Could anyone please explain or give a link to a good guide on UnsafeMutablePointers? I can't freaking understand how they work and how to modify them.
Here's an example.
I am migrating my custom video player to Swift from Objective-C.
In Objective-C I create MTAudioProcessingTapRef using a callbacks structure:
MTAudioProcessingTapCallbacks callbacks;
callbacks.clientInfo = (__bridge void *)(self);
callbacks.init = initTap;
// Init other fields of callbacks
MTAudioProcessingTapCreate(kCFAllocatorDefault, &callbacks, kMTAudioProcessingTapCreationFlag_PostEffects, &tap);
Here I cast retainable MyClass pointer to void pointer to use it as clientInfo later.
(__bridge T) op casts the operand to the destination type T. If T is a
non-retainable pointer type, then op must have a retainable object
pointer type.
Then tap gets initialized:
void initTap(MTAudioProcessingTapRef tap, void *clientInfo, void **tapStorageOut)
{
*tapStorageOut = clientInfo;
}
Here I pass a pointer to self into tapStorageOut to grab self inside tap's callback function.
And then processing is performed:
void processTap(MTAudioProcessingTapRef tap, CMItemCount numberFrames, MTAudioProcessingTapFlags flags, AudioBufferList *bufferListInOut,
CMItemCount *numberFramesOut, MTAudioProcessingTapFlags *flagsOut)
{
MyClass *self = (__bridge MyClass *) MTAudioProcessingTapGetStorage(tap);
MTAudioProcessingTapGetSourceAudio(tap, numberFrames, bufferListInOut, flagsOut, NULL, numberFramesOut);
}
Now I have a few issues here.
I did found how to cast types into other types. Here are the functions:
func bridge<type : AnyObject>(object : type) -> UnsafeRawPointer
{
let unmanagedObject : Unmanaged = Unmanaged.passUnretained(object)
let unsafeMutableRawObject : UnsafeMutableRawPointer = unmanagedObject.toOpaque()
return UnsafeRawPointer(unsafeMutableRawObject)
}
func bridge<type : AnyObject>(pointer : UnsafeRawPointer) -> type
{
let unmanagedObject : Unmanaged<type> = Unmanaged<type>.fromOpaque(pointer)
let object : type = unmanagedObject.takeUnretainedValue()
return object
}
but I have zero understanding of what all of these letters do. Some explanation of this by one of you guys would be awesome.
Let's look at initTap function. Here I have a pointer A (tapStorageOut) that references a pointer B that references some data. I change pointer B to pointer C, which is my clientInfo. Clear as a sunny day.
Now, in Swift tapStorageOut is UnsafeMutablePointer now, whatever that thing is. And I have zero clue about how to deal with it.
In Objective-C when I process data I have a bufferListInOut variable which is a pointer to AudioBufferList structure.
In Swift however it has UnsafeMutablePointer type. So again, not understanding how UnsafeMutablePointers work prevents me from grabbing the data.
The main use of a pointer in Swift is working with C API and such. For the most part you should use reference semantics instead of pointers in Swift. That means using a class, when you pass a class instance around it automatically passes a reference instead of making a copy. Thus, it saves resources and any changes you make to a reference to the instance are reflected everywhere it is referenced. A Swift class is generally instantiated on the heap.
When you convert Objective-C to Swift pointers to objects are generally treated as references to those objects. Internally, a Swift reference is pretty much semantic sugar for a pointer.
Swift structures, on the other hand, have value semantics. They are generally instantiated on the stack and when you pass them around they are copied rather than passing a reference. The same goes when you mutate them, a new instance is created with the new values and it is swapped for the old instance. There are some tricks done where a struct will wrap a block of memory and hold a pointer to that memory. Thus a struct may have some reference semantics internally but try to avoid breaking the expectation of a struct's value being copied when it's passed around.
Some good reading:
Fundamentals of Callbacks for Swift Developers
Thinking in Swift, Part 3: Struct vs. Class
Lazy Initialization with Swift
I'd read these and take a good, hard look at your architecture before trying to use stuff like UnsafeMutablePointer. Yes, they are useful in some circumstances but they can be a pain to work with and are not necessary for most pure Swift tasks. Especially in a Swift API!
Reference cycles in Swift occur when properties of reference types have strong ownership of each other (or with closures).
Is there, however, a possibility of having reference cycles with value types only?
I tried this in playground without succes (Error: Recursive value type 'A' is not allowed).
struct A {
var otherA: A? = nil
init() {
otherA = A()
}
}
A reference cycle (or retain cycle) is so named because it indicates a cycle in the object graph:
Each arrow indicates one object retaining another (a strong reference). Unless the cycle is broken, the memory for these objects will never be freed.
