How to show 2 different type of mappings between 2 entity classes, holding each other's reference - entity-framework

The mappings between the 2 tables(Department and Employee) is as follows (Link for the image showing mapping is also provided):
Every department has one and only one department head.
Every department can have more than one employee.
dept_id and empId are primary keys of their respective tables.
dept_head(It is the Employee Id) and dept are foreign keys of their
respective tables.
Mapping Employee and Department table
I created entity classes for the above 2 tables (The structure is provided below).
Employee Class:
public class Employee implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Column(name = "empId")
private Integer empId;
#Size(max = 45)
#Column(name = "name")
private String name;
#Size(max = 45)
#Column(name = "address")
private String address;
#Size(max = 45)
#Column(name = "grade")
private String grade;
#Size(max = 45)
#Column(name = "email")
private String email;
#JoinColumn(name = "dept", referencedColumnName = "dept_id")
#ManyToOne
private Department deptartment;
.. ...
}
Department class:
public class Department implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Basic(optional = false)
#NotNull
#Size(min = 1, max = 8)
#Column(name = "dept_id")
private String deptId;
#Size(max = 45)
#Column(name = "name")
private String name;
#JoinColumn(name = "dept_head", referencedColumnName = "empId")
#OneToOne
private Employee deptHead;
#OneToMany(mappedBy = "deptartment")
private List<Employee> employeeList;
....
...
}
If I am adding mappedBy in Employee Class (like I did in Department), to show OneToOne mapping between empId and deptHead,the code is compiling and running. However, If I do not add the mappedBy statement in Employee class, as the above code shows, the code still compiles and runs fine.
I would want to know why the code above works even if I am not providing mappedBy in employee class.
If anybody can help me clearing the above doubts and explaining the logic behind its working would be great as I am new to this.

It is not quite clear where you tried to user it with and without the mappedBy attribute.
But if I get your question correctly, you ask why you can have only one or both sides annotated?
It depends on which side is the source and destination of your relation or wheter it's bi-directional. On the Java-side you can have a relation always in both directions due to object references, but on the Database-side, you might only have it in one direction.
Check out JPA Wiki book on that topic for more details.
Additionally, the API doc for OneToOne states:
Specifies a single-valued association to another entity that has
one-to-one multiplicity. It is not normally necessary to specify the
associated target entity explicitly since it can usually be inferred
from the type of the object being referenced. If the relationship is
bidirectional, the non-owning side must use the mappedBy element of
the OneToOne annotation to specify the relationship field or property
of the owning side.

Related

Why my foreign key is null when saving to h2 db, using JPA

What is the difference between these 2 codes. The 1st one shows null on my foreign key which is individualId. The 2nd one is not. Why?
//1st code:
#Entity
#JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
public class Individual {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "INDIVIDUAL_ID")
private Long individualId;
#OneToMany(mappedBy="individual",cascade = CascadeType.ALL, fetch = FetchType.LAZY)
private List<Identification> identifications = new ArrayList<Identification>();
}
#Entity
public class Identification {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "IDT_ID")
private Long id;
#ManyToOne
#JoinColumn(name="individualId")
private Individual individual;
//second code
//replaced #OneToMany in the first code & then i just dont add #ManyToOne in the Identification Class and it works fine. Why?
#OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
#JoinColumn(name = "INDIVIDUAL_ID", referencedColumnName = "INDIVIDUAL_ID")
private List<Identification> identifications = new ArrayList<Identification>();
When i search for JPA tutorial in google the 1st code is the one that i always read. declare #OneToMany in the parent class and add mappedBy, declare #ManyToOne in the child class. But why the 2nd code works perfect than the 1st code? it just let me declare #OneToMany only in the parent class ?
In the class Identification the name of the #JoinColumn does not match any column in your class Individual. It must be the name of the column in the database, which is INDIVIDUAL_ID:
#JoinColumn(name="INDIVIDUAL_ID")

