Running functions in sequence - sprite-kit

Question

I am trying to make a game that starts after a 3 second delay. So I am trying to add a sequence, so that the startGame function is called in a sequence after a delay. I can then call that function with the delay included at the beginning, but I keep getting an error when I try the run the sequence at the end of the second function.
I have the start game function:
func startGame(){
let spawn = SKAction.run(createEnemy)
let wait = SKAction.wait(forDuration: 2)
let spawnSequence = SKAction.sequence([wait, spawn])
let spawnForever = SKAction.repeatForever(spawnSequence)
self.run(spawnForever)
}
and then I have another function that uses that function in a sequence to add a delay.
func beginGame(){
let countdown = SKAction.wait(forDuration: 3)
let startGame = SKAction.run(self.startGame)
let startSequence = SKAction.sequence([countdown, startGame])
**self.beginGame().run(startSequence)**
}
I then call the beginGame() function at the along with the setup function. along with the setup function at the end.
scene.setup()
scene.beginGame()
I am getting an "Value of tuple '()' has no member 'run'"
Sorry for the stupid question, I'm a beginner at swift.

Answer 1

Try
let spawn = SKAction.run { self.createEnemy() }
and
let startGame = SKAction.run { self.startGame() }
run block is a closure so it might need the brackets
try this...
func startGame() -> SKAction {
let spawn = SKAction.run { self.hello() }
let wait = SKAction.wait(forDuration: 2)
let spawnSequence = SKAction.sequence([wait, spawn])
let spawnForever = SKAction.repeatForever(spawnSequence)
return spawnForever
}
func beginGame() {
let countdown = SKAction.wait(forDuration: 3)
let startGame = self.startGame()
let startSequence = SKAction.sequence([countdown, startGame])
}
self.beginGame()

Answer 2

SKActions should be run on a node. Your line of code
self.beginGame().run(startSequence) appears to be trying to run your sequence on the function beginGame(). Because beginGame()which does not have a defined return type.
According to https://developer.apple.com/library/content/documentation/Swift/Conceptual/Swift_Programming_Language/Functions.html
Functions without a defined return type return a special value of type
Void. This is simply an empty tuple, which is written as ().
and as the compiler is telling you, you cannot use run on a tuple.