Given the following code if I use the first method in the if branch to obtain a MIDIDestination the code works correctly, and MIDI data is sent. If I use the second method from the else branch, no data is sent.
var client = MIDIClientRef()
var port = MIDIPortRef()
var dest = MIDIEndpointRef()
MIDIClientCreate("jveditor" as CFString, nil, nil, &client)
MIDIOutputPortCreate(client, "output" as CFString, &port)
if false {
dest = MIDIGetDestination(1)
} else {
var device = MIDIGetExternalDevice(0)
var entity = MIDIDeviceGetEntity(device, 0)
dest = MIDIEntityGetDestination(entity, 0)
}
var name: Unmanaged<CFString>?
MIDIObjectGetStringProperty(dest, kMIDIPropertyDisplayName, &name)
print(name?.takeUnretainedValue() as! String)
var gmOn : [UInt8] = [ 0xf0, 0x7e, 0x7f, 0x09, 0x01, 0xf7 ]
var pktlist = MIDIPacketList()
var current = MIDIPacketListInit(&pktlist)
current = MIDIPacketListAdd(&pktlist, MemoryLayout<MIDIPacketList>.stride, current, 0, gmOn.count, &gmOn)
MIDISend(port, dest, &pktlist)
In both cases the printed device name is correct, and the status of every call is noErr.
I have noticed that if I ask for the kMIDIManufacturerName property that I get different results - specifically using the first method I get Generic, from the USB MIDI interface to which the MIDI device is connected, and with the second method I get the value of Roland configured via the Audio MIDI Setup app.
The reason I want to use the second method is specifically so that I can filter out devices that don't have the desired manufacturer name, but as above I can't then get working output.
Can anyone explain the difference between these two methods, and why the latter doesn't work, and ideally offer a suggestion as to how I can work around that?
It sounds like you want to find only the MIDI destination endpoints to talk to a certain manufacturer's devices. Unfortunately that isn't really possible, since there is no protocol for discovering what MIDI devices exist, what their attributes are, and how they are connected to the computer.
(Remember that MIDI is primitive 1980s technology. It doesn't even require bidirectional communication. There are perfectly valid MIDI setups with MIDI devices that you can send data to, but can never receive data from, and vice versa.)
The computer knows what MIDI interfaces are connected to it (for instance, a USB-MIDI interface). CoreMIDI calls these "Devices". You can find out how many there are, how many ports each has, etc. But there is no way to find out anything about the physical MIDI devices like keyboards and synthesizers that are connected to them.
"External devices" are an attempt to get around the discovery problem. They are the things that appear in Audio MIDI Setup when you press the "Add Device" button. That's all!
Ideally your users would create an external device for each physical MIDI device in their setup, enter all the attributes of each one, and set up all the connections in a way that perfectly mirrors their physical MIDI cables.
Unfortunately, in reality:
There may not be any external devices. There is not much benefit to creating them in Audio MIDI Setup, and it's a lot of boring data entry, so most people don't bother.
If there are external devices, you can't trust any of the information that the users added. The manufacturer might not be right, or might be spelled wrong, for instance.
It's pretty unfriendly to force your users to set things up in Audio MIDI Setup before they can use your software. Therefore, no apps do that... and therefore nobody sets anything up in Audio MIDI Setup. It's a chicken-and-egg problem.
Even if there are external devices, your users might want to send MIDI to other endpoints (like virtual endpoints created by other apps) that are not apparently connected to external devices. You should let them do what they want.
The documentation for MIDIGetDevice() makes a good suggestion:
If a client iterates through the devices and entities in the system, it will not ever visit any virtual sources and destinations created by other clients. Also, a device iteration will return devices which are "offline" (were present in the past but are not currently present), while iterations through the system's sources and destinations will not include the endpoints of offline devices.
Thus clients should usually use MIDIGetNumberOfSources, MIDIGetSource, MIDIGetNumberOfDestinations and MIDIGetDestination, rather iterating through devices and entities to locate endpoints.
In other words: use MIDIGetNumberOfDestinations and MIDIGetDestination to get the possible destinations, then let your users pick one of them. That's all.
If you really want to do more:
Given a destination endpoint, you can use MIDIEndpointGetEntity and MIDIEndpointGetDevice to get to the MIDI interface.
Given any MIDI object, you can find its connections to other objects. Use MIDIObjectGetDataProperty to get the value of property kMIDIPropertyConnectionUniqueID, which is an array of the unique IDs of connected objects. Then use MIDIObjectFindByUniqueID to get to the object. The outObjectType will tell you what kind of object it is.
