E-num / get Dummies in pyspark - pyspark

Question

I would like to create a function in PYSPARK that get Dataframe and list of parameters (codes/categorical features) and return the data frame with additional dummy columns like the categories of the features in the list
PFA the Before and After DF:
before and After data frame- Example
The code in python looks like that:
enum = ['column1','column2']
for e in enum:
print e
temp = pd.get_dummies(data[e],drop_first=True,prefix=e)
data = pd.concat([data,temp], axis=1)
data.drop(e,axis=1,inplace=True)
data.to_csv('enum_data.csv')

Answer 1

First you need to collect distinct values of TYPES and CODE. Then either select add column with name of each value using withColumn or use select fro each column.
Here is sample code using select statement:-
import pyspark.sql.functions as F
df = sqlContext.createDataFrame([
(1, "A", "X1"),
(2, "B", "X2"),
(3, "B", "X3"),
(1, "B", "X3"),
(2, "C", "X2"),
(3, "C", "X2"),
(1, "C", "X1"),
(1, "B", "X1"),
], ["ID", "TYPE", "CODE"])
types = df.select("TYPE").distinct().rdd.flatMap(lambda x: x).collect()
codes = df.select("CODE").distinct().rdd.flatMap(lambda x: x).collect()
types_expr = [F.when(F.col("TYPE") == ty, 1).otherwise(0).alias("e_TYPE_" + ty) for ty in types]
codes_expr = [F.when(F.col("CODE") == code, 1).otherwise(0).alias("e_CODE_" + code) for code in codes]
df = df.select("ID", "TYPE", "CODE", *types_expr+codes_expr)
df.show()
OUTPUT
+---+----+----+--------+--------+--------+---------+---------+---------+
| ID|TYPE|CODE|e_TYPE_A|e_TYPE_B|e_TYPE_C|e_CODE_X1|e_CODE_X2|e_CODE_X3|
+---+----+----+--------+--------+--------+---------+---------+---------+
| 1| A| X1| 1| 0| 0| 1| 0| 0|
| 2| B| X2| 0| 1| 0| 0| 1| 0|
| 3| B| X3| 0| 1| 0| 0| 0| 1|
| 1| B| X3| 0| 1| 0| 0| 0| 1|
| 2| C| X2| 0| 0| 1| 0| 1| 0|
| 3| C| X2| 0| 0| 1| 0| 1| 0|
| 1| C| X1| 0| 0| 1| 1| 0| 0|
| 1| B| X1| 0| 1| 0| 1| 0| 0|
+---+----+----+--------+--------+--------+---------+---------+---------+

Answer 2

The solutions provided by Freek Wiemkeijer and Rakesh Kumar are perfectly adequate, however, since I coded it up, I thought it was worth posting this generic solution as it doesn't require hard coding of the column names.
pivot_cols = ['TYPE','CODE']
keys = ['ID','TYPE','CODE']
before = sc.parallelize([(1,'A','X1'),
(2,'B','X2'),
(3,'B','X3'),
(1,'B','X3'),
(2,'C','X2'),
(3,'C','X2'),
(1,'C','X1'),
(1,'B','X1')]).toDF(['ID','TYPE','CODE'])
#Helper function to recursively join a list of dataframes
#Can be simplified if you only need two columns
def join_all(dfs,keys):
if len(dfs) > 1:
return dfs[0].join(join_all(dfs[1:],keys), on = keys, how = 'inner')
else:
return dfs[0]
dfs = []
combined = []
for pivot_col in pivot_cols:
pivotDF = before.groupBy(keys).pivot(pivot_col).count()
new_names = pivotDF.columns[:len(keys)] + ["e_{0}_{1}".format(pivot_col, c) for c in pivotDF.columns[len(keys):]]
df = pivotDF.toDF(*new_names).fillna(0)
combined.append(df)
join_all(combined,keys).show()
This gives as output:
+---+----+----+--------+--------+--------+---------+---------+---------+
| ID|TYPE|CODE|e_TYPE_A|e_TYPE_B|e_TYPE_C|e_CODE_X1|e_CODE_X2|e_CODE_X3|
+---+----+----+--------+--------+--------+---------+---------+---------+
| 1| A| X1| 1| 0| 0| 1| 0| 0|
| 2| C| X2| 0| 0| 1| 0| 1| 0|
| 3| B| X3| 0| 1| 0| 0| 0| 1|
| 2| B| X2| 0| 1| 0| 0| 1| 0|
| 3| C| X2| 0| 0| 1| 0| 1| 0|
| 1| B| X3| 0| 1| 0| 0| 0| 1|
| 1| B| X1| 0| 1| 0| 1| 0| 0|
| 1| C| X1| 0| 0| 1| 1| 0| 0|
+---+----+----+--------+--------+--------+---------+---------+---------+

Answer 3

I was looking for the same solution but is scala, maybe this will help someone:
val list = df.select("category").distinct().rdd.map(r => r(0)).collect()
val oneHotDf = list.foldLeft(df)((df, category) => finalDf.withColumn("category_" + category, when(col("category") === category, 1).otherwise(0)))

Answer 4

If you'd like to get the PySpark version of pandas "pd.get_dummies" function, you can you the following function:
import itertools
def spark_get_dummies(df):
categories = []
for i, values in enumerate(df.columns):
categories.append(df.select(values).distinct().rdd.flatMap(lambda x: x).collect())
expressions = []
for i, values in enumerate(df.columns):
expressions.append([F.when(F.col(values) == i, 1).otherwise(0).alias(str(values) + "_" + str(i)) for i in categories[i]])
expressions_flat = list(itertools.chain.from_iterable(expressions))
df_final = df.select(*expressions_flat)
return df_final
The reproducible example is:
df = sqlContext.createDataFrame([
("A", "X1"),
("B", "X2"),
("B", "X3"),
("B", "X3"),
("C", "X2"),
("C", "X2"),
("C", "X1"),
("B", "X1"),
], ["TYPE", "CODE"])
dummies_df = spark_get_dummies(df)
dummies_df.show()
You will get:

Answer 5

The first step is to make a DataFrame from your CSV file.
See Get CSV to Spark dataframe ; the first answer gives a line by line example.
Then you can add the columns. Assume you have a DataFrame object called df, and the columns are: [ID, TYPE, CODE].
The rest van be fixed with DataFrame.withColumn() and pyspark.sql.functions.when:
from pyspark.sql.functions import when
df_with_extra_columns = df.withColumn("e_TYPE_A", when(df.TYPE == "A", 1).otherwise(0).withColumn("e_TYPE_B", when(df.TYPE == "B", 1).otherwise(0)
(this adds the first two columns. you get the point.)