Whenever I write a testbench for my systemverilog code, the output seems to always be X even though the implementation is correct. Where is my error?
`timescale 1ns / 1ps
module fsm( input logic clk, input logic reset,
input logic start, clockwise,
output logic [3:0] pattern);
parameter A=4'b1100,
B=4'b0110,
Ab=4'b0011,
Bb=4'b1001;
typedef enum logic [1:0] {S0,S1,S2,S3} statetype;
statetype state, nextstate;
//state register
always# (posedge clk)
begin
if (reset)
state= S0;
else
state = nextstate;
end
//nextstate logic
always_comb
case(state)
S0: if(start==1 && clockwise==0)
nextstate<= S3;
else if(start==1&&clockwise==1)
nextstate<=S1;
else
nextstate<=S0;
S1: if(start==1 && clockwise==0)
nextstate<= S0;
else if(start==1&&clockwise==1)
nextstate<=S2;
else
nextstate<=S1;
S2: if(start==1 && clockwise==0)
nextstate<= S1;
else if(start==1&&clockwise==1)
nextstate<=S3;
else
nextstate<=S2;
S3: if(start==1 && clockwise==0)
nextstate<= S2;
else if(start==1&&clockwise==1)
nextstate<=S0;
else
nextstate<=S3;
endcase
//output logic
always# (posedge clk)
case(state)
S0: pattern= A;
S1: pattern= B;
S2: pattern= Ab;
S3: pattern= Bb;
endcase
endmodule
and here is my testbench
module fsmtest();
logic clk, reset, clockwise, start;
logic [3:0] pattern;
fsm dut(clk, reset, start, clockwise, pattern);
//generate clock
always
begin
clk=0; #5; clk=1; #5;
end
initial
begin
reset=0;
start=1;
clockwise=1;
#10;
start=0;
#10;
end
endmodule
I'm not sure if it is my finite state machine that is wrong or if it's the testbench. Hoping to get some help, thanks in advance.
You never asserted reset, so your state machine remains uninitialized. You should fix this by adding a default branch to your case statement. Then, if your DUT ever comes up in an un-encoded state, it is guaranteed to get into a known state.
Related
I am currently in the process of designing a counter in SystemVerilog and I am unsure of how to design the D-flip flip module.
A flip-flop is inferred by synthesis tool for all signals assigned in an always_ff process.
So if you are designing an 8b counter, you would write:
logic [7:0] cnt;
always_ff # (posedge clk or negedge rst_n) begin : proc_cnt
if(!rst_n) cnt <= 0;
else cnt <= cnt + 1;
end
I'm trying to understanding how the following code works, but struggling to put it together in my head. Could someone give me a more intuitive (visual) explanation of how this pipelined multiplier stage works?
// This is one stage of an 8 stage (9 depending on how you look at it)
// pipelined multiplier that multiplies 2 64-bit integers and returns
// the low 64 bits of the result. This is not an ideal multiplier but
// is sufficient to allow a faster clock period than straight *
module mult_stage(
input clock, reset, start,
input [63:0] product_in, mplier_in, mcand_in,
output logic done,
output logic [63:0] product_out, mplier_out, mcand_out
);
logic [63:0] prod_in_reg, partial_prod_reg;
logic [63:0] partial_product, next_mplier, next_mcand;
assign product_out = prod_in_reg + partial_prod_reg;
assign partial_product = mplier_in[7:0] * mcand_in;
assign next_mplier = {8'b0,mplier_in[63:8]};
assign next_mcand = {mcand_in[55:0],8'b0};
//synopsys sync_set_reset "reset"
always_ff #(posedge clock) begin
prod_in_reg <= #1 product_in;
partial_prod_reg <= #1 partial_product;
mplier_out <= #1 next_mplier;
mcand_out <= #1 next_mcand;
end
// synopsys sync_set_reset "reset"
always_ff #(posedge clock) begin
if(reset)
done <= #1 1'b0;
else
done <= #1 start;
end
endmodule
I am trying to assign value on a specific bit of a 2D array(code[i][k]). This is a net type. But the value not being assigned.reg [3:0] code[0:3] gets unknown logic value 'X'.
Here is the code snippet
for(k=0;k<len;k++) begin
if (tc[k] == 1'b0) begin
code[i][k]= 1'b0;//----> value is not assigning as expected
end else begin
code[i][k]= 1'b1;// ---> value is not assigning as expected
end
end
codeLen[i] = len;
This for loop belongs to always block.Here, code and codeLen is output type.
output [3:0] code[0:3];
output [3:0] codeLen[0:3];
reg [3:0] code[0:3];
reg [3:0] codeLen[0:3];
codeLen[i] is assigned correctly but not the code[i][k]. I was trying to assign k-th bit of i-th byte.
