How can i create a Perl subroutine which would take in an array and find the longest common prefix for 2 or more of its elements? (strings)
I have this code:
sub longest_common_prefix {
$prefix = shift;
for (#_) {
chop $prefix while (! /^\Q$prefix\E/);
}
return $prefix;
}
But it only works if you are looking for the longest common prefix of all strings.
For example, if i pass an array with the following strings:
aaaBGFB
aaaJJJJ
jjfkBBB
aaaHGHG
I want it to return aaa as the answer.
Thanks!
I'd use a modified trie.
Normally, one could use the following to add to a trie:
sub add {
my $p = \shift;
my $s = shift;
$p = \( $$p->{$_} ) for split(//, $s);
$$p->{''} = 1;
}
But we need two modifications:
All prefixes of a string must be added when adding a string. For example, adding abc should also add a and ab to the trie.
When adding to the trie, we want to return the length of previously-existing part of the path taken.
So we need:
sub add {
my $p = \shift;
my $s = shift;
my $cp_len = 0;
for (split(//, $s)) {
$p = \( $$p->{$_} );
++$cp_len if $$p->{$_}{''};
$$p->{''} = 1;
}
return $cp_len;
}
Combine (an optimized version of) this with an algorithm to find the longest strings in a list and with an algorithm to remove duplicate strings from a list to get the following solution:
use strict;
use warnings;
use feature qw( say );
sub add {
my $p = \shift;
my $s = shift;
my $cp_len = 0;
for (split(//, $s)) {
++$cp_len if exists($$p->{$_});
$p = \( $$p->{$_} );
}
return $cp_len;
}
my $t;
my $lcp_len = 0; # lcp = longest common prefix
my %lcps;
while (<>) {
chomp;
my $cp_len = add($t, $_)
or next;
if ($cp_len >= $lcp_len) {
if ($cp_len > $lcp_len) {
$lcp_len = $cp_len;
%lcps = ();
}
$lcps{ substr($_, 0, $cp_len) } = 1;
}
}
my #lcps = sort keys %lcps;
if (#lcps) {
say "Longest common prefix(es): #lcps";
} else {
say "No common prefix";
}
Data:
abc
abc
abcd
abcde
hijklx
hijkly
mnopqx
mnopqy
Output:
Longest common prefix(es): hijkl mnopq
The time taken by the above is proportional to the number of input characters.
One way would be to store the information in a hash. In this example, I set the hash key to the length of each prefix, and the value being the actual prefix found.
Note that this method overwrites a key and value if a same-length prefix exists, so you'll always get the last prefix found of the longest length (sort() takes care of finding the longest one).
The regex says "find the first character in the string and capture it, and use that char found in a second capture, and capture as many as there are". This string is then join()ed into a scalar and put into the hash.
use warnings;
use strict;
my %prefixes;
while (<DATA>){
my $prefix = join '', /^(.)(\1+)/;
$prefixes{length $prefix} = $prefix;
}
my $longest = (sort {$b <=> $a} keys %prefixes)[0];
print "$prefixes{$longest}\n";
__DATA__
aaBGFB
aaaJJJJ
jjfkBBB
aaaHGHG
Output:
aaa
You can keep a hash of an array of words keyed by the first character. By definition, if you have words starting with the same letter, those words share at least a one character common prefix of that one letter. Then reduce to the single longest prefix by stepping through the hash by character:
use strict; use warnings;
sub lcp {
(join("\0", #_) =~ /^ ([^\0]*) [^\0]* (?:\0 \1 [^\0]*)* $/sx)[0];
}
my %HoA;
my $longest='';
while (my $line=<DATA>){
$line =~ s/^\s+|\s+$//g ;
push #{ $HoA{substr $line, 0, 1} }, $line if $line=~/^[a-zA-Z]/;
}
for my $key ( sort (keys %HoA )) {
if (scalar #{ $HoA{$key} } > 1){
my $lon=lcp(#{ $HoA{$key} });
my $s = join ', ', map { qq/"$_"/ } #{ $HoA{$key} };
print "lcp: \"$lon\" for ($s)\n";
if (length($lon) > length($longest)) {
$longest=$lon;
}
}
else{
print "$key: no common prefix\n";
}
}
print "\nlongest common prefix is \"$longest\"\n";
__DATA__
aardvark
aaaBGFB
aaaJJJJ
jjfkBBB
aaaHGHG
interspecies
interstellar
interstate
Prints:
lcp: "aa" for ("aardvark", "aaaBGFB", "aaaJJJJ", "aaaHGHG")
lcp: "inters" for ("interspecies", "interstellar", "interstate")
j: no common prefix
longest common prefix is "inters"
Related
I want to alternate between upper and lower case, however I only managed to get the whole string upper or lower, or the first character.
I have not found a proper function to execute what I need. Please have a look and help me out. Cheers.