When capturing and storing value types (structs and enums), there is no such thing as a reference. Values are copied, rather than referenced, although values can hold references to objects.
In other words, values can have outgoing arrows in the object graph, but no incoming arrows. That means they can't participate in a cycle.
As the compiler told you, what you're trying to do is illegal. Exactly because this is a value type, there's no coherent, efficient way to implement what you're describing. If a type needs to refer to itself (e.g., it has a property that is of the same type as itself), use a class, not a struct.
Alternatively, you can use an enum, but only in a special, limited way: an enum case's associated value can be an instance of that enum, provided the case (or the entire enum) is marked indirect:
enum Node {
case None(Int)
indirect case left(Int, Node)
indirect case right(Int, Node)
indirect case both(Int, Node, Node)
}
Disclaimer: I'm making an (hopefully educated) guess about the inner workings of the Swift compiler here, so apply grains of salt.
Aside from value semantics, ask yourself: Why do we have structs? What is the advantage?
One advantage is that we can (read: want to) store them on the stack (resp. in an object frame), i.e. just like primitive values in other languages. In particular, we don't want to allocate dedicated space on the heap to point to. That makes accessing struct values more efficient: we (read: the compiler) always knows where exactly in memory it finds the value, relative to the current frame or object pointer.
In order for that to work out for the compiler, it needs to know how much space to reserve for a given struct value when determining the structure of the stack or object frame. As long as struct values are trees of fixed size (disregarding outgoing references to objects; they point to the heap are not of interest for us), that is fine: the compiler can just add up all the sizes it finds.
If you had a recursive struct, this fails: you can implement lists or binary trees in this way. The compiler can not figure out statically how to store such values in memory, so we have to forbid them.
Nota bene: The same reasoning explains why structs are pass-by-value: we need them to physically be at their new context.
Quick and easy hack workaround: just embed it in an array.
struct A {
var otherA: [A]? = nil
init() {
otherA = [A()]
}
}
You normally cannot have a reference cycle with value types simply because Swift normally doesn't allow references to value types. Everything is copied.
However, if you're curious, you actually can induce a value-type reference cycle by capturing self in a closure.
The following is an example. Note that the MyObject class is present merely to illustrate the leak.
class MyObject {
static var objCount = 0
init() {
MyObject.objCount += 1
print("Alloc \(MyObject.objCount)")
}
deinit {
print("Dealloc \(MyObject.objCount)")
MyObject.objCount -= 1
}
}
struct MyValueType {
var closure: (() -> ())?
var obj = MyObject()
init(leakMe: Bool) {
if leakMe {
closure = { print("\(self)") }
}
}
}
func test(leakMe leakMe: Bool) {
print("Creating value type. Leak:\(leakMe)")
let _ = MyValueType(leakMe: leakMe)
}
test(leakMe: true)
test(leakMe: false)
Output:
Creating value type. Leak:true
Alloc 1
Creating value type. Leak:false
Alloc 2
Dealloc 2
Is there, however, a possibility of having reference cycles with value types only?
Depends on what you mean with "value types only".
If you mean completely no reference including hidden ones inside, then the answer is NO. To make a reference cycle, you need at least one reference.
But in Swift, Array, String or some other types are value types, which may contain references inside their instances. If your "value types" includes such types, the answer is YES.
Reference cycles in Swift occur when properties of reference types have strong ownership of each other (or with closures).
Is there, however, a possibility of having reference cycles with value types only?
I tried this in playground without succes (Error: Recursive value type 'A' is not allowed).
struct A {
var otherA: A? = nil
init() {
otherA = A()
}
}
A reference cycle (or retain cycle) is so named because it indicates a cycle in the object graph:
Each arrow indicates one object retaining another (a strong reference). Unless the cycle is broken, the memory for these objects will never be freed.
When capturing and storing value types (structs and enums), there is no such thing as a reference. Values are copied, rather than referenced, although values can hold references to objects.
In other words, values can have outgoing arrows in the object graph, but no incoming arrows. That means they can't participate in a cycle.
As the compiler told you, what you're trying to do is illegal. Exactly because this is a value type, there's no coherent, efficient way to implement what you're describing. If a type needs to refer to itself (e.g., it has a property that is of the same type as itself), use a class, not a struct.