Details
I have created a module which takes 6 inputs and returns two 2-dimensional arrays as output.
Here is the module:
`timescale 1ns / 1ps
module generate_code(CLK,nRST,nodes,nodeCount,characters,charCount,code,codeLen);
input CLK;
input nRST;
input integer nodeCount;//Total nodes in huffman tree
input integer charCount;//Total unique characters
input [6:0] characters[0:3];
input [23:0] nodes[0:6]; // total characters
output [3:0] code[0:3]; //[2:0] max code length <= total characters
output [3:0] codeLen[0:3];
reg [3:0] code[0:3];
reg [3:0] codeLen[0:3];
reg[3:0] tc;//temprary code reg. Holds a single bit in each byte
integer len=0;//code length
reg [23:0] tNode;
function void FindRoot;
reg [23:0] aNode;//local
integer i;
begin
for (i=0; i<nodeCount;i++) begin // For all nodes
aNode= nodes[i]; // aNode is current node
if (tNode[23:16] == aNode[14:7]) begin
tc[len]= tNode[15];//15th bit of nodes is codebit
len++;
//aNode is parent of tNode. Is it root?
if(aNode[23:16]==8'b0000_0000) begin//or frequency==nodeCount or node_id = 8'b1111_1111
return;
end else begin
tNode=aNode;
FindRoot();
end
end
end
end
endfunction
always#(posedge CLK or negedge nRST)
begin
if(!nRST) begin
// init
end
else begin
// Do code generation
integer i,j,k;
for(i= 0;i < charCount;i++) begin // For all character we are going to find codeword
for(j=0; j<nodeCount; j++) begin
tNode= nodes[j];//current node
if (characters[i] == tNode[6:0]) begin
// Got the character. tNode is a leaf nodes. Lets back track to root.
break;
end
end
len=0;
FindRoot();
for(k=0;k<len;k++) begin
if (tc[k] == 1'b0) begin
code[i][k]= 1'b0;
end else begin
code[i][k]= 1'b1;
end
end
//code[i]=2;
codeLen[i]= len;
end
end
end
endmodule
When I am assigning values to code[][], it is expected that following loop is executed. Though not all the bits of code[][] will be set. During debugging, when I come to assignment, I found that value is not being assigned (code[i][k] =1 or 0). Its getting unknown logic value X.
for(k=0;k<len;k++) begin
if (tc[k] == 1'b0) begin
code[i][k]= 1'b0;
end else begin
code[i][k]= 1'b1;
end
end
Testbench:
`timescale 1ns / 1ps
module generate_code_test;
// Inputs
reg CLK;
reg nRST;
integer nodeCount=7;//Total nodes in huffman tree
integer charCount=4;//Total unique characters
reg [6:0] characters[0:3];
reg [23:0] nodes[0:6]; // total characters
// Outputs
wire [3:0] code[0:3]; //[2:0] max code length <= total characters
wire [3:0] codeLen[0:3];
generate_code uut (
.CLK(CLK),
.nRST(nRST),
.nodes(nodes),
.nodeCount(nodeCount),
.characters(characters),
.charCount(charCount),
.code(code),
.codeLen(codeLen)
);
initial begin
// Initialize Inputs
CLK = 0;
nRST = 0;
nodeCount= 7;
charCount= 4;
characters[0]= 7'b110_0001;
characters[1]= 7'b110_0010;
characters[2]= 7'b110_0011;
characters[3]= 7'b110_0100;
nodes[0] = 24'b0000_0011_0_0000_0001_110_0001;
nodes[1] = 24'b0000_0011_1_0000_0010_110_0011;
nodes[2] = 24'b0000_0101_1_0000_0011_111_1111;
nodes[3] = 24'b0000_0101_0_0000_0100_110_0010;
nodes[4] = 24'b1111_1111_1_0000_0101_111_1111;
nodes[5] = 24'b1111_1111_0_0000_0110_110_0100;
nodes[6] = 24'b0000_0000_0_1111_1111_111_1111;
// Wait 10 ns for global reset to finish
#10;
nRST = 1;
end
parameter DELAY = 1;
always
#DELAY CLK = ~CLK;
endmodule
The code has been compiled in ModelSim 2016
I just started learning verilog. So I would really appreciate your help to show my mistakes.
Regards.