#!/usr/bin/perl
my $mystring = "this is my string I want each character to alternate between upper and lowercase";
my #myarray = split("", $mystring);
print ucfirst("#myarray");
A more general approach using function factory
use strict;
use warnings;
sub periodic {
my #subs = #_;
my $i = 0;
return sub {
$i = 0 if $i > $#subs;
return $subs[$i++]->(#_);
};
}
my $mystring = "this is my string I want each character to alternate between upper and lowercase";
my $f = periodic(
sub { uc pop },
sub { lc pop },
# sub { .. },
# sub { .. },
);
$mystring =~ s/([a-z])/ $f->($1) /egi;
print $mystring, "\n";
output
ThIs Is My StRiNg I wAnT eAcH cHaRaCtEr To AlTeRnAtE bEtWeEn UpPeR aNd LoWeRcAsE
How about:
my $mystring = "this is my string I want each character to alternate between upper and lowercase";
my #myarray = split("", $mystring);
my $cnt = 1;
for (#myarray) {
next unless /[a-z]/i;
$_ = ($cnt%2 ? uc($_) : lc($_));
$cnt++;
}
say join('',#myarray);
Output:
ThIs Is My StRiNg I wAnT eAcH cHaRaCtEr To AlTeRnAtE bEtWeEn UpPeR aNd LoWeRcAsE
My first thought was to use a regex substitution. Try this:
use strict;
use warnings;
my $str = "this string, I will change";
# Ignore whitespace and punctuation.
$str =~ s/(\w)(\w)/\L$1\U$2/g;
# Or include all characters in the uc/lc alternation.
# $str =~ s/(.)(.)/\L$1\U$2/g;
print $str, "\n";
If, for some reason, you wish to avoid regexes, try:
my $str = "this string, I will change";
my #ary;
my $count = 0;
for my $glyph ( split //, lc $str ) {
$glyph = uc $glyph if $count % 2;
push #ary, $glyph;
$count++;
}
print join( "", #ary ), "\n";
Try this:
use strict;
use warnings;
use 5.016;
use Data::Dumper;
my $str = 'hello';
my $x = 0;
$str =~ s/(.)/($x++ % 2 == 0) ? "\U$1" : "\L$1"/eg;
say $str;
--output:--
HeLlO
Save script below with name alter.pl
#!/usr/bin/perl
print#ARGV[0]=~s/([a-z])([^a-z]*)([a-z])/uc($1).$2.lc$3/egri
And run script by command
$ perl alter.pl "this is my string I want each character to alternate between upper and lowercase"
Output
ThIs Is My StRiNg I wAnT eAcH cHaRaCtEr To AlTeRnAtE bEtWeEn UpPeR aNd LoWeRcAse
You have some good answers already but I thought I'd chip in because I hadn't seen map yet.
print map { $c++ % 2 ? lc : uc } split ( //, $mystring );
splits $mystring into characters (split //);
uses map to apply a function to each letter.
uses $c++ to autoincrement, then take a modulo 2 to decide if this should be uppercase or lower case.
join the resultant array.
Gives:
#!c:\Strawberry\perl\bin
use strict;
use warnings;
my $mystring = "this is my string I want each character to alternate between upper and lowercase";
my $c;
print join ( "", map { $c++ % 2 ? lc : uc } split ( //, $mystring ));
Prints:
ThIs iS My sTrInG I WaNt eAcH ChArAcTeR To aLtErNaTe bEtWeEn uPpEr aNd lOwErCaSe
map is a useful function that applies some code to each element in a list, and then 'returns' the list that's produced. So if we treat your string as a list of characters, it works nicely.
Try this. simple if else condition enough for this
my $mystring = "this is my string I want each character to alternate between upper and lowercase";
#xz = split( '', $mystring );
for ( $i = 0; $i < scalar #xz; $i++ ) {
if ( $i % 2 ) {
print uc "$xz[$i]";
}
else {
print "$xz[$i]";
}
}
Given this string:
<VACC-PROP-0><VACC-PROP-0><NUM><EXP-V-0><MIR-0><PREP>
What I want to do is to enumerate all possible ordered length like this:
<VACC-PROP-0><VACC-PROP-0><NUM><EXP-V-0><MIR-0><PREP>
<VACC-PROP-0><VACC-PROP-0><NUM><EXP-V-0><MIR-0>
<VACC-PROP-0><VACC-PROP-0><NUM><EXP-V-0>
<VACC-PROP-0><VACC-PROP-0><NUM>
<VACC-PROP-0><VACC-PROP-0>
<VACC-PROP-0>
<VACC-PROP-0><NUM><EXP-V-0><MIR-0><PREP>
<NUM><EXP-V-0><MIR-0><PREP>
<EXP-V-0><MIR-0><PREP>
<MIR-0><PREP>
<PREP>
Not that the above is done by hand. It's possible that I may be missing something.
But the idea is to identify all possible ordered tokens of all length (number of tokens).
I tried this code but failed, what's the best way to do it?
use Data::Dumper;
my $str = "<VACC-PROP-0><VACC-PROP-0><NUM><EXP-V-0><MIR-0><PREP>";
# Remove all the brackets
my #tokens = grep {!/^$/} split(/[><]/,$str);
# Print the combinations
foreach my $i (0 .. $#tokens) {
print join(" ", #tokens[0..$i]),"\n";
}
Execute here: https://eval.in/51023
You want nested loops of arbitrarily depth.
for my $use_token0 (0..1) {
for my $use_token1 (0..1) {
for my $use_token2 (0..1) {
...
