schema):Destination Table Structure
In SSIS, i created three Data Flow tasks for filling the Dimension Tables (project, employee and time) with distinct values (using group by, as S1 and S2 contain a lot of duplicate rows)first, and a fourth data flow task (see image below) to insert the FactTable data, and this is where I'm running into problems:
Data Flow Task FactTable
I am using three LookUp functions to retrieve the foreignKeys project_id, employee_id and time_id from the Dimension tables (using project name, employee number and timestamp). If the id is found, it is passed on all the way to Merge Join 1, if not, a new Dimension Entry is created (lets say project) and the generated project_id passed on instead. Same goes for employee and time respectively.
There is two issues with this:
1) The "amount of hours" (passed by Multicast four, see image above) is not matched in the final result (No Match)
2) The amount of rows being inserted keeps increasing forever (Endless Join, I belive due to the Merge joins).
What I've tried:
I have used one UNION instead of three Merge Joins before, but this resulted in the foreign keys being in seperate rows each, instead of merged together.
I used Merge (instead of Merge Join) and combined the join as well as sort conditions in as I fell all possible ways.
I understand that this scenario might be confusing for everybody else, but thank your for taking time looking at it! Any help is greatly appreciated.
Solved it
For anybody having similar issues:
Seperate Data Flows for filling Dimension Tables with those filling Fact Tables will do the trick.
Its a clean solution and easier to debug.
Also: Dont run the LookUp Functions in parallel, but rather one after each other and pass on the attributes. Saves unnecessary Merges as well.
So as a Sum Up:
Four Data Flow Tasks, three for filling dimension tables ONLY and one for filling fact tables ONLY.
Loading Multiple Tables using SSIS keeping foreign key relationships
The answer posted by onupdatecascade is basically it.
Good luck!

CASE in JOIN not working PostgreSQL

I got the following tables:
Teams
Matches
I want to get an output like:
matches.semana | teams.nom_equipo | teams.nom_equipo | Winner
1 AMERICA CRUZ AZUL AMERICA
1 SANTOS MORELIA MORELIA
1 LEON CHIVAS LEON
The columns teams.nom_equipo reference to matches.num_eqpo_lo & to matches.num_eqpo_v and at the same time they reference to the column teams.nom_equipo to get the name of each team based on their id
Edit: I have used the following:
SELECT m.semana, t_loc.nom_equipo AS LOCAL, t_vis.nom_equipo AS VISITANTE,
CASE WHEN m.goles_loc > m.goles_vis THEN 'home'
WHEN m.goles_vis > m.goles_loc THEN 'visitor'
ELSE 'tie'
END AS Vencedor
FROM matches AS m
JOIN teams AS t_loc ON (m.num_eqpo_loc = t_loc.num_eqpo)
JOIN teams AS t_vis ON (m.num_eqpo_vis = t_vis.num_eqpo)
ORDER BY m.semana;
But as you can see from the table Matches in row #5 from the goles_loc column (home team) & goles_vis (visitor) column, they have 2 vs 2 (number of goals - home vs visitor) being a tie but and when I run the code I get something that is not a tie:
Matches' score
Resultset from Select:
I also noticed that since the row #5 the names of both teams in the matches are not correct (both visitor & home team).
So, the Select brings correct data but in other order different than the original order (referring to the order from the table matches)
The order from the second week must be:
matches.semana | teams.nom_equipo | teams.nom_equipo | Winner
5 2 CRUZ AZUL TOLUCA TIE
6 2 MORELIA LEON LEON
7 2 CHIVAS SANTOS TIE
Row 8 from the Resultset must be Row # 5 and so on.
Any help would be really thanked!
When doing a SELECT which includes null for a column, that's the value it will always be, so winner in your case will never be populated.
Something like this is probably more along the lines of what you want:
SELECT m.semana, t_loc.nom_equipo AS loc_equipo, t_vis.nom_equipo AS vis_equipo,
CASE WHEN m.goles_loc - m.goles_vis > 0 THEN t_loc.nom_equipo
WHEN m.goles_vis - m.goles_loc > 0 THEN t_vis.nom_equipo
ELSE NULL
END AS winner
FROM matches AS m
JOIN teams AS t_loc ON (m.nom_eqpo_loc = t.num_eqpo)
JOIN teams AS t_vis ON (m.nom_eqpo_vis = t.num_eqpo)
ORDER BY m.semana;
Untested, but this should provide the general approach. Basically, you JOIN to the teams table twice, but using different conditions, and then you need to calculate the scores. I'm using NULL to indicate a tie, here.
Edit in response to comment from OP:
It's the same table -- teams -- but the JOINs produce different results, because the query uses different JOIN conditions in each JOIN.
The first JOIN, for t_loc, compares m.nom_eqpo_loc to t.num_eqpo. This means it gets the teams rows for the home team.
The second JOIN, for t_vis, compares m.nom_eqpo_vis to t.num_eqpo. This means it gets the teams rows for the visting team.
Therefore, in the CASE statement, t_loc refers to the home team, while t_vis refers to the visting one, enabling both to be used in the CASE statement, enabling the correct name to be found for winning.
Edit in response to follow-up comment from OP:
My original query was sorting by m.semana, which means other columns can appear in any order (essentially whichever Postgres feels is most efficient).
If you want the resulting table to be sorted exactly the same way as the matches table, then use the same ORDER BY tuple in its ORDER BY.
So, the ORDER BY clause would then become:
ORDER BY m.semana, m.nom_eqpo_loc, m.nom_eqpo_vis
Basically, the matches table PRIMARY KEY tuple.