Alternatively, you can use an enum, but only in a special, limited way: an enum case's associated value can be an instance of that enum, provided the case (or the entire enum) is marked indirect:
enum Node {
case None(Int)
indirect case left(Int, Node)
indirect case right(Int, Node)
indirect case both(Int, Node, Node)
}
Disclaimer: I'm making an (hopefully educated) guess about the inner workings of the Swift compiler here, so apply grains of salt.
Aside from value semantics, ask yourself: Why do we have structs? What is the advantage?
One advantage is that we can (read: want to) store them on the stack (resp. in an object frame), i.e. just like primitive values in other languages. In particular, we don't want to allocate dedicated space on the heap to point to. That makes accessing struct values more efficient: we (read: the compiler) always knows where exactly in memory it finds the value, relative to the current frame or object pointer.
In order for that to work out for the compiler, it needs to know how much space to reserve for a given struct value when determining the structure of the stack or object frame. As long as struct values are trees of fixed size (disregarding outgoing references to objects; they point to the heap are not of interest for us), that is fine: the compiler can just add up all the sizes it finds.
If you had a recursive struct, this fails: you can implement lists or binary trees in this way. The compiler can not figure out statically how to store such values in memory, so we have to forbid them.
Nota bene: The same reasoning explains why structs are pass-by-value: we need them to physically be at their new context.
Quick and easy hack workaround: just embed it in an array.
struct A {
var otherA: [A]? = nil
init() {
otherA = [A()]
}
}
You normally cannot have a reference cycle with value types simply because Swift normally doesn't allow references to value types. Everything is copied.
However, if you're curious, you actually can induce a value-type reference cycle by capturing self in a closure.
The following is an example. Note that the MyObject class is present merely to illustrate the leak.
class MyObject {
static var objCount = 0
init() {
MyObject.objCount += 1
print("Alloc \(MyObject.objCount)")
}
deinit {
print("Dealloc \(MyObject.objCount)")
MyObject.objCount -= 1
}
}
struct MyValueType {
var closure: (() -> ())?
var obj = MyObject()
init(leakMe: Bool) {
if leakMe {
closure = { print("\(self)") }
}
}
}
func test(leakMe leakMe: Bool) {
print("Creating value type. Leak:\(leakMe)")
let _ = MyValueType(leakMe: leakMe)
}
test(leakMe: true)
test(leakMe: false)
Output:
Creating value type. Leak:true
Alloc 1
Creating value type. Leak:false
Alloc 2
Dealloc 2
Is there, however, a possibility of having reference cycles with value types only?
Depends on what you mean with "value types only".
If you mean completely no reference including hidden ones inside, then the answer is NO. To make a reference cycle, you need at least one reference.
But in Swift, Array, String or some other types are value types, which may contain references inside their instances. If your "value types" includes such types, the answer is YES.
An NSNumber containing a Bool is easily confused with other types that can be wrapped in the NSNumber class:
NSNumber(bool:true).boolValue // true
NSNumber(integer: 1).boolValue // true
NSNumber(integer: 1) as? Bool // true
NSNumber(bool:true) as? Int // 1
NSNumber(bool:true).isEqualToNumber(1) // true
NSNumber(integer: 1).isEqualToNumber(true) // true
However, information about its original type is retained, as we can see here:
NSNumber(bool:true).objCType.memory == 99 // true
NSNumber(bool:true).dynamicType.className() == "__NSCFBoolean" // true
NSNumber(bool:true).isEqualToValue(true) || NSNumber(bool:true).isEqualToValue(false) //true
The question is: which of these approaches is the best (and/or safest) approach to determining when a Bool has been wrapped within an NSNumber rather than something else? Are all equally valid? Or, is there another, better solution?
You can ask the same question for Objective-C, and here is an answer in Objective-C - which you can call from, or translate into, Swift.
NSNumber is toll-free bridged to CFNumberRef, which is another way of saying an NSNumber object is in fact a CFNumber one (and vice-versa). Now CFNumberRef has a specific type for booleans, CFBooleanRef, and this is used when creating a boolean CFNumberRef aka NSNumber *... So all you need to do is check whether your NSNumber * is an instance of CFBooleanRef:
- (BOOL) isBoolNumber:(NSNumber *)num
{
CFTypeID boolID = CFBooleanGetTypeID(); // the type ID of CFBoolean
CFTypeID numID = CFGetTypeID((__bridge CFTypeRef)(num)); // the type ID of num
return numID == boolID;
}
Note: You may notice that NSNumber/CFNumber objects created from booleans are actually pre-defined constant objects; one for YES, one for NO. You may be tempted to rely on this for identification. However, though is currently appears to be true, and is shown in Apple's source code, to our knowledge it is not documented so should not be relied upon.
