View [
Size 400x400
button "click" [
view/flags [
Size 300x100
text "modal window"
]['modal 'pop-up]
]
]
Problem is if I click button 4 times it will create 4 modal window. But I want no other modal window if 1 modal window is already open. How can I do it
You have several typos in your code preventing it from working properly:
should be popup instead of pop-up.
flags in the block are expected to be words not lit-words, so it should be [modal popup].
After those fixes, your code works as expected.
Note: I think the /flags argument block should be improved to accept lit-words.
EDIT: /flags now accepts lit-words.
Related
I'd like to be able to toggle open the panel (termainl, debug, output, etc.. area) and focus on a specific custom view given an id. I know this is possible since there are focus commands for terminal debug etc but searching them up in the vscode source code just gives string references and not publicly usable functions. Any help would be appreciated. (Please don't give shortcut answers like ctrl+j, I want to do this with code)
I tried copying the format of the focus view commands above but the focus of the custom view didn't work. Seems like its not an automatic thing.
I think you want this. Every custom TreeView or WebView gets some commands added automatically by vscode. For example, my Editor Manager ViewContainer, with this view:
"views": {
"editorManager": [
{
"id": "editor-groups",
"name": "Groups",
"size": 1,
"visibility": "visible"
}
]
}
gets these commands added automatically (they can be found in the Keyboard Shortcuts, at least when the extension is activated):
editor-groups.focus
workbench.actions.treeView.editor-groups.refresh
workbench.actions.treeView.editor-groups.collapseAll
workbench.view.extension.editorManager
workbench.view.extension.editorManager.resetViewContainerLocation
You probably want the first one to focus your view in the Panel.
vscode.commands.executeCommand("editor-groups.focus");
During script execution a pop up won't go away, and it happens only through QTP(v12.02).
I am trying DOM to bypass the problem, the pop up event was on selection of a drop down value, so I used some code to find the correct index and use DOM to select the value
Browser().Page().WebList().Object.selectedIndex = itmindx
With this the pop up issue got resolved, but now to complete the process,I need to click the Save button which is disabled as the page didn't refreshed when the value was selected ( tried refreshing through QTP, tab out etc--didn't worked as it loads the previous value).So I used the fire event method
Browser().Page().WebList().Fireevent "onchange"
with this I ran in to the same issue of multiple pop ups. Used the following
Browser().Page().WebList().Object.onchange()
but then QTP won't executes the next line unless I hit enter externally on the pop up(multiple pop up is resovled but now QTP is stuck. I don't want to use RS.... Any solutions?
To enable the button
Browser().Page().WebButton().Object.disabled = false
Or
To hit enter for the popup
CreateObject("WScript.Shell").SendKeys("{ENTER}")
[ http://ss64.com/vb/sendkeys.html ]
Go for hitting the Enter button using SendKeys. It is not a good idea accessing DOM and change the state ourselves. There is a chance that you might miss potential defects!
I am trying to Right click on an element and then select an option "Rename" from the list. I have got "right clicking" working but can't select option from the list. Referred links 1, 2
Note 1:
1: On right click the menu options that are visible are native context menus. So, they don't appear in my DOM that I can see.
2: The App runs only in Chrome browser(not sure if it is a browser issue)
I have tried the following code:
browser.actions().mouseMove(elementVar).perform();
browser.actions().click(protractor.Button.RIGHT).click(protractor.Button.ARROW_DOWN).click(protractor.Button.ARROW_DOWN).click(protractor.Button.ARROW_DOWN).perform();
Consider, "Rename" to be the third option in the list.
Note 2:
If I am just running the app and enter 'R' from my keyboard, it selects the "Rename" option. But when I tried to run it in my test, it doesn't select the "Rename" option. See below code I tried:
browser.actions().mouseMove(elementVar).perform();
browser.actions().click(protractor.Button.ARROW_RIGHT).sendKeys('R',protractor.Key.ENTER).perform();
None of the above code works. Let me know if more information is required.
EDIT:
I am guessing the following to be happening:
once I mouse over, the script "right clicks" and after that the "tooltip" is displayed. Since the "tooltip" is displayed after "right click" I think the menu list goes to the background(the list is still visible along with the tool-tip), which is why the arrow down keys aren't working. Is this possible? If yes, how can I wait for the tooltip to be invisible and then right click?
Input: I tried to wait for tool-tip to be invisible and then right click, but still the "Arrow_down" doesn't work.
Is there a way to bring the menu list in the front once we have right clicked?
IMPORTANT:
I took a screenshot after I right clicked on the element, and the screenshot doesn't show the "menu list". Below is the code for screenshot:
browser.actions().click(protractor.Button.RIGHT).perform()
.then(function() {
browser.takeScreenshot().then(function(screenShot) {
writeScreenShot(screenShot, "image.png");
});
});
//writeScreenShot takes two variables actual screenshot data and the file name. And the screenshot is saved as "image.png"
What needs to be done?
