saved movie in matlab cannot be played - matlab

I have created a movie in matlab and I want to save it. I wrote below code to do that, it shows the movie when the code is running correctly but the file which have been saved, can not be played. The error is: "could not determine type of stream"
clear all
close all
l = 27;
r = 4; noise_t = 0.02; v0 = 0.1; nn = 300;
x = rand(1,nn).*l; y = rand(1,nn).*l; vx = 0.1.*(rand(1,nn)-0.5.*ones(1,nn)); vy = 0.1.*(rand(1,nn)-0.5.*ones(1,nn));
figure('Color',[0 0 0])
axis([0 115 0 40])
axis('square')
hold on
vidObj = VideoWriter('che.avi');
open(vidObj);
time = 900;
neigh=[];
eigh=[];
for t = 1:time;
eig=[];
for number = 1:nn;
distance(1:nn) = (ones(1,nn).*x(number)-x).^2 + (ones(1,nn).*y(number)-y).^2;
neighbour_s = distance < r^2;
eig(1,nn) = sum(neighbour_s);
a = dot(double(neighbour_s),vx)/(sum(neighbour_s));
b = dot(double(neighbour_s),vy)/(sum(neighbour_s));
vx1(number) = a/norm([b,a]); vy1(number) = b/norm([b,a]); mvx(number) = vx1(number); mvy(number) = vy1(number);
end
vx_center = noise_t .*(rand(1,nn)-0.5); vy_center = noise_t .*(rand(1,nn)-0.5);
vx = mvx + vx_center; vy = mvy + vy_center;
x = x + vx; y = y + vy;
index = (x < 0); x(index) = rem(x(index),l) + l;
index = (y < 0); y(index) = rem(y(index),l) + l;
index = (x > l); x(index) = rem(x(index),l);
index = (y > l); y(index) = rem(y(index),l);
eigh = [eigh;eig];
cla
vecc=eigh(:);
vecc= vecc(find(vecc>0));
hist(vecc,80)
drawnow
currFrame = getframe;
writeVideo(vidObj,currFrame);
drawnow
end

It is necessary for you to explicitly close the VideoWriter object using the close method when you are done writing new frames to it. This will finalize the video and make it playable.
% At the end of your script
close(vidObj)

Related

Servo motor routing according to Matlab x, y, z coordinates

I work to about missile routing. I calculated throuhout the flight x,y,z coordinates of missile . I have data set about missile x,y,z coordinates. My goal is to move the servo motor according to x, y, z coordinates.
My input is 3-dimensional(x,y,z). I want to simulate in two dimensions. And for this I use vectoral calculation. The servo motor can take values between 0-1. But the result larger than 1 . When the results are reduced at the same rate, result is smaller than 0. But I get still the error
Undefined function 'writePosition' for input arguments of type 'matlab.graphics.chart.primitive.Surface'.
I will be grateful if you could help me.
My data example:
missile_x = 0.015
missile_y = 0.054
missile_z = 0.254
missile_flight = 0.00018794
My flight rotation code:
missile_x = vpa(Xval{id}(k)/10,5)
missile_y = vpa(Yval{id}(k)/10,5)
missile_z = vpa(Zval{id}(k)/10,5)
missile_flight = vpa(0.00555556*(missile_x^2+missile_y^2+missile_z^2)^1/2,5)
writePosition(s, missile_flight);
current_pos = readPosition(s);
current_pos = current_pos*missile_flight;
fprintf('Current motor position is %d degrees\n', current_pos);
pause(2);
Missile X,Y,Z calculation code:
dt = 0.005; %time step
g = 9.81; %gravity
ro = 1.2; %air density
A = pi*(0.2)^2; % reference area
Vmag = 0; % missile velocity vectoral value [m/sn]
t = 0;
T(1) = t;
U(1) = 0; %the missile is initially at rest at t = 0; So the velocity is 0
V(1) = 0;
W(1) = 0;
X(1) = X0;
Y(1) = Y0;
Z(1) = Z0;
n = 1;
h = interp2(x_terrain, y_terrain, h_terrain,X(1), Y(1));
while (Z(n) >= h)
[Thx, Thy, Thz] = thrust(t, Thmag0, theta, phi, Tburn, U(n), V(n), W(n));
Vmag = (U(n)^2 + V(n)^2 + W(n)^2)^(1/2);
Thmag = (Thx^2 + Thy^2 + Thz^2)^(1/2);
m = mass(t, m0, mf, Tburn);
[rho,sound_speed] = atmosphere(Z(n));
Cd = drag_coeff(Vmag,sound_speed);
U(n+1) = U(n) + (Thx/m - (Cd*rho*A/(2*m))*(U(n)*(U(n)^2+V(n)^2+W(n)^2)^(1/2)))*dt;
V(n+1) = V(n) + (Thy/m - (Cd*rho*A/(2*m)*(V(n)*(U(n)^2+V(n)^2+W(n)^2)^(1/2))))*dt;
W(n+1) = W(n) + (Thz/m - (Cd*rho*A/(2*m))*(W(n)*(U(n)^2+V(n)^2+W(n)^2)^(1/2)) - g)*dt;
X(n+1) = X(n) + U(n+1)*dt;
Y(n+1) = Y(n) + V(n+1)*dt;
Z(n+1) = Z(n) + W(n+1)*dt;
h = interp2(x_terrain, y_terrain, h_terrain, ...
X(end), Y(end));
t = t + dt;
T(n+1) = t;
n = n+1 ;
end
Tval = T;
Xval = X;
Yval = Y;
Zval = Z;