HTH
Addendum
Swift code translation (by GoodbyeStackOverflow):
func isBoolNumber(num:NSNumber) -> Bool
{
let boolID = CFBooleanGetTypeID() // the type ID of CFBoolean
let numID = CFGetTypeID(num) // the type ID of num
return numID == boolID
}
The first one is the correct one.
NSNumber is an Objective-C class. It is built for Objective-C. It stores the type using the type encodings of Objective-C. So in Objctive-C the best solution would be:
number.objCType[0] == #encoding(BOOL)[0] // or string compare, what is not necessary here
This ensures that a change of the type encoding will work after re-compile.
AFAIK you do not have #encoding() in Swift. So you have to use a literal. However, this will not break, because #encoding() is replaced at compile time and changing the encodings would break with compiled code. Unlikely.
The second approach uses a internal identifier. This is likely subject of change.
I think the third approach will have false positives.
Don't rely on the class name as it likely belongs to a class cluster, and it is an implementation detail (and therefore subject to change).
Unfortunately, the Objective-C BOOL type was originally a just typedef for a signed char in C, which is always encoded as c (this is the 99 value you are seeing, since c in ASCII is 99).
In modern Objective-C, I believe the BOOL type is an actual Boolean type (i.e. no longer just a typedef for signed char) but for compatibility, it still encodes as c when given to #encode().
So, there's no way to tell whether the 99 originally referred to a signed char or a BOOL, as far as NSNumber is concerned they are the same.
Maybe if you explain why you need to know whether the NSNumber was originally a BOOL, there may be a better solution.
Playing around with Swift, coming from a Java background, why would you want to choose a Struct instead of a Class? Seems like they are the same thing, with a Struct offering less functionality. Why choose it then?
According to the very popular WWDC 2015 talk Protocol Oriented Programming in Swift (video, transcript), Swift provides a number of features that make structs better than classes in many circumstances.
Structs are preferable if they are relatively small and copiable because copying is way safer than having multiple references to the same instance as happens with classes. This is especially important when passing around a variable to many classes and/or in a multithreaded environment. If you can always send a copy of your variable to other places, you never have to worry about that other place changing the value of your variable underneath you.
With Structs, there is much less need to worry about memory leaks or multiple threads racing to access/modify a single instance of a variable. (For the more technically minded, the exception to that is when capturing a struct inside a closure because then it is actually capturing a reference to the instance unless you explicitly mark it to be copied).
Classes can also become bloated because a class can only inherit from a single superclass. That encourages us to create huge superclasses that encompass many different abilities that are only loosely related. Using protocols, especially with protocol extensions where you can provide implementations to protocols, allows you to eliminate the need for classes to achieve this sort of behavior.
The talk lays out these scenarios where classes are preferred:
Copying or comparing instances doesn't make sense (e.g., Window)
Instance lifetime is tied to external effects (e.g., TemporaryFile)
Instances are just "sinks"--write-only conduits to external state (e.g.CGContext)
It implies that structs should be the default and classes should be a fallback.
On the other hand, The Swift Programming Language documentation is somewhat contradictory:
Structure instances are always passed by value, and class
instances are always passed by reference. This means that they are
suited to different kinds of tasks. As you consider the data
constructs and functionality that you need for a project, decide
whether each data construct should be defined as a class or as a
structure.
As a general guideline, consider creating a structure when one or more
of these conditions apply:
The structure’s primary purpose is to encapsulate a few relatively simple data values.
It is reasonable to expect that the encapsulated values will be copied rather than referenced when you assign or pass around an
instance of that structure.
Any properties stored by the structure are themselves value types, which would also be expected to be copied rather than referenced.
The structure does not need to inherit properties or behavior from another existing type.
Examples of good candidates for structures include:
The size of a geometric shape, perhaps encapsulating a width property and a height property, both of type Double.
A way to refer to ranges within a series, perhaps encapsulating a start property and a length property, both of type Int.
A point in a 3D coordinate system, perhaps encapsulating x, y and z properties, each of type Double.
In all other cases, define a class, and create instances of that class
to be managed and passed by reference. In practice, this means that
most custom data constructs should be classes, not structures.
Here it is claiming that we should default to using classes and use structures only in specific circumstances. Ultimately, you need to understand the real world implication of value types vs. reference types and then you can make an informed decision about when to use structs or classes. Also, keep in mind that these concepts are always evolving and The Swift Programming Language documentation was written before the Protocol Oriented Programming talk was given.
This answer was originally about difference in performance between struct and class. Unfortunately there are too much controversy around the method I used for measuring. I left it below, but please don't read too much into it. I think after all these years, it has become clear in Swift community that struct (along with enum) is always preferred due to its simplicity and safety.
