Organize files using PowerShell using path as variables? - powershell

Question

I have a script that reorganizes files in C:\Year\Month\"StoreFiles" to "C:\Store\Date\"StoreFiles" based on modified date.
#Variables
$StoreName = "aStore"
$SourceDir = "C:\Source"
$TargetDir = "C:\$StoreName"
# Create Folder based on Store List
if(-Not (Test-Path -Path $TargetDir)) {
New-Item -ItemType Directory -Path $TargetDir
}
# Search & create folders based on date
Get-ChildItem "$SourceDir\*$StoreName*" -Recurse | ForEach-Object {
$x = $_.LastWriteTime.ToShortDateString()
$new_folder_name = Get-Date $x -Format MMM-yyyy
$des_path = "$TargetDir\$new_folder_name"
if (Test-Path $des_path) {
Copy-Item $_.FullName $des_path
} else {
New-Item -ItemType Directory -Path $des_path
Copy-Item $_.FullName $des_path
}
}
Works great however the modified date isn't ideal. Can I use the original folder path of "C:\Year\Month\"StoreFiles" and use it as dates for the new output?
In a sense I am trying to do the following:
"C:\Year\Month\"StoreFiles" to "C:\Store\Month-Year\"StoreFiles"
Maybe I should assign the folder path as a variable and use it accordingly for the new output?
Or is there another way I should think about doing this.

Answer 1

try Something like this
$dirroot="C:\temp\Root"
$store="C:\store"
Get-ChildItem $dirroot -file -Recurse |
where FullName -match ([Regex]::Escape($dirroot) + "\\\d{4}\\\d{1,2}\\" + [Regex]::Escape($_.Name)) |
% {
$elements=$_.FullName.Replace($dirroot, '').Split('\')
New-Item -ItemType Directory -Path "$store\$($elements[2])-$($elements[1])" -Force
Copy-Item $_.FullName "$store\$($elements[2])-$($elements[1])\$($elements[3])"
}

Answer 2

Cann't you use something like this?
$DateInfo = '' | select-object -Property 'Year', 'Month'
$File = 'c:\2014\may\filename.txt'
$TopFolderpath = [io.Path]::GetDirectoryName($File)
$TopFolderName = [io.Path]::GetFileName($TopFolderpath)
$DateInfo.Month = $TopFolderName
$Subfolderpath = [io.Path]::GetDirectoryName($TopFolderpath)
$SubFolderName = [io.Path]::GetFileName($Subfolderpath)
$DateInfo.Year = $SubFolderName
$DateInfo