Type of expression is ambiguous without more context Swift - swift

I am getting a 'Type of expression is ambiguous without more context ' on this part of code from a project I am trying to upgrade to latest Swift version. I can't seem to figure it out. I tried different things but can't get it to work.
The problem is on the syntax of this line
let imageToDeleteParameters = imagesToDelete.map { ["id": $0.id, "url": $0.url.absoluteString, "_destroy": true] }
Full code:
extension TutorialCreationRequest: WebserviceParametrable {
func toParameters() -> [String: AnyObject] {
let imageParameters = images.map { ["url": $0] }
let imageToDeleteParameters = imagesToDelete.map { ["id": $0.id, "url": $0.url.absoluteString, "_destroy": true] }
return [
"title": title,
"is_draft": isDraft,
"difficulty": difficulty,
"duration": duration,
"cost": cost,
"user_id": userId,
"description": description,
"to_sell": toSell,
"images": [imageParameters, imageToDeleteParameters].flatMap { $0 }
]
}
}


This happens when you have a function with wrong argument names.
Example:
functionWithArguments(argumentNameWrong: , argumentName2: )
and You declared your function as:
functionWithArguments(argumentName1: , argumentName2: ){}
This usually happens when you changed the name of a Variable. Make sure you refactor when you do that.


This can happen if any part of your highlighted method or property is attempting to access a property or method with the incorrect type.
Here is a troubleshooting checklist, make sure:
the type of arguments match in the call site and implementation.
the argument names match in the call site and implementation.
the method name matches in the call site and implementation.
the returned value of a property or method matches in the usage and implementation (ie: enumerated())
you don't have a duplicated method with potentially ambiguous types such as with protocols or generics.
the compiler can infer the correct type when using type inference.
A Strategy
Try breaking apart your method into a greater number of simpler method/implementations.
For example, lets say you are running compactMap on an array of custom Types. In the closure you are passing to the compactMap method, you initialize and return another custom struct. When you get this error, it is difficult to tell which part of your code is offending.
For debugging purposes, you can use a for in loop instead of compactMap.
instead of passing the arguments, directly, you can assign them to constants in the for loop.
By this point, you may come to a realization, such as, instead of the property you thought you wanted to assign actually had a property on it that had the actual value you wanted to pass.


Not an answer to this question, but as I came here looking for the error others might find this also useful:
For me, I got this Swift error when I tried to use the for (index, object) loop on an array without adding the .enumerated() part ...


The compiler can't figure out what type to make the Dictionary, because it's not homogenous. You have values of different types. The only way to get around this is to make it a [String: Any], which will make everything clunky as all hell.
return [
"title": title,
"is_draft": isDraft,
"difficulty": difficulty,
"duration": duration,
"cost": cost,
"user_id": userId,
"description": description,
"to_sell": toSell,
"images": [imageParameters, imageToDeleteParameters].flatMap { $0 }
] as [String: Any]
This is a job for a struct. It'll vastly simplify working with this data structure.


I had this message when the type of a function parameter didn't fit. In my case it was a String instead of an URL.


Explicitly declaring the inputs for that mapping function should do the trick:
let imageToDeleteParameters = imagesToDelete.map {
(whatever : WhateverClass) -> Dictionary<String, Any> in
["id": whatever.id, "url": whatever.url.absoluteString, "_destroy": true]
}
Substitute the real class of "$0" for "WhateverClass" in that code snippet, and it should work.


I got this error when I put a space before a comma in the parameters when calling a function.
eg, I used:
myfunction(parameter1: parameter1 , parameter2: parameter2)
Whereas it should have been:
myfunction(parameter1: parameter1, parameter2: parameter2)
Deleting the space got rid of the error message


In my case, this error message shown when I don't added optional property to constructor.
struct Event: Identifiable, Codable {
var id: String
var summary: String
var description: String?
// also has other props...
init(id: String, summary: String, description: String?){
self.id = id
self.summary = summary
self.description = description
}
}
// skip pass description
// It show message "Type of expression is ambiguous without more context"
Event(
id: "1",
summary: "summary",
)
// pass description explicity pass nil to description
Event(
id: "1",
summary: "summary",
description: nil
)
but it looks always not occured.
I test in my playground this code, it show warning about more concrete
var str = "Hello, playground"
struct User {
var id: String
var name: String?
init(id: String, name: String?) {
self.id = id
self.name = name
}
}
User(id: "hoge") // Missing argument for parameter 'name' in call


