Get the whole range of date in SAS - date

I know the date in SAS looks like 01Jan2017. What I want is 1 January 2017. Is there function to make it?
Thank,
Andrea

Your question is pretty vague - it's hard to tell if you just want to display it differently or store it differently.
Display it differently: Just change the format to keep the date as a number in the background (number of days since 01JAN1960) but display it how you would like.
data ds1;
date = '01JAN2017'd;
format date WORDDATX20.;
run;
Store it differently: You can use the put function to create a separate character variable containing the formatted version of your date.
data ds2;
date1 = '01JAN2017'd;
date2 = put(date1, WORDDATX20.);
run;
Answers provided by Bhavika and pm2r should also help you understand what's going on here.

your code would look like this:
data _null_;
length date1 8. string $40;
date1=today();
string = cats( date1 );
put string=;
string = cats( put(date1,date10.) );
put string=;
string = cats( put(date1,WORDDATX20.) );
put string=;
run;
and the output would be:
string=20838
string=19JAN2017
string=19 January 2017

Related

Format a date by reversing the position of the year, month and days

The value received from the Date Picker is in the format "02-06-2020" (formatted with mask = "DD-MM-YYYY" in q-date).
I need to convert it to "2020-06-02" format to send it to the server.
I tried the following, but I get undefined.
Example:
let myDate = "02-06-2020";
console.log(date.formatDate(myDate, "YYYY-MM-DD")) //undefined
I would appreciate suggestions for finding a solution.
Thanks.
You can use moment js.
moment(moment('13-01-2020', 'DD-MM-YYYY')).format('YYYY-MM-DD');
or
date.split("-").reverse().join("-");

How to reformat dates?

Hello currently my dates are stored as numeric in the form of 40547. How can I convert these to MMDDYY10.?
data SevenSec11;
set Seven11;
DateRecieved = input(put(DateRecieved, 8.), MMDDYY10.);
format DateRecieved MMDDYY10.;
run;
How to convert it depends on what the value represents. If it is dates as stored by Excel then change the offset value. If it is supposed to represent MMDDYY values then use the Z6. format in your PUT() function call.
data test;
input num ;
sasdate1 = num + '30DEC1899'd ;
sasdate2 = input(put(num ,z6.),mmddyy10.);
format num comma7. sasdate: yymmdd10. ;
cards;
40547
;
Result:
Obs num sasdate1 sasdate2
1 40,547 2011-01-04 1947-04-05
Note that using Y-M-D order for dates will eliminate confusion that truncated leading zeros can cause. It will also prevent half of your audience from confusing April 5th with May 4th.

Trying to build Expression for Table field to sort text dates, some with missing elements

Hi I am a newbie and have a problem I have been trying to solve for weeks. I have a table imported from excel with dates in text format (because dates go back to 1700s) Most are in the format "mmmyyyy", so it is relatively easy to add "1" to the date, convert to date format, and sort in correct date order. The problem I have is that some of the dates in the table are simply "yyyy", and some are empty. I cannot find an expression that works to convert these last two to eg 1 Jan yyyy and 1 Jan 1000 within the same expression. Is this possible, or would I need to do this in two queries? Sorry if this question is very basic - I cannot find an answer anywhere.
TIA
You can do something like:
Public Function ConvertDate(Byval Expression As Variant) As Date
Dim Result As Date
If IsNull(Expression) Then
Result = DateSerial(1000, 1, 1)
ElseIf Len(Expression) = 4 Then
Result = DateSerial(Expression, 1, 1)
Else
Result = DateValue(Right(Expression, 4) & "/" & Left(Expression, 3) & "/1")
End If
ConvertDate = Result
End Function

GWT DateTimeFormat returns the wrong date

I have the following code
String test = "21/04/2013";
fmt = DateTimeFormat.getFormat("MM/dd/yyyy");
Date dateTest = fmt.parse(test);
Window.alert(fmt.format(dateTest));
And the alert box shows the date
09/04/2014
instead of
21/04/2013
Why?
As others already say, it's because of your pattern. What they don't say is why it behaves that way.
When parsing 21/04/2013 as MM/dd/yyyy, DateTimeFormat will decompose the date as:
Month Day of month Year
21 4 2013
and it'll then adjust things to make a valid date. To do that, the Month part is truncated at 12 (so that temporary date is Dec 4th, 2013) and the remainder (21 - 12 = 9) is then added, leading to Sept. 4th 2014, which according to your format displays as 09/04/2014.
You wanted to show 21/04/2013 but the format was MM/dd/yyyy.
It should be dd/MM/yyyy
So change it like this:
String test = "21/04/2013";
fmt = DateTimeFormat.getFormat("dd/MM/yyyy");
Date dateTest = fmt.parse(test);
Window.alert(fmt.format(dateTest));
You're reversing day and month.
String test = "21/04/2013";
fmt = DateTimeFormat.getFormat("dd/MM/yyyy");
Date dateTest = fmt.parse(test);
Window.alert(fmt.format(dateTest));

What is the most efficient way to convert an eight digit number to a date?

