Trace:
Error: Main method not found in class newpackage.Myclass, please
define the main methods: public static void main(String[] args) or a
JavaFX application class must extend javafx.application.Application.
MyClass.java
package newpackage;
import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.firefox.FirefoxDriver;
//import javafx.application.*;
public class Myclass {
public static void main(String[] args) {
System.setProperty("webdriver.gecko.driver","C:\\Users \\karokiaswamy\\Documents\\Selenium_installation\\geckodriver-v0.15.0-win64)\\geckodriver.exe");
WebDriver driver = new FirefoxDriver();
driver.get("http://Application URL");
driver.findElement(By.xpath("//*[#id='siteLoginTab']/form/table/tbody/tr[1]/td[1]/input")).sendKeys("USER NAME");
driver.findElement(By.xpath("//*[#id='siteLoginTab']/form/table/tbody/tr[1]/td[2]/input")).sendKeys("Password");
driver.findElement(By.xpath("//*[#id='siteLoginTab]/form/table/tbody/tr[1]/td[3]/input")).click();
driver.findElement(By.xpath(".//*[#id='siteLoginTab']/form/table/tbody/tr[1]/td[2]/input")).sendKeys(" ");
driver.findElement(By.xpath(".//*[#id='siteMain']/div[1]/div/form/table/tbody/tr[3]/td/input")).click();
driver.findElement(By.xpath(".//*[#id='siteMain']/div[1]/div/form/table/tbody/tr[3]/td/input")).click();
}
}
Related
I got the HTML in console using getpagesource in selenium java .
Now i need only the tag 'Forms' in the console result.
How do i do that?
public class Test {
private static final String HTMLPageSourceCode = null;
public static void main(String[] args) throws InterruptedException {
System.setProperty("webdriver.chrome.driver","C:\\Selenium project\\chromedriver_win32/chromedriver.exe");
WebDriver driver = new ChromeDriver();
driver.manage().window().maximize();
driver.get("https://''/tandem/login/?");
String pagesource = driver.getPageSource();
System.out.println(pagesource);
}
You can use following code snippet for this :
import java.util.List;
import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.firefox.FirefoxDriver;
//Sample Java class to fetch list of all tag with tagname forms
public class Test {
public static void main(String[] args) {
String geckoDriverPath=Class1.class.getResource("/firefox/geckodriver.exe").getPath();
System.setProperty("webdriver.gecko.driver",geckoDriverPath);
WebDriver driver = new FirefoxDriver();
driver.get("http://www.URL.com");
List<WebElement>list =driver.findElements(By.tagName("form"));
for(WebElement ele:list) {
System.out.println(ele.getText());
}
}
}
Once you get the lists you can fetch individual form element and perform action like getting text.Hope, this helps
I am trying to invoke a POST service via Postman. My application is running on embedded tomcat server. However when I try to invoke the service, the error I get is "No mapping found for HTTP request with URI [/findrouting] in DispatcherServlet with name 'dispatcherServlet'"
It is not even recognizing http:localhost:8080/
RoutingRequest and RoutingResponse are the POJOs with getters and setters.
Am I missing something here. I did check lots of examples but didn't find any solution to my problem.
Please see my code below :
package com.ab.hello.ambassador.server;
import java.util.Arrays;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.boot.context.web.SpringBootServletInitializer;
import org.springframework.context.ApplicationContext;
#SpringBootApplication
public class Application extends SpringBootServletInitializer {
public static void main(String[] args) {
ApplicationContext ctx = SpringApplication.run(AmbassadorApplication.class, args);
System.out.println("List of Beans instantiated");
String[] beanNames = ctx.getBeanDefinitionNames();
Arrays.sort(beanNames);
for (String beanName : beanNames) {
System.out.println(beanName);
}
}
}
package com.ab.hello.ambassador.server.controller;
import static org.springframework.http.MediaType.APPLICATION_JSON_VALUE;
import static org.springframework.web.bind.annotation.RequestMethod.POST;
import org.springframework.web.bind.annotation.RequestBody;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.ResponseBody;
import org.springframework.web.bind.annotation.RestController;
import com.dp.connect.ambassador.server.RoutingRequest;
import com.dp.connect.ambassador.server.RoutingResponse;
#RestController
public class ApplicationController {
#RequestMapping("/")
public String index() {
return "Spring Boot POC Welcomes You!";
}
#RequestMapping(method = POST, value = "/findrouting", consumes = { APPLICATION_JSON_VALUE }, produces = {
APPLICATION_JSON_VALUE })
public RoutingResponse findRoute(#RequestBody RoutingRequest request) throws Exception {
// some business logic that would return response; as of now I have set it to null
RoutingResponse response = null;
return response;
}
}
Thanks for your time. After struggling for quite a long time. I figured out this piece of code. Added annotation #EnableWebMvc. This solved my problem.
