Powershell: Copy-Item not working when in ForEach loop - powershell

Question

The script I am including below needs to accomplish the following tasks. It needs to get a list of servers from AD, then iterate through each of those server names and grab the second to the newest folder in a directory, rename it, and copy it to another server.
The Copy-Item command is not working when I have it in the foreach loop, as written below:
#gathering server names
$serverList = (Get-ADComputer -Filter "Name -like 'Q0*00*'" -SearchBase "OU=MPOS,OU=Prod,OU=POS,DC=N,DC=NET").name | Sort-Object | Out-File C:\Temp\MPOS\MPOSServers.txt
$serverListPath = "C:\Temp\MPOS\MPOSServers.txt"
#Retrieve a list of MPOS Print servers from text file and set to $serverNames
$serverNames = Get-Content -Path $serverListPath
#Iterate through each of the server names
foreach ($serverName in $serverNames) {
$reportServer = "a03"
Get-ChildItem "\\$($serverName)\d$\MPosLogs\Device" |
Where { $_.PSIsContainer } |
Sort CreationTime -Descending |
Select -Skip 1 |
Select -First 1 |
ForEach-Object {
Rename-Item -Path $_.FullName -NewName ("$serverName" + "_" + $_.Name) -PassThru |
Copy-Item -Destination "\\$($serverName)\c$\temp\MPOS\Logs"
}
}
However, it works fine if I am testing it outside of the ForEach loop, as written below:
Get-ChildItem "\\$($serverName)\d$\MPosLogs\Device" |
Where { $_.PSIsContainer } |
Sort CreationTime -Descending |
Select -Skip 1 |
Select -First 1 |
ForEach-Object {
Rename-Item -Path $_.FullName -NewName ("$serverName" + "_" + $_.Name) -PassThru |
Copy-Item -Destination "\\$($serverName)\c$\temp\MPOS\Logs"
}
Any ideas as to why it is not working in the full script? I am not changing anything when I test it, I am just running the above commands without being in the ForEach loop. It is completing the rest of the tasks, except for the folder copies. The folder copy only works if I am testing it outside of the ForEach loop on a single server.
When I say "it doesn't work", there are no errors or anything like that. It simply is not copying the folders.
Thank you! :)
LG

Answer 1

#MikeGaruccio well that is extremely embarrassing. I think I have just been staring at this script for too long, and did not realize that I was not actually copying the folders to $reportServer - it's a good thing you asked!!! It definitely matters. All is well now, after changing the final $serverName to actually read $reportServer. Thank you, and sorry for wasting your time...I appreciate your help a lot.