If performance is important to your app, do measure it yourself. I still think most of the time struct performance is superior, but the best answer is just as someone said in the comments: it depends.
=== OLD ANSWER ===
Since struct instances are allocated on stack, and class instances are allocated on heap, structs can sometimes be drastically faster.
However, you should always measure it yourself and decide based on your unique use case.
Consider the following example, which demonstrates 2 strategies of wrapping Int data type using struct and class. I am using 10 repeated values are to better reflect real world, where you have multiple fields.
class Int10Class {
let value1, value2, value3, value4, value5, value6, value7, value8, value9, value10: Int
init(_ val: Int) {
self.value1 = val
self.value2 = val
self.value3 = val
self.value4 = val
self.value5 = val
self.value6 = val
self.value7 = val
self.value8 = val
self.value9 = val
self.value10 = val
}
}
struct Int10Struct {
let value1, value2, value3, value4, value5, value6, value7, value8, value9, value10: Int
init(_ val: Int) {
self.value1 = val
self.value2 = val
self.value3 = val
self.value4 = val
self.value5 = val
self.value6 = val
self.value7 = val
self.value8 = val
self.value9 = val
self.value10 = val
}
}
func + (x: Int10Class, y: Int10Class) -> Int10Class {
return IntClass(x.value + y.value)
}
func + (x: Int10Struct, y: Int10Struct) -> Int10Struct {
return IntStruct(x.value + y.value)
}
Performance is measured using
// Measure Int10Class
measure("class (10 fields)") {
var x = Int10Class(0)
for _ in 1...10000000 {
x = x + Int10Class(1)
}
}
// Measure Int10Struct
measure("struct (10 fields)") {
var y = Int10Struct(0)
for _ in 1...10000000 {
y = y + Int10Struct(1)
}
}
func measure(name: String, #noescape block: () -> ()) {
let t0 = CACurrentMediaTime()
block()
let dt = CACurrentMediaTime() - t0
print("\(name) -> \(dt)")
}
Code can be found at https://github.com/knguyen2708/StructVsClassPerformance
UPDATE (27 Mar 2018):
As of Swift 4.0, Xcode 9.2, running Release build on iPhone 6S, iOS 11.2.6, Swift Compiler setting is -O -whole-module-optimization:
class version took 2.06 seconds
struct version took 4.17e-08 seconds (50,000,000 times faster)
(I no longer average multiple runs, as variances are very small, under 5%)
Note: the difference is a lot less dramatic without whole module optimization. I'd be glad if someone can point out what the flag actually does.
UPDATE (7 May 2016):
As of Swift 2.2.1, Xcode 7.3, running Release build on iPhone 6S, iOS 9.3.1, averaged over 5 runs, Swift Compiler setting is -O -whole-module-optimization:
class version took 2.159942142s
struct version took 5.83E-08s (37,000,000 times faster)
Note: as someone mentioned that in real-world scenarios, there will be likely more than 1 field in a struct, I have added tests for structs/classes with 10 fields instead of 1. Surprisingly, results don't vary much.
ORIGINAL RESULTS (1 June 2014):
(Ran on struct/class with 1 field, not 10)
As of Swift 1.2, Xcode 6.3.2, running Release build on iPhone 5S, iOS 8.3, averaged over 5 runs
class version took 9.788332333s
struct version took 0.010532942s (900 times faster)
OLD RESULTS (from unknown time)
(Ran on struct/class with 1 field, not 10)
With release build on my MacBook Pro:
The class version took 1.10082 sec
The struct version took 0.02324 sec (50 times faster)
Similarities between structs and classes.
I created gist for this with simple examples.
https://github.com/objc-swift/swift-classes-vs-structures
And differences
1. Inheritance.
structures can't inherit in swift. If you want
class Vehicle{
}
class Car : Vehicle{
}
Go for an class.
2. Pass By
Swift structures pass by value and class instances pass by reference.
Contextual Differences
Struct constant and variables
Example (Used at WWDC 2014)
struct Point{
var x = 0.0;
var y = 0.0;
}
Defines a struct called Point.
var point = Point(x:0.0,y:2.0)
Now if I try to change the x. Its a valid expression.
point.x = 5
But if I defined a point as constant.
let point = Point(x:0.0,y:2.0)
point.x = 5 //This will give compile time error.
In this case entire point is immutable constant.
If I used a class Point instead this is a valid expression. Because in a class immutable constant is the reference to the class itself not its instance variables (Unless those variables defined as constants)
Assuming that we know Struct is a value type and Class is a reference type.