#SpringBootApplication
#EnableWebMvc
public class Application extends SpringBootServletInitializer {
#Override
protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
return application.sources(Application.class);
}
public static void main(String[] args) throws Exception {
SpringApplication.run(Application.class, args);
}
}
Try to define the path in your controller:
#RestController
#RequestMapping("/")
public class ApplicationController {
#RequestMapping
public String index() {
return "Spring Boot POC Welcomes You!";
}
#RequestMapping(method = POST, value = "/findrouting", consumes = { APPLICATION_JSON_VALUE }, produces = {
APPLICATION_JSON_VALUE })
public RoutingResponse findRoute(#RequestBody RoutingRequest request) throws Exception {
// some business logic that would return response; as of now I have set it to null
RoutingResponse response = null;
return response;
}
}
Change the below line
ApplicationContext ctx = SpringApplication.run(AmbassadorApplication.class, args);
with
ApplicationContext ctx = SpringApplication.run(Application.class, args);
according to spring docs , seems need to Override a config method:
#SpringBootApplication
public class Application extends SpringBootServletInitializer {
#Override
protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {
return application.sources(Application.class);
}
public static void main(String[] args) throws Exception {
SpringApplication.run(Application.class, args);
}
}
package First;
import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.firefox.FirefoxDriver;
public class First1 {
public static WebDriver driver=new FirefoxDriver();
public static WebElement webele;
public static void LaunchApp(String url){
driver.get(url);
}
public static String webele(String loc){
webele= driver.findElement(By.id(loc));
System.out.println("abc");
}
}
package First;
public class First2 {
public static void main(String[] args) {
First1.LaunchApp("https://facebook.com").sendkeys("hdkjasj");
}
}
Here is my next class in the same package to call the method webele with arguments. when trying to call the first class in the second I am getting error as cannot invoke sendkeys(String) into primitive Type void.
I need to start a javafx Application from another "container" class and call functions on the Application, but there doesn't seem to be any way of getting hold of a reference to the Application started using the Application.launch() method. Is this possible?
Thanks
Suppose this is our JavaFX class:
import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.stage.Stage;
public class OKButton extends Application {
#Override
public void start(Stage stage) {
Button btn = new Button("OK");
Scene scene = new Scene(btn, 200, 250);
stage.setTitle("OK");
stage.setScene(scene);
stage.show();
}
}
Then we may launch it from another class like this:
import javafx.application.Application;
public class Main {
public static void main(String[] args) {
Application.launch(OKButton.class, args);
}
}
I had the same problem as this and got round it using this hack:
import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.control.Label;
import javafx.scene.layout.BorderPane;
import javafx.stage.Stage;
import java.util.concurrent.CountDownLatch;
public class StartUpTest extends Application {
public static final CountDownLatch latch = new CountDownLatch(1);
public static StartUpTest startUpTest = null;
public static StartUpTest waitForStartUpTest() {
try {
latch.await();
} catch (InterruptedException e) {
e.printStackTrace();
}
return startUpTest;
}
public static void setStartUpTest(StartUpTest startUpTest0) {
startUpTest = startUpTest0;
latch.countDown();
}
public StartUpTest() {
setStartUpTest(this);
}
public void printSomething() {
System.out.println("You called a method on the application");
}
#Override
public void start(Stage stage) throws Exception {
BorderPane pane = new BorderPane();
Scene scene = new Scene(pane, 500, 500);
stage.setScene(scene);
Label label = new Label("Hello");
pane.setCenter(label);
stage.show();
}
public static void main(String[] args) {
Application.launch(args);
}
}
and then the class you are launching the application from:
public class StartUpStartUpTest {
public static void main(String[] args) {
new Thread() {
#Override
public void run() {
javafx.application.Application.launch(StartUpTest.class);
}
}.start();
StartUpTest startUpTest = StartUpTest.waitForStartUpTest();
startUpTest.printSomething();
}
}
Hope that helps you.
Launch JavaFX in other Class using Button:
class Main extends Application{
public void start(Stage s)throws Exception{
event();
s.show();
}
public void event(){
btn.setOnAction(new EventHandler<ActionEvent>(){
public void handle(ActionEvent ae){
Stage s = new Stage();
new SubClassName().start(s);
}
});
}
public static void main(String[] args) {
launch(args);
}
}
class SubClassName{
public void start(Stage s){
Pane pane = new Pane();
Scene addFrame = new Scene(pane,280,450);
s.setScene(addFrame);
s.show();
}
}
I'm not sure what you're trying to achieve, but note that you can e.g call from another class Application.launch to start the JavaFX Application thread and Platform.exit to stop it.
The above ways of invoking other javafx class from another sometimes work. Struggling to find an ultimate way to do this brought me to the following walk around:
Suppose this is the javafx class that exteds Application we wish to show from a different class, then we should add the following lines
class ClassToCall extends Application{
//Create a class field of type Shape preferably static...
static Stage classStage = new Stage();
#Override
public void start(Stage primaryStage){
// Assign the class's stage object to
// the method's local Stage object:
classStage = primaryStage ;
// Here comes some more code that creates a nice GUI.....
// ......
}
}
And now from the other place in the project, in order to open the window
that the above class creates do the following:
// Suppose we want to do it with a button clicked:
btn1.setOnAction(new EventHandler<ActionEvent>() {
#Override
public void handle(ActionEvent event) {
//create an object of the class you wish to invoke its
//start() method:
ClassToCall ctc = new ClassToCall();
// Then call its start() method in the following way:
ctc.start(ClassToCall.classStage);
}// End handle(ActionEvent event)
});// End anonymous class
public class ABC{ public static void main(String[] args) { out.println("Hello"); } }
This works, though static imports are not generally considered a good thing in java.
import static java.lang.System.out;
public class ABC {
public static void main(String[] args) {
out.println("hello");
}
}