I'm updating a value inside an array. But, I want that the update validates that the value cannot be less than zero.
{
_id: ObjectId(),
items: [
{
_id: ObjectId(),
stock: 5
}
]
}
In this case, if I want to decrease stock in -6. I need that the query raise an exception or something similar.
I was trying with two queries. One to know the actual value and then if the subtraction was > 0, I did the update.
Is there a way to make this in one query?
You can take advantage of the fact that ObjectId is unique in for each element in the array and use the $ positional update operator to do this beautifully
from bson.objectid import ObjectId
collection.update_one(
{"items": {
"$elemMatch": {
"_id" : ObjectId("58ccc8c2dbe8051261b38e58"),
"stock": {"$gt": 0 }
}
}},
{"$inc": {"items.$.stock": -6 }}
)
Related
I am fairly new to MongoDB and cant seem to find a solution to this problem.
I have a database of documents that has this structure:
{
id: 1
elements: [ {elementId: 1, nr1: 1, nr2: 3}, {elementId:2, nr1:5, nr2: 10} ]
}
I am looking for a query that can add a value nr3 which is for example nr2/nr1 to all the objects in the elements array, so that the resulting document would look like this:
{
id: 1
elements: [ {elementId: 1, nr1: 1, nr2: 3, nr3:3}, {elementId:2, nr1:5, nr2: 10, nr3: 2} ]
}
So I imagine a query along the lines of this:
db.collection.updateOne({id:1}, {$set:{"elements.$[].nr3": nr2/nr1}})
But I cant find how to get the value of nr2 and nr1 of the same object in the array.
I found some similar questions on stackoverflow stating this is not possible, but they were 5+ years old, so I thought maybe they have added support for something like this.
I realize I can achieve this with first querying the document and iterate over the elements-array doing updates along the way, but for the purpose of learning I would love to see if its possible to do this in one query.
You can use update with aggregation pipeline starting from MongoDB v4.2,
$map to iterate loop of elements
divide nr2 with nr1 using $divide
merge current object and new field nr3 using $mergeObjects
db.collection.updateOne(
{ id: 1 },
[{
$set: {
elements: {
$map: {
input: "$elements",
in: {
$mergeObjects: [
"$$this",
{ nr3: { $divide: ["$$this.nr2", "$$this.nr1"] } }
]
}
}
}
}
}]
)
Playground
db.collection.update(
{ id:1},
{ "$set": { "elements.$[elem].nr3":elements.$[elem].nr2/elements.$[elem].nr1} },
{ "multi": true }
);
I guess this should work
For example, I want to update half of data whose _id is an odd number. such as:
db.col.updateMany({"$where": "this._id is an odd number"})
Instead of integer, _id is mongo's ObejectId which be regard as hexadecimal "string". It is not supported to code as:
db.col.updateMany(
{"$where": "this._id % 2 = 1"},
{"$set": {"a": 1}}
)
so, what is the correct format?
And what if molding according to _id？
This operation can also be done using two database calls.
Get List of _id from collection.
Push only ODD _id into an array.
Update the collection.
Updating the collection:
db.collection.update(
{ _id: { $in: ['id1', 'id2', 'id3'] } }, // Array with odd _id
{ $set: { urkey : urValue } }
)
I have a collection full of products each of which has a subdocument array of up to 100 variants (SKUs) of that product:
e.g.
{
'_id': 12345678,
'handle': 'my-product-handle',
'updated': false
'variants': [
{
'_id': 123412341234,
'sku': 'abc123',
'inventory': 1
},
{
'_id': 123412341235,
'sku': 'abc124',
'inventory': 2
},
...
]
}
My goal is to be able to update the inventory quantity of all instances of a SKU number. It is important to note that in the system I'm working with, SKUs are not unique. Therefore, if a SKU shows up multiple times in a single product or across multiple products, they all need to be updated to the new inventory quantity.
Furthermore, I need the "updated" field to be changed to "true" *only if the inventory quantity for that SKU has changed"
As an example, if I want to update all instances of SKU "abc123" to have 25 inventory, the example of above would return this:
{
'_id': 12345678,
'handle': 'my-product-handle',
'updated': true
'variants': [
{
'_id': 123412341234,
'sku': 'abc123',
'inventory': 25
},
{
'_id': 123412341235,
'sku': 'abc124',
'inventory': 2
},
...
