Trying to use Spring with JPA and JTA with only Spring Annotation - spring-data-jpa

Question

I am setting up an application that accept a REST call and then does some DB work. I am trying to use Spring to do everything via annotations, except I would like to keep the persistence.xml file. However, I am being thrown an error that there is not a Bean called the unitName I have added to the #PersistenceContext.
#Repository
#Transactional
public class UserController implements Serializable {
private static final long serialVersionUID = 4625223295588959802L;
#PersistenceContext(unitName="PerfJPASpring")
private EntityManager em;
#Transactional
public void addUser(User user) {
em.persist(user);
}
#Transactional
public void deleteAll() {
em.createNamedQuery("User.deleteAll").executeUpdate();
}
#Transactional
public List<User> selectAllRecords() {
return em.createNamedQuery("User.findAll").getResultList();
}
}
The other issue I have is how do I get Spring to use the persistence.xml and not define the DataSource in the LocalContainerEntityManagerFactoryBean. I have added the Datasource to the App Server.
#Configuration
#EnableTransactionManagement
#EnableJpaRepositories(basePackageClasses=UserController.class)
public class DatabaseConfig {
#Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
EclipseLinkJpaVendorAdapter vendorAdapter = new EclipseLinkJpaVendorAdapter();
vendorAdapter.setGenerateDdl(true);
vendorAdapter.setShowSql(false);
LocalContainerEntityManagerFactoryBean factory = new LocalContainerEntityManagerFactoryBean();
factory.setJpaVendorAdapter(vendorAdapter);
factory.setPackagesToScan("com.example.jpa.model");
factory.setDataSource(dataSource());
Properties jpaProps = new Properties();
jpaProps.put("eclipselink.weaving", "false");
factory.setJpaProperties(jpaProps);
return factory;
}
#Bean
public JpaTransactionManager transactionManager() throws SQLException {
JpaTransactionManager txManager = new JpaTransactionManager();
txManager.setEntityManagerFactory(entityManagerFactory().getObject());
return txManager;
}
public DataSource dataSource() {
try {
Context initCtx = new InitialContext();
return (DataSource) initCtx.lookup("jdbc/userdb");
} catch (Exception e) {
e.printStackTrace();
throw new RuntimeException("Unable to lookup datasource", e);
}
}
}
The unitName does match that in the persistence.xml file.
<?xml version="1.0" encoding="UTF-8"?>
<persistence version="2.1" xmlns="http://xmlns.jcp.org/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/persistence http://xmlns.jcp.org/xml/ns/persistence/persistence_2_1.xsd">
<persistence-unit name="PerfJPASpring" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>jdbc/userdb</jta-data-source>
<class>com.example.jpa.model.User</class>
</persistence-unit>
</persistence>
And this is the error I am receiving.
Uncaught init() exception created by servlet [DispatcherServlet] in application [PerfJPASpring]: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'userController': Injection of persistence dependencies failed; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No bean named 'PerfJPASpring' is defined
at org.springframework.orm.jpa.support.PersistenceAnnotationBeanPostProcessor.postProcessPropertyValues(PersistenceAnnotationBeanPostProcessor.java:357)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1219)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:543)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:482)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:306)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:230)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:302)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:197)
at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:751)
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:839)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:538)
at org.springframework.web.servlet.FrameworkServlet.configureAndRefreshWebApplicationContext(FrameworkServlet.java:668)
at org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:540)
at org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:494)
at org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:136)
at javax.servlet.GenericServlet.init(GenericServlet.java:244)
at [internal classes]
Could point me in the right direction for Spring to use the unitName and how I can avoid specifying the datasource in the Db Config?
Thanks.

Answer 1

I found the issue. First, since I am using JTA, then I can remove #Transactional and remove the Datasource and replace it with the setPersistenceUnitName. Now it uses the persistence.xml file and JTA.
The Service:
#Repository
public class UserController implements Serializable {
private static final long serialVersionUID = 4625223295588959802L;
#PersistenceContext(unitName="PerfJPASpring")
private EntityManager em;
public void addUser(User user) {
em.persist(user);
}
public void deleteAll() {
em.createNamedQuery("User.deleteAll").executeUpdate();
}
public List<User> selectAllRecords() {
return em.createNamedQuery("User.findAll").getResultList();
}
}
Database Config:
#Configuration
#EnableJpaRepositories(basePackageClasses=UserController.class)
public class DatabaseConfig {
#Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactory() {
EclipseLinkJpaVendorAdapter vendorAdapter = new EclipseLinkJpaVendorAdapter();
vendorAdapter.setGenerateDdl(true);
vendorAdapter.setShowSql(false);
LocalContainerEntityManagerFactoryBean factory = new LocalContainerEntityManagerFactoryBean();
factory.setJpaVendorAdapter(vendorAdapter);
factory.setPackagesToScan("com.example.jpa.model");
factory.setPersistenceUnitName("PerfJPASpring");
Properties jpaProps = new Properties();
jpaProps.put("eclipselink.weaving", "false");
factory.setJpaProperties(jpaProps);
return factory;
}
#Bean
public JpaTransactionManager transactionManager() throws SQLException {
JpaTransactionManager txManager = new JpaTransactionManager();
txManager.setEntityManagerFactory(entityManagerFactory().getObject());
return txManager;
}
}