If you don't know what a value type and a reference type are then see What's the difference between passing by reference vs. passing by value?
Based on mikeash's post:
... Let's look at some extreme, obvious examples first. Integers are
obviously copyable. They should be value types. Network sockets can't
be sensibly copied. They should be reference types. Points, as in x, y
pairs, are copyable. They should be value types. A controller that
represents a disk can't be sensibly copied. That should be a reference
type.
Some types can be copied but it may not be something you want to
happen all the time. This suggests that they should be reference
types. For example, a button on the screen can conceptually be copied.
The copy will not be quite identical to the original. A click on the
copy will not activate the original. The copy will not occupy the same
location on the screen. If you pass the button around or put it into a
new variable you'll probably want to refer to the original button, and
you'd only want to make a copy when it's explicitly requested. That
means that your button type should be a reference type.
View and window controllers are a similar example. They might be
copyable, conceivably, but it's almost never what you'd want to do.
They should be reference types.
What about model types? You might have a User type representing a user
on your system, or a Crime type representing an action taken by a
User. These are pretty copyable, so they should probably be value
types. However, you probably want updates to a User's Crime made in
one place in your program to be visible to other parts of the program.
This suggests that your Users should be managed by some sort of user
controller which would be a reference type. e.g
struct User {}
class UserController {
var users: [User]
func add(user: User) { ... }
func remove(userNamed: String) { ... }
func ...
}
Collections are an interesting case. These include things like arrays
and dictionaries, as well as strings. Are they copyable? Obviously. Is
copying something you want to happen easily and often? That's less
clear.
Most languages say "no" to this and make their collections reference
types. This is true in Objective-C and Java and Python and JavaScript
and almost every other language I can think of. (One major exception
is C++ with STL collection types, but C++ is the raving lunatic of the
language world which does everything strangely.)
Swift said "yes," which means that types like Array and Dictionary and
String are structs rather than classes. They get copied on assignment,
and on passing them as parameters. This is an entirely sensible choice
as long as the copy is cheap, which Swift tries very hard to
accomplish.
...
I personally don't name my classes like that. I usually name mine UserManager instead of UserController but the idea is the same
In addition don't use class when you have to override each and every instance of a function ie them not having any shared functionality.
So instead of having several subclasses of a class. Use several structs that conform to a protocol.
Another reasonable case for structs is when you want to do a delta/diff of your old and new model. With references types you can't do that out of the box. With value types the mutations are not shared.
Here are some other reasons to consider:
structs get an automatic initializer that you don't have to maintain in code at all.
struct MorphProperty {
var type : MorphPropertyValueType
var key : String
var value : AnyObject
enum MorphPropertyValueType {
case String, Int, Double
}
}
var m = MorphProperty(type: .Int, key: "what", value: "blah")
To get this in a class, you would have to add the initializer, and maintain the intializer...
Basic collection types like Array are structs. The more you use them in your own code, the more you will get used to passing by value as opposed to reference. For instance:
func removeLast(var array:[String]) {
array.removeLast()
println(array) // [one, two]
}
var someArray = ["one", "two", "three"]
removeLast(someArray)
println(someArray) // [one, two, three]
Apparently immutability vs. mutability is a huge topic, but a lot of smart folks think immutability -- structs in this case -- is preferable. Mutable vs immutable objects
Some advantages:
automatically threadsafe due to not being shareable
uses less memory due to no isa and refcount (and in fact is stack allocated generally)
methods are always statically dispatched, so can be inlined (though #final can do this for classes)
easier to reason about (no need to "defensively copy" as is typical with NSArray, NSString, etc...) for the same reason as thread safety
Structs are value type and Classes are reference type
Value types are faster than Reference types
Value type instances are safe in a multi-threaded environment as
multiple threads can mutate the instance without having to worry
about the race conditions or deadlocks
Value type has no references unlike reference type; therefore there
is no memory leaks.
Use a value type when:
You want copies to have independent state, the data will be used in
code across multiple threads
Use a reference type when:
You want to create shared, mutable state.
Further information could be also found in the Apple documentation
https://docs.swift.org/swift-book/LanguageGuide/ClassesAndStructures.html
Additional Information
Swift value types are kept in the stack. In a process, each thread has its own stack space, so no other thread will be able to access your value type directly. Hence no race conditions, locks, deadlocks or any related thread synchronization complexity.
Value types do not need dynamic memory allocation or reference counting, both of which are expensive operations. At the same time methods on value types are dispatched statically. These create a huge advantage in favor of value types in terms of performance.
