I have small perl script test.pl. This perl script uses input as YAML file database.yml
To convert these perl script into executable, I run following command shown below.
pp -o -x teste.exe test.pl.
It creates executable but when i try to run this executable it throws error that database.yml file not found in that directory.
How can i ensure that executable includes YAML file while creating the exe of perl script?
Note :- I am using perl verison 5.8 in Unix.
By using the -a switch :
pp -a database.yml -o -x teste.exe test.pl
From pp documentation :
-a, --addfile=FILE|DIR
Add an extra file into the package. If the file is a directory, recursively add all files inside that directory, with links turned into actual files.
By default, files are placed under "/" inside the package with their original names. You may override this by appending the target filename after a ";", like this:
% pp -a "old_filename.txt;new_filename.txt"
% pp -a "old_dirname;new_dirname"
You may specify "-a" multiple times.
Related
I am using the yarn build command inside a Makefile, which generates two files with names that contain hashes, like main.abc123.js and main.def456.css.
These files need to be referenced from an HTML file, so I've tried automating the entire process. The relevant part in my Makefile is :
build-da:
yarn build
$(eval JS_FILE:=$(shell python -c 'import json, os; config=json.load(open("build/asset-manifest.json")); print(os.path.basename(config["main.js"]))'))
$(eval CSS_FILE:=$(shell python -c 'import json, os; config=json.load(open("build/asset-manifest.json")); print(os.path.basename(config["main.css"]))'))
$(SED) -i -e 's/main\.[^.]*\.js/$(JS_FILE)/g' my_file.html
$(SED) -i -e 's/main\.[^.]*\.css/$(CSS_FILE)/g' my_file.html
Basically, I'm grabbing the generated filenames from asset-manifest.json and trying to use sed to replace that name inside the html file.
This works perfectly fine about 80-90% of cases, but it sometimes fails without any reason, so I'm trying to figure out what is wrong with it.
System: Arch Linux in VirtualBox 5.1.26 on Windows 10 Host
I try to use perl like sed in the terminal for in place substitution the input file:
perl -i -p -e 's/orig/replace/g' input_file
But I always get:
Can't remove input_file Text file busy, skipping file
This happens only if the file is inside a VirtualBox vboxsf share. With all other tools (sed, mv, vim or whatever) it is no problem to change the file.
This problem seems to be related to:
https://www.virtualbox.org/ticket/2553
https://forums.virtualbox.org/viewtopic.php?t=4437
I can't find any solution googling around :(
Update:
Using perl -i.bak -p -e 's/orig/replace/g' input_file I get a similar message:
Can't rename input_file to input_file.bak: Text file busy, skipping file.
This is exactly the same message as gedit shows:
So it is the same behavior, but googling around I can only find the Gedit topic. It seems noone has noticed this with perl -i.
While you are running a unix OS, you are still using a Windows file system. NTFS doesn't support anonymous files like unix file systems, and Perl -i requires support for anonymous files.
The workaround is to use a temporary files by using -i<ext> (e.g. -i~) instead of -i.
I have same problem. My solution is a bashscript. Copy files to tmp. Search and Replace. Overwrite tmp-files with original-files. Than delete tmp-dir. If you need you can use parameter in script for dynamic search&replace and create an alias for call the script direct and everywhere.
#!/bin/bash
echo "Removing text from .log files..."
echo "Creating tmp-dir..."
mkdir /tmp/myTmpFiles/
echo "Copy .log files to tmp..."
cp -v /home/user/sharedfolder/*.log /tmp/myTmpFiles/
echo "Search and Replace in tmp-files..."
perl -i -p0e 's/orig/replace/g' /tmp/myTmpFiles/*.log
echo "Copy .log to sharedfolder"
cp -v /tmp/myTmpFiles/*.log /home/user/sharedfolder/
echo "Remove tmp-dir..."
rm -vr /tmp/myTmpFiles/
echo "Done..."
