Sum value without summing the strikeout value - crystal-reports

I need to calculate the overall sum without strikeout value
invoice values
--------------------------------
VI 320
VI 260
VI 72
VI 72
-VI- -72-
Just imagine the last value with - symbol is the strikeout value
the total sum should be 724.
i tried doing like the following formula but it return 0 value
IF {Command.void_flg} = 0 THEN
Sum ({Command.Vessel_amt})

First create a new formula #Vessel amt
if ({Command.void_flg}) = 0 THEN
{Command.Vessel_amt}
else 0
Then create another formula #Sum amt.
SUM({#Vessel amt})
Then drag #Sum amtto the place you want.

Related

Sum in range until value change

I'am trying to use this formula to make it work
=ARRAYFORMULA(IF(ISDATE_STRICT(S2:S) ; (MATCH(MAX(AB2:AB),AB2:AB;0)-1) ; "" ))
If there is a date in Column "S" I want it to display the sum of the blanks that would appear if in Column "S" is text
=ARRAYFORMULA(IF(ISDATE_STRICT(S2:S) ; ArrayFormula(MATCH(FALSE ; ISBLANK(AB2:AB) ; 0)-1) ; "" ))
I've tried this one as well but I only get 0's as a result.
Any idea how I can make it work?
Here is the sample sheet.
https://docs.google.com/spreadsheets/d/19f5phXeAwXwrKbWz7njgbznmurOav72GUuo_5IGcbls/edit?usp=sharing
in Q2 use:
=ARRAYFORMULA(IF(ISBLANK(
I1:INDEX(I:I; ROWS(I:I)-1));
{N2:INDEX(N:N; ROWS(N:N))\
I1:INDEX(N:N; ROWS(N:N)-1)};
I1:INDEX(O:O; ROWS(O:O)-1)))
in X2 use:
=INDEX(LAMBDA(x; IFNA(VLOOKUP(x; QUERY(VLOOKUP(ROW(x);
IF(ISDATE_STRICT(x); {ROW(x)\x}); 2; 1);
"select Col1,count(Col1) group by Col1"); 2; 0)-1))
(Q2:INDEX(Q:Q; MAX((Q:Q<>"")*ROW(Q:Q)))))
UPDATE:
we start with column Q. we can take a range Q2:Q but that range contains a lot of empty rows. the next best thing is to check the last non-empty row and set it as the end of the range resulting in Q2:Q73. but static 73 won't do in case the dataset would grow or shrink so to get 73 dynamically we take the MAX of multiplication of Q:Q not being empty and row number of that case eg. Q:Q<>"" will output only TRUE or FALSE so what we are getting is
...
TRUE * 72 = 1 * 72 = 72
TRUE * 73 = 1 * 73 = 73
FALSE * 74 = 0 * 74 = 0
...
so the formula for getting Q2:Q73 is:
=Q2:INDEX(Q:Q; MAX((Q:Q<>"")*ROW(Q:Q)))
it could also be:
=INDEX(INDIRECT("Q2:Q"&MAX((Q:Q<>"")*ROW(Q:Q))))
but it's just long to type... next, we use the new LAMBDA function that allows us to reference cell/range/formula with a placeholder. simple LAMBDA syntax is:
=LAMBDA(x; x)(A1)
where x is A1 and we can do whatever we want with the 2nd (x) argument of LAMBDA like for example:
=LAMBDA(a, a+a*120-a/a)(A1)
you can think of it as:
LAMBDA(A1, A1+A1*120-A1/A1)(A1)
or as just:
=A1+A1*120-A1/A1
the issue here is that we repeat A1 4 times but with LAMBDA we do it only once. also, imagine if we would have 100 characters long formula instead of A1 so the final formula with lambda would be 300 characters shorter compared to "old way" formula.
back to our formula... x is the representation of Q2:Q73. now let's focus on VLOOKUP. basically, the idea here is that IF Q column contains a date we return that date, otherwise we return the last date from above. simply put:
=ARRAYFORMULA(VLOOKUP(ROW(Q2:Q73);
IF(ISDATE_STRICT(Q2:Q73); {ROW(Q2:Q73)\Q2:Q73}); 2; 1))
as you can see Y2, Y3 and Y4 are the same so all we need to do is to count them up and later take away one to exclude Q2 but include just Q3 and Q4 eg. 3-1=2. for that we use simple QUERY where the output is:
date count
30.06.2022 3
so all we need to do is to pair up dates from Q column to QUERY output for that we use the outer VLOOKUP where the output is as follows:
3
#N/A
#N/A
9
#N/A
#N/A
...
now is the right time for that -1 correction while we have these errors coz ERROR-1=ERROR and 3-1=2 so after this -1 correction the output is:
2
#N/A
#N/A
8
#N/A
#N/A
...
and all we need to do now is to hide errors with IFERROR and the output is column X

Putting 0 at a string to make it of some length in SQL

I have a table with a column named Code filled up with TEXT values as:
Code
-------
1111
23456
212
954737
323
1234567
Given a natural number n > 0: For every row with
LENGHT(Code) < n
I need to concatenate 0 to the left of Code to get a new string with size n.
Example:
If n = 7 for the previous values I need to get
0001111
0023456
0000212
0954737
0000323
1234567
Using psql... is it possible to do this?
Thanks
you can use this function
LPAD(Code::text, 7, '0')

How do I store each detail section value in a separate Variable?