When you send ARROW keys to the browser, you have to send them as keys instead of passing them to click() function and the ARROW_DOWN key is part of Key object and not BUTTON. Here's how -
browser.actions().mouseMove(elementVar).perform();
browser.actions().click(protractor.Button.RIGHT).sendKeys(protractor.Key.ARROW_DOWN).sendKeys(protractor.Key.ARROW_DOWN).sendKeys(protractor.Key.ARROW_DOWN).perform();
For your second try, you should send RIGHT in the place of protractor.Button.ARROW_RIGHT to right click. When you send two actions/keys to sendKeys() function, you have to join them using chord object which combines the action of pressing two keys at a time(ex: CTRL+C for copy). But in your case i don't think its really necessary. Here's how to use it -
browser.actions().mouseMove(elementVar).perform();
browser.actions().click(protractor.Button.RIGHT).sendKeys(protractor.Key.chord("r", protractor.Key.ENTER).perform(); //Not necessary as you wont be pressing R+ENTER in your keyboard
OR
browser.actions().click(protractor.Button.RIGHT).sendKeys('R').sendKeys(protractor.Key.ENTER).perform();
Hope this helps.
use XPath to solve your problem
browser.actions().mouseMove(target).perform();
browser.actions().click(protractor.Button.RIGHT).perform();
element(by.xpath('//*[#id="context-menu"]/ul/li[1]')).click();
In your case it will be "//*[#id="context-menu"]/ul/li[3]" most probably.
I want to push toolstripbutton down in my code and I can't seem to be able to do that. I know on Delphi RAD Studio or XE, you can do the following and cause the button to be pressed.
ToolStripButton1.Down := true;
The only ToolStripButton property I see that comes close to "down" is checked true or false. If I do set it to true, it only highlights the toolstripbutton not press it down.
Here is how the button looks when I put my mouse on it and click:
You can clearly see that the Zoom In button is down.
Here is how the button looks when I try to do the samething through my code by setting CheckOnClick true and Checked true.
In this image, the only thing you can see is the blue box around it. I suppose if I had used just the text on the button, you will see that the whole button filled with blue color to show that it was pressed.
I also have toolstrip button in my other program which acts the same way but I had to use imagelist control to switch between pressed or down or checked verses not pressed or down or checked.
So, is there a way to press the ToolStripButton programmatically in Delphi Prism or C#?
Set the ToolStripButton.CheckOnClick property to True. (It's found in the Behavior section of the Items Collection Editor.)
This makes clicking it just like toggling the Down property in a Delphi TSpeedButton (making it flat or depressed), and if ToolStripButton1.Checked is the equivalent of if SpeedButton1.Down in Delphi.
To set up the test, I did the following:
Created a new Winforms application
Dropped a ToolStrip onto the new MainForm
Added four ToolStripButton items and gave them images to make them easier to see.
Set the CheckOnClick property to True for each of them
Set the Checked property of toolStripButton1 to True;
Added the code below to toolStripButton1.Click
method MainForm.toolStripButton1_Click(sender: System.Object; e: System.EventArgs);
begin
toolStripButton2.Checked := not toolStripButton2.Checked;
toolStripButton4.Checked := toolStripButton2.Checked;
end;
Running the app (initial startup, toolStripButton1 checked and the others unchecked):
The first button is clearly down, and the rest are up.
After clicking toolStripButton1 once:
The first button is now up (unchecked) and the second and fourth are down (checked). (I should pay more attention to the consistency in sizing if I do successive images in future posts.)
If have placed this code in the preceding control in the 'Leave' event.
Private Sub PurposeComboBox_Leave(sender As Object, e As EventArgs) Handles PurposeComboBox.Leave
Me.AppliancesForSelectedFunctionToolStripButton.PerformClick()
End Sub
I do not know if you could place code in Form Load or not.
Hope this helps.
I'm using Fancybox afterShow to display image descriptions on the side via overlay like so:
afterShow : function (){
var description = "<div class='hidden_tab'>"+$("#tab").html()+"</div>"
$('#fancybox-overlay').html(description);
}
The problem is that I need modal to be false so users can click out. But the hidden_tab tabs, when clicked, also exit fancybox.
Is there a way to section where modal takes affect? Or a workaround? I have tried setting z-index for the hidden_tab to be high but this did not do the trick.
If you need to set modal : false then try adding closeClick : false (which prevents closing when clicking INSIDE fancybox)
BTW, the default value of modal is false. Don't assume that people will necessarily understand why modal was set to true in your script.