For me the case was Type inference
I have changed the function parameters from int To float but did not update the calling code, and the compiler did not warn me on wrong type passed to the function
Before
func myFunc(param:Int, parma2:Int) {}
After
func myFunc(param:Float, parma2:Float) {}
Calling code with error
var param1:Int16 = 1
var param2:Int16 = 2
myFunc(param:param1, parma2:param2)// error here: Type of expression is ambiguous without more context
To fix:
var param1:Float = 1.0f
var param2:Float = 2.0f
myFunc(param:param1, parma2:param2)// ok!


My problem were the parameters without default value
I changed
let contaPadrao = RedeConta(
agencia: cPadrao?.agencia,
conta: cPadrao?.conta,
dac: cPadrao?.dac
)
to
let contaPadrao = RedeConta(
agencia: cPadrao?.agencia ?? "",
conta: cPadrao?.conta ?? "",
dac: cPadrao?.dac ?? ""
)


You have two " " before the =
let imageToDeleteParameters = imagesToDelete.map { ["id": $0.id, "url": $0.url.absoluteString, "_destroy": true] }


In my case it happened with NSFetchedResultsController and the reason was that I defined the NSFetchedResultsController for a different model than I created the request for the initialization (RemotePlaylist vs. Playlist):
var fetchedPlaylistsController:NSFetchedResultsController<RemotePlaylist>!
but initiated it with a request for another Playlist:
let request = Playlist.createFetchRequest()
fetchedPlaylistsController = NSFetchedResultsController(fetchRequest: request, ...


In my case, I ran into this error when I was creating a distribution build, and a class was referring to Debug only context method.
Something like this. Try compiling the below class for the Distribution build.
class MyClass {
func sayHello() {
helloWorld()
}
#if DEBUG
func helloWorld() {
print("Hello world")
}
#endif
}


Make sure if there is any delegate methods are available with extension, then implement those and error will disappear.


In my case, the arguments I was passing had optional String values. Providing a default value to fall back on ( in case the value is nil ) solved this issue for me.
I changed this -
router?.pushToDetailsScreen(
gitHubRepositoryOwnerName: gitHubRepositoryDetails?[index].owner?.login,
gitHubRepositoryName: gitHubRepositoryDetails?[index].name,
avatarUrl: gitHubRepositoryDetails?[index].owner?.avatar_url)
to this -
router?.pushToDetailsScreen(
gitHubRepositoryOwnerName: gitHubRepositoryDetails?[index].owner?.login ?? "",
gitHubRepositoryName: gitHubRepositoryDetails?[index].name ?? "",
avatarUrl: gitHubRepositoryDetails?[index].owner?.avatar_url ?? "")


This error could be shown due to multiple reasons. One of the most prominent reasons is a type mismatch. For example,
Suppose, parameter icons is a type of array and we passed an Enum as IconDismiss.
## Wrong
text.config = TextField.Config(isClearable: true, icons: IconDismiss)
## Correct
text.config = TextField.Config(isClearable: true, icons: [IconDismiss])


In my case it was very similar to what #scottyBlades said. I had changed a member variable name and not updated it in a callback and that caused the confusing/unhelpful error.
class SomeClass {
var newVarName: String
func doSomething() {
Async.makeCall { result in // << error shows here
self.oldVarName = result // not changing it to newVarName was the cause
}
}
}


As theEye's answer it is not an answer to this question, but as I also came here looking for the error im posting my case as others might find this also useful:
I got this error message when I was by error trying to calculate a value of two different types.
In my case I was trying to divide a CGFloat by a Double

Related

How can I have a variable and a function with same name in Swift

I want to have a variable and a function with same name, therefore I have this codes:
var testString: String = "some string from variable!"
// use case: print(testString)
func testString() -> String {
return "some string from function!"
}
// use case: print(testString())
As you can see there is a big difference in both use cases! one like testString and the other with testString(), but xCode complain this to me:
Invalid redeclaration of 'testString()'
Which I do not know why it has to be an issue! one thing is a variable and other is function!
How ever I done a little hack and I deformed the function to this one in down, now it compile and no issue! the use case is still the same like testString()
func testString(_ value: String? = nil) -> String {
return "some string from function!"
}
// use case: print(testString())
Now I have the things I wanted, but I have unwished initializer for function! how can I solve this issue in general?

