How to create 100 files on windows folder with rdfc.exe? - powershell

I am trying to create 100 random files (each of 1 MB) . Found that rdfc.exe can be used for this purpose. I can create a single file with command
c:\rdfc>rdfc.exe z:\test1.txt 1 MB
Random Data File Creator v0.1.0.4 (2004/12/19)
Copyright (C)2004 by Michael Berthold
Visit http://www.bertel.de/software/rdfc
1.00 MB written to 'z:\test1.txt' in 0 sec. (ca. 0.00 MB/sec.)
However I need to create 100 files using this? Can anyone help with a powershell script of batch file to do this?

CW answer of Squashmans comment:
Using a for /l loop you can perform a loop n times by using the syntax
for /l %%g in (1,1,n) do <yourCommand>
So in your case this would evaluate to
for /l %%g in (1,1,100) do rdfc.exe Z:\test%%g.txt 1 MB
%%g contains the current number in this case between 1 and 100. For command-line use only, you have to use only one percentage signs in both places.
Note that you probably can prevent these messages by prepending the line #echo off to your script in case you are executing above with it.

try Something like this
$Expath="PAth_Of_rdfc/rdfc.exe "
1..100 | %{. $Expath $("z:\test{0}.txt" -f $_) 1 MB}

Related

Netlogo - Behavior Space

I want to run experiments using behavior space. However, the number of experiments needed is depending on the length of a list which is dynamic subject to the external data loaded. Hence , I want to do something like below which is not supported:
what is the correct way to do so? thanks
You note that you do this with a .bat or .sha file. If that's the case, here's a .bat solution. However, I'm not sure what your data looks like- in this example I just used the number of entries in a csv file to determine the number of runs needed.
So, I have a data file called 'example_data.csv' that looks like this:
1
100
1000
10000
I have an .nlogo file with an Input widget that defines a global variable called n_runs. I pulled out the xml for an BehaviorSpace experiment and saved it in a file called "experiment_base.xml"- it looks like:
<experiments>
<experiment name="experiment" repetitions="1" sequentialRunOrder="false" runMetricsEveryStep="false">
<setup>setup</setup>
<go>tick</go>
<timeLimit steps="5"/>
<metric>count turtles</metric>
<steppedValueSet variable="n_runs" first="1" step="1" last="1"/>
</experiment>
</experiments>
I have a .bat file that:
counts the number of entries in my 'example_data.csv"
reads in the 'experiment_base.xml' file and replaces the last="1" with the number read above, then writes this as a new experiment called 'mod_experiments.xml'
runs the experiment using the newly generated experiments file
This entire bat file looks like:
#echo off
cls
setlocal EnableDelayedExpansion
set "cmd=findstr /R /N "^^" example_data.csv | find /C ":""
for /f %%a in ('!cmd!') do set number=%%a
powershell -Command "(gc experiment_base.xml) -replace '<steppedValueSet variable=\"n_runs\" first=\"1\" step=\"1\" last=\"1\"/>', '<steppedValueSet variable=\"n_runs\" first=\"1\" step=\"1\" last=\"%number%\"/>' | Set-Content mod_experiments.xml
echo "Running experiment..."
netlogo-headless.bat ^
--model dynamic_behaviorspace.nlogo ^
--setup-file mod_experiments.xml ^
--table table-output.csv
This outputs results for 4 experiments, since I had 4 values in my data file. If I modify the number of entries in the csv and rerun the .bat file, I get results for a corresponding number of runs.

How to batch rename files to 3-digit numbers?