But that's pretty awkward, and you're not guaranteed to find any useful information.
Based on a hint from Kurt Revis's answer, I've found the solution.
The destination that I needed to find is associated with the source of the external device, with the connection between them found using the kMIDIPropertyConnectionUniqueID property of that source.
Replacing the code in the if / else branch in the question with the code below works:
var external = MIDIGetExternalDevice(0)
var entity = MIDIDeviceGetEntity(external, 0)
var src = MIDIEntityGetSource(entity, 0)
var connID : Int32 = 0
var dest = MIDIObjectRef()
var type = MIDIObjectType.other
MIDIObjectGetIntegerProperty(src, kMIDIPropertyConnectionUniqueID, &connID)
MIDIObjectFindByUniqueID(connID, &dest, &type)
A property dump suggests that the connection Unique ID property is really a data property (perhaps containing multiple IDs) but the resulting CFData appears to be in big-endian format so reading it as an integer property instead seems to work fine.
Related
I've hunted high and low and cannot find a solution to this problem. I am looking for a method to change the input/output devices which an AVAudioEngine will use on macOS.
When simply playing back an audio file the following works as expected:
var outputDeviceID:AudioDeviceID = xxx
let result:OSStatus = AudioUnitSetProperty(outputUnit, kAudioOutputUnitProperty_CurrentDevice, kAudioUnitScope_Global, 0, &outputDeviceID, UInt32(MemoryLayout<AudioObjectPropertyAddress>.size))
if result != 0 {
print("error setting output device \(result)")
return
}
However if I initialize the audio input (with let input = engine.inputNode) then I get an error once I attempt to start the engine:
AVAEInternal.h:88 required condition is false: [AVAudioEngine.mm:1055:CheckCanPerformIO: (canPerformIO)]
I know that my playback code is OK since, if I avoid changing the output device then I can hear the microphone and the audio file, and if I change the output device but don't initialize the inputNode the file plays to the specified destination.
Additionally to this I have been trying to change the input device, I understood from various places that the following should do this:
let result1:OSStatus = AudioUnitSetProperty(inputUnit, kAudioOutputUnitProperty_CurrentDevice, kAudioUnitScope_Output, 0, &inputDeviceID, UInt32(MemoryLayout<AudioObjectPropertyAddress>.size))
if result1 != 0 {
print("failed with error \(result1)")
return
}
However, this doesn't work - in most cases it throws an error (10853) although if I select a sound card that has both inputs and outputs it succeeds - it appears that when I am attempting to set the output or the input node it is actually setting the device for both.
I would think that this meant that an AVAudioEngine instance can only deal with one device, however it is quite happy working with the default devices (mic and speakers/headphones) so I am confident that isn't the issue. Looking at some solutions I have seen online people simply change the default input, but this isn't a massively nice solution.
Does anyone have any ideas as to whether this is possible?
It's worth noting that kAudioOutputUnitProperty_CurrentDevice is the only property available, there is not an equivalent kAudioInputUnitProperty_CurrentDevice key, due to the fact that as I understand it both the inputNode and outputNode are classed as "Output Units" (as they both emit sound somewhere).
Any ideas would be much appreciated as this is very very frustrating!!
Thanks
So I filed a support request with apple on this and another issue and the response confirms that an AVAudioEngine can only be assigned to a single Aggregate device (that is, a device with both input and output channels) - the system default units create effectively an aggregate device internally which is why they work, although I've found an additional issue in that if the input device also has output capabilities (and you activate the inputNode) then that device has to be both the input and output device as otherwise the output appears not to work.
So answer is that I think there is no answer..
My aim is to write an audio app for low latency realtime audio analysis on OSX. This will involve connecting to one or more USB interfaces and taking specific channels from these devices.
I started with the learning core audio book and writing this using C. As I went down this path it came to light that a lot of the old frameworks have been deprecated. It appears that the majority of what I would like to achieve can be written using AVAudioengine and connecting AVAudioUnits, digging down into core audio level only for the lower things like configuring the hardware devices.
I am confused here as to how to access two devices simultaneously. I do not want to create an aggregate device as I would like to treat the devices individually.