Please check this image for details
Formula - #B
If {Command.Dept} in ["AAA","BBB","CCC","DDD"] and {#TOT}>0
Then
{#TOT}
So this should give me only values as follow
190
170
190
220
Formula - #C
If {Command.Dept} in ["AAA-Bud","BBB-Bud","CCC-Bud","DDD-Bud"] and {#TOT}>0
Then
{#TOT}
So this should give me only values as follow
150
200
230
260
Now I created another formula
#Percent
If ({#B} <> 0 AND {#C}<>0)
Then
({#B}/{#C})* 100
When I plug #Percent formula on my repot I am getting error
"Division By Zero" error.
So if I plug formula #B
I'm getting correct values for 1st 4 rows, but next 4rows (AAA-Bud","BBB-Bud","CCC-Bud","DDD-Bud") I'm getting 0.
For formula #C 1st 4 rows gives me 0 and next 4 rows (AAA-Bud","BBB-Bud","CCC-Bud","DDD-Bud") gives me correct values.
So how do I avoid those zeros so I can calulate correct percent values?
try
If {#C} >0
Then
({#B}/{#C})* 100

Calculation of Previous field

New to CR and use CR v10 and SQL Server 2000.
For the first record i.e Beginning Balance , the calculation is sum(field) from the input date, which I have calculated in SP as BegDateSum
But for the rest of the records under a group, the calculation should be previous(balance)+IN+OUT
Sample has been given:
Date Doc Descrip IN OUT Balance
Group Header-------- Beginning Balance-------------- 50 <---- sum(field) from my inputdate
3/2/2012 A -1 0 49 <-- (50+(-1)+0)
4/2/2012 B -2 0 47 <-- (49+(-2)+0)
5/2/2012 C 0 3 50
6/2/2012 D -2 3 51
How do I achieve this?
I am not sure whether to use running total, in case I have to how to do it.
A running total field won't work in this case, they are designed to add up (or count, or average, etc) one field and give you the sub-totals automatically. But, we can do some custom functions that will give the results you need. Assuming that your initial 50 is a static value, you would set a variable to that amount, and then add the IN and OUT values as you go along (printing that result of that).
First, initialize the value in the report header with a formula like:
WhilePrintingRecords;
Global NumberVar Balance;
Balance := 50;
""; //print nothing on the screen
Then, the formula to calculate and show the new balance, in the bar where the data is:
WhilePrintingRecords;
Global NumberVar Balance;
Balance := Balance + {tableName.IN} + {tableName.OUT};
The last line both calculates the new value, and tells what the result of the formula should be.
If the "50" is calculated somehow, then that will have to be done before the formula that calculates the new balance. If it is based off of the first record read in, you'll want to use a formula that includes If PreviousIsNull({tableName.Balance}) Then ..., that is usually a good indicator of the first record in the data set (unless that field can be null).

how to create unique integer number from 3 different integers numbers(1 Oracle Long, 1 Date Field, 1 Short)

the thing is that, the 1st number is already ORACLE LONG,
second one a Date (SQL DATE, no timestamp info extra), the last one being a Short value in the range 1000-100'000.
how can I create sort of hash value that will be unique for each combination optimally?
string concatenation and converting to long later:
I don't want this, for example.
Day Month
12 1 --> 121
1 12 --> 121
When you have a few numeric values and need to have a single "unique" (that is, statistically improbable duplicate) value out of them you can usually use a formula like:
h = (a*P1 + b)*P2 + c
where P1 and P2 are either well-chosen numbers (e.g. if you know 'a' is always in the 1-31 range, you can use P1=32) or, when you know nothing particular about the allowable ranges of a,b,c best approach is to have P1 and P2 as big prime numbers (they have the least chance to generate values that collide).
For an optimal solution the math is a bit more complex than that, but using prime numbers you can usually have a decent solution.
For example, Java implementation for .hashCode() for an array (or a String) is something like:
h = 0;
for (int i = 0; i < a.length; ++i)
h = h * 31 + a[i];
Even though personally, I would have chosen a prime bigger than 31 as values inside a String can easily collide, since a delta of 31 places can be quite common, e.g.:
"BB".hashCode() == "Aa".hashCode() == 2122
Your
12 1 --> 121
1 12 --> 121
problem is easily fixed by zero-padding your input numbers to the maximum width expected for each input field.
For example, if the first field can range from 0 to 10000 and the second field can range from 0 to 100, your example becomes:
00012 001 --> 00012001
00001 012 --> 00001012
In python, you can use this:
#pip install pairing
import pairing as pf
n = [12,6,20,19]
print(n)
key = pf.pair(pf.pair(n[0],n[1]),
pf.pair(n[2], n[3]))
print(key)
m = [pf.depair(pf.depair(key)[0]),
pf.depair(pf.depair(key)[1])]
print(m)
Output is:
[12, 6, 20, 19]
477575
[(12, 6), (20, 19)]