As a reminder here is a list of Swift
Value types:
Struct
Enum
Tuple
Primitives (Int, Double, Bool etc.)
Collections (Array, String, Dictionary, Set)
Reference types:
Class
Anything coming from NSObject
Function
Closure
Structure is much more faster than Class. Also, if you need inheritance then you must use Class. Most important point is that Class is reference type whereas Structure is value type. for example,
class Flight {
var id:Int?
var description:String?
var destination:String?
var airlines:String?
init(){
id = 100
description = "first ever flight of Virgin Airlines"
destination = "london"
airlines = "Virgin Airlines"
}
}
struct Flight2 {
var id:Int
var description:String
var destination:String
var airlines:String
}
now lets create instance of both.
var flightA = Flight()
var flightB = Flight2.init(id: 100, description:"first ever flight of Virgin Airlines", destination:"london" , airlines:"Virgin Airlines" )
now lets pass these instance to two functions which modify the id, description, destination etc..
func modifyFlight(flight:Flight) -> Void {
flight.id = 200
flight.description = "second flight of Virgin Airlines"
flight.destination = "new york"
flight.airlines = "Virgin Airlines"
}
also,
func modifyFlight2(flight2: Flight2) -> Void {
var passedFlight = flight2
passedFlight.id = 200
passedFlight.description = "second flight from virgin airlines"
}
so,
modifyFlight(flight: flightA)
modifyFlight2(flight2: flightB)
now if we print the flightA's id and description, we get
id = 200
description = "second flight of Virgin Airlines"
Here, we can see the id and description of FlightA is changed because the parameter passed to the modify method actually points to the memory address of flightA object(reference type).
now if we print the id and description of FLightB instance we get,
id = 100
description = "first ever flight of Virgin Airlines"
Here we can see that the FlightB instance is not changed because in modifyFlight2 method, actual instance of Flight2 is passes rather than reference ( value type).
Answering the question from the perspective of value types vs reference types, from this Apple blog post it would appear very simple:
Use a value type [e.g. struct, enum] when:
Comparing instance data with == makes sense
You want copies to have independent state
The data will be used in code across multiple threads
Use a reference type [e.g. class] when:
Comparing instance identity with === makes sense
You want to create shared, mutable state
As mentioned in that article, a class with no writeable properties will behave identically with a struct, with (I will add) one caveat: structs are best for thread-safe models -- an increasingly imminent requirement in modern app architecture.
Struct vs Class
[Stack vs Heap]
[Value vs Reference type]
Struct is more preferable. But Struct does not solve all issues by default. Usually you can hear that value type is allocated on stack, but it is not always true. Only local variables are allocated on stack
//simple blocks
struct ValueType {}
class ReferenceType {}
struct StructWithRef {
let ref1 = ReferenceType()
}
class ClassWithRef {
let ref1 = ReferenceType()
}
func foo() {
//simple blocks
let valueType1 = ValueType()
let refType1 = ReferenceType()
//RetainCount
//StructWithRef
let structWithRef1 = StructWithRef()
let structWithRef1Copy = structWithRef1
print("original:", CFGetRetainCount(structWithRef1 as CFTypeRef)) //1
print("ref1:", CFGetRetainCount(structWithRef1.ref1)) //2 (originally 3)
//ClassWithRef
let classWithRef1 = ClassWithRef()
let classWithRef1Copy = classWithRef1
print("original:", CFGetRetainCount(classWithRef1)) //2 (originally 3)
print("ref1:", CFGetRetainCount(classWithRef1.ref1)) //1 (originally 2)
}
*You should not use/rely on retainCount, because it does not say useful information
To check stack or heap
During compiling SIL(Swift Intermediate Language) can optimize you code
swiftc -emit-silgen -<optimization> <file_name>.swift
//e.g.
swiftc -emit-silgen -Onone file.swift
//emit-silgen -> emit-sil(is used in any case)
//-emit-silgen Emit raw SIL file(s)
//-emit-sil Emit canonical SIL file(s)
//optimization: O, Osize, Onone. It is the same as Swift Compiler - Code Generation -> Optimization Level
There you can find alloc_stack(allocation on stack) and alloc_box(allocation on heap)
[Optimization Level(SWIFT_OPTIMIZATION_LEVEL)]
With classes you get inheritance and are passed by reference, structs do not have inheritance and are passed by value.
There are great WWDC sessions on Swift, this specific question is answered in close detail in one of them. Make sure you watch those, as it will get you up to speed much more quickly then the Language guide or the iBook.
I wouldn't say that structs offer less functionality.