}
}
}
For that, you use Algorithm::Loops's NestedLoops.
use Algorithm::Loops qw( NestedLoops );
my $str = "<VACC-PROP-0><VACC-PROP-0><NUM><EXP-V-0><MIR-0><PREP>";
my #tokens = split /(?<=>)(?=<)/, $str;
my $iter = NestedLoops([ ( [0,1] ) x #tokens ]);
while ( my #bools = $iter->() ) {
say #tokens[ grep $bools[$_], 0..$#tokens ];
}
Although, in this case, you could simply use
my $str = "<VACC-PROP-0><VACC-PROP-0><NUM><EXP-V-0><MIR-0><PREP>";
my #tokens = split /(?<=>)(?=<)/, $str;
for my $i (0 .. (1<<#tokens)-1) {
say #tokens[ grep $i & (1 << ($#tokens-$_)), 0..$#tokens ];
}
I have the following string:
$str = "list
XYZ
status1 : YES
value1 : 100
status2 : NO
value2 : 200
Thats all";
I want to convert it into a hash using a function which takes this string as input and returns a hash with status1 as key and YES as value for example.
How to do so?
And how to reference the returned hash?
Like always, there's more than one way to do it. Here come five.
Pure regular expressions (YEAH!)
I think this is the coolest one. The regex returns a list of all captures which is exactly the list we want to initialize the hash with:
my %regex = $str =~ /(\S+)\s*:\s*(\S+)/g;
Iterative
This is the most straightforward way for most programmers, I think:
my #lines = split /\R/ => $str;
my %iterative = ();
for (#lines) {
next unless /(\S+)\s*:\s*(\S+)/;
$iterative{$1} = $2;
}
Nothing to explain here. I first split the string in lines, then iterate over them, leaving out lines that don't look like foo : bar. Done.
List processing
Writing everything as a big list expression feels a little bit hackish, but maybe this is interesting to learn more ways to express stuff:
my %list = map { /(\S+)\s*:\s*(\S+)/ and $1 => $2 }
grep { /:/ }
split /\R/ => $str;
Read from right to left: Like in the example above we start with splitting the string in lines. grep filters the lines for : and in the final map I transform matching line strings in a list of length two, with a key and a value.
List reducing
Non-trivial use-cases of List::Util's reduce function are very rare. Here's one, based on the list approach from above, returning a hash reference:
my $reduced = reduce {
$a = { $a =~ /(\S+)\s*:\s*(\S+)/ } unless ref $a;
$a->{$1} = $2 if $b =~ /(\S+)\s*:\s*(\S+)/;
return $a;
} grep { /:/ } split /\R/ => $str;
State machine
Here's a funny one with regex usage for white-space separation only. It needs to keep track of a state:
# preparations
my $state = 'idle';
my $buffer = undef;
my %state = ();
my #words = split /\s+/ => $str;
# loop over words
for my $word (#words) {
# last word was a key
if ($state eq 'idle' and $word eq ':') {
$state = 'got_key';
}
# this is a value for the key in buffer
elsif ($state eq 'got_key') {
$state{$buffer} = $word;
$state = 'idle';
$buffer = undef;
}
# remember this word
else {
$buffer = $word;
}
}
Just for fun (note that I recommend using one of memowe's) here is one that (ab)uses the YAML:
#!/usr/bin/env perl
use strict;
use warnings;
use YAML;
my $str = "list
XYZ
status1 : YES
value1 : 100
status2 : NO
value2 : 200
Thats all";
$str = join "\n", grep { /:/ } split "\n", $str;
my $hash = Load "$str\n";
#!/usr/bin/perl
use warnings;
$\="\n";
sub convStr {
my $str = $_[0];
my %h1=();
while ($str =~m/(\w+)\s+:\s+(\w+)/g) {
$h1{$1} =$2;
}
return \%h1;
}
my $str = "list
XYZ
status1 : YES
value1 : 100
status2 : NO
value2 : 200
Thats all";
my $href=convStr($str);
foreach (keys(%$href)) {
print $_ , "=>", $href->{$_};
}
On running this, I get:
status2=>NO
value1=>100
status1=>YES
value2=>200
my %hhash;
my #lines = split /\s+\n/, $str;
foreach (#lines)
{
$_=~s/^\s+//g;
if(/:/)
{
$key=(split(/:/))[0];
$value=(split(/:/))[1];
$hhash{$key}=$value;
}
}
I want Perl (5.8.8) to find out what word has the most letters in common with the other words in an array - but only letters that are in the same place. (And preferably without using libs.)
Take this list of words as an example:
BAKER
SALER
BALER
CARER
RUFFR
Her BALER is the word that has the most letters in common with the others. It matches BAxER in BAKER, xALER in SALER, xAxER in CARER, and xxxxR in RUFFR.
I want Perl to find this word for me in an arbitrary list of words with the same length and case. Seems I've hit the wall here, so help is much appreciated!
What I've tried until now
Don't really have much of a script at the moment:
use strict;
use warnings;
my #wordlist = qw(BAKER SALER MALER BARER RUFFR);
foreach my $word (#wordlist) {
my #letters = split(//, $word);
# now trip trough each iteration and work magic...
}
Where the comment is, I've tried several kinds of code, heavy with for-loops and ++ varables. Thus far, none of my attempts have done what I need it to do.
So, to better explain: What I need is to test word for word against the list, for each letterposition, to find the word that has the most letters in common with the others in the list, at that letter's position.
One possible way could be to first check which word(s) has the most in common at letter-position 0, then test letter-position 1, and so on, until you find the word that in sum has the most letters in common with the other words in the list. Then I'd like to print the list like a matrix with scores for each letterposition plus a total score for each word, not unlike what DavidO suggest.
What you'd in effect end up with is a matrix for each words, with the score for each letter position, and the sum total score fore each word in the matrix.