ERROR: update or delete on table "tablename" violates foreign key constraint

I'm trying to delete the parent student or parent course and I get this error:
Caused by: org.postgresql.util.PSQLException: ERROR: update or delete on table "student" violates foreign key constraint "fkeyvuofq5vwdylcf78jar3mxol" on table "registration"
RegistrationId class is a composite key used in Registration class. I'm using Spring data jpa and spring boot.
What am I doing wrong? I know that putting cascadetype.all should also remove the children when the parent is deleted but it is giving me an error instead.
#Embeddable
public class RegistrationId implements Serializable {
#JsonIgnoreProperties("notifications")
#OneToOne(cascade=CascadeType.ALL)
#JoinColumn(name = "student_pcn", referencedColumnName="pcn")
private Student student;
#JsonIgnoreProperties({"teachers", "states", "reviews"})
#OneToOne(cascade=CascadeType.ALL)
#JoinColumn(name = "course_code", referencedColumnName="code")
private Course course;
Registration class
#Entity(name = "Registration")
#Table(name = "registration")
public class Registration {
#EmbeddedId
private RegistrationId id;
When you're using a relational DB, you are setting entities with relationships between these entities.
The error that you're getting means that:
You're trying to delete a record that its primary key is functioning as a foreign key in another table, thus you can't delete it.
In order to delete that record, first, delete the record with the foreign key, and then delete the original that you wanted to delete.
I made it work by using hibernate #OnDelete annotation. Some how the JPA.persistence CascadeTypes were not working. They had no effect for whichever I chose.
Just like below. Now I can remove the parent Student or the parent Course and all children(Registrations) are deleted with them.
#Embeddable
public class RegistrationId implements Serializable {
#JsonIgnoreProperties("notifications")
#OnDelete(action = OnDeleteAction.CASCADE)
#OneToOne
#JoinColumn(name = "student_pcn", referencedColumnName="pcn")
private Student student;
#JsonIgnoreProperties({"teachers", "states", "reviews"})
#OnDelete(action = OnDeleteAction.CASCADE)
#OneToOne
#JoinColumn(name = "course_code", referencedColumnName="code")
private Course course;
Foreign keys guarantee that an entry will exist in another table. This is a way of ensuring data integrity. SQL will never allow you to delete this entry while it still deletes in the other table. Either (1) this is letting you know you would have made a grave mistake by deleting this thing which is required or (2) you would like to put in a cascading delete so that not only is this entry deleted but so is what is supposed to be referencing it in the other table. Information on cascading deletes can be found here and written fairly easily (https://www.techonthenet.com/sql_server/foreign_keys/foreign_delete.php). If neither of these two descriptions fits you, evaluate why your foreign key relationship exists in the first place because it probably should not.
Try this method too. I got the answer with this method,This is just a test to remove.
Pay attention to the cascade!
MyUser Entity
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String firstname;
private String lastname;
private String mobile;
#Column(unique = true)
private String email;
private Long date;
private LocalTime localiime;
private LocalTime localiimeend;
#ManyToOne(fetch = FetchType.LAZY,cascade = CascadeType.MERGE)
#JoinColumn(foreignKey = #ForeignKey(name = "role_fk"))
private Role role;
Role Entity
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
private String description;
#OneToMany(mappedBy = "role", fetch = FetchType.LAZY, cascade = CascadeType.ALL)
private List<MyUser> users;
#ManyToOne (fetch = FetchType.LAZY,cascade = CascadeType.MERGE)
#JoinColumn(foreignKey = #ForeignKey(name = "rolecat_fk"))
private rolecat rolecat;
rolecat Entity
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
#OneToMany(mappedBy = "rolecat", fetch = FetchType.LAZY, cascade = CascadeType.ALL)
private List<Role> roles;

JPA ManyToMany and mappedBY

I completely understand #OneToMany, #ManyToOne, and #ManyToMany. However the mappedBy = "some collection or class" has be confused.
From my understanding, the many part is always the owning side. For example,
#Entity
#Table(name = "company")
public class CompanyEntity implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "idcompany")
private Integer idcompany;
#Basic(optional = false)
#Column(name = "name")
private String name;
#Basic(optional = false)
#Column(name = "address")
private String address;
#OneToMany
private Collection<EmployeeEnity> employeeEnity
This is saying a company can have many employees. The one being the company and the Many being the employees.
However with #ManyToMany we still have a inverse side too. This is what I do not understand. #ManyToMany just means there is a table in the middle, so how do you determine the inverse and the owner?
I know mappedBy is mandatory, but choosing on where to put it is confusing me.
For a bidirectional OneToMany, the many side MUST be the owner side.
For a ManyToMany, you have the choice: you decide which side is the owner side and which side is the inverse side.
Note that, in your example, either the association is unidirectional, and the unique side (the one side) is thus obviously the owner side, or the association is bidirectional, and the mapping is thus incorrect, since the one side MUST be the inverse side and should thus have a mappedBy attribute:
#OneToMany(mappedBy = "company")
private Collection<EmployeeEntity> employees;

QueryDSL / JPQL : how to build a join query?