Sure, self is immutable except in a mutating function, but that's about it.
Inheritance works fine as long as you stick to the good old idea that every class should be either abstract or final.
Implement abstract classes as protocols and final classes as structs.
The nice thing about structs is that you can make your fields mutable without creating shared mutable state because copy on write takes care of that :)
That's why the properties / fields in the following example are all mutable, which I would not do in Java or C# or swift classes.
Example inheritance structure with a bit of dirty and straightforward usage at the bottom in the function named "example":
protocol EventVisitor
{
func visit(event: TimeEvent)
func visit(event: StatusEvent)
}
protocol Event
{
var ts: Int64 { get set }
func accept(visitor: EventVisitor)
}
struct TimeEvent : Event
{
var ts: Int64
var time: Int64
func accept(visitor: EventVisitor)
{
visitor.visit(self)
}
}
protocol StatusEventVisitor
{
func visit(event: StatusLostStatusEvent)
func visit(event: StatusChangedStatusEvent)
}
protocol StatusEvent : Event
{
var deviceId: Int64 { get set }
func accept(visitor: StatusEventVisitor)
}
struct StatusLostStatusEvent : StatusEvent
{
var ts: Int64
var deviceId: Int64
var reason: String
func accept(visitor: EventVisitor)
{
visitor.visit(self)
}
func accept(visitor: StatusEventVisitor)
{
visitor.visit(self)
}
}
struct StatusChangedStatusEvent : StatusEvent
{
var ts: Int64
var deviceId: Int64
var newStatus: UInt32
var oldStatus: UInt32
func accept(visitor: EventVisitor)
{
visitor.visit(self)
}
func accept(visitor: StatusEventVisitor)
{
visitor.visit(self)
}
}
func readEvent(fd: Int) -> Event
{
return TimeEvent(ts: 123, time: 56789)
}
func example()
{
class Visitor : EventVisitor
{
var status: UInt32 = 3;
func visit(event: TimeEvent)
{
print("A time event: \(event)")
}
func visit(event: StatusEvent)
{
print("A status event: \(event)")
if let change = event as? StatusChangedStatusEvent
{
status = change.newStatus
}
}
}
let visitor = Visitor()
readEvent(1).accept(visitor)
print("status: \(visitor.status)")
}
In Swift, a new programming pattern has been introduced known as Protocol Oriented Programming.
Creational Pattern:
In swift, Struct is a value types which are automatically cloned. Therefore we get the required behavior to implement the prototype pattern for free.
Whereas classes are the reference type, which is not automatically cloned during the assignment. To implement the prototype pattern, classes must adopt the NSCopying protocol.
Shallow copy duplicates only the reference, that points to those objects whereas deep copy duplicates object’s reference.
Implementing deep copy for each reference type has become a tedious task. If classes include further reference type, we have to implement prototype pattern for each of the references properties. And then we have to actually copy the entire object graph by implementing the NSCopying protocol.
class Contact{
var firstName:String
var lastName:String
var workAddress:Address // Reference type
}
class Address{
var street:String
...
}
By using structs and enums, we made our code simpler since we don’t have to implement the copy logic.
Many Cocoa APIs require NSObject subclasses, which forces you into using class. But other than that, you can use the following cases from Apple’s Swift blog to decide whether to use a struct / enum value type or a class reference type.
https://developer.apple.com/swift/blog/?id=10
One point not getting attention in these answers is that a variable holding a class vs a struct can be a let while still allowing changes on the object's properties, while you cannot do this with a struct.
This is useful if you don't want the variable to ever point to another object, but still need to modify the object, i.e. in the case of having many instance variables that you wish to update one after another. If it is a struct, you must allow the variable to be reset to another object altogether using var in order to do this, since a constant value type in Swift properly allows zero mutation, while reference types (classes) don't behave this way.
As struct are value types and you can create the memory very easily which stores into stack.Struct can be easily accessible and after the scope of the work it's easily deallocated from the stack memory through pop from the top of the stack.
On the other hand class is a reference type which stores in heap and changes made in one class object will impact to other object as they are tightly coupled and reference type.All members of a structure are public whereas all the members of a class are private.
The disadvantages of struct is that it can't be inherited .
Structure and class are user defied data types
By default, structure is a public whereas class is private
Class implements the principal of encapsulation
Objects of a class are created on the heap memory
Class is used for re usability whereas structure is used for grouping
the data in the same structure
Structure data members cannot be initialized directly but they can be
assigned by the outside the structure
Class data members can be initialized directly by the parameter less
constructor and assigned by the parameterized constructor