Purpose of the Program
Hehe, I might as well say it: The program is for hacking terminals in the game Fallout 3. :D My thinking is that it's a great way to learn Perl while also having fun gaming.
Here's one of the Fallout 3 terminal hacking tutorials I've used for research: FALLOUT 3: Hacking FAQ v1.2, and I've already made a program to shorten the list of words, like this:
#!/usr/bin/perl
# See if one word has equal letters as the other, and how many of them are equal
use strict;
use warnings;
my $checkword = "APPRECIATION"; # the word to be checked
my $match = 4; # equal to the match you got from testing your checkword
my #checkletters = split(//, $checkword); #/
my #wordlist = qw(
PARTNERSHIPS
REPRIMANDING
CIVILIZATION
APPRECIATION
CONVERSATION
CIRCUMSTANCE
PURIFICATION
SECLUSIONIST
CONSTRUCTION
DISAPPEARING
TRANSMISSION
APPREHENSIVE
ENCOUNTERING
);
print "$checkword has $match letters in common with:\n";
foreach my $word (#wordlist) {
next if $word eq $checkword;
my #letters = split(//, $word);
my $length = #letters; # determine length of array (how many letters to check)
my $eq_letters = 0; # reset to 0 for every new word to be tested
for (my $i = 0; $i < $length; $i++) {
if ($letters[$i] eq $checkletters[$i]) {
$eq_letters++;
}
}
if ($eq_letters == $match) {
print "$word\n";
}
}
# Now to make a script on to find the best word to check in the first place...
This script will yield CONSTRUCTION and TRANSMISSION as its result, just as in the game FAQ. The trick to the original question, though (and the thing I didn't manage to find out on my own), is how to find the best word to try in the first place, i.e. APPRECIATION.
OK, I've now supplied my own solution based on your help, and consider this thread closed. Many, many thanks to all the contributers. You've helped tremendously, and on the way I've also learned a lot. :D
Here's one way. Having re-read your spec a couple of times I think it's what you're looking for.
It's worth mentioning that it's possible there will be more than one word with an equal top score. From your list there's only one winner, but it's possible that in longer lists, there will be several equally winning words. This solution deals with that. Also, as I understand it, you count letter matches only if they occur in the same column per word. If that's the case, here's a working solution:
use 5.012;
use strict;
use warnings;
use List::Util 'max';
my #words = qw/
BAKER
SALER
BALER
CARER
RUFFR
/;
my #scores;
foreach my $word ( #words ) {
my $score;
foreach my $comp_word ( #words ) {
next if $comp_word eq $word;
foreach my $pos ( 0 .. ( length $word ) - 1 ) {
$score++ if substr( $word, $pos, 1 ) eq substr( $comp_word, $pos, 1);
}
}
push #scores, $score;
}
my $max = max( #scores );
my ( #max_ixs ) = grep { $scores[$_] == $max } 0 .. $#scores;
say "Words with most matches:";
say for #words[#max_ixs];
This solution counts how many times per letter column each word's letters match other words. So for example:
Words: Scores: Because:
ABC 1, 2, 1 = 4 A matched once, B matched twice, C matched once.
ABD 1, 2, 1 = 4 A matched once, B matched twice, D matched once.
CBD 0, 2, 1 = 3 C never matched, B matched twice, D matched once.
BAC 0, 0, 1 = 1 B never matched, A never matched, C matched once.
That gives you the winners of ABC and ABD, each with a score of four positional matches. Ie, the cumulative times that column one, row one matched column one row two, three, and four, and so on for the subsequent columns.
It may be able to be optimized further, and re-worded to be shorter, but I tried to keep the logic fairly easy to read. Enjoy!
UPDATE / EDIT
I thought about it and realized that though my existing method does exactly what your original question requested, it did it in O(n^2) time, which is comparatively slow. But if we use hash keys for each column's letters (one letter per key), and do a count of how many times each letter appears in the column (as the value of the hash element), we could do our summations in O(1) time, and our traversal of the list in O(n*c) time (where c is the number of columns, and n is the number of words). There's some setup time too (creation of the hash). But we still have a big improvement. Here is a new version of each technique, as well as a benchmark comparison of each.
use strict;
use warnings;
use List::Util qw/ max sum /;
use Benchmark qw/ cmpthese /;
my #words = qw/
PARTNERSHIPS
REPRIMANDING
CIVILIZATION
APPRECIATION
CONVERSATION
CIRCUMSTANCE
PURIFICATION
SECLUSIONIST
CONSTRUCTION
DISAPPEARING
TRANSMISSION
APPREHENSIVE
ENCOUNTERING
/;
