Lets say I have two protocols:
protocol TheirPcol {}
protocol MyPcol {
func extraFunc()
}
What I want to do is to create a protocol extension for 'TheirPcol' which lets extraFunc() work on anything which conforms to 'TheirPcol'. So something like this:
extension TheirPcol : MyPcol { // Error 'Extension of protocol 'TheirPcol' cannot have an inheritance clause.
func extraFunc() { /* do magic */}
}
struct TheirStruct:TheirPcol {}
let inst = TheirStruct()
inst.extraFunc()
The kicker in this is that 'TheirPcol', 'TheirStruct' are all handled by an external API which I do not control. So I'm passed the instance 'inst'.
Can this be done? Or am I going to have to do something like this:
struct TheirStruct:TheirPcol {}
let inst = TheirStruct() as! MyPcol
inst.extraFunc()
It seems there are two use-cases of why you may want to do what you are doing. In the first use-case, Swift will allow you to do what you want, but not very cleanly in the second use-case. I'm guessing you fall into the second category, but I'll go through both.
Extending the functionality of TheirPcol
One reason why you might want to do this is simply to give extra functionality to TheirPcol. Just like the compiler error says, you cannot extend Swift protocols to conform to other protocols. However, you can simply extend TheirPcol.
extension TheirPcol {
func extraFunc() { /* do magic */ }
}
Here, you are giving all objects that conform to TheirPcol the method extraFunc() and giving it a default implementation. This accomplishes the task of extending functionality for the objects conforming to TheirPcol, and if you want it to apply to your own objects as well then you could conform your objects to TheirPcol. In many situations, however, you want to keep MyPcol as your primary protocol and just treat TheirPcol as conforming to MyPcol. Unfortunately, Swift does not currently support protocol extensions declaring conformance to other protocols.
Using TheirPcol objects as if they were MyPcol
In the use case (most likely your use case) where you really do need the separate existence of MyPcol, then as far as I am aware there is no clean way to do what you want yet. Here's a few working but non-ideal solutions:
Wrapper around TheirPcol
One potentially messy approach would be to have a struct or class like the following:
struct TheirPcolWrapper<T: TheirPcol>: MyPcol {
var object: T
func extraFunc() { /* Do magic using object */ }
}
You could theoretically use this struct as an alternative to casting, as in your example, when you need to make an existing object instance conform to MyPcol. Or, if you have functions that accept MyPcol as a generic parameter, you could create equivalent functions that take in TheirPcol, then convert it to TheirPcolWrapper and send it off to the other function taking in MyPcol.
Another thing to note is if you are being passed an object of TheirPcol, then you won't be able to create a TheirPcolWrapper instance without first casting it down to an explicit type. This is due to some generics limitations of Swift. So, an object like this could be an alternative:
struct TheirPcolWrapper: MyPcol {
var object: MyPcol
func extraFunc() { /* Do magic using object */ }
}
This would mean you could create a TheirPcolWrapper instance without knowing the explicit type of the TheirPcol you are given.
For a large project, though, both of these could get messy really fast.
Extending individual objects using a child protocol
Yet another non-ideal solution is to extend each object that you know conforms to TheirPcol and that you know you wish to support. For example, suppose you know that ObjectA and ObjectB conform to TheirPcol. You could create a child protocol of MyPcol and then explicitly declare conformance for both objects, as below:
protocol BridgedToMyPcol: TheirPcol, MyPcol {}
extension BridgedToMyPcol {
func extraFunc() {
// Do magic here, given that the object is guaranteed to conform to TheirPcol
}
}
extension ObjectA: BridgedToMyPcol {}
extension ObjectB: BridgedToMyPcol {}
Unfortunately, this approach breaks down if there are a large number of objects that you wish to support, or if you cannot know ahead of time what the objects will be. It also becomes a problem when you don't know the explicit type of a TheirPcol you are given, although you can use type(of:) to get a metatype.
A note about Swift 4
You should check out Conditional conformances, a proposal accepted for inclusion in Swift 4. Specifically, this proposal outlines the ability to have the following extension:
extension Array: Equatable where Element: Equatable {
static func ==(lhs: Array<Element>, rhs: Array<Element>) -> Bool { ... }
}
While this is not quite what you are asking, at the bottom you'll find "Alternatives considered", which has a sub-section called "Extending protocols to conform to protocols", which is much more what you're trying to do. It provides the following example:
extension Collection: Equatable where Iterator.Element: Equatable {
static func ==(lhs: Self, rhs: Self) -> Bool {
// ...
}
}
Then states the following:
This protocol extension would make any Collection of Equatable elements Equatable, which is a powerful feature that could be put to good use. Introducing conditional conformances for protocol extensions would exacerbate the problem of overlapping conformances, because it would be unreasonable to say that the existence of the above protocol extension means that no type that conforms to Collection could declare its own conformance to Equatable, conditional or otherwise.