it's not possible, as they share the same namespace:
https://forums.swift.org/t/why-doesnt-swift-allow-a-variable-and-a-function-with-the-same-name/5038

Failing cast from Any to Int

I have the following dictionary of type [String: Any] (this is what the log looks like):
["name": Cesare de Cal, "last_name": de Cal, "email": hi#cesare.io, "id": 1012058902268810, "first_name": Cesare]
I want to get the profile ID "id":
if let fbID = fbValues["id"] as? Int {
print("here should be the fb Id", fbID)
} else {
print("cast failed") // cast failed
}
but this cast fails. Why? I'm assuming "id" (1012058902268810) is a number, right?

rob already provided you with a possible solution. Just to answer your question about why the cast fails, it fails because of how type casting works in Swift:
From the documentation:
Type casting is a way to check the type of an instance, or to treat
that instance as a different superclass or subclass from somewhere
else in its own class hierarchy. (...)
A constant or variable of a certain class type may actually
refer to an instance of a subclass behind the scenes. Where you
believe this is the case, you can try to downcast to the subclass type
with a type cast operator (as? or as!). (...)
Casting does not actually modify the instance or change its values. The underlying instance remains the same; it is simply treated and accessed as an instance of the type to which it has been cast.
This will work:
let something: Any = 1
let number = something as! Int
This won't work:
let something: Any = "1"
let number = something as! Int
This won't work either because Int has no initializer for type Any:
let something: Any = "1"
let number = Int(something)
But this will work - first you cast to String and then you coerce to Int (and Int has an initializer that accepts String)
let something: Any = "1"
let string = something as! String
let number = Int(string)!
Edit to answer Cesare: You're right. I edited my answer to just provide more info about type casting since you already had your problem solved ;)
And these were just some examples for getting the cast/coercion point across. In a real scenario you shouldn't be forcing unwrapping any of this as John Montgomery pointed out.

If you don't know whether the id value is coming in as a String or an Int, you could try handling both:
switch fbValues["id"] {
case nil:
print("no id given")
case let string as String:
if let id = Int(string) { print("id = \(id)") }
else { print("non-numeric id \(string)") }
case let id as Int:
print("id = \(id)")
default:
print("what is this I don't even")
}

Convert or cast object to string

how can i convert any object type to a string?
let single_result = results[i]
var result = ""
result = single_result.valueForKey("Level")
now i get the error: could not assign a value of type any object to a value of type string.
and if i cast it:
result = single_result.valueForKey("Level") as! String
i get the error:
Could not cast value of type '__NSCFNumber' (0x103215cf0) to 'NSString' (0x1036a68e0).
How can i solve this issue?

You can't cast any random value to a string. A force cast (as!) will fail if the object can't be cast to a string.
If you know it will always contain an NSNumber then you need to add code that converts the NSNumber to a string. This code should work:
if let result_number = single_result.valueForKey("Level") as? NSNumber
{
let result_string = "\(result_number)"
}
If the object returned for the "Level" key can be different object types then you'll need to write more flexible code to deal with those other possible types.
Swift arrays and dictionaries are normally typed, which makes this kind of thing cleaner.
I'd say that #AirSpeedVelocity's answer (European or African?) is the best. Use the built-in toString function. It sounds like it works on ANY Swift type.
EDIT:
In Swift 3, the answer appears to have changed. Now, you want to use the String initializer
init(describing:)
Or, to use the code from the question:
result = single_result.valueForKey("Level")
let resultString = String(describing: result)
Note that usually you don't want valueForKey. That is a KVO method that will only work on NSObjects. Assuming single_result is a Dictionary, you probably want this syntax instead:
result = single_result["Level"]

This is the documentation for the String initializer provided here.
let s = String(describing: <AnyObject>)
Nothing else is needed. This works for a diverse range of objects.

