I followed the procedures in this question, and also tried setting individual text object with larger fonts. Here is my sample code:
hf = figure;
set(hf, 'DefaultAxesFontSize', 14)
hx = axes('Parent',hf);
[hx,hp1,hp2] = plotyy(hx, rand(10,1),rand(10,1),rand(10,1),rand(10,1),'scatter');
hlx = xlabel(hx(1), 'Only half of this line show up');
hl1 = ylabel(hx(1), 'Not usually truncated but less border');
hl2 = ylabel(hx(2), 'Only part of this line show up');
ht = title(hx(1), 'Too close to border');
As can be seen in the picture, the labels get truncated by the border of the figure. I have to drag the figure to very large - contrary to desired - in order to reveal all text.
How can I automatically set the text box according to the text font size, so that even for small graphs they don't get cut?
I know I can do it manually by setting Position of the axes but it's kind of manual and guess-and-try. Is there any automatic way to calculate the margins?
One thing that can be done is to calculate increased margin according to new text font size. Assume we know Matlab's default font size is 10, or otherwise get it by get(hf,'DefaultAxesFontSize').
Then get the relative position of the axes by get(hx, 'Position'), which gives four percentage values. First two define left and bottom margin. Since it's for the labels, increasing the font size from 10 to 14 means the text box should grow by 1.4 times. The next two numbers define the size of the axis. Since text boxes on both sides grow by 1.4 times, assuming original size being x, then new size is 1-[(1-x)*1.4] = 1.4x - 0.4.
Suggested workaround:
hf = figure;
set(hf, 'DefaultAxesFontSize', 14)
hx = axes('Parent',hf);
set(hx, 'Position', [1.4 1.4 1.4 1.4].*get(hx, 'Position')+ [0 0 -.4 -.4])
[hx,hp1,hp2] = plotyy(hx, rand(10,1),rand(10,1),rand(10,1),rand(10,1),'scatter');
hlx = xlabel(hx(1), 'Only half of this line show up');
hl1 = ylabel(hx(1), 'Not usually truncated but less border');
hl2 = ylabel(hx(2), 'Only part of this line show up');
ht = title(hx(1), 'Too close to border');
You may replace the manually entered number 1.4 with the ratio between newly assigned (bigger, hopefully) font size and the original size which is 10.
Related
I have a Matlab script that creates a Model Block for each element i found in a text file.
The problem is that all Models are created on each other in the window. So i'm trying to make a loop like:
for each element in text file
I add a Model block
I place right to the previous one
end
So it can look like this:
As you can see on the left, all models are on each other and I would like to place them like the one on the right.
I tried this:
m = mdlrefCountBlocks(diagrammeName)+500;
add_block('simulink/Ports & Subsystems/Model',[diagrammeName '/' component_NameValue]);
set_param(sprintf('%s/%s',diagrammeName,component_NameValue), 'ModelFile',component_NameValue);
size_blk = get_param(sprintf('%s/%s',diagrammeName,component_NameValue),'Position');
X = size_blk(1,1);
Y = size_blk(1,2);
Width = size_blk(1,3);
Height = size_blk(1,4);
set_param(sprintf('%s/%s',diagrammeName,component_NameValue),'Position',[X+m Y X+Width Y+Height]);
Inside the loop but it returns an error Invalid definition of rectangle. Width and height should be positive.
Thanks for helping!
The position property of a block does actually not contain its width and height, but the positions of the corners on the canvas (see Common Block Properties):
vector of coordinates, in pixels: [left top right bottom]
The origin is the upper-left corner of the Simulink Editor canvas before any canvas resizing. Supported coordinates are between -1073740824 and 1073740823, inclusive. Positive values are to the right of and down from the origin. Negative values are to the left of and up from the origin.
So change your code to e.g.:
size_blk = get_param(sprintf('%s/%s',diagrammeName,component_NameValue),'Position');
set_param(sprintf('%s/%s',diagrammeName,component_NameValue),'Position', size_blk + [m 0 0 0]);
I would like to add labels to some points plotted using the command scatter. For the sake of simplicity, let's say I have only one point:
x = 10;
pointSize = 100;
fontSize = 20;
P = scatter(x, 0, pointSize, [0,0,0], 'filled');
text(x, 0, 'pointLabel',...
'HorizontalAlignment', 'center',...
'VerticalAlignment', 'bottom',...
'FontSize', fontSize);
The problem with the previous commands is that the text pointLabel overlaps with the point P depending on the values assigned to the properties pointsize and fontSize.
I have read the documentation of the text command, but the examples only show how to put a label horizontally aligned with a specific point in the diagram. If the alignment needs to be horizontal it is easy, but I could not find a general way to compute the y coordinate of the label pointLabel from the values of the other dimensions.
Clearly I can reach a good alignment by testing various combinations of values, but I am looking for a general solution.
Is there anyone who can help me?
This assumes you are using >=R2014b, though it can also be accomplished in older versions using set and get commands.
When a text object is created, its default units are data coordinates, but those can be changed. In your case, I'd go with points.
x = 10;
pointSize = 100;
fontSize = 20;
P = scatter(x, 0, pointSize, [0,0,0], 'filled');
t = text(x, 0, 'pointLabel',...
'HorizontalAlignment', 'center',...
'VerticalAlignment', 'bottom',...