# Just a test run for each solution.
my( $top, $indexes_ref );
($top, $indexes_ref ) = find_top_matches_force( \#words );
print "Testing force method: $top matches.\n";
print "#words[#$indexes_ref]\n";
( $top, $indexes_ref ) = find_top_matches_hash( \#words );
print "Testing hash method: $top matches.\n";
print "#words[#$indexes_ref]\n";
my $count = 20000;
cmpthese( $count, {
'Hash' => sub{ find_top_matches_hash( \#words ); },
'Force' => sub{ find_top_matches_force( \#words ); },
} );
sub find_top_matches_hash {
my $words = shift;
my #scores;
my $columns;
my $max_col = max( map { length $_ } #{$words} ) - 1;
foreach my $col_idx ( 0 .. $max_col ) {
$columns->[$col_idx]{ substr $_, $col_idx, 1 }++
for #{$words};
}
foreach my $word ( #{$words} ) {
my $score = sum(
map{
$columns->[$_]{ substr $word, $_, 1 } - 1
} 0 .. $max_col
);
push #scores, $score;
}
my $max = max( #scores );
my ( #max_ixs ) = grep { $scores[$_] == $max } 0 .. $#scores;
return( $max, \#max_ixs );
}
sub find_top_matches_force {
my $words = shift;
my #scores;
foreach my $word ( #{$words} ) {
my $score;
foreach my $comp_word ( #{$words} ) {
next if $comp_word eq $word;
foreach my $pos ( 0 .. ( length $word ) - 1 ) {
$score++ if
substr( $word, $pos, 1 ) eq substr( $comp_word, $pos, 1);
}
}
push #scores, $score;
}
my $max = max( #scores );
my ( #max_ixs ) = grep { $scores[$_] == $max } 0 .. $#scores;
return( $max, \#max_ixs );
}
The output is:
Testing force method: 39 matches.
APPRECIATION
Testing hash method: 39 matches.
APPRECIATION
Rate Force Hash
Force 2358/s -- -74%
Hash 9132/s 287% --
I realize your original spec changed after you saw some of the other options provided, and that's sort of the nature of innovation to a degree, but the puzzle was still alive in my mind. As you can see, my hash method is 287% faster than the original method. More fun in less time!
As a starting point, you can efficiently check how many letters they have in common with:
$count = ($word1 ^ $word2) =~ y/\0//;
But that's only useful if you loop through all possible pairs of words, something that isn't necessary in this case:
use strict;
use warnings;
my #words = qw/
BAKER
SALER
BALER
CARER
RUFFR
/;
# you want a hash to indicate which letters are present how many times in each position:
my %count;
for my $word (#words) {
my #letters = split //, $word;
$count{$_}{ $letters[$_] }++ for 0..$#letters;
}
# then for any given word, you get the count for each of its letters minus one (because the word itself is included in the count), and see if it is a maximum (so far) for any position or for the total:
my %max_common_letters_count;
my %max_common_letters_words;
for my $word (#words) {
my #letters = split //, $word;
my $total;
for my $position (0..$#letters, 'total') {
my $count;
if ( $position eq 'total' ) {
$count = $total;
}
else {
$count = $count{$position}{ $letters[$position] } - 1;
$total += $count;
}
if ( ! $max_common_letters_count{$position} || $count >= $max_common_letters_count{$position} ) {
if ( $max_common_letters_count{$position} && $count == $max_common_letters_count{$position} ) {
push #{ $max_common_letters_words{$position} }, $word;
}
else {
$max_common_letters_count{$position} = $count;
$max_common_letters_words{$position} = [ $word ];
}
}
}
}
# then show the maximum words for each position and in total:
for my $position ( sort { $a <=> $b } grep $_ ne 'total', keys %max_common_letters_count ) {
printf( "Position %s had a maximum of common letters of %s in words: %s\n",
$position,
$max_common_letters_count{$position},
join(', ', #{ $max_common_letters_words{$position} })
);
}
printf( "The maximum total common letters was %s in words(s): %s\n",
$max_common_letters_count{'total'},
join(', ', #{ $max_common_letters_words{'total'} })
);
Here's a complete script. It uses the same idea that ysth mentioned (although I had it independently). Use bitwise xor to combine the strings, and then count the number of NULs in the result. As long as your strings are ASCII, that will tell you how many matching letters there were. (That comparison is case sensitive, and I'm not sure what would happen if the strings were UTF-8. Probably nothing good.)
use strict;
use warnings;
use 5.010;
use List::Util qw(max);
sub findMatches
{
my ($words) = #_;
# Compare each word to every other word:
my #matches = (0) x #$words;
for my $i (0 .. $#$words-1) {
for my $j ($i+1 .. $#$words) {
my $m = ($words->[$i] ^ $words->[$j]) =~ tr/\0//;
$matches[$i] += $m;
$matches[$j] += $m;
}
}
# Find how many matches in the best word:
my $max = max(#matches);
# Find the words with that many matches:
my #wanted = grep { $matches[$_] == $max } 0 .. $#matches;
wantarray ? #$words[#wanted] : $words->[$wanted[0]];
} # end findMatches
my #words = qw(
BAKER
SALER
BALER
CARER
RUFFR
);
say for findMatches(\#words);
Haven't touched perl in a while, so pseudo-code it is. This isn't the fastest algorithm, but it will work fine for a small amount of words.
totals = new map #e.g. an object to map :key => :value
for each word a
for each word b
next if a equals b
totals[a] = 0
for i from 1 to a.length
if a[i] == b[i]
totals[a] += 1
end
end
end
end
return totals.sort_by_key.last
Sorry about the lack of perl, but if you code this into perl, it should work like a charm.
A quick note on run-time: this will run in time number_of_words^2 * length_of_words, so on a list of 100 words, each of length 10 characters, this will run in 100,000 cycles, which is adequate for most applications.
Here's a version that relies on transposing the words in order to count the identical characters. I used the words from your original comparison, not the code.