The toString function accepts any type and will always produce a string.
If it’s a Swift type that implements the Printable protocol, or has overridden NSObject’s description property, you’ll get whatever the .description property returns. In the case of NSNumber, you’ll get a string representation of the number.
If it hasn’t, you’ll get a fairly unhelpful string of the class name plus the memory address. But most standard classes, including NSNumber, will produce something sensible.
import Foundation
class X: NSObject {
override var description: String {
return "Blah"
}
}
let x: AnyObject = X()
toString(x) // return "Blah"
"\(x)" // does the same thing but IMO is less clear
struct S: Printable {
var description: String {
return "asdf"
}
}
// doesn't matter if it's an Any or AnyObject
let s: Any = S()
toString(s) // reuturns "asdf"
let n = NSNumber(double: 123.45)
toString(n) // returns "123.45"
n.stringValue // also works, but is specific to NSNumber
(p.s. always use toString rather than testing for Printable. For one thing, String doesn’t conform to Printable...)

toString() doesn't seem to exist in Swift 3 anymore.
Looks like there's a failable initializer that will return the passed in value's description.
init?(_ description: String)
Docs here https://developer.apple.com/reference/swift/string/1540435-init

Cannot invoke 'append' with an argument list of type'(String)'

What is wrong here and how to solve this problem?
struct Venue {
let building: String
var rooms: [String]?
}
func addRoom(building: String, room: String) {
if let venueIndex = find(venues.map {$0.building}, building) {
venues[venueIndex].rooms.append(room) //Cannot invoke 'append' with an argument list of type'(String)'
}
}
var venues: [Venue] = [...]

The problem is that venues[venueIndex].rooms is not a [String] but a [String]?. Optionals don’t have an append method – the value wrapped inside them might, but they don’t.
You could use optional chaining to do the append in the case where it isn’t nil:
venues[venueIndex].rooms?.append(room)
But you may instead want to initialize rooms to an empty index instead when it is nil, in which case you need to do a slightly messier assignment rather than an append:
venues[venueIndex].rooms = (venues[venueIndex].rooms ?? []) + [room]
However, it is worth asking yourself, does rooms really need to be optional? Or could it just be a non-optional array with a starting value of empty? If so, this will likely simplify much of your code.

How do I print the type or class of a variable in Swift?

Is there a way to print the runtime type of a variable in swift? For example:
var now = NSDate()
var soon = now.dateByAddingTimeInterval(5.0)
println("\(now.dynamicType)")
// Prints "(Metatype)"
println("\(now.dynamicType.description()")
// Prints "__NSDate" since objective-c Class objects have a "description" selector
println("\(soon.dynamicType.description()")
// Compile-time error since ImplicitlyUnwrappedOptional<NSDate> has no "description" method
In the example above, I'm looking for a way to show that the variable "soon" is of type ImplicitlyUnwrappedOptional<NSDate>, or at least NSDate!.

Update September 2016
Swift 3.0: Use type(of:), e.g. type(of: someThing) (since the dynamicType keyword has been removed)
Update October 2015:
I updated the examples below to the new Swift 2.0 syntax (e.g. println was replaced with print, toString() is now String()).
From the Xcode 6.3 release notes:
#nschum points out in the comments that the Xcode 6.3 release notes show another way:
Type values now print as the full demangled type name when used with
println or string interpolation.
import Foundation
class PureSwiftClass { }
var myvar0 = NSString() // Objective-C class
var myvar1 = PureSwiftClass()
var myvar2 = 42
var myvar3 = "Hans"
print( "String(myvar0.dynamicType) -> \(myvar0.dynamicType)")
print( "String(myvar1.dynamicType) -> \(myvar1.dynamicType)")
print( "String(myvar2.dynamicType) -> \(myvar2.dynamicType)")
print( "String(myvar3.dynamicType) -> \(myvar3.dynamicType)")
print( "String(Int.self) -> \(Int.self)")
print( "String((Int?).self -> \((Int?).self)")
print( "String(NSString.self) -> \(NSString.self)")
print( "String(Array<String>.self) -> \(Array<String>.self)")
Which outputs:
String(myvar0.dynamicType) -> __NSCFConstantString
String(myvar1.dynamicType) -> PureSwiftClass
String(myvar2.dynamicType) -> Int
String(myvar3.dynamicType) -> String
String(Int.self) -> Int
String((Int?).self -> Optional<Int>
String(NSString.self) -> NSString
String(Array<String>.self) -> Array<String>
Update for Xcode 6.3:
You can use the _stdlib_getDemangledTypeName():
print( "TypeName0 = \(_stdlib_getDemangledTypeName(myvar0))")
print( "TypeName1 = \(_stdlib_getDemangledTypeName(myvar1))")
print( "TypeName2 = \(_stdlib_getDemangledTypeName(myvar2))")
print( "TypeName3 = \(_stdlib_getDemangledTypeName(myvar3))")
and get this as output:
TypeName0 = NSString
TypeName1 = __lldb_expr_26.PureSwiftClass
TypeName2 = Swift.Int
TypeName3 = Swift.String
Original answer:
Prior to Xcode 6.3 _stdlib_getTypeName got the mangled type name of a variable. Ewan Swick's blog entry helps to decipher these strings:
e.g. _TtSi stands for Swift's internal Int type.
Mike Ash has a great blog entry covering the same topic.

