$this->load->helper('download');
$html=$this->load->view('cvhome',$dta,TRUE);
$name = "download.pdf";
force_download($name, $html);
When I run this I am getting a pdf file that is invalid. Please advice on how to pass the view to the variable html and pass it as argument.
Related
My image upload doesn't work:
Controller:
if (Input::hasFile('image')) {
$bikecreate->image = Input::file('image');
$destinationPath = public_path().'/upload/';
$filename = str_random(6) . '_' . $bikecreate->users_id ;
Input::file('image')->move($destinationPath, $filename);
}
Form:
{{ Form::file('image', array('files' => true)) }}
After accepting form everything looks ok, but after the end of upload, filepath in database show .tmp/file at my server.
Without seeing the rest of your code it's hard to see exactly what's going on but my guess is that your line $bikecreate->image = Input::file('image') is where you're setting the file's path for the database. You've actually set the UploadedFile instance as the image property on $bikecreate there, which, presumably, when serialised to something to put into the database gets __toString() called on it.
__toString() called on a File instance (which itself inherits __toString from SPLFileInfo returns the path to that file. So you'd think you're get the uploaded filename, but actually because an uploaded file is actually a temporary file in PHP, you get the temporary name.
Try changing that line to the following:
$bikecreate->image = Input::file('image')->getClientOriginalName();
This retrieves the actual original name of the uploaded file, not the temporary path given to it by PHP.
It goes without saying that this is only pertinent to UploadedFiles, normal files should just be able to be __toStringed to get the path to the file, although you'll notice that it would be the full path and not the basename. To get that, use getBaseName().
How to get the name of the loaded template file in smarty plugin?
If you're using Smarty 3 then the template object gets passed as last parameter to any plugin function:
smarty_function_foo($params, $smarty, $template)
You can get the filepath with:
$template->getTemplateFilepath();
It should always be passed in as the last function, so for a block function it would be:
smarty_block_foo($params, $content, $smarty, $repeat, $template)
Can anyone suggest how using the form validation rules I can say the following:-
If no file is uploaded - then create a rule to say 'no file uploaded' using the form validator library.
I am using CodeIgniter 2.
For instance - it is simple to validate on a text input field using the following, but I cannot understand how this is done with upload (that uses the $_FILES array rather than $_POST)
eg.
$this->form_validation->set_rules('title', 'Title', 'required'); // input field named 'title' is required
CodeIgniter's File Uploading class handles its own validation - no need to use the Form Validation class.
Per the documentation,
$this->upload->display_errors()
Retrieves any error messages if the do_upload() function returned
false. The function does not echo automatically, it returns the data
so you can assign it however you need.
In your example above, if the file input is left empty, $this->upload->display_errors() will return the following:
You did not select a file to upload.
So, set your preferences (see the "Setting Preferences" section of the documentation for exactly what is available):
// The following are just examples from the documentation...
$config['upload_path'] = './uploads/';
$config['allowed_types'] = 'gif|jpg|png';
$config['max_size'] = '100';
$config['max_width'] = '1024';
$config['max_height'] = '768';
// ... other preferences as necessary
If any of the above fail during the attempted upload, $this->upload->display_errors() will retrieve the appropriate error message. Simply pass it to your view to display the error(s).
Hope that helps.
i have a problem with calling a function which name is a string.
I made few helpers which i want to echo in my phtml file like this:
echo $this->EditProfile();
echo $this->ViewProfile();
The EditProfile() and ViewProfile() are names of the View Helpers which i created and i'm calling them in view. And this method is working fine. But when i want dynamicly call a function by name stored in database im trying to do this in this way:
im getting the names of helpers from database and store them into array and then trying to display them in foreach.
foreach ($this->modules as $key => $module)
{
echo $this->$module['name'];
}
the variable
$module['name']
contains a valid name of Helper which i want to call in phtml file (checked with Zend_debug::dump() and with just an echo $module['name'] in foeach and id display it properly... but this echo its not working and not calling the View Helper, nothing is displayed
when i try eval or call_user_func too nothing is displayed too... How can i do this in foreach or other loop?
ok solved it myself :)
dont know is this solution properly but its actually working ;)
instead call_user_func i mentioned that magical function __call is same as call_user_func_array
so i edited code like this below
foreach ($this->modules as $key => $module)
{
$this->__call($module['name'],array(null));
}
in this case array is null cause none parameters are passed to function. If in my helper ill need parameters ill pass them in this array in future.
And this solution works fine for me :)
If someone have better solution please post it here and share your opinion ;)
regards
Darek
I am trying to upload a file from a web page without using:
my $query = CGI->new;
my $filename = $query->param("File");
my $upload_filehandle = $query->upload("File");
My form has several input fields and only one of them is a file name. So when I parse the form I parse all of the input fields in one pass. This means that I have the filename withough using my $filename = $query->param("File"); but, as far as I can tell, this means I can't use my $upload_filehandle = $query->upload("File"); to do the actual uploading.
Any advice is appreciated.
Regards.
How are you parsing the input fields? More importantly why are you using CGI and reimplementing some of its functionality?
This should still work:
my %args = how_you_are_parsing_the_url();
my $query = CGI->new; #this parses the url as well
my $upload_filehandle = $query->upload("File"); #assuming the input is named File