Compute points from Bezier Path - swift

Question

Let's say I have a random bezier path, like this:
let bezierPath = UIBezierPath()
bezierPath.move(to: CGPoint(x: 3, y: 0.84))
bezierPath.addCurve(to: CGPoint(x: 11, y: 8.84), controlPoint1: CGPoint(x: 3, y: 1.84), controlPoint2: CGPoint(x: 9, y: 4.59))
// [...]
bezierPath.addCurve(to: CGPoint(x: 3, y: 0.84), controlPoint1: CGPoint(x: 7, y: 4.84), controlPoint2: CGPoint(x: 3, y: -0.16))
bezierPath.close()
I would like to create a function that compute a CGPoint for a given percentage, where 0% is the first point and 100% the last point of the bezierPath:
extension UIBezierPath {
func getPointFor(percentage: Float) -> CGPoint {
//Computation logic
return result
}
}
I have found this post but the solution doesn't allow me to get all points (position at 15.5% of the path for example).
Is there a way to do this?

Answer 1

I have found a solution written in objective-c. You can find the source code here.
I manage to use it by using a bridging header :
#ifndef bridging_header_h
#define bridging_header_h
#import "UIBezierPath+Length.h"
#endif /* bridge_header_h */
And you can use the two functions like this:
print("length=\(bezierPath.length())")
for i in 0...100 {
let percent:CGFloat = CGFloat(i) / 100.0
print("point at [\(percent)]=\(bezierPath.point(atPercentOfLength: percent))")
}
output:
length=143.316117804497
point at [0.0]=(3.0, 0.839999973773956)
point at [0.01]=(3.26246070861816, 1.29733419418335)
point at [0.02]=(3.97137236595154, 1.91627132892609)
point at [0.03]=(5.00902938842773, 2.69386911392212)
[...]
point at [0.99]=(3.27210903167725, 0.765813827514648)
point at [1.0]=(3.0, 0.839999973773956)