Edit: A new toString function has been introduced in Swift 1.2 (Xcode 6.3).
You can now print the demangled type of any type using .self and any instance using .dynamicType:
struct Box<T> {}
toString("foo".dynamicType) // Swift.String
toString([1, 23, 456].dynamicType) // Swift.Array<Swift.Int>
toString((7 as NSNumber).dynamicType) // __NSCFNumber
toString((Bool?).self) // Swift.Optional<Swift.Bool>
toString(Box<SinkOf<Character>>.self) // __lldb_expr_1.Box<Swift.SinkOf<Swift.Character>>
toString(NSStream.self) // NSStream
Try calling YourClass.self and yourObject.dynamicType.
Reference: https://devforums.apple.com/thread/227425.

Swift 3.0
let string = "Hello"
let stringArray = ["one", "two"]
let dictionary = ["key": 2]
print(type(of: string)) // "String"
// Get type name as a string
String(describing: type(of: string)) // "String"
String(describing: type(of: stringArray)) // "Array<String>"
String(describing: type(of: dictionary)) // "Dictionary<String, Int>"
// Get full type as a string
String(reflecting: type(of: string)) // "Swift.String"
String(reflecting: type(of: stringArray)) // "Swift.Array<Swift.String>"
String(reflecting: type(of: dictionary)) // "Swift.Dictionary<Swift.String, Swift.Int>"

Is this what you're looking for?
println("\(object_getClassName(now))");
It prints "__NSDate"
UPDATE: Please note this no longer seems to work as of Beta05

My current Xcode is Version 6.0 (6A280e).
import Foundation
class Person { var name: String; init(name: String) { self.name = name }}
class Patient: Person {}
class Doctor: Person {}
var variables:[Any] = [
5,
7.5,
true,
"maple",
Person(name:"Sarah"),
Patient(name:"Pat"),
Doctor(name:"Sandy")
]
for variable in variables {
let typeLongName = _stdlib_getDemangledTypeName(variable)
let tokens = split(typeLongName, { $0 == "." })
if let typeName = tokens.last {
println("Variable \(variable) is of Type \(typeName).")
}
}
Output:
Variable 5 is of Type Int.
Variable 7.5 is of Type Double.
Variable true is of Type Bool.
Variable maple is of Type String.
Variable Swift001.Person is of Type Person.
Variable Swift001.Patient is of Type Patient.
Variable Swift001.Doctor is of Type Doctor.

As of Xcode 6.3 with Swift 1.2, you can simply convert type values into the full demangled String.
toString(Int) // "Swift.Int"
toString(Int.Type) // "Swift.Int.Type"
toString((10).dynamicType) // "Swift.Int"
println(Bool.self) // "Swift.Bool"
println([UTF8].self) // "Swift.Array<Swift.UTF8>"
println((Int, String).self) // "(Swift.Int, Swift.String)"
println((String?()).dynamicType)// "Swift.Optional<Swift.String>"
println(NSDate) // "NSDate"
println(NSDate.Type) // "NSDate.Type"
println(WKWebView) // "WKWebView"
toString(MyClass) // "[Module Name].MyClass"
toString(MyClass().dynamicType) // "[Module Name].MyClass"

You can still access the class, through className (which returns a String).
There are actually several ways to get the class, for example classForArchiver, classForCoder, classForKeyedArchiver (all return AnyClass!).
You can't get the type of a primitive (a primitive is not a class).
Example:
var ivar = [:]
ivar.className // __NSDictionaryI
var i = 1
i.className // error: 'Int' does not have a member named 'className'
If you want to get the type of a primitive, you have to use bridgeToObjectiveC(). Example:
var i = 1
i.bridgeToObjectiveC().className // __NSCFNumber

