Currently I am working on a project where I have a file full of IP addresses I want to delete the IP adddresses that are private (whole range) and using bash to accomplish it. I do make a match of private addresses but unable to delete it.
I have tried:
sed -i '/(192)\.(168)(\.([2][0-5][0-5]|[1][0-9][0-9]|[1-9][0-9]|[0-9])){2}/d' validIPOnly
same for
127.x.x.x,172.16.x.X,10.x.x.x
When using capture groups with sed you either need to escape the ( ) or specify option -E:
$ sed -E -i '/(...)...'
or
$ sed -i '/\(...\)...`
For GNU sed only use the -r option instead of -E.
Related
I have a file with multiple paths in the same line:
cat modules.dep
kernel/mm/zsmalloc.ko:
kernel/crypto/lzo.ko:
kernel/drivers/char/tpm/tpm_vtpm_proxy.ko: kernel/drivers/char/tpm/tpm.ko
kernel/drivers/block/virtio_blk.ko:
kernel/drivers/block/zram/zram.ko: kernel/mm/zsmalloc.ko
kernel/drivers/nvdimm/virtio_pmem.ko: kernel/drivers/nvdimm/nd_virtio.ko
kernel/drivers/nvdimm/nd_virtio.ko:
kernel/drivers/net/virtio_net.ko: kernel/drivers/net/net_failover.ko kernel/net/core/failover.ko
kernel/drivers/net/net_failover.ko: kernel/net/core/failover.ko
extra/virtio_gpu/virtio-gpu.ko: kernel/drivers/virtio/virtio_dma_buf.ko
extra/wlan_simulation/virt_wifi_sim.ko: kernel/drivers/net/wireless/virt_wifi.ko
I would like to change it to:
/lib/modules/zsmalloc.ko:
/lib/modules/lzo.ko:
/lib/modules/tpm_vtpm_proxy.ko: /lib/modules/tpm.ko
/lib/modules/virtio_blk.ko:
/lib/modules/zram.ko: /lib/modules/zsmalloc.ko
/lib/modules/virtio_pmem.ko: /lib/modules/nd_virtio.ko
/lib/modules/nd_virtio.ko:
/lib/modules/virtio_net.ko: /lib/modules/net_failover.ko /lib/modules/failover.ko
/lib/modules/net_failover.ko: /lib/modules/failover.ko
/lib/modules/virtio-gpu.ko: /lib/modules/virtio_dma_buf.ko
/lib/modules/virt_wifi_sim.ko: /lib/modules/virt_wifi.ko
But my attempt:
sed -i 's/\(.*\)\//\/lib\/modules\//g' modules.load
works only, if there is just one path per line.
How can I achieve this, via sed, with multiple paths per line?
I am using sed from BusyBox in D(ASH) Standalone.
BusyBox v1.32.1-Magisk (2021-01-21 00:17:27 PST) multi-call binary.
Usage: sed [-i[SFX]] [-nrE] [-f FILE]... [-e CMD]... [FILE]...
or: sed [-i[SFX]] [-nrE] CMD [FILE]...
-e CMD Add CMD to sed commands to be executed
-f FILE Add FILE contents to sed commands to be executed
-i[SFX] Edit files in-place (otherwise sends to stdout)
Optionally back files up, appending SFX
-n Suppress automatic printing of pattern space
-r,-E Use extended regex syntax
If no -e or -f, the first non-option argument is the sed command string.
Remaining arguments are input files (stdin if none).
This sed should work:
sed -E 's~[^[:blank:]]+/~/lib/modules/~g' modules.dep
/lib/modules/zsmalloc.ko:
/lib/modules/lzo.ko:
/lib/modules/tpm_vtpm_proxy.ko: /lib/modules/tpm.ko
/lib/modules/virtio_blk.ko:
/lib/modules/zram.ko: /lib/modules/zsmalloc.ko
/lib/modules/virtio_pmem.ko: /lib/modules/nd_virtio.ko
/lib/modules/nd_virtio.ko:
/lib/modules/virtio_net.ko: /lib/modules/net_failover.ko /lib/modules/failover.ko
/lib/modules/net_failover.ko: /lib/modules/failover.ko
/lib/modules/virtio-gpu.ko: /lib/modules/virtio_dma_buf.ko
/lib/modules/virt_wifi_sim.ko: /lib/modules/virt_wifi.ko
[^[:blank:]]+/ finds 1+ non-whitespace characters followed by a / thus matching longest string until it gets a / in each of the multiple string per line.