Using core audio I can list the audio device ID for all devices and change the default system output device here (and can do the input device using similar methods). However this only allows me one physical device, and will always track the device in system preferences.
static func setOutputDevice(newDeviceID: AudioDeviceID) {
let propertySize = UInt32(MemoryLayout<UInt32>.size)
var deviceID = newDeviceID
var propertyAddress = AudioObjectPropertyAddress(
mSelector: AudioObjectPropertySelector(kAudioHardwarePropertyDefaultOutputDevice),
mScope: AudioObjectPropertyScope(kAudioObjectPropertyScopeGlobal),
mElement: AudioObjectPropertyElement(kAudioObjectPropertyElementMaster))
AudioObjectSetPropertyData(AudioObjectID(kAudioObjectSystemObject), &propertyAddress, 0, nil, propertySize, &deviceID)
}
I then found that the kAudioUnitSubType_HALOutput is the way to go for specifying a static device only accessible through this property. I can create a component of this type using:
var outputHAL = AudioComponentDescription(componentType: kAudioUnitType_Output, componentSubType: kAudioUnitSubType_HALOutput, componentManufacturer: kAudioUnitManufacturer_Apple, componentFlags: 0, componentFlagsMask: 0)
let component = AudioComponentFindNext(nil, &outputHAL)
guard component != nil else {
print("Can't get input unit")
exit(-1)
}
However I am confused about how you create a description of this component and then find the next device that matches the description. Is there a property where I can select the audio device ID and link the AUHAL to this?
I also cannot figure out how to assign an AUHAL to an AVAudioEngine. I can create a node for the HAL but cannot attach this to the engine. Finally is it possible to create multiple kAudioUnitSubType_HALOutput components and feed these into the mixer?
I have been trying to research this for the last week, but nowhere closer to the answer. I have read up on channel mapping and everything I need to know down the line, but at this level getting the audio at. lower level seems pretty undocumented, especially when using swift.
I'm considering using Matlab Compiler to distribute software for a price. I'm investigating (very) simple methods to discourage re-distribution without annoying users. Any recommendations?
One thought is to email a user a license key and have them input this during the installation process to be verified on a license server. If the key matches what is on the server, the installation proceeds as usual, otherwise, a warning message is shown to inform the user to purchase another license. However, this method requires a specified function to run only during the installation process, and not thereafter (so as not to annoy the user). Is this possible using Matlab Compiler or otherwise?
I suppose I could create a file on the user's disk that the program looks for when it starts (if it exists, then it is not being run for the first time), but if the user copies the whole directory, that file would get copied too.
In order to create an effective licensing system, you have to link it to one or more properties of a user machine (MAC address, OS ID, hard disk serial numbers, CPU serial numbers, etc...).
If you don't to this, you are just going to release licenses that can be transferred from one user to another. If one user decides to spread his license file worldwide, you are doomed because everyone could potentially take that license file and use it to unlock your application.
But if you link your license files to one or more properties of a user machine, as mentioned above, you must be able to obtain these properties either:
before the user decides to buy your application;
when the user activates his license.
First Scenario
You release your software as a trial. When it is started for the first time, you set an expiration date in the registry or in a file well hidden somewhere. You check against the expiration date when the application starts and, once it is reached, you throw an error and you don't let the used play with your application anymore.
Within the application, you create a Register Now button somewhere. When it is clicked, the application retrieves the machine properties and passes them to the web page / form that will be opened to let the user perform the payment. That page will be in charge to validate the machine properties, receive the payment and, finally, deliver a valid license code based on these properties.
Within the application, you must implement the same logics that allowed your form to create the license code, because you will need to use them in order to validate the code itself every time your application starts. A pseudo-code example:
mp1 = GetMachineProperty1();
mp2 = GetMachineProperty2();
mp3 = GetMachineProperty3();
lc = GetLicenseCode();
if (~strcmp(sha1([mp1 mp2 mp3]),lc))
errordlg('Invalid license code!');
return;
end
This is the simplest path. But keep in mind that if one or more properties of the user machine change (because he changes a device or reinstalls his OS), his license will be invalidated and you will have to provide a customer assistance service that takes care of this kind of situations.
Second Scenario
This one is much harder. You will not be able to know the user's machine properties in advance. So your licensing system will work on a two-steps basis. You release a unique code (called LID for example) when the used purchases your application. Then, once the user inserts that it in your application, your application must send it back together with the machine properties. The final key (called LKey for example) is then computed and sent back to the user.
mp1 = GetMachineProperty1();
mp2 = GetMachineProperty2();
mp3 = GetMachineProperty3();
lkey = GetLicenseKey();
if (~strcmp(sha1([mp1 mp2 mp3]),lkey))
errordlg('Invalid license code!');
return;
end
Machine Properties
The first solution has been provided to you through a comment: the MachineGuid value located in the registry key HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Cryptography. It's pretty solid. But it will only work on Windows machines. Use winqueryreg to access the registry.