While I realize you're not asking for the ability to have conditional conformances, this is the closest thing I could find regarding discussion of protocols being extended to conform to other protocols.
Related
Question
I have a protocol defined as follows:
protocol MyProtocol {
associatedtype MySubprotocol
}
Can I require that the associated type MySubprotocol is a protocol as well?
So semantically it would be sth. like this:
protocol MyProtocol {
associatedtype MySubprotocol: AnyProtocol
}
Background
I know that I can do nothing with that protocol inside a given concrete type that implements MyProtocol, but I can use it "from outside" for protocol composition. My ultimate goal would be to define a "Sum protocol" from all the associated types of all MyProtocol implementations, e.g. when I have the following structs that implement MyProtocol,
struct MyImpl_1: MyProtocol {
typealias MySubProtocol = MySubProtocol_1
}
struct MyImpl_2: MyProtocol {
typealias MySubProtocol = MySubProtocol_2
}
...
I want to create a composite protocol like this:
protocol AllRequirements:
MyImpl_1.MySubprotocol,
MyImpl_2.MySubprotocol,
... {}
This requires MyImpl_1.MySubprotocol etc. to be a protocol, otherwise I can't compose it. (I know, I could use the concrete type MySubProtocol_1 instead, but I want compile-time safety when a developer creates a new implementation of MyProtocol (i.e. another MyImpl_n).
Example Use Case
I have a couple of "Worker" objects, each of which performs a specific task. As I want to enforce a common API, I create a common protocol for all of these types:
protocol: Worker {
associatedtype Toolset
func getTheJobDone()
}
Here's an example for a concrete type:
struct Cleaner: Worker {
typealias Toolset = AnyBrush
let brush: AnyBrush
init(brush: AnyBrush) {
self.brush = brush
}
func getTheJobDone() {
brush.applyToFloor()
}
}
In practice, I will have multiple types of this sort to perform different tasks. I want each of these Workers to define their own requirements, i.e. the interface (protocol) they require to get their job done. So in this case, I would create a protocol AnyBrush along with the Cleaner:
protocol AnyBrush {
func applyToFloor()
}
which I then require as the worker's Toolset (see above).
This approach works for me, but when I create a new Worker type, the current protocol definition will allow me to specify any type for the Toolset, so someone could (for some unknown reason) do this:
typealias Toolset = Int
which doesn't make sense at all.
So that's why I'm asking this question. For these two goals:
Force a common interface (API) for all workers.
Use the compiler to enforce that the associated type Toolset is always a protocol.
One might ask me to trust my co-workers and my future self that we're going to use a protocol because if we don't understand that, we got a much more serious problem, but I would still like to see if it's possible to require a protocol.
I have a base protocol that describes the router behavior:
protocol BaseRouterProtocol: AnyObject {
associatedtype View: MainView
func dismiss(viewController: ViewController<View>?)
}
extension BaseRouterProtocol {
func dismiss(viewController: ViewController<View>?) {
viewController?.navigationController?.popViewController(animated: true)
}
}
I want to adopt this protocol to another like this:
protocol StartRouterProtocol: BaseRouterProtocol where View == StartView {
func showTermsVC()
func showSignInVC()
}
But when I create a variable of this type:
let router: StartRouterProtocol
Compiler throws me an error:
Protocol 'StartRouterProtocol' can only be used as a generic constraint because it has Self or associated type requirements
Why does this happening if I have described the type that I expect?
Once a protocol has an associated type, that protocol can't be used as a type by itself for instance declarations-- only for generic constraints and declaring conformance.
So in this case, Swift is saying "yeah, but what is the concrete type for StartRouterProtocol's associated type?"
In this case, it's asking you to either:
Use a concrete type directly, i.e. let router: MyStartViewClass with this conformance declaration, elsewhere: class MyStartViewClass: StartRouterProtocol { ... })
OR, push the need for a concrete type up one layer, as a generic constraint i.e.
class MyRouterController<T: StartRouterProtocol> {
let router: T
}
This is probably not what you were hoping for, but unfortunately associated types add complexity to how you use protocols, especially if you're familiar with generics & interfaces from other languages. (i.e. Java/C# interfaces)
You can work around some aspects of associated types by using a concept called "type erasure" -- but that can cause other problems and complexity.
Here's some further reading that may help: https://medium.com/monstar-lab-bangladesh-engineering/swift-from-protocol-to-associatedtype-then-type-erasure-a4093f6a2d08
I am on Swift 5. I have a protocol:
protocol Pipe {
associatedtype T
func await() -> Void
func yield( to: Any, with listener: Selector ) -> Void
}
And I would like to reference an instance of this protocol somewhere in code. That is, I want foo : , or a variable of generic type T implementing Pipe. Per this documentation: https://docs.swift.org/swift-book/ReferenceManual/GenericParametersAndArguments.html
I tried writing:
var imageSource: <Pipe T>
and any permutation of said symbols, ie imageSource: but the syntax is wrong across all cases.