You can use reflect to get information about object.
For example name of object class:
var classname = reflect(now).summary

Xcode 8 Swift 3.0 use type(of:)
let className = "\(type(of: instance))"

I had luck with:
let className = NSStringFromClass(obj.dynamicType)

SWIFT 5
With the latest release of Swift 3 we can get pretty descriptions of type names through the String initializer. Like, for example print(String(describing: type(of: object))). Where object can be an instance variable like array, a dictionary, an Int, a NSDate, an instance of a custom class, etc.
Here is my complete answer: Get class name of object as string in Swift
That question is looking for a way to getting the class name of an object as string but, also i proposed another way to getting the class name of a variable that isn't subclass of NSObject. Here it is:
class Utility{
class func classNameAsString(obj: Any) -> String {
//prints more readable results for dictionaries, arrays, Int, etc
return String(describing: type(of: obj))
}
}
I made a static function which takes as parameter an object of type Any and returns its class name as String :) .
I tested this function with some variables like:
let diccionary: [String: CGFloat] = [:]
let array: [Int] = []
let numInt = 9
let numFloat: CGFloat = 3.0
let numDouble: Double = 1.0
let classOne = ClassOne()
let classTwo: ClassTwo? = ClassTwo()
let now = NSDate()
let lbl = UILabel()
and the output was:
diccionary is of type Dictionary
array is of type Array
numInt is of type Int
numFloat is of type CGFloat
numDouble is of type Double
classOne is of type: ClassOne
classTwo is of type: ClassTwo
now is of type: Date
lbl is of type: UILabel

In Xcode 8, Swift 3.0
Steps:
1. Get the Type:
Option 1:
let type : Type = MyClass.self //Determines Type from Class
Option 2:
let type : Type = type(of:self) //Determines Type from self
2. Convert Type to String:
let string : String = "\(type)" //String

In Swift 3.0, you can use type(of:), as dynamicType keyword has been removed.

To get a type of object or class of object in Swift, you must need to use a type(of: yourObject)
type(of: yourObject)

When using Cocoa (not CocoaTouch), you can use the className property for objects that are subclasses of NSObject.
println(now.className)
This property is not available for normal Swift objects, which aren't subclasses of NSObject (and in fact, there is no root id or object type in Swift).
class Person {
var name: String?
}
var p = Person()
println(person.className) // <- Compiler error
In CocoaTouch, at this time there is not a way to get a string description of the type of a given variable. Similar functionality also does not exist for primitive types in either Cocoa or CocoaTouch.
The Swift REPL is able to print out a summary of values including its type, so it is possible this manner of introspection will be possible via an API in the future.
EDIT: dump(object) seems to do the trick.

The top answer doesn't have a working example of the new way of doing this using type(of:. So to help rookies like me, here is a working example, taken mostly from Apple's docs here - https://developer.apple.com/documentation/swift/2885064-type
doubleNum = 30.1
func printInfo(_ value: Any) {
let varType = type(of: value)
print("'\(value)' of type '\(varType)'")
}
printInfo(doubleNum)
//'30.1' of type 'Double'

I've tried some of the other answers here but milage seems to very on what the underling object is.
However I did found a way you can get the Object-C class name for an object by doing the following:
now?.superclass as AnyObject! //replace now with the object you are trying to get the class name for
Here is and example of how you would use it:
let now = NSDate()
println("what is this = \(now?.superclass as AnyObject!)")
In this case it will print NSDate in the console.

I found this solution which hopefully might work for someone else.
I created a class method to access the value. Please bear in mind this will work for NSObject subclass only. But at least is a clean and tidy solution.
class var className: String!{
let classString : String = NSStringFromClass(self.classForCoder())
return classString.componentsSeparatedByString(".").last;
}

In the latest XCode 6.3 with Swift 1.2, this is the only way I found:
if view.classForCoder.description() == "UISegment" {
...
}

Many of the answers here do not work with the latest Swift (Xcode 7.1.1 at time of writing).
The current way of getting the information is to create a Mirror and interrogate that. For the classname it is as simple as:
let mirror = Mirror(reflecting: instanceToInspect)
let classname:String = mirror.description
Additional information about the object can also be retrieved from the Mirror. See http://swiftdoc.org/v2.1/type/Mirror/ for details.