I got a fix for my problem. Not all the bits of code[][] has been set. This leads to unknown logic value in code[][] even after setting the bit. It gets solved after initializing all the bits of code[][] in always block.
A couple of days ago I asked about a module (here) I wanted to implement which takes the MSB of input samples, accumulates them (by shifting) and combines them into the output sample when the 32 output bit is "filled".
Thanks to the help there, I got this implementation, which doesn't produce any compilation errors and seemed fine with Xilinx 12.1:
module my_rx_dsp0
#(
//frontend bus width
parameter WIDTH = 24
)
(
//control signals
input clock, //dsp clock
input reset, //active high synchronous reset
input clear, //active high on packet control init
input enable, //active high when streaming enabled
//user settings bus, controlled through user setting regs API
input set_stb, input [7:0] set_addr, input [31:0] set_data,
//full rate inputs directly from the RX frontend
input [WIDTH-1:0] frontend_i,
input [WIDTH-1:0] frontend_q,
//full rate outputs directly to the DDC chain
output [WIDTH-1:0] ddc_in_i,
output [WIDTH-1:0] ddc_in_q,
//strobed samples {I16,Q16} from the RX DDC chain
input [31:0] ddc_out_sample,
input ddc_out_strobe, //high on valid sample
output ddc_out_enable, //enables DDC module
//strobbed baseband samples {I16,Q16} from this module
output reg [31:0] bb_sample,
output reg bb_strobe //high on valid sample
);
reg [3:0] i_msb;
reg [3:0] q_msb;
reg [31:0] temp_buff = 0;
reg [1:0] count = 0;
always #(posedge clock) begin
if(ddc_out_strobe) begin
// bit shifter for MSB
temp_buff <= {i_msb,q_msb,temp_buff[31:8]};
// to avoid if-else condition
count <= (count==2'd3) ? 2'd0 : (count+1);
end
end
always #(*) begin
i_msb = ddc_out_sample[31:28];
q_msb = ddc_out_sample[15:12];
// to avoid if-else condition
bb_strobe = (count==2'd3);
bb_sample = bb_strobe ? temp_buff : 32'd0;
end
assign ddc_in_i = frontend_i;
assign ddc_in_q = frontend_q;
assign ddc_out_enable = enable;
endmodule //my_rx_dsp0_custom
Now I wanted to implement a testbench that tests my_rx_dsp0.v with some examples.
I implemented a my_rx_dsp0_tb_2.v, which reads 32 bit samples from a file named my_input.dat to feed to the module as inputs ddc_out_sample.
They are then compared to the correct values stored at my_output.dat.
Note: I did not write this testbench myself, I adapted it from another testbench from an open-source project.
Here is the implementation:
module my_rx_dsp0_tb ( );
reg clk;
reg reset;
reg enable;
reg ddc_out_strobe; //high on valid sample
reg [31:0] ddc_out_sample;
wire [31:0] bb_sample = 32'd0;
wire bb_strobe;
wire ddc_out_enable = 1'b1; //enables DDC module
parameter WIDTH = 24;
parameter clocks = 2; // number of clocks per input
reg endofsim = 0;
integer number_of_errors;
initial number_of_errors = 0;
wire set_stb = 1;
wire [7:0] set_addr;
wire [31:0] set_data;
wire [WIDTH-1:0] frontend_i;
wire [WIDTH-1:0] frontend_q;
wire [WIDTH-1:0] ddc_in_i;
wire [WIDTH-1:0] ddc_in_q;
reg signed [31:0] compare_out;
// Setup the clock
initial clk = 1'b0;
always #5 clk <= ~clk ;
// Come out of reset after a while
initial reset = 1'b1 ;
initial #1000 reset = 1'b0 ;
// Enable the entire system
initial enable = 1'b1 ;
// Instantiate UUT
my_rx_dsp0 #(.WIDTH(WIDTH)) UUT_rx_dsp0
( .clock(clk), .reset(reset), .clear(clear), .enable(enable),
.set_stb(set_stb), .set_addr(set_addr), .set_data(set_data),
.frontend_i(frontend_i), .frontend_q(frontend_q),
.ddc_in_i(ddc_in_i), .ddc_in_q(ddc_in_q),
.ddc_out_sample(ddc_out_sample), .ddc_out_strobe(ddc_out_strobe), .ddc_out_enable(ddc_out_enable),
.bb_sample(bb_sample), .bb_strobe(bb_strobe) );
//-------Setup file IO-------//
//
integer i, r_in, r_out, infile, outfile;
initial begin
infile = $fopen("my_input.dat","r");
outfile = $fopen("my_output.dat","r");
$timeformat(-9, 2, " ns", 10) ;
// for n=9,p=2 digits after decimal pointer
//min_field_width=10 number of character positions for %t
end
//-------Get sim values and display errors-------//
//
initial begin
// Initialize inputs
ddc_out_strobe <= 1'd0;
ddc_out_sample <= 32'd0;