I am new to sed script. I have been researching how to add text to a line in file.
so the line I have in the text file looks like this
hosts allow = 192.168.122. 172.24.0
i want to add IP so line looks like
hosts allow = 192.168.122. 192.12.0 172.24.0
Through trial and error I only have:
sed -i '/allow/ s/.*/&,192.12.0./' testfile
which gives:
hosts allow = 192.168.122. 172.24.0. 192.12.0.
Check this test :
$ cat file1
hosts allow = 192.168.122. 172.24.0
hosts allow = 111.111.111. 222.222.222 333.333.333
$ sed -E 's/(.* = .*)( .*)/\1 george \2/g' file1
hosts allow = 192.168.122. george 172.24.0
hosts allow = 111.111.111. 222.222.222 george 333.333.333
$ sed -r 's/(.* = .[^ ]*)(.*)/\1 george \2/g' file1
hosts allow = 192.168.122. george 172.24.0
hosts allow = 111.111.111. george 222.222.222 333.333.333
This test uses sed with extended regex support (-E or -r switch) and capturing groups enclosed within ( )
Your question is too vague to say for sure (do you want to add a string to the middle of a set or after the first one or before the last one or at a fixed location or something else) but this might be what you're looking for:
$ sed 's/ [^[:space:]]*/& 192.12.0/2' file
hosts allow = 192.12.0 192.168.122. 172.24.0
$ sed 's/ [^[:space:]]*/& 192.12.0/3' file
hosts allow = 192.168.122. 192.12.0 172.24.0
$ sed 's/ [^[:space:]]*/& 192.12.0/4' file
hosts allow = 192.168.122. 172.24.0 192.12.0
Here's an awk solution, which I find more legible than sed solutions:
awk '$1$2$3 == "hostsallow=" { $NF="192.12.0 $NF" } { print }' \
testfile > tmp && mv tmp testfile
This takes the first three columns and ensures they concatenate to "hostsallow=" without spaces (I doubt you'll run into a host sallow = … line), then takes the value of the last column (identified as NF for the number of fields and whose value is identified with a $) and assigns the new value, a space, and the old value to it. All lines are then printed. Warning, this will collapse whitespace (in this case, I see that as a feature).
Unfortunately, awk doesn't have a -i option the way sed does, so this has to be saved in a temporary file and then put back on top of the original file.
I have tried to scan through the other posts in stack overflow for this, but couldn't get my code work, hence I am posting a new question.
Below is the content of file temp.
<?xml version="1.0" encoding="UTF-8"?>
<env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/<env:Body><dp:response xmlns:dp="http://www.datapower.com/schemas/management"><dp:timestamp>2015-01-
22T13:38:04Z</dp:timestamp><dp:file name="temporary://test.txt">XJzLXJlc3VsdHMtYWN0aW9uX18i</dp:file><dp:file name="temporary://test1.txt">lc3VsdHMtYWN0aW9uX18i</dp:file></dp:response></env:Body></env:Envelope>
This file contains the base64 encoded contents of two files names test.txt and test1.txt. I want to extract the base64 encoded content of each file to seperate files test.txt and text1.txt respectively.
To achieve this, I have to remove the xml tags around the base64 contents. I am trying below commands to achieve this. However, it is not working as expected.
sed -n '/test.txt"\>/,/\<\/dp:file\>/p' temp | perl -p -e 's#<dp:file name="temporary://test.txt">##g'|perl -p -e 's#</dp:file>##g' > test.txt
sed -n '/test1.txt"\>/,/\<\/dp:file\>/p' temp | perl -p -e 's#<dp:file name="temporary://test1.txt">##g'|perl -p -e 's#</dp:file></dp:response></env:Body></env:Envelope>##g' > test1.txt
Below command:
sed -n '/test.txt"\>/,/\<\/dp:file\>/p' temp | perl -p -e 's#<dp:file name="temporary://test.txt">##g'|perl -p -e 's#</dp:file>##g'
produces output:
XJzLXJlc3VsdHMtYWN0aW9uX18i
<dp:file name="temporary://test1.txt">lc3VsdHMtYWN0aW9uX18i</dp:response> </env:Body></env:Envelope>`
Howeveer, in the output I am expecting only first line XJzLXJlc3VsdHMtYWN0aW9uX18i. Where I am commiting mistake?