how to Improve the speed matlab

This is my matlab code. It runs too slow and I had no clue how to improve it.
Could you help me to improve the speed?
What I would like to do is to create some random points and then remove the random points to make them similar to my target points.
syms Dx Dy p q;
a = 0;
num = 10;
x = rand(1,num);
y = rand(1,num);
figure(1)
scatter(x,y,'.','g')
%num_x = xlsread('F:\bin\test_2');% num 1024
%figure(2)
%scatter(num_x(:,1),num_x(:,2),'.','r');
q = 0;
num_q = 10;
x_q = randn(1,num_q);
y_q = randn(1,num_q);
%figure(2)
hold on;
scatter(x_q,y_q,'.','r')
for i = 1:num_q;
for j = 1:num_q;
qx(i,j) = x_q(i) - x_q(j);
qy(i,j) = y_q(i) - y_q(j);
%qx(i,j) = num_x(i,1) - num_x(j,1);
%qy(i,j) = num_x(i,2) - num_x(j,2);
%d~(s(i),s(j))
if ((qx(i,j))^2+(qy(i,j)^2))> 0.01 % find neighbours
qx(i,j) = 0;
qy(i,j) = 0;
end
end
end
for i = 1:num_q;
for j = 1:num_q;
if qx(i,j)>0&&qy(i,j)>0
q = q + exp(-(((Dx - qx(i,j))^2)+((Dy - qy(i,j))^2))/4);%exp(-(((Dx - qx(i,j))^2)+((Dy - qy(i,j))^2))/4);
end
end
end
%I = ones(num,num); % I(s) should from a grayscale image
%r = 1./sqrt(I);
for s = 1:100;
for i = 1:num;
for j = 1:num;
dx(i,j) = x(i) - x(j);
dy(i,j) = y(i) - y(j);
%d~(s(i),s(j))
if ((dx(i,j))^2+(dy(i,j)^2))> 0.05 % delta p, find neighbours
dx(i,j) = 0;
dy(i,j) = 0;
end
end
end
p = 0;
for i = 1:num;
for j = 1:num;
if dx(i,j)>0&&dy(i,j)>0
p = p + exp(-(((Dx - dx(i,j))^2)+((Dy - dy(i,j))^2))/4);
end
end
end
p = p - q;
sum = 0;
for i = 1:num;
for j = 1:num;
if dx(i,j)>0&&dy(i,j)>0;
kx(i,j) = (1/2)*(Dx-dx(i,j))*exp((-(Dx-dx(i,j))^2+(Dy-dy(i,j))^2)/4);
ky(i,j) = (1/2)*(Dy-dy(i,j))*exp((-(Dx-dx(i,j))^2+(Dy-dy(i,j))^2)/4);
end
end
end
sum_x = ones(1,num);% 1行N列0矩阵
sum_y = ones(1,num);
%fx = zeros(1,num);
for i = 1:num;
for j = 1:num;
if dx(i,j)>0&&dy(i,j)>0;
fx(i) = p*kx(i,j);% j is neighbour to i
fy(i) = p*ky(i,j);
%fx(i) = matlabFunction(fx(i));
%fy(i) = matlabFunction(fy(i));
%P =quad2d(#(Dx,Dy) fx,0,0.01,0,0.01);
%fx =quad(#(Dx) fx,0,0.01);
%fx(i) =quad(#(Dy) fx(i),0,0.01);
%Q =quad2d(#(Dx,Dy) fy,0,0.01,0,0.01);
fx(i) = double(int(int(fx(i),Dx,0,0.01),Dy,0,0.01));
fy(i) = double(int(int(fy(i),Dx,0,0.01),Dy,0,0.01));
%fx(i) = vpa(p*kx(i,j));
%fy(i) = vpa(p*ky(i,j));
%fx(i) = dblquad(#(Dx,Dy)fx(i),0,0.01,0,0.01);
%fy(i) = dblquad(#(Dx,Dy)fy(i),0,0.01,0,0.01);
sum_x(i) = sum_x(i) + fx(i);
sum_y(i) = sum_y(i) + fy(i);
end
end
end
for i = 1:num;
sum_x = 4.*sum_x./num;
sum_y = 4.*sum_y./num;
x(i) = x(i) - 0.05*sum_x(i);
y(i) = y(i) - 0.05*sum_y(i);
end
a = a+1
end
hold on;
scatter(x,y,'.','b')
The fast version of your loop should be something like:
qx = bsxfun(#minus, x_q.', x_q);
qy = bsxfun(#minus, y_q.', y_q);
il = (qx.^2 + qy.^2 >= 0.01);
qx(il) = 0;
qy(il) = 0;
il = qx>0 && qy>0;
q = sum(exp(-((Dx-qx(il)).^2 + (Dy-qy(il)).^2)/4));
%// etc. for vectorization of the inner loops