'FontSize', fontSize);
% It's always a good idea to switch back to the default units, so remember them.
originalUnits = t.Units;
t.Units = 'points';
% Shift the text up by the sqrt(pi)/2 times the radius of the point
t.Position(2) = t.Position(2) + sqrt(pointSize)/2;
t.Units = originalUnits;
Check out Text Properties for more info. If you want to get really sophisticated, you can use the read-only property Extent and your known marker size and position to calculate when a label is overlapping one of your points. Since the default unit is in data space, no conversions are necessary.
If you're working with an older version of MATLAB, all of these options and properties are still available, you just have to work a little harder to use them. For instance, you can't direction set the position as above, but you would instead use get to assign it to a temporary variable, change it, and then use set to update. More lines of code, but ultimately the same effect.
I have a project to detect an object with background subtraction. But I can only set minimumblobarea with minimum pixel.. in my case, I need to set minimunblobarea to detect object in width and height to get specific object.. example : if there is an object bigger than width and height that I've set before, that object can't be detected.. so what should I do?
I Use this code
http://www.mathworks.com/help/vision/examples/motion-based-multiple-object-tracking.html
vision.BlobAnalysis returns bounding boxes of the detected blobs. The bounding box is a 4-element array of the form [x, y, width, height]. Once you have the bounding boxes you can easily check with ones have the width or the height that is too big, and exclude them.
Let's say you have N bounding boxes returned by vision.BlobAnalysys as an N-by-4 matrix called bboxes. You can use logical indexing to find boxes that are too big:
bigBoxesIdx = (bboxes(:, 3) > maxWidth) | (bboxes(:,4) > maxHeight);
bigBoxesIdx is now a logical array, where you have 1's for boxes that are too big, and 0's for the ones that are not. Note that you have to use the |, which stands for "element-wise or", rather than ||.
Now to throw away the boxes that are too big you simply do
bboxes(bigBoxesIdx, :) = [];
I have a uitable with 6 row and 6 column and i want to show it in full screen mode for doing this i can change column width but i can't change row height.
Extent is Size of uitable rectangle, but it is read only properties.
With conventional approaches the only possibility to change the row height is by adjusting the 'FontSize' property.
The following function will give you a full-screen table. You can set up 'ColumnWidth' and 'FontSize' until it fills your screen entirely.
function fancyTable
columnwidth = { 1920/2 1920/2 };
FontSize = 135;
h = figure('units','normalized','Position',[0 0 1 1],...
'numbertitle','off','MenuBar','none');
defaultData = rand(5,2);
uitable(h,'Units','normalized','Position',[0 0 1 1],...
'Data', defaultData,...
'ColumnName', [],'RowName',[],...
'ColumnWidth', columnwidth,...
'FontSize', FontSize,...
'ColumnEditable', [false false],...
'ColumnFormat', {'numeric' , 'numeric'});
end
I don't see a simple solution to change the row-height independently from the font size.
But there are some ideas at undocumented Matlab.
"
7. JIDE customizations
... Similarly, this section explains how we can use JIDE to merge together adjacent cells:
"
Could be a fiddly workaround, and there are no code-examples.
You can e.g. use the findjobj utility from the file exchange.
It will get you to the underlying java object of the table, somewhere along the lines of:
t = uitable(...);
scrollPane = findjobj(t);
% not 100% sure about this, but there'll be a `UITablePeer` object somewhere within that scrollPane
jTable = scrollPane.getComponent(0);
This jTable will have a setRowHeight method inherited from http://docs.oracle.com/javase/7/docs/api/javax/swing/JTable.html
I noticed that sometimes, when I plot the bars using the functions bar() or hist(), the bars plotted have no border. They are a little bit less nice to see, and I would prefer the border or a little bit of space between them.
The figure shows what I got now, plotting three different datasets. The third graph is zoomed in order to show the lack of space between bars.
I get there this has something to do with the 'histc' parameters in bar function. Without the histc parameters the bars have some space between each others, but then the bar will be centered on the edges values, whereas I want the edges values to be, well, EDGES of each bar.
This is (the relevant part of) the code I used:
[...]
if edges==0
%these following lines are used to take the min and max of the three dataset
maxx=max(cellfun(#max, reshape(data,1,size(data,1)*size(data,2))));
minn=min(cellfun(#min, reshape(data,1,size(data,1)*size(data,2))));
edges=minn:binW:maxx+binW;
end
[...]
y{k}=histc(data{r,c}, edges);
bar(edges,y{k} , 'histc');
[...]
I think if you change the color of your bar plots you'll see that there actually is a border it just doesn't show up very well. You can also change the width of the bars so that they are more distinct.
% something to plot
data = 100*rand(1000,1);
edges = 1:100;
hData = histc(data,edges);
figure
subplot(2,1,1)
h1 = bar(edges,hData,'histc');
% change colors
set(h1,'FaceColor','m')
set(h1,'EdgeColor','b')
% Change width
subplot(2,1,2)
h1 = bar(edges,hData,0.4,'histc');
The EdgeColor and LineWidth properties of the Barseries object control the bar outlines. Try using the code and playing with the red, green, blue, and width values to get a better result.
red = 1;
green = 1;
blue = 1;
width = 3;
h = bar(edges,y{k} , 'histc');
set(h,'EdgeColor',[red green blue],'LineWidth',width);