When i run below command, I am getting expected output:
sed -n '/test1.txt"\>/,/\<\/dp:file\>/p' temp | perl -p -e 's#<dp:file name="temporary://test1.txt">##g'|perl -p -e 's#</dp:file></dp:response></env:Body></env:Envelope>##g'
It produces below string
lc3VsdHMtYWN0aW9uX18i
I can then easily route this to test1.txt file.
UPDATE
I have edited the question by updating the source file content. The source file doesn't contain any newline character. The current solution will not work in that case, I have tried it and failed. wc -l temp must output to 1.
OS: solaris 10
Shell: bash
sed -n 's_<dp:file name="\([^"]*\)">\([^<]*\).*_\1 -> \2_p' temp
I add \1 -> to show link from file name to content but for content only, just remove this part
posix version so on GNU sed use --posix
assuming that base64 encoded contents is on the same line as the tag around (and not spread on several lines, that need some modification in this case)
Thanks to JID for full explaination below
How it works
sed -n
The -n means no printing so unless explicitly told to print, then there will be no output from sed
's_
This is to substitute the following regex using _ to separate regex from the replacement.
<dp:file name=
Regular text
"\([^"]*\)"
The brackets are a capture group and must be escaped unless the -r option is used( -r is not available on posix). Everything inside the brackets is captured. [^"]* means 0 or more occurrences of any character that is not a quote. So really this just captures anything between the two quotes.
>\([^<]*\)<
Again uses the capture group this time to capture everything between the > and <
.*
Everything else on the line
_\1 -> \2
This is the replacement, so replace everything in the regex before with the first capture group then a -> and then the second capture group.
_p
Means print the line
Resources
http://unixhelp.ed.ac.uk/CGI/man-cgi?sed
http://www.grymoire.com/Unix/Sed.html
/usr/xpg4/bin/sed works well here.
/usr/bin/sed is not working as expected in case if the file contains just 1 line.
below command works for a file containing only single line.
/usr/xpg4/bin/sed -n 's_<env:Envelope\(.*\)<dp:file name="temporary://BackUpDir/backupmanifest.xml">\([^>]*\)</dp:file>\(.*\)_\2_p' securebackup.xml 2>/dev/null
Without 2>/dev/null this sed command outputs the warning sed: Missing newline at end of file.
This because of the below reason:
Solaris default sed ignores the last line not to break existing scripts because a line was required to be terminated by a new line in the original Unix implementation.
GNU sed has a more relaxed behavior and the POSIX implementation accept the fact but outputs a warning.
I'm using Sed on a Mac. I am trying to do a simple string replace on a file that is not in the directory. I do:
sed -i 's/old/new/' /Users/A/file
and it says invalid command code A.
What do I need to do?
The -i option in OSX/BSD sed is a little different than the GNU/Linux version in that it requires a backup extension to be given, even if it's an empty string (which means that no backup will be made). The "invalid command code" error message occurs because s/old/new is taken as the backup extension and /Users/A/file is taken as the script (where A is seen as an invalid command name). So it needs to be something like:
sed -i '' 's/old/new/' /Users/A/file
if you have perl:
perl -p -i -e 's/old/new/' /Users/A/file
The -i in sed is not a standard across OS's (not a POSIX standard). This should work every time:
cp /Users/A/file /Users/A/file.sed
cat /Users/A/file.sed | sed 's/old/new' > /Users/A/file
I have a file env which looks like
....
LEGACY_DATABASE_SERVER=10.0.0.1
SERVER=10.1.1.1
and here is my sed command:
sed -e "s/SERVER=.*/SERVER=$INSTANCE_IP/g;n" $ENV_FILE > $ENV_FILE.tmp && mv $ENV_FILE.tmp $ENV_FILE
the problem is that sed is also replacing LEGACY_DATABASE_SERVER which is not what I want. I only want SERVER replaced.
(LEGACY_DATABASE_SERVER is a super string of SERVER and I only want to replace SERVER)
What am I missing?
Presumably, you want to make sure that sed knows "SERVER" is at the beginning of the line:
sed -e "s/^SERVER=.*/SERVER=$INSTANCE_IP/g;n" $ENV_FILE > $ENV_FILE.tmp && mv $ENV_FILE.tmp $ENV_FILE