I have a SQL Query, where I need the week ending date to appear as Monday. I tested the following code, but received responses on Saturday, Sunday, Monday, etc. Please help?
SELECT DATEADD(DD, 7-(DATEPART(DW, MIN([Date])))
, MIN([Date])) AS EndOfWeek, COUNT(*) AS TermsPerWeek
FROM Table
WHERE [Date] NOT LIKE 'null'
AND ([Date] LIKE '%2016%' OR [Date] LIKE '%2017%')
GROUP BY DATEPART(WEEK,[Date]);
Using set datefirst:
set datefirst = 2
This will treat the start of the week as Tuesday, and the end as Monday.
Related
timestamp with timezone is this - 2020-05-31T10:05:07Z
this is not working, despite referencing official documentation. I need to extract may 2020 or separate month and year to compare against May 2020
SELECT date_trunc('hour', TIMESTAMP '2020-05-31T10:05:07Z')
SELECT date_part('day', TIMESTAMP '2020-05-31T10:05:07Z');
If you want to check if a timestamp value is "may 2020", you have different options.
to_char(the_value, 'yyyy-mm') = '2020-05'
or
extract(month from the_value) = 5
and extract(year from the_value) = 2020
or
(extract(month from the_value), extract(year from the_value)) = (5, 2020)
extract() and date_part() are the same thing - but I prefer the standard compliant extract() version.
demo:db<>fiddle
You need to_char() to format a date or timestamp. Mon gives you the first three letters of a month name:
SELECT
to_char(
TIMESTAMP '2020-05-31T10:05:07Z',
'Mon YYYY'
)
Returning the entire month name you can use Month instead of Mon. But, for some reasons, the length of the Month value is fixed to the longest month name available. That means May is returned with right padded spaces. To avoid this, you need to add the modifier FM:
SELECT
to_char(
TIMESTAMP '2020-05-31T10:05:07Z',
'FMMonth YYYY'
)
I am currently writing a Crystal Report that has a DB2 query as its backend. I have finished the query but am stuck on the date portion of it. I am going to be running it twice a month - once on the 16th, and once on the 1st of the next month. Here's how it should work:
If I run it on the 16th of the month, it will give me results from the 1st of that same month to the 15th of that month.
If I run it on the 1st of the next month, it will give me results from the 16th of the previous month to the last day of the previous month.
This comes down a basic bi-monthly report. I've found plenty of hints to do this in T-SQL, but no efficient ways on how to accomplish this in DB2. I'm having a hard time wrapping my head around the logic to get this to consistently work, taking into account differences in month lengths and such.
There are 2 expressions for start and end date of an interval depending on the report date passed, which you may use in your where clause.
The logic is as follows:
1) If the report date is the 1-st day of a month, then:
DATE_START is 16-th of the previous month
DATE_END is the last day of the previous month
2) Otherwise:
DATE_START is 1-st of the current month
DATE_END is 15-th of the current month
SELECT
REPORT_DATE
, CASE DAY(REPORT_DATE) WHEN 1 THEN REPORT_DATE - 1 MONTH + 15 ELSE REPORT_DATE - DAY(REPORT_DATE) + 1 END AS DATE_START
, CASE DAY(REPORT_DATE) WHEN 1 THEN REPORT_DATE - 1 ELSE REPORT_DATE - DAY(REPORT_DATE) + 15 END AS DATE_END
FROM
(
VALUES
DATE('2020-02-01')
, DATE('2020-02-05')
, DATE('2020-02-16')
) T (REPORT_DATE);
The result is:
|REPORT_DATE|DATE_START|DATE_END |
|-----------|----------|----------|
|2020-02-01 |2020-01-16|2020-01-31|
|2020-02-05 |2020-02-01|2020-02-15|
|2020-02-16 |2020-02-01|2020-02-15|
In Db2 (for Unix, Linux and Windows) it could be a WHERE Condition like
WHERE
(CASE WHEN date_part('days', CURRENT date) > 15 THEN yourdatecolum >= this_month(CURRENT date) AND yourdatecolum < this_month(CURRENT date) + 15 days
ELSE yourdatecolum > this_month(CURRENT date) - 1 month + 15 DAYS AND yourdatecolum < this_month(CURRENT date)
END)
Check out the THIS_MONTH function - there are multiple ways to do it. Also DAYS_TO_END_OF_MONTH might be helpful
I want to just select data for the current week. So...
If the current date is a Monday just select Monday
If the current date is a Tuesday select Monday and Tuesday's data
If the current date is Wednesday select Monday, Tuesday and Wednesday
...and so on. I want it to reset on Sunday and I believe it's some kind of "where" clause just don't know what. As you can see below I'm just counting the number of pieces into the oven and want it to accumulate as the week goes on and then reset on Sunday.
select
count(*) as PiecesIntoOven
from ovenfeederfloat
where...??
Thanks for the help.