This should work with any length words, and any length list. Output is:
Word score
---- -----
BALER 12
SALER 11
BAKER 11
CARER 10
RUFFR 4
The code:
use warnings;
use strict;
my #w = qw(BAKER SALER BALER CARER RUFFR);
my #tword = t_word(#w);
my #score;
push #score, str_count($_) for #tword;
#score = t_score(#score);
my %total;
for (0 .. $#w) {
$total{$w[$_]} = $score[$_];
}
print "Word\tscore\n";
print "----\t-----\n";
print "$_\t$total{$_}\n" for (sort { $total{$b} <=> $total{$a} } keys %total);
# transpose the words
sub t_word {
my #w = #_;
my #tword;
for my $word (#w) {
my $i = 0;
while ($word =~ s/(.)//) {
$tword[$i++] .= $1;
}
}
return #tword;
}
# turn each character into a count
sub str_count {
my $str = uc(shift);
while ( $str =~ /([A-Z])/ ) {
my $chr = $1;
my $num = () = $str =~ /$chr/g;
$num--;
$str =~ s/$chr/$num /g;
}
return $str;
}
# sum up the character counts
# while reversing the transpose
sub t_score {
my #count = #_;
my #score;
for my $num (#count) {
my $i = 0;
while( $num =~ s/(\d+) //) {
$score[$i++] += $1;
}
}
return #score;
}
Here is my attempt at an answer. This will also allow you to see each individual match if you need it. (ie. BALER matches 4 characters in BAKER). EDIT: It now catches all matches if there is a tie between words (I added "CAKER" to the list to test).
#! usr/bin/perl
use strict;
use warnings;
my #wordlist = qw( BAKER SALER BALER CARER RUFFR CAKER);
my %wordcomparison;
#foreach word, break it into letters, then compare it against all other words
#break all other words into letters and loop through the letters (both words have same amount), adding to the count of matched characters each time there's a match
foreach my $word (#wordlist) {
my #letters = split(//, $word);
foreach my $otherword (#wordlist) {
my $count;
next if $otherword eq $word;
my #otherwordletters = split (//, $otherword);
foreach my $i (0..$#letters) {
$count++ if ( $letters[$i] eq $otherwordletters[$i] );
}
$wordcomparison{"$word"}{"$otherword"} = $count;
}
}
# sort (unnecessary) and loop through the keys of the hash (words in your list)
# foreach key, loop through the other words it compares with
#Add a new key: total, and sum up all the matched characters.
foreach my $word (sort keys %wordcomparison) {
foreach ( sort keys %{ $wordcomparison{$word} }) {
$wordcomparison{$word}{total} += $wordcomparison{$word}{$_};
}
}
#Want $word with highest total
my #max_match = (sort { $wordcomparison{$b}{total} <=> $wordcomparison{$a}{total} } keys %wordcomparison );
#This is to get all if there is a tie:
my $maximum = $max_match[0];
foreach (#max_match) {
print "$_\n" if ($wordcomparison{$_}{total} >= $wordcomparison{$maximum}{total} )
}
The output is simply: CAKER BALER and BAKER.
The hash %wordcomparison looks like:
'SALER'
{
'RUFFR' => 1,
'BALER' => 4,
'BAKER' => 3,
'total' => 11,
'CARER' => 3
};
You can do this, using a dirty regex trick to execute code if a letter matches in its place, but not otherwise, thankfully it's quite easy to build the regexes as you go:
An example regular expression is:
(?:(C(?{ $c++ }))|.)(?:(A(?{ $c++ }))|.)(?:(R(?{ $c++ }))|.)(?:(E(?{ $c++ }))|.)(?:(R(?{ $c++ }))|.)
This may or may not be fast.
use 5.12.0;
use warnings;
use re 'eval';
my #words = qw(BAKER SALER BALER CARER RUFFR);
my ($best, $count) = ('', 0);
foreach my $word (#words) {
our $c = 0;
foreach my $candidate (#words) {
next if $word eq $candidate;
my $regex_str = join('', map {"(?:($_(?{ \$c++ }))|.)"} split '', $word);
my $regex = qr/^$regex_str$/;
$candidate =~ $regex or die "did not match!";
}
say "$word $c";
if ($c > $count) {
$best = $word;
$count = $c;
}
}
say "Matching: first best: $best";
Using xor trick will be fast but assumes a lot about the range of characters you might encounter. There are many ways in which utf-8 will break with that case.
Many thanks to all the contributers! You've certainly shown me that I still have a lot to learn, but you have also helped me tremendously in working out my own answer. I'm just putting it here for reference and possible feedback, since there are probably better ways of doing it. To me this was the simplest and most straight forward approach I could find on my own. Enjøy! :)
#!/usr/bin/perl
use strict;
use warnings;
# a list of words for testing
my #list = qw(
BAKER
SALER
BALER
CARER
RUFFR
);
# populate two dimensional array with the list,
# so we can compare each letter with the other letters on the same row more easily
my $list_length = #list;
my #words;
for (my $i = 0; $i < $list_length; $i++) {
my #letters = split(//, $list[$i]);
my $letters_length = #letters;
for (my $j = 0; $j < $letters_length; $j++) {
$words[$i][$j] = $letters[$j];
}
}
# this gives a two-dimensionla array:
#
# #words = ( ["B", "A", "K", "E", "R"],
# ["S", "A", "L", "E", "R"],
# ["B", "A", "L", "E", "R"],
# ["C", "A", "R", "E", "R"],
# ["R", "U", "F", "F", "R"],
# );
# now, on to find the word with most letters in common with the other on the same row
# add up the score for each letter in each word
my $word_length = #words;
my #letter_score;
for my $i (0 .. $#words) {
for my $j (0 .. $#{$words[$i]}) {
for (my $k = 0; $k < $word_length; $k++) {
if ($words[$i][$j] eq $words[$k][$j]) {
$letter_score[$i][$j] += 1;
}
}
# we only want to add in matches outside the one we're testing, therefore
$letter_score[$i][$j] -= 1;
}
}
# sum each score up
my #scores;
for my $i (0 .. $#letter_score ) {
for my $j (0 .. $#{$letter_score[$i]}) {
$scores[$i] += $letter_score[$i][$j];
}
}
# find the highest score
my $max = $scores[0];
foreach my $i (#scores[1 .. $#scores]) {
if ($i > $max) {
$max = $i;
}
}
# and print it all out :D
for my $i (0 .. $#letter_score ) {
print "$list[$i]: $scores[$i]";
if ($scores[$i] == $max) {
print " <- best";
}
print "\n";
}
When run, the script yields the following:
BAKER: 11
SALER: 11
BALER: 12 <- best
CARER: 10
RUFFR: 4
As per the title, I'm trying to find a way to programmatically determine the longest portion of similarity between several strings.