I have some files: file1.txt, file2.txt and I would like to rename them like this: file1.something.txt and file2.something.txt
I looked for some similar questions and I come up with this:
for i in file*.txt; do echo mv $i file*.something.txt; done
but unfortunately the output is:
mv file1.txt file*.something.txt
mv file2.txt file*.something.txt
and therefore only 1 file is created.
Could please somebody help?
(I am using a macbook air, I am not sure if this is relevant)
Thank you very much
Try this :
rename -n 's/\.txt/something.txt' *
(remove -n switch when your tests are OK)
There are other tools with the same name which may or may not be able to do this, so be careful.
If you run the following command (GNU)
$ file "$(readlink -f "$(type -p rename)")"
and you have a result like
.../rename: Perl script, ASCII text executable
and not containing:
ELF
then this seems to be the right tool =)
If not, to make it the default (usually already the case) on Debian and derivative like Ubuntu :
$ sudo update-alternatives --set rename /path/to/rename
(replace /path/to/rename to the path of your perl's rename command.
If you don't have this command, search your package manager to install it or do it manually
Last but not least, this tool was originally written by Larry Wall, the Perl's dad.
I understand that -i flag takes a file (which may contain list of URLs) and I know that -o followed by a name can be specified to rename a item being downloaded using wget.
example:
wget -i list_of_urls.txt
wget -o my_custom_name.mp3 http://example.com/some_file.mp3
I have a file that looks like this:
file name: list_of_urls.txt
http://example.com/some_file.mp3
http://example.com/another_file.mp3
http://example.com/yet_another_file.mp3
I want to use wget to download these files with the -i flag but also save each file as 1.mp3, 2.mp3 and so on.
Can this be done?
You can use any script language (PHP or Python) for generate batch file. In thin batch file each line will contains run wget with url and -O options.
Or you can try write cycle in bash script.
I ran a web search again and found https://superuser.com/questions/336669/downloading-multiple-files-and-specifying-output-filenames-with-wget
Wget can't seem to do it but Curl can with -K flag, the file supplied can contain url and output name. See http://curl.haxx.se/docs/manpage.html#-K
If you are willing to use some shell scripting then https://unix.stackexchange.com/questions/61132/how-do-i-use-wget-with-a-list-of-urls-and-their-corresponding-output-files has the answer.
I have a bug report from a reliable person that on Cygwin and Perl 5.14.2, using perl's -i switch with no value creates a .bak backup file. It shouldn't according to the documentation in perlrun:
If no extension is supplied, no backup is made and the current
file is overwritten.
I don't have access to Cygwin at the moment. Does anyone else see this behavior? Can you explain it? Is is something about creating the backup file, which should only be a temporary file, and failing to remove it?
Here's the steps I suggest to recreate it. Remember, this is for Cygwin:
Create and change into empty directory
Create a text file in that directory. The contents are not important
Run perl -p -i -e 's/perl/Perl/g' filename
Check for a .bak file when you are done
Save the answers for an explanation of what might be happening if you find that backup file. Upvoting a prior comment for "Yes I see that" or "No, can't reproduce it" can be an informal poll.
perldoc perlcygwin sayeth (edited for clarity):
Because of Windows-ish restrictions, inplace editing of files with perl -i
must create a
backup of each file being edited. Therefore Perl adds the suffix .bak automatically — as
though invoked with perl -i.bak— if
you use perl -i with no explicit backup extension.
Arguably this information should be in perlport also.
Yes. For example:
# show we're in cygwin
% uname -a
CYGWIN_NT-6.1-WOW64 xzodin 1.7.15(0.260/5/3) 2012-05-09 10:25 i686 Cygwin
# show that directory is empty
% ls
# create a file
% touch foo
# invoke 'perl -pi' (but do nothing)
% perl -pi -e "" foo
# show that a backup file with extension '.bak' is created.
% ls
foo foo.bak