In fact, T conform to two protocols, Renderable and Pipe, so I really want:
var imageSource: <Pipe, Renderable T>
Syntax wise this is gibberish, but semantically it's not an uncommon use case.
__________________ EDIT after two answers have been given __________
I tried simplifying the Pipe protocol for this post, but now I realize I simplified it too much. In my code base it's
protocol Pipe {
associatedtype T
func await() -> Void
func yield( to: Any, with listener: Selector ) -> Void
func batch() -> [T]
}
That's why there's a T there. But it's not crucial, I can drop the batch() -> [T] if I am able to write what I want above.
An associated type is used when you want your protocol to work with a variety of types, think a Container protocol that might have several methods all dealing with one contained type.
But your protocol is not that, it doesn't need to know any other types to specify the necessary behavior, so get rid of the associated type.
protocol Pipe {
func await() -> Void
func yield( to: Any, with listener: Selector ) -> Void
}
class Foo {
var imageSource: Pipe & Renderable
}
This is called a generalized existential, and is not available in Swift. A protocol with an associated type describes other types; it is not a type itself and cannot be the type of a variable, or put into a collection.
This specific protocol doesn't make a lot of sense, since you don't use T anywhere. But what you would need to do is pull this into the containing type:
struct Something<Source> where Source: Pipe & Renderable {
var imageSource: Source
}
I suspect you really want to redesign this in a different way, however. This looks like a fairly common misuse of protocols. You probably want Pipe and Renderer types that are structs (or even just functions). Without knowing what the calling code looks like, I can't say precisely how you would design it.
If you remove T (which isn't being used here), then Max's answer will address this issue. Protocols without associated types have an implicit existential type, and so you can treat them somewhat as "normal" types (assigning them to variables or putting them in collections).
I'm just working on a codebase where the most classes conform to an empty protocol. Is there any point of doing so? Actually conforming that protocol does nothing.
Edit as reaction to #vacawama's helpful comment : the protocol is only used once
import Foundation
protocol myUrlRequestConfig {}
extension myUrlRequest: myUrlRequestConfig {
public static func configGetAppConfig() -> URLRequest {
let request = ....
return request
}
}
An empty protocol can be useful if you want to create an easy way to add static functions or variables to several different classes. Of course, this only makes sense if the static functionality is the same for all classes conforming to the protocol.
Here is an example: I have a protocol sizeable. Every class that conforms to Sizeable is extended with the static variable stride and size.
protocol Sizeable { }
extension Sizeable {
static var size: Int {
return MemoryLayout<Self>.size
}
static var stride: Int {
return MemoryLayout<Self>.stride
}
}
class Foo: Sizeable {}
class Baa: Sizeable {}
Foo.size
Baa.size
Our app has three perfectly legitimate uses for an empty protocol:
The protocol has an extension with method definitions. The implementation in the extension is automatically injected into any type that adopts the protocol.
The protocol has other protocols that adopt it. This allows multiple protocols to be unified under a single head.
The protocol marks the adopter as wanting some other type to behave in a certain way. Code can always is whether an object is ThisEmptyProtocol and if it is, can behave differently than if it isn't.
I'm working on a framework to make it easier to work with Key Value Observing and I've defined a protocol for converting native Swift types to NSObject as follows:
public protocol NSObjectConvertible {
func toNSObject () -> NSObject
}
Extending the builtin types was easy, simply defining the function to convert the given type to the appropriate NSObject:
extension Int8: NSObjectConvertible {
public func toNSObject () -> NSObject {
return NSNumber(char: self)
}
}
When I got to the Array type, I hit a number of snags, which I tried to work out. I didn't want to extend any array type, but only arrays whose element type was itself NSObjectConvertible. And naturally, needed Array to itself conform to the protocol.
After hunting around on SO, it looks like extending the Array type itself is a little harder because it's generic, but extending SequenceType can be done. Except that I can't both constrain the element type and declare its conformance to the protocol in the same declaration.
The following:
extension SequenceType where Generator.Element == NSObjectConvertible : NSObjectConvertible = {
public func toNSObject () -> NSObject {
return self.map() { return $0.toNSObject() }
}
}
Produces a compiler error:
Expected '{' in extension
And the carat points to the ":" where I'm trying to declare the protocol conformance. Removing the protocol conformance compiles without errors, but obviously doesn't help the case.
I'm not sure if this is a bug, or if Swift simply can't (or doesn't want to) support what I'm trying to do. Even if I simply define the extension, then try to take care of the conformance in the body, it produces the risk of passing sequences that don't really conform to what they should.
At best it's a hacky solution to just fail in cases where a sequence with non-conforming members are passed. I'd much rather let the compiler prevent it from happening.
(This is in Swift 2.1, Xcode 7.1.1)
You can't add the protocol conformance, unfortunately.