Why are the final image dimensions in my perspective projection not in (-1,-1) to (1,1)?

I have implemented a perspective projection algorithm according to chapter 6 Computer Graphics Principles and Practices (CGP&P) by Foley, van Dam, Feiner, Hughes (2nd edition). I have
N'per = M * Sper * Spar * T (-prp) * R * T (-vrp).
As I understand it, the final image should be in canonical form size of (-1,-1) to (1,1) and z in (0,-1). However, the final image X-Y dimensions (see Figure 1) do not seem correct. I'm mostly trying to understand how the final image size is determined. I have included the matlab code below. My frustum (f) is defined by eyepoint (EP) at a specified lat/lon that has been converted to ECEF; distances: near plane (nDist) = 300; view plane (vDist) = 900; and far plane (fDist) = 25000. A line of sight (LOS) vector created at the EP is the center of projection. The frustum correctly finds and returns the buildings that within it along the LOS. Field of View is (10 deg x 10 deg). Now I'm just trying to project those buildings onto a defined window so that I can "quantize" (paint?) the grid and indicate which building is located at which x,y pair in the view plane. Unfortunately, because the window is not returning at the indicated size, it makes the painting more difficult for me. And besides, I'd just like to know what I'm doing wrong to not end up with the correct dimensions.
Matlab code (no attempts at optimizations or anything. just brute-force implementation!
function iPersProj = getPersProj(bldg, bi, f, plotpersp, fPersPlot)
color = [rand rand rand];
face = eFaces.bottom;
iPersProjBtm = persproj(f, bldg, face);
face = eFaces.top;
iPersProjTop = persproj(f, bldg, face);
iPersProj = [iPersProjTop;iPersProjBtm];
hold on;
scatter3(iPersProjTop(:,1), ...
iPersProjTop(:,2), ...
iPersProjTop(:,3),'+','CData',color);
scatter3(iPersProjBtm(:,1), ...
iPersProjBtm(:,2), ...
iPersProjBtm(:,3),'o','CData',color);
pPersProj=[iPersProjTop;
iPersProjTop(1,:); ...
iPersProjBtm; ...
iPersProjBtm(1,:); ...
iPersProjBtm(2,:); ...
iPersProjTop(4,:); ...
iPersProjTop(3,:); ...
iPersProjBtm(3,:); ...
iPersProjBtm(4,:); ...
iPersProjTop(2,:); ...
iPersProjTop(1,:)];
line (pPersProj(:,1), pPersProj(:,2),'Color',color);
text (pPersProj(1,1), pPersProj(1,2), int2str(bi));
end
function proj = persproj(f, bldg, face)
vrp = f.vC; %center view plane
vpn = f.Z; % LOS for frustum
cop = -f.EP;
F = f.vDist - f.nDist;
B = f.vDist - f.fDist;
umin = -5;
vmin = -5;
umax = 5;
vmax = 5;
R = getrotation (f);
Tvrp = gettranslation(-vrp);
ed = R * Tvrp * [f.EP 1]'; %translate eyepoint to camera?
prp = [0 0 ed(3)];
sh = getsh(prp, umax, umin, vmax, vmin);
Tprp = gettranslation(-prp);
vrpp = -prp(3); %(sh * Tprp * [0;0;0;1]); %vrp-prime per CGP&P
zmin = -(vrpp + F)/(vrpp+B);
zmax = -(vrpp + B)/(vrpp+B);
zprj = -vrpp/(vrpp+B);
sper = getsper(vrpp, B, umax, umin, vmax, vmin);
M=[ 1 0 0 0; ...
0 1 0 0; ...
0 0 1/(1+zmin) -zmin/(1+zmin); ...
0 0 -1 0];
proj = zeros(4,4);
for i=1:4
Q=bldg.coords(i,:,face);
uvdw = M * sper * sh * Tprp * R * Tvrp * [Q';1];
proj (i,1) = uvdw(1);
proj (i,2) = uvdw(2);
proj (i,3) = uvdw(3);
end
end
function sper = getsper (vrpz, B, umax, umin, vmax, vmin)
dx=umax-umin;
dy=vmax-vmin;
sper=zeros(4,4);
sper(1,1) = 2*vrpz/(dx*(vrpz+B));
sper(2,2) = 2*vrpz/(dy*(vrpz+B));
sper(3,3) = -1/(vrpz+B);
sper(4,4) = 1;
end
function sh = getsh (prp, umax, umin, vmax, vmin)
sx=umax+umin;
sy=vmax+vmin;
cw = [sx/2 sy/2 0 1]';
dop = cw - [prp 1]';
shx = - dop(1)/dop(3);
shy = - dop(2)/dop(3);
sh=zeros(4,4);
sh(1,1) = 1;
sh(2,2) = 1;
sh(3,3) = 1;
sh(4,4) = 1;
sh(1,3) = shx;
sh(2,3) = shy;
end
function R = getrotation (f)
rz = f.Z;
rx=cross(f.Y, rz);
rx=rx/norm(rx);
ry=cross(rz,rx);
R=zeros(4,4);
R(1,1:3) = rx;
R(2,1:3) = ry;
R(3,1:3) = rz;
R(4,4) = 1;
end
function T = gettranslation(p)
T = zeros(4,4);
T(1:3,4) = p';
T(1,1) = 1;
T(2,2) = 1;
T(3,3) = 1;
T(4,4) = 1;
end
Figure 1: Prospective Projection but dimensions are not (-1,-1) to (1,1)1