I apologize in advance that this question is not specific. But my goal is to take a bunch of image files, which are currently named as: 0.tif, 1.tif, 2.tif, etc... and rename them just as numbers to 000.tif, 001.tif, 002.tif, ... , 010.tif, etc...
The reason I want to do this is because I am trying to load the images into matlab and for batch processing but matlab does not order them correctly. I use the dir command as dir(*.tif) to get all the images and load them into an array of files that I can iterate over and process, but in this array element 1 is 0.tif, element 2 is 1.tif, element 3 is 10.tif, element 4 is 100.tif, and so on.
I want to keep the ordering of the elements as I process them. However, I do not care if I have to change the order of the elements BEFORE processing them (i.e. I can make it work to rename, for example, 2.tif to 10.tif if I had to) but I am looking for a way to convert the file names the way I initially described.
If there is a better way to get matlab to properly order the files when it loads them into the array using dir please let me know because that would be much easier.
Thanks!!
You can do this without having to rename the files, if you want. When you grab the files using dir, you'll have a list of files like so:
files =
'0.tif'
'1.tif'
'10.tif'
...
You can grab just the numeric part using regexp:
nums = regexp(files,'\d+','match');
nums = str2double([nums{:}]);
nums =
0 1 10 11 12 ...
regexp returns its matches as a cell-array, the second line converts it back to actual numbers.
We can now get an actual numeric order by sorting the resulting array:
[~,order] = sort(nums);
and then put the files in the correct order:
files = files(order);
This should (I haven't tested it, I don't have a folder full of numerically labelled files handy) produce a list of files like so:
files=
'0.tif'
'1.tif'
'2.tif'
'3.tif'
...
this is partially dependent on the version of matlab you have. If you have a version with findstr this should work well
num_files_to_rename = numel(name_array);
for ii=1:num_files_to_rename
%in my test i used cells to store my strings you may need to
%change the bracket type for your application
curr_file = name_array{ii};
%locates the period in the file name (assume there is only one)
period_idx = findstr(curr_file ,'.');
%takes everything to the left of the period (excluding the period)
file_name = str2num(curr_file(1:period_idx-1));
%zeropads the file name to 3 spaces using a 0
new_file_name = sprintf('%03d.tiff',file_name)
%you can uncomment this after you are sure it works as you planned
%movefile(curr_file, new_file_name);
end
the actual rename operation movefile is commented out for now. make sure the output names are as you expect before uncommenting it and renaming all the files.
EDIT there is no real error checking in this code, it just assumes every file name has one and only one period, and an actual number as the name
The Batch file below do the rename of the files you want:
#echo off
setlocal EnableDelayedExpansion
for /F "delims=" %%f in ('dir /B *.tif') do (
set "name=00%%~Nf"
ren "%%f" "!name:~-3!.tif"
)
Note that this solution preserve the same order of your original files, even if there are missing numbers in the sequence..

Script to batch rename to retain only some characters of original filename?

I need to rename thousands of rar files with original filenames of variable sizes. I must make them 10 characters long by keeping the first 3 and the last 4 characters of the original filename and adding in the middle 3 random characters [numbers].
Example:
input:
"John Doe - Jane Doe - 19073275.rar"
"XXXX - XYXY- 98705674.rar
output:
"Joh1273275.rar"
"XXX9795674.rar"
Next, the .bat should generate a .txt with the original name and the modified one underneath for each file!
I know it's possible but I'm completely stupid when it comes to writing it. Please help!
The Batch file below do what you want:
#echo off
setlocal EnableDelayedExpansion
for %%a in (*.rar) do (
set name=%%~Na
set num=00!random!
set newName=!name:~0,3!!num:~-3!!name:~-4!
ren "%%a" "!newName!%%~Xa"
echo "%%a" modified to "!newName!%%~Xa" >> log.txt
)
I'd write a script to generate the names in any simple way (say first 6 + last 4), and then check for any duplicates to be cleaned up by hand (or a second pass shifting the middle, or ...). Unless this is a repetitive job (do it daily), it isn't worth fully automatizing.

Can you put form elements in a DOS batch file?

Can you put form elements in a batch file? I was curious when I saw it in Word 5.5 for DOS. I can't find out how to do it, but I know NOTHING about all that junk in an executable file for DOS. Can somebody please help me?
If you want to ask for free text in a batch file use:
SET /P UserName=What is your UserName?
This puts the user's response in an environment variable named UserName, which can be accessed with %UserName%
like this:
ECHO Hello, %UserName%. Welcome to planet Earth!
You can put any executable command in a batch file, hence you can do anything in a batch file. If you see anything terribly fancy (like windowing), you probably are looking at a third party program, rather than a command built into the command processor itself.
Off the top of my head, the closest thing to a form (something that you can select items from) that I can think of is the CHOICE command. To find out how to use it, type this at a command prompt:
CHOICE /?
Here's the description...
This tool allows users to select one item from a list
of choices and returns the index of the selected choice.
Here are some syntax examples...
CHOICE /?
CHOICE /C YNC /M "Press Y for Yes, N for No or C for Cancel."
CHOICE /T 10 /C ync /CS /D y
CHOICE /C ab /M "Select a for option 1 and b for option 2."
CHOICE /C ab /N /M "Select a for option 1 and b for option 2."
And here's a full example:
CHOICE /C:ABCDN /N /T:10 /D:N /M:"Format drive A:, B:, C:, D: or None?"
REM Note that ERRORLEVEL handlers must be in decreasing order...
IF ERRORLEVEL 5 SET DRIVE=None
IF ERRORLEVEL 4 SET DRIVE=drive D:
IF ERRORLEVEL 3 SET DRIVE=drive C:
IF ERRORLEVEL 2 SET DRIVE=drive B:
IF ERRORLEVEL 1 SET DRIVE=drive A:
ECHO You chose to format %DRIVE%

