I have a Table 'Purchases' that has fields similar to this simplified example:
CustomerID Item1 Price1 Item2 Price2 Item3 Price3 ... Item40 Price40
111 15 26.00 23 5.00 31 2.75 36 17.50
906 3 4.63 17 .77 18 3.74 19 22.60
There may be values in all, some or none of the Item/Price fields.
If there is an Item, there will be a price.
Items are always entered in Item# order. If there are 3 Items they will be in the first three Item fields ...
I want to join the above table to another table - Customers - that has CustomerID, Name, Address, Email ... so that I can get a list of all Customers who have purchased Items 15, 17, 18 & 36. At this point, I don't want to show which of the required items each Customer has purchased.
I would appreciate any suggestions.
Another Option (less dynamic but more performant), but you will have to list the 40 item fields
Declare #YourTable table (CustomerID int, Item1 int, Price1 decimal(10,2), Item2 int, Price2 decimal(10,2), Item3 int, Price3 decimal(10,2), Item40 int, Price40 decimal(10,2))
Insert into #YourTable values
(111,15,26.00,23,5.00,31,2.75,36,17.50),
(906, 3, 4.63,17, .77,18,3.74,19,22.60)
Select Distinct
A.CustomerID
From #YourTable A
Cross Apply (Values (Item1)
,(Item2)
,(Item3)
-- ... Items 4 - 39
,(Item40)
) B (value)
Where B.Value in (15,17,18,36)
Related
I got the following table articles:
ID
category
price
1
category1
10
2
category1
55
3
category2
15
4
category3
20
5
category4
25
I would like to get the highest price of each category.
The result would be:
ID
category
price
2
category1
55
3
category2
15
4
category3
20
5
category4
25
select Max(price), ID, category from article
group by ID,category
returns:
ID
category
price
1
category1
10
2
category1
55
3
category2
15
4
category3
20
5
category4
25
Unfortunately I get both rows for category 1. But I only would like to have the highest price in category 1 which is 55.
Can someone help me?
see above
Try this...
I've reproduced your sample data and then added a rnk column which ranks by price descending witin each category, used this in the subquery and just returned anything where rank is 1.
DECLARE #articles TABLE (ID int, Category varchar(20), Price float)
INSERT INTO #articles VALUES
(1, 'category1', 10),
(2, 'category1', 55),
(3, 'category2', 15),
(4, 'category3', 20),
(5, 'category4', 25)
SELECT
ID, Category, Price
FROM (
SELECT
ID, Category, Price
, RANK() OVER(PARTITION BY Category ORDER BY Price DESC) as rnk
FROM #articles
) a
WHERE a.rnk = 1
Which gives these results
Bote If you have two articles for the same category with the same price, both will be returned.
--===== This is NOT a part of the solution.
-- We're just making "Readily Consumable Test Data" here.
-- This is how you should post sample data to help those
-- that would help you. You'll get more thumbs up on your
-- questions, as well
SELECT *
INTO #Articles
FROM (VALUES
(1, 'category1', 10)
,(2, 'category1', 55)
,(3, 'category2', 15)
,(4, 'category3', 20)
,(5, 'category4', 25)
)d(ID,category,price)
;
--===== One possible easy solution that will also display "ties".
WITH cteRankByCategory AS
(
SELECT *,DR = DENSE_RANK() OVER (PARTITION BY Category ORDER BY Category, Price DESC)
FROM #Articles
)
SELECT ID,Category,MaxPrice = Price
FROM cteRankByCategory
WHERE DR = 1
ORDER BY Category
;
I have a table with records belonging to same person but the person was assigned with 2 different id's.
I need to combine the sales and then hold on to the id having highest sales.
For Example:
ID Name Sales
1 ABC 10
4 ABC 60
5 xyz 100
6 xyz 10
I need result as
ID Name Sales
4 ABC 70
5 XYZ 110
Please help me with a sql query for the above.
try this:
create table #mytable
(id int,
name nvarchar(20),
Sales int)
insert into #mytable
values
(1,'ABC',10),
(4,'ABC',60),
(5,'xyz',100),
(6,'xyz',10)
select (select top(1) ID
from #mytable r2
where r2.name=r1.name
and r2.Sales=MAX(r1.Sales))as ID,
name,
sum(Sales)
from #mytable r1
group by name
drop table #mytable
I have two tables
MappingTable > Id, ItemId, Quantity
ItemTable > ItemId, Name, DateOfPurchase
I wanted to find out the duplicate rows having same Quantity and same DateOfPurchase.
eg. I have
Id ItemId Quantity
1 01 4
2 03 5
3 05 4
ItemId Name DateOfPurchase
01 AB 2019-10-30 18:30:00
05 XY 2019-10-30 18:17:00
Result:
Quantity DateOfPurchase Name
4 2019-10-30 AB
4 2019-10-30 XY
So, I might join these tables and then find duplicates
How can I do that?