If you're looking to do this in Sql Server, see below. Essentially this converts the current date to its numeric (0-6) value, then finds the 0th date for that week and uses it to set the lower bound of the where clause.
select sum(numberofpieces)
from Test
where dateofwork <= getdate()
and dateofwork >= (DATEADD(DAY, DATEPART(WEEKDAY,getdate()) * -1, getdate()) + 1)
Note that the '0' value is impacted by DATEFIRST. https://stackoverflow.com/a/1113891/4824030
I'm not certain how to do this in Oracle. Something like the below should work, but it's being finicky in sqlfiddle.
select sum(numberofpieces)
from Test
where dateofwork <= current_timestamp
and dateofwork >= (((to_char(level+trunc(current_timestamp,'D'),'Day') * -1) + current_timestamp) + 1)
Ive this query which return data for 30 days from current date , need to modify it to return data for current month only not 30 days from current date
SELECT count(1) AS counter FROM users.logged WHERE createddate >=
date_trunc('month', CURRENT_DATE);
any tips how to tweak this query , at based on Postgres
regards
Something like this should work.
SELECT count(1) AS counter
FROM users.logged
WHERE date_trunc('month', createddate) = date_trunc('month', current_date);
It is already supposed to return the values in current month. Truncation does the conversion 10 Nov 2013 14:16 -> 01 Nov 2013 00:00 and it will return the data since the beginning of this month. The problem seems to be something else.
Ive this query which return data for 30 days from current date , need to modify it to return data for current month only not 30 days from current date
That's incorrect. Your query:
SELECT count(1) AS counter FROM users.logged WHERE createddate >= date_trunc('month', CURRENT_DATE);
returns all dates >= Nov 1st 00:00:00, in other words what you say that you want already. Or then, you've simplified your query and left out the more important bits — those that are broken. If not:
It might be that you've dates in the future and that you're getting incorrect counts as a result. If so, add an additional criteria in the where clause:
AND created_date < date_trunc('month', CURRENT_DATE) + interval '1 month'
It might also be that your sample data has a bizarre row with a time zone such that it looks like the timestamp is from this month but the date/time arithmetics land it last month.
This is will give you data for the current month only. I try to extract month and year. The last step is you can compare created date against current date-time.
SELECT count(1) AS counter
FROM users.logged
WHERE
EXTRACT(MONTH FROM createddate) = EXTRACT(MONTH FROM current_date)
AND EXTRACT(YEAR FROM createddate) = EXTRACT(YEAR FROM current_date);
I work at a college and our student management systems academic year start date is determined by the Monday on or before the 1st of August. I need to match this in my query, is there a way to easily get the date of the Monday on or before this date.
The accepted answer didn't work for me because I needed both a Sunday week and a Monday week in the same query. This works across different "datefirst" settings:
SELECT DATEADD(d, -((DATEPART(WEEKDAY, '20110515') - DATEPART(dw, '19000101') + 7) % 7), '20110515')
"DATEPART(dw, '19000101')" will determine your "datefirst" setting since 1900-01-01 was on a Monday. If you want a Tuesday based week, you can change 19000101 to 19000102.
BTW, '20110515' is the only date format that works across all SQL Server culture settings. Dates like '2011-05-06' will get mis-interpreted in certain countries. (credit to Itzik Ben-Gan for pointing this out)
set datefirst 1; -- Make Monday the first day of the week
select dateadd(dd, -1*(datepart(dw, '2009-08-01')-1), '2009-08-01')
Returns July 27th, 2009, which is the Monday on or before August 1. Change it to 2005 when Aug 1 was a Monday and the query will return 08-01
You could use datepart to get the weekday, and then do a little math to back into your monday. This example is using the US default of datefirst 7 (in which Monday is day 2 of the week). Adjust the days to add to be which day of the week Monday is for your locale.
select dateadd(dd, -datepart(dw, '2009-08-01') + 2, '2009-08-01')
very hacky
DECLARE #weekday int
SELECT #weekday = DATEPART(WEEKDAY, '1-Aug-2009')
SELECT CASE
WHEN #weekday = 1 THEN '1-Aug-2009' ELSE DATEADD ( dd,(#weekday-2)*-1, '1-Aug-2009')
END
This is a generic algorithm that will return the first Monday of any month (#inputdate):
DATEADD(wk, DATEDIFF(wk, 0, dateadd(dd, 6 - datepart(day, #inputDate), #inputDate)), 0)
It is a common method for getting the first monday of the month in SQL Server. This link explains how the above calculation works along with many other date calculations.
Here is how the above algorithm could be used to get the Monday on or before the 1st day of a month:
-- Set month to get Monday before or at 1st of month.
DECLARE #inputDate DATETIME
SET #inputDate = '2009-08-01'
-- Get first Monday of month.
DECLARE #firstMonday DATETIME
SET #firstMonday = DATEADD(wk, DATEDIFF(wk, 0, dateadd(dd, 6 - datepart(day, #inputDate), #inputDate)), 0)
-- Determine date for first Monday on or before 1st of month.
DECLARE #startDate DATETIME
SET #startDate = #firstMonday
IF #firstMonday > #inputDate
SET #startDate = DATEADD(wk, -1, #firstMonday)
SELECT #startDate