cmd line rename file with date and time

Project moving forwards, I can see why creating .bat files to do things can become addictive!
I can now save somefile.txt at regular intervals, I then rename somefile.txt by adding the time and date to create a unique file name
ren somefile.txt somefile_%time:~0,2%%time:~3,2%-%date:~-10,2%%date:~3,2%%date:~-4,4%.txt
As an example, the code above has just renamed somefile.txt to somefile_1317_13022011.txt (1317hrs on 13th February 2011)
I ran
ren somefile.txt somefile_%time:~0,2%%time:~3,2%-%date:~-10,2%%date:~7,2%%date:~-4,4%.txt
yesterday, it ran successfully until midnight, and then it crashed (syntax error) although it was saving as 12012011 for the date (12th Jan 2011) instead of the correct date of 12022011.
Will the current version ran past midnight? Am I confusing myself with UK vs US date format?
Animuson gives a decent way to do it, but no help on understanding it. I kept looking and came across a forum thread with this commands:
Echo Off
IF Not EXIST n:\dbfs\doekasp.txt GOTO DoNothing
copy n:\dbfs\doekasp.txt n:\history\doekasp.txt
Rem rename command is done twice (2) to allow for 1 or 2 digit hour,
Rem If before 10am (1digit) hour Rename starting at location (0) for (2) chars,
Rem will error out, as location (0) will have a space
Rem and space is invalid character for file name,
Rem so second remame will be used.
Rem
Rem if equal 10am or later (2 digit hour) then first remame will work and second will not
Rem as doekasp.txt will not be found (remamed)
ren n:\history\doekasp.txt doekasp-%date:~4,2%-%date:~7,2%-%date:~10,4%_#_%time:~0,2%h%time:~3,2%m%time:~6,2%s%.txt
ren n:\history\doekasp.txt doekasp-%date:~4,2%-%date:~7,2%-%date:~10,4%_#_%time:~1,1%h%time:~3,2%m%time:~6,2%s%.txt
I always name year first YYYYMMDD, but wanted to add time. Here you will see that he has given a reason why 0,2 will not work and 1,1 will, because (space) is an invalid character. This opened my eyes to the issue. Also, by default you're in 24hr mode.
I ended up with:
ren Logs.txt Logs-%date:~10,4%%date:~7,2%%date:~4,2%_%time:~0,2%%time:~3,2%.txt
ren Logs.txt Logs-%date:~10,4%%date:~7,2%%date:~4,2%_%time:~1,1%%time:~3,2%.txt
Output:
Logs-20121707_1019
Digging up the old thread because all solutions have missed the simplest fix...
It is failing because the substitution of the time variable results in a space in the filename, meaning it treats the last part of the filename as a parameter into the command.
The simplest solution is to just surround the desired filename in quotes "filename".
Then you can have any date pattern you want (with the exception of those illegal characters such as /,\,...)
I would suggest reverse date order YYYYMMDD-HHMM:
ren "somefile.txt" "somefile-%date:~10,4%%date:~7,2%%date:~4,2%-%time:~0,2%%time:~3,2%.txt"
following should be your right solution
ren somefile.txt somefile_%time:~0,2%%time:~3,2%-%DATE:/=%.txt
I took the above but had to add one more piece because it was putting a space after the hour which gave a syntax error with the rename command.
I used:
set HR=%time:~0,2%
set HR=%Hr: =0%
set HR=%HR: =%
rename c:\ops\logs\copyinvoices.log copyinvoices_results_%date:~10,4%-%date:~4,2%-%date:~7,2%_%HR%%time:~3,2%.log
This gave me my format I needed:
copyinvoices_results_2013-09-13_0845.log
problem in %time:~0,2% can't set to 24 hrs format, ended with space(1-9), instead of 0(1-9)
go around with:
set HR=%time:~0,2%
set HR=%Hr: =0% (replace space with 0 if any <has a space in between : =0>)
then replace %time:~0,2% with %HR%
good luck
ls | xargs -I % mv % %_`date +%d%b%Y`
One line is enough.
ls all files/dirs under current dir and append date to each file.
I tried to do the same:
<fileName>.<ext> --> <fileName>_<date>_<time>.<ext>
I found that :
rename 's/(\w+)(\.\w+)/$1'$(date +"%Y%m%d_%H%M%S)'$2/' *