Another good alternative is the Window Domain Controller Security ID, which is another machine-specific unique identifier. You can retrieve it using Java code within Matlab:
wdc_sid = com.sun.security.auth.module.NTSystem.getDomainSID();
or through the Windows registry key HKEY_CURRENT_USER\SOFTWARE\Microsoft\Windows\CurrentVersion\Group Policy\GroupMembership. The registry approach should be the one to use if you want to maintain a certain backward compatibility with old Matlab releases. Unfortunately, the Window Domain Controller Security ID is another identifier that is available only on machines that run under Windows.
If you want to adapt your licensing system to every possible OS and environment, you have to use a more generic approach, based on universally accessible hardware properties: MAC adresses, hard disk serials and such things. As far as I know, the most reliable property is the MAC address, because its uniqueness, althrough not granted, is almost certain and it's very unfrequent to change a network adapter (there are more chances to break an hard disk actually). Retrieve the MAC adresses of the machine network adapters using Java code as follows:
mac_addrs = '';
net_int = java.net.NetworkInterface.getNetworkInterfaces();
while (net_int.hasMoreElements)
mac_addr = net_int.nextElement.getHardwareAddress();
if (~isempty(mac_addr))
mac_addrs = [mac_addrs, '-', sprintf('%.2X',typecast(mac_addr,'uint8'))];
end
end
mac_addrs = mac_addrs(2:end);
The above computation produces a character array that represents the result of the concatenation of all the MAC addresses found on the machine. Again, for compatibility reasons, this may not work on old Matlab releases, so you have to use a much more complex approach, described here.
[EDIT]
This approach to retrieve the MAC address based on the underlying OS could be easier:
switch computer('arch')
case {'maci','maci64'}
[~,a]=system('ifconfig');
c=strfind(a,'en0');if ~isempty(c),a=a(c:end);end
c=strfind(a,'en1');if ~isempty(c),a=a(1:c-1);end
% find the mac address
b=strfind(a,'ether');
mac_add=a(1,b(1)+6:b(1)+22);
case {'win32','win64'}
[~,a]=system('getmac');b=strfind(a,'=');
mac_add=a(b(end)+1:b(end)+19);
case {'glnx86','glnxa64'}
[~,a]=system('ifconfig');b=strfind(a,'Ether');
mac_add=a(1,b(1)+17:b(1)+33);
otherwise,mac_add=[];
end
I found it in the comments of this article.
Assumed I have a JTAG-chain with several devices from different manufactures:
How does my software, which shall communicate with a specific system within that chain, known the length of the IR for all the others devices within the chain? I do have to know them to send a certain instruction to my device, right?
It is possible to detect the total length of all IR registers in your JTAG daisy-chain. It is also possible to detect the number of devices (or TAPs) in your chain. But you can't detect the individual IR length of a single TAP.
What you can do: You can read out the JTAG ID code register of all of you TAPs. The ID code register (in DR path) is always 32 bit and gets selected by test-logic-reset.
With the ID code you can identify the existing TAPs and look up in the datasheet the length of the individual IR registers.
And yes: In general you do have to know the individual IR length of all the TAPs in your chain to communicate with one of them.
try here: http://www.fpga4fun.com/JTAG3.html
When IR = '1...1', the BYPASS is selected.
The idea is to send a lot of '1' so regardless of IR length all devices will select BYPASS.
Apple introduced the CNCopyCurrentNetworkInfo() function in OS 4.1.
https://developer.apple.com/library/ios/#documentation/SystemConfiguration/Reference/CaptiveNetworkRef/Reference/reference.html#//apple_ref/doc/c_ref/kCNNetworkInfoKeySSIDData
According to the documentation it should:
Return the current network info for a given network interface.
However, when used it seems to return the correct SSID (readable network name) but a garbage BSSID(the MAC address of the Wireless Access Point). I have tried this connected to multiple different networks with two different iPads and the results are the same.
On my home network, the function returns:
{
BSSID = "0:19:db:8:5c:cc";
SSID = "Das Boot";
SSIDDATA = <44617320 426f6f74>;
}
In reality, the BSSID of my router is 0:4:ed:66:81:xx where the xx definitely is not cc
Does anyone have experience using this function and have I missed something obvious (more likely) or is this an Apple bug (much less likely) ?
Any input is greatly appreciated,
Nicke.