I've tried to read through the QueryDSL docs but I am still very confused. I'm accustomed to writing a lot of SQL, but this is my first real crack at using QueryDSL w/ JPQL (JPA2).
I have the following entity:
#Entity
public class Provider implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
#Version
#Column(name = "version")
private Integer version;
private String name;
#ManyToMany(cascade=CascadeType.ALL)
#JoinTable(name = "provider_contact", joinColumns = #JoinColumn(name = "contact_id", referencedColumnName = "id"), inverseJoinColumns = #JoinColumn(name = "provider_id", referencedColumnName = "id"))
#OrderColumn
private Collection<Contact> contact;
}
where Contact is a simple entity with an id for a pk.
#Entity
public class Contact {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "id")
private Long id;
/**
* User first name
*/
#NotNull
private String firstName;
/**
* User last name
*/
#NotNull
private String lastName;
}
I'm trying to write a query which returns a Contact object given a specific Contact.id and Provider.id. If the Contact object is not a part of the Provider's Contact collection, I'm looking for a null value.
I've tried the following:
public Contact getContact( long providerId, long contactId ){
Predicate p = QProvider.provider.id.eq(providerId).and(QContact.contact.id.eq(contactId));
JPQLQuery query = new JPAQuery(em);
return query.from(QProvider.provider).innerJoin(QProvider.provider.contact).where(p).singleResult(QContact.contact);
}
but I'm getting the following error:
Caused by: java.lang.IllegalArgumentException: Undeclared path 'contact'. Add this path as a source to the query to be able to reference it.
at com.mysema.query.types.ValidatingVisitor.visit(ValidatingVisitor.java:78)
at com.mysema.query.types.ValidatingVisitor.visit(ValidatingVisitor.java:30)
at com.mysema.query.types.PathImpl.accept(PathImpl.java:94)
I'm presuming it has something to do with the fact that my predicate references QContact.contact direction and not part of the QProvider.provider.contact object, but I'm really at a loss as to figure out how this should be done.
Am I even on the right track? I'm not even sure my join is correct either.
This should work
public Contact getContact(long providerId, long contactId) {
QProvider provider = QProvider.provider;
QContact contact = QContact.contact;
return new JPAQuery(em).from(provider)
.innerJoin(provider.contact, contact)
.where(provider.id.eq(providerId), contact.id.eq(contactId))
.singleResult(contact);
}

JPA Many to One relationship

I am bit beginner on JPA and need some help on fetching the Many to One relationship in JPA.
I have below entities.
User which stores all user information . User extends Audiatable abstract class which is for holding auidt paramters like last modified date, creation date etc.
I am trying to add another fields as lastUpdatedByUser which should get fetched from lastUpdatedBy for which I amtrying to add Many-One relationship.
But the relation is not working somehow, am I doing something wrong here?
AuditableEntity.java
public abstract class AuditableEntity<T extends Entity<T, ID>, ID> implements Auditable {
private static final long serialVersionUID = 1L;
#Column(name = "cruserid")
private Long createdBy;
#Column(name = "crdate")
#Type(type = JpaConstants.TYPE_LOCAL_DATE_TIME)
private LocalDateTime createdOn;
#Column(name = "chuserid")
private Long lastUpdatedBy;
#Column(name = "chdate")
#Type(type = JpaConstants.TYPE_LOCAL_DATE_TIME)
private LocalDateTime lastUpdatedOn;
#Transient
#ManyToOne(fetch = FetchType.LAZY, targetEntity = User.class)
#JoinColumn(name = "usrId", referencedColumnName = "chuserid")
private User lastUpdatedByUser;
User.java
public class User extends AuditableEntity<User, Long> {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "usrId")
private Long id;
#Column(name = "usrName")
private String name;
#Column(name = "loginame")
private String loginName;
}
Well, you marked the association with #Transient, which means that the field is not persistent and should be ignored by JPA.
And you also seem to have two different fields to store the same information: lastUpdatedBy and lastUpdateByUser. Remove the first one, and map the second one as
#ManyToOne(fetch = FetchType.LAZY)
#JoinColumn(name = "chuserid")
private User lastUpdatedByUser;
This tells that the association is a ManyToOne to the User entity (no need to specify the targetEntity since it's the type of the field), and that this association is materialized by the join column named "chuserid", in the auditable entity's table, and referencing the ID of the User entity (referencedColumnName is only useful when you use composite IDs, or when you reference an entity by a column which is the the ID)