Merge neo4j relationships into one while returning the result if certain condition satisfies

My use case is:
I have to return whole graph in result but the condition is
If there are more than 1 relationship in between two particular nodes in the same direction then I have to just merge it into 1 relationship. For ex: Lets say there are two nodes 'm' and 'n' and there are 3 relations in between these nodes say r1, r2, r3 (in the same direction) then when I get the result after firing cypher query I should get only 1 relation in between 'n' and 'm'.
I need to perform some operations on top of it like the resultant relation that we got from merging all the relations should contain the properties and their values that I want to retain. Actually I will retain all the properties of any one of the relations that are merging depending upon the timestamp field that is one of the properties in relation.
Note : I have same properties throughout all my relations (The number of properties and name of properties are same across all relations. Values may differ for sure)
Any help would be appreciated. Thanks in advance.
You mean something like this?
Delete all except the first
MATCH (a)-[r]->(b)
WITH a,b,type(r) as type, collect(r) as rels
FOREACH (r in rels[1..] | DELETE r)
Ordering by timestamp first
MATCH (a)-[r]->(b)
WITH a,r,b
ORDER BY r.timestamp DESC
WITH a,b,type(r) as type, collect(r) as rels
FOREACH (r in rels[1..] | DELETE r)
If you want to do all those operations virtually just on query results you'd do them in your programming language of choice.

what's the utility of array type?

I'm totally newbie with postgresql but I have a good experience with mysql. I was reading the documentation and I've discovered that postgresql has an array type. I'm quite confused since I can't understand in which context this type can be useful within a rdbms. Why would I have to choose this type instead of using a classical one to many relationship?
Thanks in advance.
I've used them to make working with trees (such as comment threads) easier. You can store the path from the tree's root to a single node in an array, each number in the array is the branch number for that node. Then, you can do things like this:
SELECT id, content
FROM nodes
WHERE tree = X
ORDER BY path -- The array is here.
PostgreSQL will compare arrays element by element in the natural fashion so ORDER BY path will dump the tree in a sensible linear display order; then, you check the length of path to figure out a node's depth and that gives you the indentation to get the rendering right.
The above approach gets you from the database to the rendered page with one pass through the data.
PostgreSQL also has geometric types, simple key/value types, and supports the construction of various other composite types.
Usually it is better to use traditional association tables but there's nothing wrong with having more tools in your toolbox.
One SO user is using it for what appears to be machine-aided translation. The comments to a follow-up question might be helpful in understanding his approach.
I've been using them successfully to aggregate recursive tree references using triggers.
For instance, suppose you've a tree of categories, and you want to find products in any of categories (1,2,3) or any of their subcategories.
One way to do it is to use an ugly with recursive statement. Doing so will output a plan stuffed with merge/hash joins on entire tables and an occasional materialize.
with recursive categories as (
select id
from categories
where id in (1,2,3)
union all
...
)
select products.*
from products
join product2category on...
join categories on ...
group by products.id, ...
order by ... limit 10;
Another is to pre-aggregate the needed data:
categories (
id int,
parents int[] -- (array_agg(parent_id) from parents) || id
)
products (
id int,
categories int[] -- array_agg(category_id) from product2category
)
index on categories using gin (parents)
index on products using gin (categories)
select products.*
from products
where categories && array(
select id from categories where parents && array[1,2,3]
)
order by ... limit 10;
One issue with the above approach is that row estimates for the && operator are junk. (The selectivity is a stub function that has yet to be written, and results in something like 1/200 rows irrespective of the values in your aggregates.) Put another way, you may very well end up with an index scan where a seq scan would be correct.
To work around it, I increased the statistics on the gin-indexed column and I periodically look into pg_stats to extract more appropriate stats. When a cursory look at those stats reveal that using && for the specified values will return an incorrect plan, I rewrite applicable occurrences of && with arrayoverlap() (the latter has a stub selectivity of 1/3), e.g.:
select products.*
from products
where arrayoverlap(cat_id, array(
select id from categories where arrayoverlap(parents, array[1,2,3])
))
order by ... limit 10;
(The same goes for the <# operator...)