Example:
file:///home/gms8994/Music/t.A.T.u./
file:///home/gms8994/Music/nina%20sky/
file:///home/gms8994/Music/A%20Perfect%20Circle/
Ideally, I'd get back file:///home/gms8994/Music/, because that's the longest portion that's common for all 3 strings.
Specifically, I'm looking for a Perl solution, but a solution in any language (or even pseudo-language) would suffice.
From the comments: yes, only at the beginning; but there is the possibility of having some other entry in the list, which would be ignored for this question.
Edit: I'm sorry for mistake. My pity that I overseen that using my variable inside countit(x, q{}) is big mistake. This string is evaluated inside Benchmark module and #str was empty there. This solution is not as fast as I presented. See correction below. I'm sorry again.
Perl can be fast:
use strict;
use warnings;
package LCP;
sub LCP {
return '' unless #_;
return $_[0] if #_ == 1;
my $i = 0;
my $first = shift;
my $min_length = length($first);
foreach (#_) {
$min_length = length($_) if length($_) < $min_length;
}
INDEX: foreach my $ch ( split //, $first ) {
last INDEX unless $i < $min_length;
foreach my $string (#_) {
last INDEX if substr($string, $i, 1) ne $ch;
}
}
continue { $i++ }
return substr $first, 0, $i;
}
# Roy's implementation
sub LCP2 {
return '' unless #_;
my $prefix = shift;
for (#_) {
chop $prefix while (! /^\Q$prefix\E/);
}
return $prefix;
}
1;
Test suite:
#!/usr/bin/env perl
use strict;
use warnings;
Test::LCP->runtests;
package Test::LCP;
use base 'Test::Class';
use Test::More;
use Benchmark qw(:all :hireswallclock);
sub test_use : Test(startup => 1) {
use_ok('LCP');
}
sub test_lcp : Test(6) {
is( LCP::LCP(), '', 'Without parameters' );
is( LCP::LCP('abc'), 'abc', 'One parameter' );
is( LCP::LCP( 'abc', 'xyz' ), '', 'None of common prefix' );
is( LCP::LCP( 'abcdefgh', ('abcdefgh') x 15, 'abcdxyz' ),
'abcd', 'Some common prefix' );
my #str = map { chomp; $_ } <DATA>;
is( LCP::LCP(#str),
'file:///home/gms8994/Music/', 'Test data prefix' );
is( LCP::LCP2(#str),
'file:///home/gms8994/Music/', 'Test data prefix by LCP2' );
my $t = countit( 1, sub{LCP::LCP(#str)} );
diag("LCP: ${\($t->iters)} iterations took ${\(timestr($t))}");
$t = countit( 1, sub{LCP::LCP2(#str)} );
diag("LCP2: ${\($t->iters)} iterations took ${\(timestr($t))}");
}
__DATA__
file:///home/gms8994/Music/t.A.T.u./
file:///home/gms8994/Music/nina%20sky/
file:///home/gms8994/Music/A%20Perfect%20Circle/
Test suite result:
1..7
ok 1 - use LCP;
ok 2 - Without parameters
ok 3 - One parameter
ok 4 - None of common prefix
ok 5 - Some common prefix
ok 6 - Test data prefix
ok 7 - Test data prefix by LCP2
# LCP: 22635 iterations took 1.09948 wallclock secs ( 1.09 usr + 0.00 sys = 1.09 CPU) # 20766.06/s (n=22635)
# LCP2: 17919 iterations took 1.06787 wallclock secs ( 1.07 usr + 0.00 sys = 1.07 CPU) # 16746.73/s (n=17919)
That means that pure Perl solution using substr is about 20% faster than Roy's solution at your test case and one prefix finding takes about 50us. There is not necessary using XS unless your data or performance expectations are bigger.
The reference given already by Brett Daniel for the Wikipedia entry on "Longest common substring problem" is very good general reference (with pseudocode) for your question as stated. However, the algorithm can be exponential. And it looks like you might actually want an algorithm for longest common prefix which is a much simpler algorithm.