Swift version 4:
print("\(type(of: self)) ,\(#function)")
// within a function of a class
Thanks #Joshua Dance

In lldb as of beta 5, you can see the class of an object with the command:
fr v -d r shipDate
which outputs something like:
(DBSalesOrderShipDate_DBSalesOrderShipDate_ *) shipDate = 0x7f859940
The command expanded out means something like:
Frame Variable (print a frame variable) -d run_target (expand dynamic types)
Something useful to know is that using "Frame Variable" to output variable values guarantees no code is executed.

I've found a solution for self-developed classes (or such you have access to).
Place the following computed property within your objects class definition:
var className: String? {
return __FILE__.lastPathComponent.stringByDeletingPathExtension
}
Now you can simply call the class name on your object like so:
myObject.className
Please note that this will only work if your class definition is made within a file that is named exactly like the class you want the name of.
As this is commonly the case the above answer should do it for most cases. But in some special cases you might need to figure out a different solution.
If you need the class name within the class (file) itself you can simply use this line:
let className = __FILE__.lastPathComponent.stringByDeletingPathExtension
Maybe this method helps some people out there.

Based on the answers and comments given by Klass and Kevin Ballard above, I would go with:
println(_stdlib_getDemangledTypeName(now).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(soon).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(soon?).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(soon!).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar0).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar1).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar2).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar3).componentsSeparatedByString(".").last!)
which will print out:
"NSDate"
"ImplicitlyUnwrappedOptional"
"Optional"
"NSDate"
"NSString"
"PureSwiftClass"
"Int"
"Double"

let i: Int = 20
func getTypeName(v: Any) -> String {
let fullName = _stdlib_demangleName(_stdlib_getTypeName(i))
if let range = fullName.rangeOfString(".") {
return fullName.substringFromIndex(range.endIndex)
}
return fullName
}
println("Var type is \(getTypeName(i)) = \(i)")

Swift 4:
// "TypeName"
func stringType(of some: Any) -> String {
let string = (some is Any.Type) ? String(describing: some) : String(describing: type(of: some))
return string
}
// "ModuleName.TypeName"
func fullStringType(of some: Any) -> String {
let string = (some is Any.Type) ? String(reflecting: some) : String(reflecting: type(of: some))
return string
}
Usage:
print(stringType(of: SomeClass())) // "SomeClass"
print(stringType(of: SomeClass.self)) // "SomeClass"
print(stringType(of: String())) // "String"
print(fullStringType(of: String())) // "Swift.String"

There appears to be no generic way to print the type name of an arbitrary value's type. As others have noted, for class instances you can print value.className but for primitive values it appears that at runtime, the type information is gone.
For instance, it looks as if there's not a way to type: 1.something() and get out Int for any value of something. (You can, as another answer suggested, use i.bridgeToObjectiveC().className to give you a hint, but __NSCFNumber is not actually the type of i -- just what it will be converted to when it crosses the boundary of an Objective-C function call.)
I would be happy to be proven wrong, but it looks like the type checking is all done at compile time, and like C++ (with RTTI disabled) much of the type information is gone at runtime.

This is how you get a type string of your object or Type which is consistent and takes into account to which module the object definition belongs to or nested in. Works in Swift 4.x.
#inline(__always) func typeString(for _type: Any.Type) -> String {
return String(reflecting: type(of: _type))
}
#inline(__always) func typeString(for object: Any) -> String {
return String(reflecting: type(of: type(of: object)))
}
struct Lol {
struct Kek {}
}
// if you run this in playground the results will be something like
typeString(for: Lol.self) // __lldb_expr_74.Lol.Type
typeString(for: Lol()) // __lldb_expr_74.Lol.Type
typeString(for: Lol.Kek.self)// __lldb_expr_74.Lol.Kek.Type
typeString(for: Lol.Kek()) // __lldb_expr_74.Lol.Kek.Type

Not exactly what you are after, but you can also check the type of the variable against Swift types like so:
let object: AnyObject = 1
if object is Int {
}
else if object is String {
}
For example.

Xcode 7.3.1, Swift 2.2:
String(instanceToPrint.self).componentsSeparatedByString(".").last