I am using ColdFusion 9.0.1 and some database that I cannot change.
I am accessing a database that stores a date as an eight digit numeric with zero decimal places like this:
YYYYMMDD
I need to be able to read the date, add and subtract days from a date, and create new dates. I am looking for a ColdFusion solution to efficiently (not much code) to convert the date to our standard format, which is
MM/DD/YYYY
And then convert it back into the database's format for saving.
I need to code this in such a way that non-ColdFusion programmers can easily read this and use it, copy and modify it for other functions (such as adding a day to a date). So, I am not looking for the most least amount of code, but efficient and readable code.
Can you suggest anything that would make this code block more flexible, readable, or more efficient (less code)?
<cfscript>
// FORMAT DB DATE FOR BROWSER
DateFromDB = "20111116";
DatedToBrowser = createBrowserDate(DateFromDB);
writeOutput(DatedToBrowser);
function createBrowserDate(ThisDate) {
ThisYear = left(ThisDate, 4);
ThisMonth = mid(ThisDate, 4, 2);
ThisDay = right(ThisDate, 2);
NewDate = createDate(ThisYear, ThisMonth, ThisDay);
NewDate = dateFormat(NewDate, "MM/DD/YYYY");
return NewDate;
}
// FORMAT BROWSER DATE FOR DB
DateFromBrowser = "11/16/2011";
DateToDB = createDBDate(DateFromBrowser);
writeDump(DateToDB);
function createDBDate(ThisDate) {
ThisYear = year(ThisDate);
ThisMonth = month(ThisDate);
ThisDay = day(ThisDate);
NewDate = "#ThisYear##ThisMonth##ThisDay#";
return NewDate;
}
</cfscript>
First find who ever did the database and kick them in the nads...
Personally I'd Convert with sql so my code only dealt with date objects.
Select Convert(DateTime, Convert(VarChar(8),DateTimeInventedByIdjitColumn))
From SomeTable
As stated by our peers, store dates as dates.
'08/06/2011' could be 8th of june of the 6th of August depending on locale.
20111643 is a valid integer..
Not using a proper date type is just a massive collection of features and bugs that at best are waiting to happen.
You can actually rewrite each function into 1 line of code.
function createBrowserDate(ThisDate) {
return mid(ThisDate,4,2) & "/" & right(ThisDate,2) & "/" & left(ThisDate,4);
}
and
function createDBDate(ThisDate) {
return dateFormat( ThisDate, "YYYYMMDD" );
}
Don't keep dates as strings - keep dates as dates and format them when you need to.
If you can't correct the database to use actual date columns (which you should if you can), then you can use these two functions to convert to/from YYYYMMDD and a date object:
function parseYMD( YYYYMMDD )
{
if ( ! refind('^\d{8}$' , Arguments.YYYYMMDD ) )
throw "Invalid Format. Expected YYYYMMDD";
return parseDateTime
( Arguments.YYYYMMDD.replaceAll('(?<=^\d{4})|(?=\d{2}$)','-') );
}
function formatYMD( DateObj )
{
return DateFormat( DateObj , 'yyyymmdd' );
}
By using date objects it means that any level of developer can work with them, without needing to care about formatting, via built-in functions like DateAdd, DateCompare, and so on.
I'm not a regular expression fan since it's not that readable to me.
Since you're using CF9, I'd typed the argument and specify the returntype of the functions to be even more readable for the next person picking up your code.
First, right after I read the date from DB, I'd parse it to a Date object using parseDBDate()
Date function parseDBDate(required String dbDate)
{
var yyyy = left(dbDate, 4);
var mm = mid(dbDate, 4, 2);
var dd = right(dbDate, 2);
return createDate(yyyy , mm, dd);
}
Once you have the date object, you can use all those built-in Date functoin like DateAdd() or DateDiff().
Call browserDateFormat() right before you need to display it.
String function browserDateFormat(required Date date)
{
return dateFormat(date, "MM/DD/YYYY");
}
Call dBDateFormat() inside <cfqueryparam value=""> when it's time to persist to DB
String function dBDateFormat(required Date date)
{
return dateFormat(date, "YYYYMMDD");
}
One liner :)
myDateString = "20110203";
myCfDate = createObject("java","java.text.SimpleDateFormat").init("yyyyMMdd").parse(myDateString,createObject("java","java.text.ParsePosition").init(0*0));
If you want to parse different patterns, change "yyyyMMdd" to any other supported pattern.
http://download.oracle.com/javase/1.5.0/docs/api/java/text/SimpleDateFormat.html
The ParsePosition is used to say where to start parsing the string.
0*0 is shorthand for JavaCast("int",0) - in the Adobe cf engine, 0 is a string, until you apply math to it, then it becomes a Double, which the ParsePosition constructor supports. Technically, it constructs with an int, but cf is smart enough to downgrade a Double to an int.
http://download.oracle.com/javase/1.5.0/docs/api/java/text/ParsePosition.html