Here's the one I use for longest common prefix (and a ref to original URL):
use strict; use warnings;
sub longest_common_prefix {
# longest_common_prefix( $|# ): returns $
# URLref: http://linux.seindal.dk/2005/09/09/longest-common-prefix-in-perl
# find longest common prefix of scalar list
my $prefix = shift;
for (#_) {
chop $prefix while (! /^\Q$prefix\E/);
}
return $prefix;
}
my #str = map {chomp; $_} <DATA>;
print longest_common_prefix(#ARGV), "\n";
__DATA__
file:///home/gms8994/Music/t.A.T.u./
file:///home/gms8994/Music/nina%20sky/
file:///home/gms8994/Music/A%20Perfect%20Circle/
If you truly want a LCSS implementation, refer to these discussions (Longest Common Substring and Longest Common Subsequence) at PerlMonks.org. Tree::Suffix would probably be the best general solution for you and implements, to my knowledge, the best algorithm. Unfortunately recent builds are broken. But, a working subroutine does exist within the discussions referenced on PerlMonks in this post by Limbic~Region (reproduced here with your data).
#URLref: http://www.perlmonks.org/?node_id=549876
#by Limbic~Region
use Algorithm::Loops 'NestedLoops';
use List::Util 'reduce';
use strict; use warnings;
sub LCS{
my #str = #_;
my #pos;
for my $i (0 .. $#str) {
my $line = $str[$i];
for (0 .. length($line) - 1) {
my $char= substr($line, $_, 1);
push #{$pos[$i]{$char}}, $_;
}
}
my $sh_str = reduce {length($a) < length($b) ? $a : $b} #str;
my %map;
CHAR:
for my $char (split //, $sh_str) {
my #loop;
for (0 .. $#pos) {
next CHAR if ! $pos[$_]{$char};
push #loop, $pos[$_]{$char};
}
my $next = NestedLoops([#loop]);
while (my #char_map = $next->()) {
my $key = join '-', #char_map;
$map{$key} = $char;
}
}
my #pile;
for my $seq (keys %map) {
push #pile, $map{$seq};
for (1 .. 2) {
my $dir = $_ % 2 ? 1 : -1;
my #offset = split /-/, $seq;
$_ += $dir for #offset;
my $next = join '-', #offset;
while (exists $map{$next}) {
$pile[-1] = $dir > 0 ?
$pile[-1] . $map{$next} : $map{$next} . $pile[-1];
$_ += $dir for #offset;
$next = join '-', #offset;
}
}
}
return reduce {length($a) > length($b) ? $a : $b} #pile;
}
my #str = map {chomp; $_} <DATA>;
print LCS(#str), "\n";
__DATA__
file:///home/gms8994/Music/t.A.T.u./
file:///home/gms8994/Music/nina%20sky/
file:///home/gms8994/Music/A%20Perfect%20Circle/
It sounds like you want the k-common substring algorithm. It is exceptionally simple to program, and a good example of dynamic programming.
My first instinct is to run a loop, taking the next character from each string, until the characters are not equal. Keep a count of what position in the string you're at and then take a substring (from any of the three strings) from 0 to the position before the characters aren't equal.
In Perl, you'll have to split up the string first into characters using something like
#array = split(//, $string);
(splitting on an empty character sets each character into its own element of the array)
Then do a loop, perhaps overall:
$n =0;
#array1 = split(//, $string1);
#array2 = split(//, $string2);
#array3 = split(//, $string3);
while($array1[$n] == $array2[$n] && $array2[$n] == $array3[$n]){
$n++;
}
$sameString = substr($string1, 0, $n); #n might have to be n-1
Or at least something along those lines. Forgive me if this doesn't work, my Perl is a little rusty.
If you google for "longest common substring" you'll get some good pointers for the general case where the sequences don't have to start at the beginning of the strings.
Eg, http://en.wikipedia.org/wiki/Longest_common_substring_problem.
Mathematica happens to have a function for this built in:
http://reference.wolfram.com/mathematica/ref/LongestCommonSubsequence.html (Note that they mean contiguous subsequence, ie, substring, which is what you want.)
If you only care about the longest common prefix then it should be much faster to just loop for i from 0 till the ith characters don't all match and return substr(s, 0, i-1).
From http://forums.macosxhints.com/showthread.php?t=33780
my #strings =
(
'file:///home/gms8994/Music/t.A.T.u./',
'file:///home/gms8994/Music/nina%20sky/',
'file:///home/gms8994/Music/A%20Perfect%20Circle/',
);
my $common_part = undef;
my $sep = chr(0); # assuming it's not used legitimately
foreach my $str ( #strings ) {
# First time through loop -- set common
# to whole
if ( !defined $common_part ) {
$common_part = $str;
next;
}
if ("$common_part$sep$str" =~ /^(.*).*$sep\1.*$/)
{
$common_part = $1;
}
}
print "Common part = $common_part\n";
Faster than above, uses perl's native binary xor function, adapted from perlmongers solution (the $+[0] didn't work for me):
sub common_suffix {
my $comm = shift #_;
while ($_ = shift #_) {
$_ = substr($_,-length($comm)) if (length($_) > length($comm));
$comm = substr($comm,-length($_)) if (length($_) < length($comm));
if (( $_ ^ $comm ) =~ /(\0*)$/) {
$comm = substr($comm, -length($1));
} else {
return undef;
}
}
return $comm;
}
sub common_prefix {
my $comm = shift #_;
while ($_ = shift #_) {
$_ = substr($_,0,length($comm)) if (length($_) > length($comm));
$comm = substr($comm,0,length($_)) if (length($_) < length($comm));
if (( $_ ^ $comm ) =~ /^(\0*)/) {
$comm = substr($comm,0,length($1));
} else {
return undef;
}
}
return $comm;
}