]
}
Thoughts?
MongoDB 3.6 has introduced the filtered positional operator $[<identifier>] which can be used to update multiple elements of an array which match an array filter condition. You can read more about this operator here: https://docs.mongodb.com/manual/reference/operator/update/positional-filtered/
For example, to update all elements of the variants array where sku is "abc123" across every document in the collection:
db.collection.update({}, { $set: { "variants.$[el].inventory": 25 }}, { multi: true, arrayFilters: [{ "el.sku": "abc123"}] })
Unfortunately I'm not aware of any way in a single query to update a document's field based on whether another field in the document was updated. This is something you would have to implement with some client-side logic and a second query.
EDIT (thanks to Asya's comment):
You can do this in a single query by only matching documents which will be modified. So if nMatched and nModified are necessarily equal, you can just set updated to true. For example, I think this would solve the problem in a single query:
db.collection.update({ variants: { $elemMatch: { inventory: { $ne: 25 }, sku: "abc123" } } }, { $set: { "variants.$[el].inventory": 25, updated: true }}, { multi: true, arrayFilters: [{ "el.sku": "abc123"}] })
First you match documents where the variants array contains documents where the sku is "abc123" and the inventory does not equal the number you are setting it to. Then you go ahead and set the inventory on all matching subdocuments and set updated to true.
I've got a mongodb aggregation pipeline with a $project stage and I'd like to include certain fields only if conditions are met. Specifically, I'd like to exclude the _id in one condition and include a second field 'second_id' in the other condition.
I know that it's not possible (yet) to exclude fields from a mongodb $project, but is it possible to conditionally include them?
Is there a way to conditionally exclude the _id field? It accepts a 0 or 1, but what if I want to determine that 0 or 1 based on an if statement. How would this be done?
Pseudocode for _id:
$project: { _id: { $ifNull: [ "$user_id", 0 ] } }
The main use of this would be to use the doc.user_id as the result _id, or allow mongodb to create a new autoincrement _id if that user_id is null.
There isn't a way currently to do this within the $project stage, but you can use the $redact stage to remove the field conditionally (i.e. you set the value to 0 like you are doing in your example.
db.collection.aggregate(
... matching and stuff ...
{$project: { _id: { $ifNull: [ "$user_id", 0 ] } }},
{$redact: {
{$cond: {
if: { $eq: [ "$user_id", 0 ] },
then: '$$PRUNE',
else: '$$DESCEND'
}}
}
I have a trick for this one:
"_id": {"$cond": [{"$eq": ["$user_id", null]}, "$nonExistinField", "$user_id"]}
Maybe this was not doable when the question was asked, but now it is.
There is a way to conditionally include/exclude a particular field in $project stage.
This can be achieved using $cond to evaluate your condition, and then return either '$true' or '$false'
{
myConditionalField:{$cond:{
if:{
$eq:['$some_field','some_value']
},
then:'$false',
else:'$true'
}}
}
Here, the field myConditionalField will be projected only if the value of some_field from previous stage matched some_value.
NOTE: Its assumed here that myConditionalField already exists from a previous stage. If it doesn't, then the else should be $some_field or whatever field you want to be projected.
In my database I have a field of name. In some records it is an empty string, in others it has a name in it.
In my query, I'm currently doing:
db.users.find({}).sort({'name': 1})
However, this returns results with an empty name field first, then alphabetically returns results. As expected, doing .sort({'name': -1}) returns results with a name and then results with an empty string, but it's in reverse-alphabetical order.
Is there an elegant way to achieve this type of sorting?
How about:
db.users.find({ "name": { "$exists": true } }).sort({'name': 1})
Because after all when a field you want to sort on is not actually present then the returned value is null and therefor "lower" in the order than any positive result. So it makes sense to exclude those results if you really are only looking for something with a matching value.
If you really want all the results in there and regarless of a null content, then I suggest you "weight" them via .aggregate():
db.users.aggregate([
{ "$project": {
"name": 1,
"score": {
"$cond": [
{ "$ifNull": [ "$name", false ] },
1,
10
]
}
}},
{ "$sort": { "score": 1, "name": 1 } }
])
And that moves all null results to the "end of the chain" by assigning a value as such.
If you want to filter out documents with an empty "name" field, change your query: db.users.find({"name": {"$ne": ""}}).sort({"name": 1})