How to show 40 gabor filter in matlab

can someone help me how to show gabor filter in matlab, i can show it but its not what i want. this is my code :
[Gf,gabout] = gaborfilter1(B,sx,sy,f,theta(j));
G{m,n,i,j} = Gf;
and this is gabor filter class:
function [Gf,gabout] = gaborfilter(I,Sx,Sy,f,theta);
if isa(I,'double')~=1
I = double(I);
end
for x = -fix(Sx):fix(Sx)
for y = -fix(Sy):fix(Sy)
xPrime = x * cos(theta) + y * sin(theta);
yPrime = y * cos(theta) - x * sin(theta);
Gf(fix(Sx)+x+1,fix(Sy)+y+1) = exp(-.5*((xPrime/Sx)^2+(yPrime/Sy)^2))*cos(2*pi*f*xPrime);
end
end
Imgabout = conv2(I,double(imag(Gf)),'same');
Regabout = conv2(I,double(real(Gf)),'same');
gabout = sqrt(Imgabout.*Imgabout + Regabout.*Regabout);
Then, I imshow with this code:
imshow(G{m,n,i,j},[]);
and the results :
But i want this result, can someone help me how to slove this?
Use the following function. I hope this is useful.
----------------------------------------------------------------
gfs = GaborFilter(51,0.45,0.05,6,4);
n=0;
for s=1:6
for d=1:4
n=n+1;
subplot(6,4,n)
imshow(real(squeeze(gfs(s,d,:,:))),[])
end
end
Sample Image
----------------------------------------------------------------
function gfs = GaborFilter(winLen,uh,ul,S,D)
% gfs(SCALE, DIRECTION, :, :)
winLen = winLen + mod(winLen, 2) -1;
x0 = (winLen + 1)/2;
y0 = x0;
if S==1
a = 1;
su = uh/sqrt(log(4));
sv = su;
else
a = (uh/ul)^(1/(S-1));
su = (a-1)*uh/((a+1)*sqrt(log(4)));
if D==1
tang = 1;
else
tang = tan(pi/(2*D));
end
sv = tang * (uh - log(4)*su^2/uh)/sqrt(log(4) - (log(4)*su/uh)^2);
end
sx = 1/(2*pi*su);
sy = 1/(2*pi*sv);
coef = 1/(2*pi*sx*sy);
gfs = zeros(S, D, winLen, winLen);
for d = 1:D
theta = (d-1)*pi/D;
for s = 1:S
scale = a^(-(s-1));
gab = zeros(winLen);
for x = 1:winLen
for y = 1:winLen
X = scale * ((x-x0)*cos(theta) + (y-y0)*sin(theta));
Y = scale * (-(x-x0)*sin(theta) + (y-y0)*cos(theta));
gab(x, y) = -0.5 * ( (X/sx).^2 + (Y/sy).^2 ) + (2*pi*1j*uh)*X ;
end
end
gfs(s, d, :, :) = scale * coef * exp(gab);
end
end
Replace the "cos" component by complex part->complex(0, (2*pi*f*xprime)) ans also multiply equation by scaling factor of (1/sqrt(2*Sy*Sx)).