One option is to use window funtions, if your database supports them:
select *
from (
select
m.*,
i.name,
i.dateOfPurchase,
count(*) over(partition by m.quantity, p.dateOfPurchase) cnt
from mapping m
inner join item i on i.itemId = m.itemId
) t
where cnt > 1
order by quantity, dateOfPurchase
I have a table called _Invoice in SQL Server 2016 - like this:
Company InvoiceNo
-----------------
10 1
10 2
10 3
20 1
20 2
20 3
20 4
I want to get the highest value from all companies.
Like this:
Company InvoiceNo
-----------------
10 3
20 3
I want this data to then update another table that is called InvoiceSeries
where the InvoiceNo is higher than the NextNo in InvoiceSeries table
I am stuck with getting the highest data from InvoiceNo:
UPDATE InvoiceSeries
SET NextNo = -- Highest number from each company--
FROM InvoiceSeries ise
JOIN _Invoice i ON ise.InvoiceSeries = i.InvoiceSeries
WHERE i.InvoiceNo > ise.NextNo
Some example data:
Columns in InvoiceSeries Columns in _Invoices
Company NextNo Company InvoiceNo
10 9007 10 9008
20 1001 10 9009
10 9010
10 9011
10 9012
20 1002
20 1003
20 1004
If I understand correctly, you are looking for the HIGHEST common invoice number
Example
Select A.*
From YourTable A
Join (
Select Top 1 with ties
InvoiceNo
From YourTable
Group By InvoiceNo
Having count(Distinct Company) = (Select count(Distinct Company) From YourTable)
Order By InvoiceNo Desc
) B on A.InvoiceNo=B.InvoiceNo
Returns
Company InvoiceNo
10 3
20 3
EDIT - Updated for comment
Select company
,Invoice=max(invoiceno)
From YourTable
Group By company
This answer assumes there will be a record in the Invoice Series table.
--Insert Sample Data
CREATE TABLE #_Invoice (Company INT, InvoiceNo INT)
INSERT INTO #_Invoice(Company, InvoiceNo)
VALUES
(10 , 1),
(10 , 2),
(10 , 3),
(20 , 1),
(20 , 2),
(20 , 3),
(20 , 4)
CREATE TABLE #InvoiceSeries(Company INT, NextNo INT)
INSERT INTO #InvoiceSeries(Company, NextNo)
VALUES
(10, 1),
(20 ,1)
UPDATE s
SET NextNo = MaxInvoiceNo
FROM #InvoiceSeries s
INNER JOIN (
--Get the Max invoice number per company
SELECT Company, MAX(InvoiceNo) as MaxInvoiceNo
FROM #_Invoice
GROUP BY Company
) i on i.Company = s.Company
AND s.NextNo < i.MaxInvoiceNo --Only join to records where the 'nextno' is less than the max
--Confirm results
SELECT * FROM #InvoiceSeries
DROP TABLE #InvoiceSeries
DROP TABLE #_Invoice
I have two tables, I'll call TableA and TableB
TableA:
StartNumber EndNumber Country
1 10 USA
11 20 USA
21 30 Canada
31 40 France
41 50 France
51 60 Germany
TableB:
SomeNumber
5
15
55
22
35
46
49
For each number in TableB, I want to find the corresponding row in TableA where the number is between the StartNumber and EndNumber and return the name of the country. I then want to group these results on the country column and return the number of times each country appears. So the results would look like this:
Country Occurrences
USA 2
Germany 1
Canada 1
France 3
Not sure how to do this.
Here the query.
Select A.Country, count(*) as Occurrences
from
tableA A
inner join
tableB B
on B.someNumber between a.startnumber and b.endnumber
group by A.country
This should do the trick (but does use a join):
declare #TableA table (StartNumber int, EndNumber int, Country varchar(16));
insert into #TableA (StartNumber, EndNumber, Country)
select 1, 10, 'USA' union
select 11, 20, 'USA' union
select 21, 30, 'Canada' union
select 31, 40, 'France' union
select 41, 50, 'France' union
select 51, 60, 'Germany';
declare #TableB table (SomeNumber int);
insert into #TableB (SomeNumber)
select 5 union
select 15 union
select 55 union
select 22 union
select 35 union
select 46 union
select 49;
select
a.Country, count(*) Occurrences
from
#TableA a inner join
#TableB b on b.SomeNumber between a.StartNumber and a.EndNumber
group by
a.Country;