// Wait for reset to go away
#(negedge reset) #0;
while(!endofsim) begin
// Write the input from the file or 0 if EndOfFile(EOF)
#(posedge clk) begin
#1
ddc_out_strobe <= 1'b1;
if(!$feof(infile))
r_in = $fscanf(infile,"%b\n",ddc_out_sample);
else
ddc_out_sample <= 32'd0;
end
//
// Clocked in; set the strobe to 0 if the # of clocks/sample
// is greater than 1
if( clocks > 1 ) begin
#(posedge clk) begin
ddc_out_strobe <= 1'b0 ;
end
// Wait for the specified # of cycles
for( i = 0 ; i < (clocks-2) ; i = i + 1 ) begin
#(posedge clk) #1 ;
end
end
//
//
// Print out the number of errors that occured
if(number_of_errors) begin
$display("FAILED: %d errors during simulation",number_of_errors) ;
end else begin
$display("PASSED: Simulation successful") ;
end
//
end
end
//-------Comparison btwn simulated values vs known good values-------//
//
always #(posedge clk) begin
if(reset)
endofsim <= 1'b0 ;
else begin
if(!$feof(outfile)) begin
if(bb_strobe) begin
r_out = $fscanf(outfile,"%b\n",compare_out);
if(compare_out != bb_sample) begin
$display("%t: %b != %b",$realtime,bb_sample,compare_out);
number_of_errors = number_of_errors + 1;
end else begin
$display("%t: %b = %b",$realtime,bb_sample,compare_out);
end
end
end else begin
// Signal end of simulation when no more outputs
endofsim <= 1'b1 ;
end
end
end
endmodule // my_rx_dsp0_tb
When simulating with ISim from Xilinx ISE Suite Edition 12.1 I do not get the desired functionality from the module. I am afraid the output contains several x states (unknown states), instead of 1s or 0s as expected.
Question Is this due to:
1) The way the files are being read with $fscanf?
2) Did I wrong by initializing reg [31:0] temp_buff = 0?
3) Or does someone have an idea on what went wrong?
The error prompts from the testbench are (as an example):
xx000x00xxx00x0xx000x0x000000000 != 10000110111001011100010001101100
The X is from having multiple conflicting drivers on bb_sample and ddc_out_enable. The wire type merges the drivers, conflicting bit values of the same strength resolve as X.
UUT_rx_dsp0 is the intended diver. However you added and additional drivers from the way you declared your wires.
...
wire [31:0] bb_sample = 32'd0; // "= 32'd0" is a continuous driver
wire bb_strobe;
wire ddc_out_enable = 1'b1; // "= 1'd1" is a continuous driver
...
What you want is:
...
wire [31:0] bb_sample;
wire bb_strobe;
wire ddc_out_enable;
...
Correcting the above will resolve the X issue. Based on the example error it looks like are data miss matches. With the provided information, it is hard to tell it if it a test-bench or design issue. Could be just clock or propagation skew.
I'm having trouble implementing a controller block for an 8-bit multiplier. It works normally, but only if I turn the reset wire on, then off, such as in the following stimulus (which works fine):
`timescale 1ns / 100ps
module Controller_tb(
);
reg reset;
reg START;
reg clk;
reg LSB;
wire STOP;
wire ADD_cmd;
wire SHIFT_cmd;
wire LOAD_cmd;
Controller dut (.reset(reset),
.START(START),
.clk(clk),
.LSB(LSB),
.STOP(STOP),
.ADD_cmd(ADD_cmd),
.SHIFT_cmd(SHIFT_cmd),
.LOAD_cmd(LOAD_cmd)
);
always
begin
clk <= 0;
#25;
clk <= 1;
#25;
end
initial
begin
LSB <= 0;
START <= 0;
reset <= 1;
#55;
reset <= 0;
#10;
START <= 1;
#100;
START <= 0;
LSB <= 1;
#200;
#20;
#100;
end
initial
$monitor ("stop,shift_cmd,load_cmd, add_cmd: " , STOP,SHIFT_cmd,LOAD_cmd,ADD_cmd);
endmodule
Here's the simulation result for the working stimulus:
Now, when I set the reset to zero, without ever bringing it high, here's what happens:
Clearly, I'm using the reset wire to bring my Controller to the IDLE state. Here's the code for the controller block:
`timescale 1ns / 1ps
module Controller(
input reset,
input START,
output STOP,
input clk,
input LSB,
output ADD_cmd,
output SHIFT_cmd,
output LOAD_cmd
);
//Five states:
//IDLE : 000 , INIT: 001, TEST: 011, ADD: 010, SHIFT: 110
localparam [2:0] S_IDLE = 0;
localparam [2:0] S_INIT = 1;
localparam [2:0] S_TEST = 2;
localparam [2:0] S_ADD = 3;
localparam [2:0] S_SHIFT = 4;
reg [2:0] state,next_state;
reg [3:0] count;
// didn't assign the outputs to wire.. if not work, check this.