Perform step-by-step integral

I have this piece of code:
time = 614.4;
Uhub = 11;
HubHt = 90;
TI = 'A';
N1 = 4096;
N2 = 32;
N3 = 32;
L1 = Uhub*time;
L2 = 150;
L3 = 220;
V = L1*L2*L3;
gamma = 3.9;
c = 1.476;
b = 5.6;
if HubHt < 60
lambda1 = 0.7*HubHt;
else
lambda1 = 42;
end
L = 0.8*lambda1;
if isequal(TI,'A')
Iref = 0.16;
sigma1 = Iref*(0.75*Uhub + b);
elseif isequal(TI,'B')
Iref = 0.14;
sigma1 = Iref*(0.75*Uhub + b);
elseif isequal(TI,'C')
Iref = 0.12;
sigma1 = Iref*(0.75*Uhub + b);
else
sigma1 = str2num(TI)*Uhub/100;
end
sigma_iso = 0.55*sigma1;
%% Wave number vectors
ik1 = cat(2,(-N1/2:-1/2),(1/2:N1/2));
ik2 = -N2/2:N2/2-1;
ik3 = -N3/2:N3/2-1;
[x y z] = ndgrid(ik1,ik2,ik3);
k1 = reshape((2*pi*L/L1)*x,N1*N2*N3,1);
k2 = reshape((2*pi*L/L2)*y,N1*N2*N3,1);
k3 = reshape((2*pi*L/L3)*z,N1*N2*N3,1);
k = sqrt(k1.^2 + k2.^2 + k3.^2);
Now I should calculate
where
The procedure to calculate the integral is
At the moment I'm using this loop
E = #(k) (1.453*k.^4)./((1 + k.^2).^(17/6));
E_int = zeros(1,N1*N2*N3);
E_int(1) = 1.5;
for i = 2:(N1*N2*N3)
E_int(i) = E_int(i) + quad(E,i-1,i);
end
neglecting for the k>400 approximation. I believe that my loop is not right.
How would you suggest to calculate the integral?
I thank you in advance.
WKR,
Francesco
This is a list of correction from the more obvious to the possibly more subtle. (Indeed I start from what you wrote in the final part going upwards).
From what you write:
E = #(k) (1.453*k.^4)./((1 + k.^2).^(17/6));
E_int = zeros(1,N1*N2*N3);
E_int(1) = 1.5;
for i = 2:(N1*N2*N3)
%//No point in doing this:
%//E_int(i) = E_int(i) + quad(E,i-1,i);
%//According to what you write, it should be:
E_int(i) = E_int(i-1) + quad(E,i-1,i);
end
You could speed the whole thing up by doing
%//Independent integration on segments
Local_int = arrayfun(#(i)quad(E,i-1,i), 2:(N1*N2*N3));
Local_int = [1.5 Local_int];
%//integral additivity
E_int = cumsum(Local_int);
Moreover, if the known condition (point 2.) really is "... ( = 1.5 if k' = 0)", then the whole implementation should really be more like
%//Independent integration on segments
Local_int = arrayfun(#(i)quad(E,i-1,i), 2:(N1*N2*N3));
%//integral additivity + cumulative removal of queues
E_int = 1.5 - [0 fliplr(cumsum(fliplr(Local_int)))]; %//To remove queues