assign ADD_cmd = (state == S_ADD);
assign SHIFT_cmd = (state == S_SHIFT);
assign LOAD_cmd = (state == S_INIT);
assign STOP = (state == S_IDLE);
always #(*) begin
case(state)
S_INIT: begin
count = 3'b000;
end
S_SHIFT: begin
count = count + 1;
end
endcase
end
always #(*)
begin
next_state = state;
case (state)
S_IDLE: next_state = START ? S_INIT : S_IDLE;
S_INIT: next_state = S_TEST;
S_TEST: next_state = LSB ? S_ADD : S_SHIFT;
S_ADD: next_state = S_SHIFT;
S_SHIFT: next_state = (count == 8) ? S_IDLE : S_TEST;
endcase
end
always #(posedge clk)
begin
//state <= S_IDLE;
if(reset) state <= S_IDLE;
else state <= next_state;
end
reg [8*6-1:0] statename;
always #* begin
case( state )
S_IDLE: statename <= "IDLE";
S_INIT: statename <= "INIT";
S_TEST: statename <= "TEST";
S_ADD: statename <= "ADD";
S_SHIFT: statename <= "SHIFT";
default: statename <= "???";
endcase
end
endmodule
I don't know how to fix this. As you can see from the code above, there is a commented portion which is basically always initializing the state to IDLE. But even that doesn't work. Here's the simulation for the code above removing the comment from '//state <= S_IDLE;':
It's going into a different state than any listed above, and I have no idea why.
So I'd like to know:
Why is it going into an unknown state? Why doesn't my uncommented code work?
What can I change for it to work as I intend?
Your problem is that without a reset or initial value, state and next_state will be X. Your case statement assigning to statename will take the default branch and decode to ???. Since your process that assigns next_state does not handle cases where state is X it will get stuck in this state forever.
Your attempt to fix this will not work:
state <= S_IDLE;
if(reset) state <= S_IDLE;
else state <= next_state;
When reset is low you are making two assignments to state, the first as S_IDLE and the second as next_state. This is not a race condition. The Verilog standard states that:
Nonblocking assignments shall be performed in the order the statements were executed.
Since no re-ordering of the event queue occurs for sequential statements within a process this translates to last assignment wins. Therefore your state <= S_IDLE; is effectively optimised away since regardless of the value of reset the assignment will be overridden.
There are two ways you could fix this so that you don't need a reset:
1. Use the default clause to make your state machine safe
always #(*)
begin
next_state = state;
case (state)
S_IDLE: next_state = START ? S_INIT : S_IDLE;
S_INIT: next_state = S_TEST;
S_TEST: next_state = LSB ? S_ADD : S_SHIFT;
S_ADD: next_state = S_SHIFT;
S_SHIFT: next_state = (count == 8) ? S_IDLE : S_TEST;
default: next_state = S_IDLE;
endcase
end
This will ensure that your state-machine is 'safe' and drops into S_IDLE if state is a non-encoded value (including X).
2. Initialise the variable
reg [2:0] state = S_IDLE;
For some synthesis targets (e.g. FPGAs) this will initialise the register to a specific value and can be used alongside or instead of a reset (see Altera Documentation on power-up values).
A couple of general points:
Depending on your synthesis tool it may be better to use an enumeration rather than explicitly defining values for your states. This allows the tool to optimise based on the overall design or use a global configuration for encodings (for example safe, one-hot).
Using a reset registers holding state is standard practice so you should carefully consider whether you really want to avoid using a reset.
The uncommented code is an example of poor coding practice because you are making 2 nonblocking assignments to state in the same timestep. Synthesis linting tools are likely to warn you of this situation.
Since using a reset is a common, good practice, I don't think you need to fix anything.